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In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
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Medium · Level 5View options
Powers of the same prime base
Sum of all composite factors
Only the last digit of the number
Only the order of factors
Medium · Level 5View options
(2\times3^2\times5\times13)
(2^2\times3\times5\times13)
(117\times10)
(9\times130)
Medium · Level 5View options
(3^5\times5)
(3^4\times5^2)
(243\times5)
(81\times15)
Medium · Level 5View options
(2^6\times3\times7)
(2^5\times3\times7)
(64\times21)
(2^6\times21)
Medium · Level 5View options
(3^3\times5\times11)
(3^2\times5\times11)
(135\times11)
(27\times55)
Medium · Level 5View options
(2^2\times3^4\times5)
(2\times3^4\times5)
(162\times10)
(4\times405)
Medium · Level 5View options
(2^3\times3\times7\times11)
(2^2\times3\times7\times11)
(8\times231)
(2^3\times21\times11)
Medium · Level 5View options
(3\times5^4)
(3^2\times5^3)
(75\times25)
(3\times625)
Medium · Level 5View options
(2^5\times3^2\times7)
(2^4\times3^2\times7)
(32\times63)
(2^5\times9\times7)
Medium · Level 5View options
(3^2\times5\times7^2)
(3\times5\times7^2)
(45\times49)
(9\times245)
Medium · Level 5View options
(2^2\times3^4\times7)
(2^3\times3^3\times7)
(4\times567)
(2^2\times81\times7)
Medium · Level 5View options
(2^2\times3^2\times5\times13)
(2\times3^2\times5\times13)
(234\times10)
(4\times585)
Medium · Level 5View options
(2\times5^2\times7^2)
(2^2\times5\times7^2)
(2\times1225)
(50\times49)
Medium · Level 5View options
(2^4\times3\times5\times11)
(2^3\times3\times5\times11)
(24\times110)
(16\times165)
Medium · Level 5View options
(3^4\times5\times7)
(3^3\times5\times7)
(81\times35)
(9\times315)
Medium · Level 5View options
(2^4\times3\times5\times13)
(2^3\times3\times5\times13)
(312\times10)
(16\times195)
Medium · Level 5View options
(2\times3^5\times7)
(2\times3^4\times7)
(2\times1701)
(486\times7)
Medium · Level 5View options
(2^3\times3^2\times7^2)
(2^2\times3^2\times7^2)
(72\times49)
(8\times441)
Medium · Level 5View options
(3^6\times5)
(3^5\times5)
(729\times5)
(81\times45)
Medium · Level 5View options
(2^4\times3^5)
(2^3\times3^5)
(16\times243)
(2^4\times243)
Medium · Level 5View options
(3^4\times7^2)
(3^3\times7^2)
(81\times49)
(63\times63)
Medium · Level 5View options
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3
Medium · Level 5View options
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1
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Medium · Level 5View options
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Question 1MediumLevel 5
What should be checked first while comparing powers in prime factorisation?
Correct answer: A
Step 1: In prime factorisation, identify the bases first. Step 2: Powers of the same base are compared, such as power of 2 with power of 2 and power of 3 with power of 3. Step 3: In exams, do not compare powers directly when bases are different.
Step 1: Write (1170=117\times10). Step 2: (117=3^2\times13) and (10=2\times5), so (1170=2\times3^2\times5\times13). Step 3: Do not keep 117 and 10 in the final form.
Step 1: Write (1215=243\times5). Step 2: Since (243=3^5), (1215=3^5\times5). Step 3: 243 is composite, so write it as a power of 3 in final prime form.
Step 1: Write (1344=64\times21). Step 2: (64=2^6) and (21=3\times7), so (1344=2^6\times3\times7). Step 3: Since 21 is composite, split it into 3 and 7.
Step 1: Write (1620=162\times10). Step 2: (162=2\times3^4) and (10=2\times5), so (1620=2^2\times3^4\times5). Step 3: Count the total power of 2 correctly.
Step 1: Write (1848=8\times231). Step 2: (8=2^3) and (231=3\times7\times11), so (1848=2^3\times3\times7\times11). Step 3: Give 231 its complete prime form.
Step 1: Write (2340=234\times10). Step 2: (234=2\times3^2\times13) and (10=2\times5), so (2340=2^2\times3^2\times5\times13). Step 3: The power of 2 becomes 2.
Step 1: Write (3120=16\times195). Step 2: (16=2^4) and (195=3\times5\times13), so (3120=2^4\times3\times5\times13). Step 3: Give 195 its complete prime form.
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