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If A = {1,2,3,4,5}, how many subsets in P(A) either contain both 2 and 3 or contain neither of them?

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Answer and explanation

Correct answer: 16

For the two elements 2 and 3, the condition allows exactly two possibilities: both are selected, or neither is selected. The other three elements, 1, 4, and 5, can each be selected or omitted independently, giving 2³ = 8 choices. Multiplying by the 2 allowed cases for the pair gives 2 × 8 = 16 subsets. Hence, option B is correct.

Tags

setscase countingpower setsubsetsPower Set and SubsetsMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

16

Why is this the correct answer?

For the two elements 2 and 3, the condition allows exactly two possibilities: both are selected, or neither is selected. The other three elements, 1, 4, and 5, can each be selected or omitted independently, giving 2³ = 8 choices. Multiplying by the 2 allowed cases for the pair gives 2 × 8 = 16 subsets. Hence, option B is correct.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Power Set and Subsets.

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