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If \(A=\{2,5,7\}\), what is \(n(\mathcal{P}(A))\)?

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Answer and explanation

Correct answer: 8

The set \(A=\{2,5,7\}\) contains 3 distinct elements, so \(n(A)=3\). For a finite set with \(n\) elements, every element has two choices in forming a subset: it is either included or excluded. Consequently, the number of subsets, and hence the number of elements in the power set, is \(2^n\). Therefore, \(n(\mathcal{P}(A))=2^3=8\).

Tags

setspower setcardinalitysubsetsPower Set and SubsetsMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

8

Why is this the correct answer?

The set \(A=\{2,5,7\}\) contains 3 distinct elements, so \(n(A)=3\). For a finite set with \(n\) elements, every element has two choices in forming a subset: it is either included or excluded. Consequently, the number of subsets, and hence the number of elements in the power set, is \(2^n\). Therefore, \(n(\mathcal{P}(A))=2^3=8\).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Power Set and Subsets.

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