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In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
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Expert · Level 3View options
Because only prime bases should remain in the final form
Because using powers becomes wrong
Because the value of the number always changes
Because addition should be used instead of multiplication
Expert · Level 3View options
(2^4\times3^5\times5^2\times7)
(2^5\times3^4\times5^2\times7)
(16\times42525)
(2^4\times243\times25\times7)
Expert · Level 3View options
(2^6\times3^4\times11^2)
(2^5\times3^5\times11^2)
(64\times9801)
(2^6\times81\times121)
Expert · Level 3View options
(2^3\times3^6\times5\times13)
(2^4\times3^5\times5\times13)
(8\times47385)
(2^3\times729\times65)
Expert · Level 3View options
(2^5\times5^3\times7^2)
(2^4\times5^4\times7)
(32\times6125)
(2^5\times125\times49)
Expert · Level 3View options
(3^4\times5^2\times11\times13)
(3^5\times5\times11\times13)
(81\times3575)
(3^4\times25\times143)
Expert · Level 3View options
(2^8\times3^2\times7\times11)
(2^7\times3^3\times7\times11)
(256\times693)
(2^8\times9\times77)
Expert · Level 3View options
(2^4\times3^3\times5^2\times7^2)
(2^5\times3^2\times5^2\times7^2)
(16\times33075)
(2^4\times27\times25\times49)
Expert · Level 3View options
(2^7\times3^5\times5)
(2^6\times3^5\times5)
(128\times1215)
(2^7\times243\times5)
Expert · Level 3View options
(2^2\times3^4\times7^2\times11)
(2^3\times3^3\times7^2\times11)
(4\times43659)
(2^2\times81\times49\times11)
Expert · Level 3View options
(2^5\times3^2\times5^2\times11)
(2^4\times3^3\times5^2\times11)
(32\times2475)
(2^5\times9\times25\times11)
Expert · Level 3View options
(2^3\times3^3\times5^2\times7\times11)
(2^4\times3^2\times5^2\times7\times11)
(8\times51975)
(2^3\times27\times25\times77)
Expert · Level 3View options
(2^6\times3^5\times7^2)
(2^5\times3^6\times7^2)
(64\times11907)
(2^6\times243\times49)
Expert · Level 3View options
(2^4\times5^2\times7^3)
(2^3\times5^3\times7^2)
(16\times8575)
(2^4\times25\times343)
Expert · Level 3View options
(3^6\times5^2\times7)
(3^5\times5^3\times7)
(729\times175)
(3^6\times25\times7)
Expert · Level 3View options
(2^5\times3^4\times5^2\times7)
(2^4\times3^5\times5^2\times7)
(32\times14175)
(2^5\times81\times25\times7)
Expert · Level 3View options
(2^7\times3^2\times11^2)
(2^6\times3^3\times11^2)
(128\times1089)
(2^7\times9\times121)
Expert · Level 3View options
(2^3\times3^2\times5^3\times13)
(2^2\times3^3\times5^3\times13)
(8\times14625)
(2^3\times9\times125\times13)
Expert · Level 3View options
(2^6\times3^3\times5^2\times11)
(2^5\times3^4\times5^2\times11)
(64\times7425)
(2^6\times27\times25\times11)
Expert · Level 3View options
(3^4\times5^2\times7^2)
(3^3\times5^3\times7^2)
(81\times1225)
(9\times11025)
Expert · Level 3View options
(2^8\times3^4\times5^2)
(2^7\times3^5\times5^2)
(256\times2025)
(2^8\times81\times25)
Expert · Level 3View options
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Expert · Level 3View options
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Question 1ExpertLevel 3
Why is the answer considered incomplete if a composite base remains in final prime factorisation?
Correct answer: A
Step 1: The aim of prime factorisation is to write the number using prime bases only. Step 2: If a base like (45) or (121) remains, it is composite and must be broken further. Step 3: Before writing the final answer, check whether every base is prime.
What is the correct prime factorisation of 680400?
Correct answer: A
Step 1: Write (680400=16\times42525). Step 2: (16=2^4) and (42525=3^5\times5^2\times7), so the correct form is (2^4\times3^5\times5^2\times7). Step 3: Do not leave 42525 in the final form.
