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9 results found for "zero-root" in Class 10.

Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(8x^2-32x=0\) को हल करते समय कौनसी गलती नहीं करनी चाहिए?

Which mistake should be avoided while solving \(8x^2-32x=0\)?

Explanation opens after your attempt
Correct Answer

A. (x=0) को छोड़नाMissing (x=0)

Step 1

Concept

(8x-2-32x=8x(x-4)), so (x=0) and (x=4) are both roots. In exams, dividing by the variable can miss (x=0).

Step 2

Why this answer is correct

The correct answer is A. (x=0) को छोड़ना / Missing (x=0). (8x-2-32x=8x(x-4)), so (x=0) and (x=4) are both roots. In exams, dividing by the variable can miss (x=0).

Step 3

Exam Tip

(8x-2-32x=8x(x-4)), इसलिए (x=0) और (x=4) दोनों मूल हैं। परीक्षा में चर से भाग देने पर (x=0) छूट सकता है।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(6x^2-18x=0\) को हल करते समय कौनसी गलती नहीं करनी चाहिए?

Which mistake should be avoided while solving \(6x^2-18x=0\)?

Explanation opens after your attempt
Correct Answer

A. (x=0) को छोड़नाMissing (x=0)

Step 1

Concept

(6x-2-18x=6x(x-3)), so (x=0) and (x=3) are both roots. In exams, dividing by the variable can miss (x=0).

Step 2

Why this answer is correct

The correct answer is A. (x=0) को छोड़ना / Missing (x=0). (6x-2-18x=6x(x-3)), so (x=0) and (x=3) are both roots. In exams, dividing by the variable can miss (x=0).

Step 3

Exam Tip

(6x-2-18x=6x(x-3)), इसलिए (x=0) और (x=3) दोनों मूल हैं। परीक्षा में चर से भाग देने पर (x=0) छूट सकता है।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(5x^2-20x=0\) को हल करते समय कौनसी सामान्य गलती हो सकती है?

What common mistake can occur while solving \(5x^2-20x=0\)?

Explanation opens after your attempt
Correct Answer

A. (x=0) को छोड़ देनाMissing (x=0)

Step 1

Concept

The correct form is (5x(x-4)=0), giving (x=0) and (x=4). In exams, dividing directly by the variable can miss (x=0).

Step 2

Why this answer is correct

The correct answer is A. (x=0) को छोड़ देना / Missing (x=0). The correct form is (5x(x-4)=0), giving (x=0) and (x=4). In exams, dividing directly by the variable can miss (x=0).

Step 3

Exam Tip

सही रूप (5x(x-4)=0) है, जिससे (x=0) और (x=4) मिलते हैं। परीक्षा में चर से सीधे भाग देने से (x=0) छूट सकता है।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^2-11x=0\) में (x=0) मूल क्यों है?

Why is (x=0) a root of \(x^2-11x=0\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (x(x-11)=0)Because (x(x-11)=0)

Step 1

Concept

(x-2-11x=x(x-11)), so zero product rule gives (x=0). In exams, do not lose this root by dividing by the variable.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (x(x-11)=0) / Because (x(x-11)=0). (x-2-11x=x(x-11)), so zero product rule gives (x=0). In exams, do not lose this root by dividing by the variable.

Step 3

Exam Tip

(x-2-11x=x(x-11)), इसलिए शून्य गुणनफल नियम से (x=0) मिलता है। परीक्षा में चर से भाग देकर यह मूल न खोएं।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^2-5x=0\) में (x=0) मूल क्यों है?

Why is (x=0) a root of \(x^2-5x=0\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (x(x-5)=0)Because (x(x-5)=0)

Step 1

Concept

(x-2-5x=x(x-5)), so zero product rule gives (x=0). In exams, do not lose this root by dividing by the variable.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (x(x-5)=0) / Because (x(x-5)=0). (x-2-5x=x(x-5)), so zero product rule gives (x=0). In exams, do not lose this root by dividing by the variable.

Step 3

Exam Tip

(x-2-5x=x(x-5)), इसलिए शून्य गुणनफल नियम से (x=0) मिलता है। परीक्षा में चर से भाग देकर यह मूल न खोएं।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^2-3x=0\) में (x=0) क्यों एक मूल है?

Why is (x=0) a root of \(x^2-3x=0\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (x(x-3)=0)Because (x(x-3)=0)

Step 1

Concept

(x-2-3x=x(x-3)), so zero product rule gives (x=0). In exams, do not lose (x=0) by dividing by (x).

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (x(x-3)=0) / Because (x(x-3)=0). (x-2-3x=x(x-3)), so zero product rule gives (x=0). In exams, do not lose (x=0) by dividing by (x).

Step 3

Exam Tip

(x-2-3x=x(x-3)), इसलिए शून्य गुणनफल नियम से (x=0) मिलता है। परीक्षा में (x) से भाग देकर (x=0) न खोएं।

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Question Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि (x=0), \(ax^2+bx+c=0\) की जड़ है, तो कौन-सी शर्त निश्चित रूप से सही है?

If (x=0) is a root of \(ax^2+bx+c=0\), which condition must be true?

Explanation opens after your attempt
Correct Answer

A. (c=0)

Step 1

Concept

Putting (x=0) gives (c=0). Thus the direct condition for zero to be a root is (c=0).

Step 2

Why this answer is correct

The correct answer is A. (c=0). Putting (x=0) gives (c=0). Thus the direct condition for zero to be a root is (c=0).

Step 3

Exam Tip

(x=0) रखने पर समीकरण (c=0) बनता है। इसलिए शून्य जड़ होने की सीधी शर्त (c=0) है।

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Question Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

किस समीकरण में (x=0) एक मूल है और दूसरा मूल ऋणात्मक है?

In which equation is (x=0) one root and the other root negative?

Explanation opens after your attempt
Correct Answer

A. \(x^2+7x=0\)

Step 1

Concept

(x-2+7x=x(x+7)), so the roots are (0) and (-7). The other root is negative.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+7x=0\). (x-2+7x=x(x+7)), so the roots are (0) and (-7). The other root is negative.

Step 3

Exam Tip

(x-2+7x=x(x+7)), इसलिए मूल (0) और (-7) हैं। दूसरा मूल ऋणात्मक है।

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Question Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

किस समीकरण में (x=0) एक मूल है और दूसरा मूल धनात्मक है?

In which equation is (x=0) one root and the other root positive?

Explanation opens after your attempt
Correct Answer

A. \(x^2-6x=0\)

Step 1

Concept

(x-2-6x=x(x-6)), so the roots are (0) and (6). The other root is positive.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-6x=0\). (x-2-6x=x(x-6)), so the roots are (0) and (6). The other root is positive.

Step 3

Exam Tip

(x-2-6x=x(x-6)), इसलिए मूल (0) और (6) हैं। दूसरा मूल धनात्मक है।

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