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In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
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Medium · Level 1View options
All factors must be prime
All factors must be even
All factors must be two-digit numbers
Sum of factors must equal the number
Medium · Level 1View options
(2^3\times3^2\times7)
(2^2\times3^3\times7)
(8\times63)
(2^3\times9\times7)
Medium · Level 1View options
(2^4\times3\times11)
(2^3\times3\times22)
(16\times33)
(2^4\times33)
Medium · Level 1View options
(2^4\times5\times7)
(2^3\times5\times14)
(16\times35)
(2^4\times35)
Medium · Level 1View options
(2\times3^2\times5\times7)
(2^2\times3\times5\times7)
(63\times10)
(2\times9\times35)
Medium · Level 1View options
(2^5\times3\times7)
(2^4\times3\times7)
(32\times21)
(2^5\times21)
Medium · Level 1View options
(2^2\times5^2\times7)
(2\times5^2\times14)
(7\times100)
(4\times175)
Medium · Level 1View options
(2^2\times3^3\times7)
(2^3\times3^2\times7)
(27\times28)
(4\times189)
Medium · Level 1View options
(3^3\times5\times7)
(3^2\times5\times7)
(27\times35)
(9\times105)
Medium · Level 1View options
(2^2\times5\times7^2)
(2\times5\times7^2)
(98\times10)
(4\times245)
Medium · Level 1View options
(2^4\times3^2\times7)
(2^3\times3^2\times7)
(16\times63)
(2^4\times63)
Medium · Level 1View options
(3\times5\times7\times11)
(11\times105)
(3\times385)
(15\times77)
Medium · Level 1View options
(2^3\times3\times7^2)
(2^2\times3^2\times7^2)
(24\times49)
(12\times98)
Medium · Level 1View options
(5^2\times7^2)
(35\times35)
(5\times245)
(7\times175)
Medium · Level 1View options
(2^4\times3^4)
(2^3\times3^5)
(36\times36)
(16\times81)
Medium · Level 1View options
(3^3\times7^2)
(3^2\times7^3)
(27\times49)
(21\times63)
Medium · Level 1View options
(2^5\times3^2\times5)
(2^4\times3^2\times5)
(144\times10)
(32\times45)
Medium · Level 1View options
(2\times3\times5\times7^2)
(2^2\times3\times5\times7)
(30\times49)
(14\times105)
Medium · Level 1View options
(2^6\times3^3)
(2^5\times3^4)
(12^3)
(64\times27)
Medium · Level 1View options
(2^3\times3^2\times5^2)
(2^2\times3^2\times5^2)
(18\times100)
(2\times900)
Medium · Level 1View options
(2^2\times3^2\times5\times11)
(2\times3^2\times5\times11)
(198\times10)
(18\times110)
Medium · Level 1View options
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4
5
Medium · Level 1View options
3
2
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5
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1
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Medium · Level 1View options
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Question 1MediumLevel 1
What is the most important condition for the final form of prime factorisation?
Correct answer: A
Step 1: In prime factorisation, a number is written as a product of prime numbers. Step 2: If any composite factor remains, the form is not final. Step 3: In exams, write only prime bases and their powers in the final answer.
Step 1: Write (504=8\times63). Step 2: (8=2^3) and (63=3^2\times7), so (504=2^3\times3^2\times7). Step 3: Do not leave composite forms like 8 and 63 in the final answer.
Step 1: (528) can be written as (16\times33). Step 2: (16=2^4) and (33=3\times11), so (528=2^4\times3\times11). Step 3: Since 33 is composite, split it into 3 and 11.
Step 1: Write (560=16\times35). Step 2: (16=2^4) and (35=5\times7), so (560=2^4\times5\times7). Step 3: Since 35 is composite, write 5 and 7 in the final form.
Step 1: Write (630=63\times10). Step 2: (63=3^2\times7) and (10=2\times5), so (630=2\times3^2\times5\times7). Step 3: Do not keep 9 or 35 in the final form.
Step 1: (672) can be written as (32\times21). Step 2: (32=2^5) and (21=3\times7), so (672=2^5\times3\times7). Step 3: Since 21 is composite, break it further.
Step 1: Write (1323=27\times49). Step 2: (27=3^3) and (49=7^2), so (1323=3^3\times7^2). Step 3: Both 27 and 49 are composite, so write them as prime powers.
Step 1: Recognise (1728=12^3). Step 2: Since (12=2^2\times3), (12^3=2^6\times3^3). Step 3: Since 12 is composite, write powers of 2 and 3 in the final form.
Step 1: Write (1800=18\times100). Step 2: (18=2\times3^2) and (100=2^2\times5^2), so (1800=2^3\times3^2\times5^2). Step 3: Give complete prime form to both 18 and 100.
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