1 reads0 ratings0 helpful
If \(a=-4\), which point on the number line is represented by \(\sqrt{a^2}\)?यदि \(a=-4\) है, तो संख्या रेखा पर \(\sqrt{a^2}\) द्वारा निरूपित बिंदु कौन-सा होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 44
Since \(\sqrt{a^2}=|a|\), substituting \(a=-4\) gives \(\sqrt{(-4)^2}=\sqrt{16}=4\). Therefore, the represented point is 4. Option A is incorrect because the principal square root is never negative, while 16 is only the value of \(a^2\). Exam tip: rewrite \(\sqrt{a^2}\) as \(|a|\) before substituting the value of \(a\).\(\sqrt{a^2}=|a|\) होता है। इसलिए \(a=-4\) रखने पर \(\sqrt{(-4)^2}=\sqrt{16}=4\), अतः संख्या रेखा पर बिंदु 4 होगा। विकल्प A गलत है क्योंकि मुख्य वर्गमूल कभी ऋणात्मक नहीं होता, जबकि 16 केवल \(a^2\) का मान है। परीक्षा-युक्ति: \(\sqrt{a^2}\) को हमेशा \(|a|\) के रूप में लिखें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
