If ( -\sqrt{122}<x<-11 ) on the number line, which value is possible?यदि संख्या रेखा पर ( -\sqrt{122}<x<-11 ), तो कौन सा मान संभव है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( -11.03 )( -11.03 )
( -\sqrt{122}\approx-11.045 ), so (x) must lie between (-11.045) and (-11). (-11.03) is correct.( -\sqrt{122}\approx-11.045 ), इसलिए (x) को (-11.045) और (-11) के बीच होना चाहिए। (-11.03) सही है।
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