What is the correct prime factorisation of 132?
Step 1: Write (132=4\times33). Step 2: (4=2^2) and (33=3\times11), so (132=2^2\times3\times11). Step 3: Do not keep composite factors like 4 and 33 in the final answer.
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SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
TOPIC PRACTICE
Up to 25 questions from this page. Select your focus, then start.
Step 1: Write (132=4\times33). Step 2: (4=2^2) and (33=3\times11), so (132=2^2\times3\times11). Step 3: Do not keep composite factors like 4 and 33 in the final answer.
Step 1: Write (150=15\times10). Step 2: (15=3\times5) and (10=2\times5), so (150=2\times3\times5^2). Step 3: When the same prime repeats, write it as a power.
Step 1: Write (162=2\times81). Step 2: Since (81=3^4), (162=2\times3^4). Step 3: Do not leave 81 in the final form; write (3^4).
Step 1: Write (168=8\times21). Step 2: (8=2^3) and (21=3\times7), so (168=2^3\times3\times7). Step 3: 8 and 21 are composite, so break them further.
Step 1: Write (180=18\times10). Step 2: (18=2\times3^2) and (10=2\times5), so (180=2^2\times3^2\times5). Step 3: Change all composite factors into prime form.
Step 1: (196) can be written as (14\times14) or (4\times49). Step 2: Since (14=2\times7), (196=2^2\times7^2). Step 3: In square numbers, exponents are often even, so check them.
Step 1: Write (210=21\times10). Step 2: (21=3\times7) and (10=2\times5), so (210=2\times3\times5\times7). Step 3: Do not keep 21 or 10 in the final answer.
Step 1: Recognise (225=15^2). Step 2: Since (15=3\times5), (225=3^2\times5^2). Step 3: 15 is composite, so write powers of 3 and 5 in the final form.
Step 1: Write (231=21\times11). Step 2: Since (21=3\times7), (231=3\times7\times11). Step 3: 21 is composite, so do not keep it in the final answer.
Step 1: Write (240=16\times15). Step 2: (16=2^4) and (15=3\times5), so (240=2^4\times3\times5). Step 3: It is necessary to change 16 into (2^4).
Step 1: Write (252=4\times63). Step 2: (4=2^2) and (63=3^2\times7), so (252=2^2\times3^2\times7). Step 3: Break 63 completely into prime form too.
Step 1: Write (270=27\times10). Step 2: (27=3^3) and (10=2\times5), so (270=2\times3^3\times5). Step 3: Do not forget to change 27 into (3^3).
Step 1: Write (294=6\times49). Step 2: (6=2\times3) and (49=7^2), so (294=2\times3\times7^2). Step 3: Write 49 as (7^2).
Step 1: Write (300=3\times100). Step 2: (100=2^2\times5^2), so (300=2^2\times3\times5^2). Step 3: Convert 100 into prime powers.
Step 1: Write (315=9\times35). Step 2: (9=3^2) and (35=5\times7), so (315=3^2\times5\times7). Step 3: Change both 9 and 35 into prime form.
Step 1: Write (324=4\times81). Step 2: (4=2^2) and (81=3^4), so (324=2^2\times3^4). Step 3: Since it is a square number, check powers carefully.
Step 1: Write (330=33\times10). Step 2: (33=3\times11) and (10=2\times5), so (330=2\times3\times5\times11). Step 3: Break all composite factors further.
Step 1: Write (343=7\times49). Step 2: Since (49=7^2), (343=7^3). Step 3: 49 is composite, so write (7^3) in the final form.
Step 1: Write (360=36\times10). Step 2: (36=2^2\times3^2) and (10=2\times5), so (360=2^3\times3^2\times5). Step 3: Be careful while counting the total power of 2.
Step 1: Write (375=3\times125). Step 2: Since (125=5^3), (375=3\times5^3). Step 3: Change 125 into (5^3).
Step 1: Write (392=8\times49). Step 2: (8=2^3) and (49=7^2), so (392=2^3\times7^2). Step 3: Convert 8 and 49 into prime powers.
Step 1: Write (400=16\times25). Step 2: (16=2^4) and (25=5^2), so (400=2^4\times5^2). Step 3: Composite forms like 20 or 10 are not final answers.
Step 1: Recognise (441=21^2). Step 2: Since (21=3\times7), (441=3^2\times7^2). Step 3: 21 is composite, so write prime bases 3 and 7.
Step 1: Write (450=45\times10). Step 2: (45=3^2\times5) and (10=2\times5), so (450=2\times3^2\times5^2). Step 3: Since 5 appears twice, write (5^2).
Step 1: Write (480=48\times10). Step 2: (48=2^4\times3) and (10=2\times5), so (480=2^5\times3\times5). Step 3: Count the total power of 2 correctly.
QUIZ COMPLETE