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If \(A=\{1,2,3\}\) and \(B=\{2,3,4,5\}\), how many elements does \(\mathcal{P}(A\cup B)\) contain?

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Answer and explanation

Correct answer: 32

First form the union by listing each distinct element only once: \(A\cup B=\{1,2,3,4,5\}\). Thus the union has 5 elements. For any finite set with n elements, its power set contains every possible subset, including the empty set and the full set, and its cardinality is \(2^n\). Hence \(|\mathcal{P}(A\cup B)|=2^5=32\). The repeated elements 2 and 3 are counted only once in the union, so option A is correct.

Tags

setspower setunioncardinalitysubsetsOperations on Sets (UnionIntersectionDifference)operations on sets union intersection differenceMathematics

Frequently asked questions

What is the correct answer to this question?

32

Why is this the correct answer?

First form the union by listing each distinct element only once: \(A\cup B=\{1,2,3,4,5\}\). Thus the union has 5 elements. For any finite set with n elements, its power set contains every possible subset, including the empty set and the full set, and its cardinality is \(2^n\). Hence \(|\mathcal{P}(A\cup B)|=2^5=32\). The repeated elements 2 and 3 are counted only once in the union, so option A is correct.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).

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