If A=-\sqrt{116}, B=-10.75, and C=-\frac{43}{4}, which point lies farthest to the left on the number line?
Answer and explanation
Correct answer: Point A
Since C=-\frac{43}{4}=-10.75, points B and C coincide. Also, \sqrt{116}\approx10.7703, so A=-\sqrt{116}\approx-10.7703. Among negative numbers, the smaller number lies farther left on the number line; therefore, point A is farthest left. Exam tip: When comparing negative numbers, the one with the greater absolute value is the smaller number.
Frequently asked questions
What is the correct answer to this question?
Point A
Why is this the correct answer?
Since C=-\frac{43}{4}=-10.75, points B and C coincide. Also, \sqrt{116}\approx10.7703, so A=-\sqrt{116}\approx-10.7703. Among negative numbers, the smaller number lies farther left on the number line; therefore, point A is farthest left. Exam tip: When comparing negative numbers, the one with the greater absolute value is the smaller number.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
