If A ∩ B = ∅, n(A) = 9, and n(B) = 11, what is n(A ∪ B)?
Answer and explanation
Correct answer: 20
For any two finite sets, n(A ∪ B) = n(A) + n(B) − n(A ∩ B). Since A ∩ B = ∅, its cardinality is zero. Thus n(A ∪ B) = 9 + 11 − 0 = 20. Equivalently, because the sets are disjoint, no element is counted twice, so their cardinalities can be added directly. Therefore, option B is correct.
Frequently asked questions
What is the correct answer to this question?
20
Why is this the correct answer?
For any two finite sets, n(A ∪ B) = n(A) + n(B) − n(A ∩ B). Since A ∩ B = ∅, its cardinality is zero. Thus n(A ∪ B) = 9 + 11 − 0 = 20. Equivalently, because the sets are disjoint, no element is counted twice, so their cardinalities can be added directly. Therefore, option B is correct.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).