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If \(a=\sqrt{6}\), \(b=\frac{5}{2}\), and \(c=2.48\), what is the increasing order of these numbers on the number line?यदि \(a=\sqrt{6}\), \(b=\frac{5}{2}\) और \(c=2.48\) हैं, तो संख्या रेखा पर इन संख्याओं का बढ़ता क्रम कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(a<c<b\)\(a<c<b\)
Since \(\sqrt{6}\approx2.449\), \(c=2.48\), and \(\frac{5}{2}=2.5\), we get \(2.449<2.48<2.5\). Therefore, the increasing order is \(a<c<b\). Remember that increasing order means arranging numbers from least to greatest.\(\sqrt{6}\approx2.449\), जबकि \(c=2.48\) और \(\frac{5}{2}=2.5\) हैं। इसलिए \(2.449<2.48<2.5\), अर्थात \(a<c<b\)। ध्यान रखें कि बढ़ते क्रम में संख्याओं को छोटे से बड़े क्रम में लिखा जाता है।
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