01 If the prime factorisations of two numbers are (2^3\times3^2\times5) and (2^2\times3^3\times7), what is their HCF?
Answer and explanation
Correct answer: A. (2^2\times3^2=36)
Explanation: Step 1: For HCF, take only the common prime factors. Step 2: The common factors are (2) and (3), and the smaller powers are (2^2) and (3^2), so the HCF is (36). Step 3: In exams, remember that HCF uses the minimum powers of common primes.