Search Class 10 Questions

1 result found for "surd addition" in Class 10.

Question Hard Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 15

यदि \(x=\sqrt{6}+\sqrt{24}\), तो (x) किसके बराबर है?

If \(x=\sqrt{6}+\sqrt{24}\), what is (x) equal to?

Explanation opens after your attempt
Correct Answer

B. \(3\sqrt{6}\)

Step 1

Concept

\(\sqrt{24}=2\sqrt{6}\).

Step 2

Why this answer is correct

So \(x=\sqrt{6}+2\sqrt{6}=3\sqrt{6}\), which is irrational.

Step 3

Exam Tip

Simplify radicals to like terms before adding. चरण 1: \(\sqrt{24}=2\sqrt{6}\) है। चरण 2: इसलिए \(x=\sqrt{6}+2\sqrt{6}=3\sqrt{6}\), जो अपरिमेय है। चरण 3: मूल को सरल करके समान पद बनाएँ, फिर जोड़ें।

Open Question Page
Ask Friends
Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.