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On the number line, in which of the following open intervals does \\(2-\\sqrt{3}\\) lie?

Answer and explanation

Correct answer: \\((0,1)\\)

Since \\(1<\\sqrt{3}<2\\), subtracting \\(\\sqrt{3}\\) from 2 gives \\(0<2-\\sqrt{3}<1\\). Therefore, the number lies in \\((0,1)\\). Its approximate value is 0.268, so the interval \\((1,2)\\) is not possible. Exam tip: estimate the irrational term first, then locate the resulting value.

Related tags

PolynomialsNumber LineIrrational NumbersInterval NotationReal NumbersRepresenting Real Numbers On The Number LineMathematicsClass 10 Mcq

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