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If A = −√116, B = −10.75, and C = −43/4, which point lies farthest to the left on the number line?यदि A = −√116, B = −10.75 और C = −43/4 हैं, तो संख्या रेखा पर सबसे बाईं ओर कौन-सा बिंदु स्थित होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Point Aबिंदु A
C = −43/4 = −10.75, so B and C are at the same position. Since √116 ≈ 10.7703, A ≈ −10.7703. This is less than −10.75, so A lies farthest to the left on the number line.C = −43/4 = −10.75, इसलिए B और C एक ही स्थान पर हैं। चूँकि √116 ≈ 10.7703, इसलिए A ≈ −10.7703। यह −10.75 से छोटी संख्या है, अतः A संख्या रेखा पर सबसे बाईं ओर स्थित है।
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