Step 1: Write (627264=64\times9801). Step 2: (64=2^6) and (9801=3^4\times11^2), so (627264=2^6\times3^4\times11^2). Step 3: Convert 9801 into prime powers.
What is the correct prime factorisation of 379080?
Correct answer: A
Step 1: Write (379080=8\times47385). Step 2: (8=2^3) and (47385=3^6\times5\times13), so the correct form is (2^3\times3^6\times5\times13). Step 3: Give 47385 its complete prime form.
Step 1: Write (196000=32\times6125). Step 2: (32=2^5) and (6125=5^3\times7^2), so (196000=2^5\times5^3\times7^2). Step 3: Do not keep 6125 in the final answer.
What is the correct prime factorisation of 289575?
Correct answer: A
Step 1: Write (289575=81\times3575). Step 2: (81=3^4) and (3575=5^2\times11\times13), so (289575=3^4\times5^2\times11\times13). Step 3: Give 3575 its complete prime form too.
Step 1: Write (177408=256\times693). Step 2: (256=2^8) and (693=3^2\times7\times11), so the correct form is (2^8\times3^2\times7\times11). Step 3: Convert 693 into prime form.
What is the correct prime factorisation of 529200?
Correct answer: A
Step 1: Write (529200=16\times33075). Step 2: (33075=3^3\times5^2\times7^2), so (529200=2^4\times3^3\times5^2\times7^2). Step 3: Do not leave 33075 in the final form.
Step 1: Write (155520=128\times1215). Step 2: (128=2^7) and (1215=3^5\times5), so (155520=2^7\times3^5\times5). Step 3: Convert 1215 into prime powers.
What is the correct prime factorisation of 174636?
Correct answer: A
Step 1: Write (174636=4\times43659). Step 2: (4=2^2) and (43659=3^4\times7^2\times11), so the correct form is (2^2\times3^4\times7^2\times11). Step 3: Convert 43659 into prime powers.
Step 1: Write (79200=32\times2475). Step 2: (2475=3^2\times5^2\times11), so (79200=2^5\times3^2\times5^2\times11). Step 3: Give 2475 its complete prime form.
What is the correct prime factorisation of 415800?
Correct answer: A
Step 1: Write (415800=8\times51975). Step 2: (51975=3^3\times5^2\times7\times11), so (415800=2^3\times3^3\times5^2\times7\times11). Step 3: Do not leave 51975 in the final form.
Step 1: Write (762048=64\times11907). Step 2: (64=2^6) and (11907=3^5\times7^2), so (762048=2^6\times3^5\times7^2). Step 3: Write 11907 as prime powers.
What is the correct prime factorisation of 137200?
Correct answer: A
Step 1: Write (137200=16\times8575). Step 2: (16=2^4) and (8575=5^2\times7^3), so the correct form is (2^4\times5^2\times7^3). Step 3: Give 8575 its final prime form.
Step 1: Write (127575=729\times175). Step 2: (729=3^6) and (175=5^2\times7), so (127575=3^6\times5^2\times7). Step 3: Give prime form to both 729 and 175.
What is the correct prime factorisation of 453600?
Correct answer: A
Step 1: Write (453600=32\times14175). Step 2: (14175=3^4\times5^2\times7), so (453600=2^5\times3^4\times5^2\times7). Step 3: Do not leave 14175 in the final form.
Step 1: Write (139392=128\times1089). Step 2: (128=2^7) and (1089=3^2\times11^2), so (139392=2^7\times3^2\times11^2). Step 3: Convert 1089 into prime powers.
What is the correct prime factorisation of 117000?
Correct answer: A
Step 1: Write (117000=8\times14625). Step 2: (14625=3^2\times5^3\times13), so (117000=2^3\times3^2\times5^3\times13). Step 3: Give 14625 its complete prime form.
Step 1: Write (475200=64\times7425). Step 2: (7425=3^3\times5^2\times11), so (475200=2^6\times3^3\times5^2\times11). Step 3: Do not leave 7425 in the final form.
Step 1: Write (99225=81\times1225). Step 2: (81=3^4) and (1225=5^2\times7^2), so (99225=3^4\times5^2\times7^2). Step 3: Convert 1225 into prime powers.
Step 1: Write (518400=256\times2025). Step 2: (256=2^8) and (2025=3^4\times5^2), so (518400=2^8\times3^4\times5^2). Step 3: Give 2025 its final prime form.
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