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If (x) is exactly midway between ( \sqrt{2} ) and ( \sqrt{8} ) on the number line, what is the value of (x)?यदि (x) संख्या रेखा पर ( \sqrt{2} ) और ( \sqrt{8} ) के ठीक मध्य में है, तो (x) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \frac{3\sqrt{2}}{2} )( \frac{3\sqrt{2}}{2} )
The midpoint is ( \frac{\sqrt{2}+\sqrt{8}}{2}=\frac{\sqrt{2}+2\sqrt{2}}{2}=\frac{3\sqrt{2}}{2} ). Take the average of the two values for the midpoint.मध्य बिंदु ( \frac{\sqrt{2}+\sqrt{8}}{2}=\frac{\sqrt{2}+2\sqrt{2}}{2}=\frac{3\sqrt{2}}{2} ) है। मध्य के लिए दोनों मानों का औसत लें।
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