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If A and B are finite sets, A is a proper subset of B, and n(A) = 6, which value of n(B) is impossible?

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Answer and explanation

Correct answer: 6

A proper subset of B means that every element of A belongs to B, but A and B are not equal. For finite sets, this necessarily gives n(A) < n(B). Since n(A) = 6, B must contain at least one additional element and therefore must have more than six elements. Hence n(B) = 6 is impossible. Values 7, 8, and 10 are all possible because B can be formed by adding one, two, or four new elements to A, respectively.

Tags

proper-subsetsfinite-setscardinalityset-inclusionmathematicsEqual sets and SubsetsSetsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

6

Why is this the correct answer?

A proper subset of B means that every element of A belongs to B, but A and B are not equal. For finite sets, this necessarily gives n(A) < n(B). Since n(A) = 6, B must contain at least one additional element and therefore must have more than six elements. Hence n(B) = 6 is impossible. Values 7, 8, and 10 are all possible because B can be formed by adding one, two, or four new elements to A, respectively.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Equal sets and Subsets.

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