If
(a=
\sqrt{17}
),
(b=
\frac{33}{8}
), and
(c=4.13
), which number will be farthest to the right on the number line?

\(c\)

On converting the values to decimals, \(\sqrt{17}\approx 4.1231\), \(\frac{33}{8}=4.125\), and \(c=4.13\). Thus, \(4.13>4.125>4.1231\), so \(c\) is farthest to the right on the number line. The closest distractor is \(b\), but \(4.13\) is greater than \(4.125\). Exam tip: Convert irrational and fractional values to comparable decimal forms before ordering them.

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.