Which number has prime factorisation (2^3\times3^2\times11)?
Step 1: Calculate (2^3=8) and (3^2=9). Step 2: (8\times9\times11=792). Step 3: First solve the powers, then multiply by 11.
Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है
SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
TOPIC PRACTICE
Up to 25 questions from this page. Select your focus, then start.
Step 1: Calculate (2^3=8) and (3^2=9). Step 2: (8\times9\times11=792). Step 3: First solve the powers, then multiply by 11.
Step 1: Calculate (5^2=25). Step 2: (3\times25\times11=825). Step 3: It is useful to simplify the power part first.
Step 1: Calculate (2^5=32) and (3^3=27). Step 2: (32\times27=864). Step 3: Simplify both powers separately.
Step 1: Calculate (2^2=4). Step 2: (4\times3\times7\times11=924). Step 3: With many factors, multiply in pairs.
Step 1: Calculate (2^4=16). Step 2: (16\times3\times5\times13=3120). Step 3: It is easy to first treat (3\times5\times13) as 195 and multiply.
Step 1: (2^4=16). Step 2: (16\times3\times5\times11=2640). Step 3: Multiply all factors to get the number from prime form.
Step 1: (3^4=81). Step 2: (81\times5\times7=2835). Step 3: Simplifying the power first keeps the calculation clear.
Step 1: In final prime form, bases should be prime. Step 2: In the first option, 2, 3, and 7 are prime bases. Step 3: 4, 81, 567, 12, and 189 are composite, so they are not final forms.
Step 1: Final prime factorisation must not contain a composite factor. Step 2: 195 is composite and (195=3\times5\times13). Step 3: Therefore, (2^4\times195) is not final form.
Step 1: Write (7776=32\times243). Step 2: (32=2^5) and (243=3^5), so (7776=2^5\times3^5). Step 3: 32 and 243 are composite, so write prime bases in the final form.
Step 1: (10000) can be written as (10^4). Step 2: Since (10=2\times5), (10^4=2^4\times5^4). Step 3: 10 is composite, so write powers of 2 and 5 in the final form.
Step 1: Write (4913=17\times289). Step 2: (289=17^2), so (4913=17^3). Step 3: Since 289 is composite, write (17^3) in the final form.
Step 1: Write (12500=125\times100). Step 2: (125=5^3) and (100=2^2\times5^2), so (12500=2^2\times5^5). Step 3: Count the total power of 5 as 5.
Step 1: Write (10206=2\times5103). Step 2: (5103=3^6\times7), so (10206=2\times3^6\times7). Step 3: Convert 5103 into prime powers.
Step 1: Write (13720=40\times343). Step 2: (40=2^3\times5) and (343=7^3), so (13720=2^3\times5\times7^3). Step 3: Write 40 and 343 in prime form.
Step 1: Calculate (2^5=32) and (3^2=9). Step 2: (32\times9\times7=2016). Step 3: Solving powers first gives the answer quickly.
Step 1: Calculate (3^2=9) and (7^2=49). Step 2: (9\times5\times49=2205). Step 3: Simplify the two powers first and multiply.
Step 1: Calculate (2^2=4) and (3^4=81). Step 2: (4\times81\times7=2268). Step 3: Simplifying the higher power first is the right method.
Step 1: Calculate (2^4=16). Step 2: (16\times3\times5\times11=2640). Step 3: Do multiplication in small steps to avoid mistakes.
Step 1: Write (4752=16\times297). Step 2: (16=2^4) and (297=3^3\times11), so (4752=2^4\times3^3\times11). Step 3: Give 297 its complete prime form.
Step 1: Write (5850=18\times325). Step 2: (18=2\times3^2) and (325=5^2\times13), so (5850=2\times3^2\times5^2\times13). Step 3: Avoid decimal forms and use whole factors.
Step 1: Write (7560=756\times10). Step 2: (756=2^2\times3^3\times7) and (10=2\times5), so (7560=2^3\times3^3\times5\times7). Step 3: Count the total power of 2 as 3.
Step 1: Calculate (3^2=9) and (5^2=25). Step 2: (2\times9\times25\times13=5850). Step 3: First do (9\times25=225), then multiply the rest.
Step 1: Divide 16384 repeatedly by 2. Step 2: Fourteen factors of 2 give (16384=2^{14}). Step 3: 128 and 16 are composite, so write the power of 2 in final prime form.
Step 1: In final prime factorisation, the base must be prime. Step 2: 25 is composite and (25=5^2). Step 3: Therefore, (25^2\times7) must be changed into (5^4\times7).
QUIZ COMPLETE