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How many elements are there in \(\mathcal{P}(\mathcal{P}(\{a\}))\)?

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Answer and explanation

Correct answer: 4

The set \(\{a\}\) has one element, so its power set has \(2^1=2\) elements: \(\varnothing\) and \(\{a\}\). Taking the power set once more gives a set with \(2^2=4\) elements. Therefore, \(|\mathcal{P}(\mathcal{P}(\{a\}))|=4\), so option B is correct. In general, if \(|A|=n\), then \(|\mathcal{P}(\mathcal{P}(A))|=2^{2^n}\).

Tags

setspower setiterated power setsingletonPower Set and SubsetsMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

4

Why is this the correct answer?

The set \(\{a\}\) has one element, so its power set has \(2^1=2\) elements: \(\varnothing\) and \(\{a\}\). Taking the power set once more gives a set with \(2^2=4\) elements. Therefore, \(|\mathcal{P}(\mathcal{P}(\{a\}))|=4\), so option B is correct. In general, if \(|A|=n\), then \(|\mathcal{P}(\mathcal{P}(A))|=2^{2^n}\).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Power Set and Subsets.

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