100 results found for "standard hues" in Class 10.
कौन सा बहुपद मानक रूप में अवरोही घातों में लिखा गया है?
Which polynomial is written in standard form with descending powers?
#standard form
#descending powers
#polynomial
A \(2x+5x^3-1\)
B \(5x^3+2x-1\)
C \(7+3x^2-x^4\)
D \(x+x^2+x^3\)
Explanation opens after your attempt
Correct Answer
B. \(5x^3+2x-1\)
Step 1
Concept
In standard form, terms are written from highest power to lowest power. \(5x^3+2x-1\) follows this order.
Step 2
Why this answer is correct
The correct answer is B. \(5x^3+2x-1\). In standard form, terms are written from highest power to lowest power. \(5x^3+2x-1\) follows this order.
Step 3
Exam Tip
मानक रूप में बड़ी घात से छोटी घात की ओर लिखते हैं। \(5x^3+2x-1\) इसी क्रम में है।
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निम्न में से कौन सा बहुपद मानक रूप में व्यवस्थित है?
Which of the following polynomials is arranged in standard form?
#polynomials
#standard-form
#easy
#arrangement
A \(2x^3+x^2+5x+1\)
B \(5x+2x^3+1+x^2\)
C \(1+5x+x^2+2x^3\)
D \(x^2+2x^3+5x+1\)
Explanation opens after your attempt
Correct Answer
A. \(2x^3+x^2+5x+1\)
Step 1
Concept
In standard form, powers are written in descending order. \(2x^3+x^2+5x+1\) follows this order.
Step 2
Why this answer is correct
The correct answer is A. \(2x^3+x^2+5x+1\). In standard form, powers are written in descending order. \(2x^3+x^2+5x+1\) follows this order.
Step 3
Exam Tip
मानक रूप में घातें घटते क्रम में लिखी जाती हैं। \(2x^3+x^2+5x+1\) में यही क्रम है।
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यदि ((x-7)(x-15)=26), तो मानक द्विघात समीकरण क्या होगा?
If ((x-7)(x-15)=26), what is the standard quadratic equation?
#quadratic
#standard-form
#application
A \(x^2-22x+79=0\)
B \(x^2-22x+131=0\)
C \(x^2+22x+79=0\)
D \(x^2-8x+105=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-22x+79=0\)
Step 1
Concept
((x-7)(x-15)=x-2 -22x+105), so \(x^2-22x+105=26\) gives \(x^2-22x+79=0\). In exams, bring all terms to one side after expansion.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-22x+79=0\). ((x-7)(x-15)=x-2 -22x+105), so \(x^2-22x+105=26\) gives \(x^2-22x+79=0\). In exams, bring all terms to one side after expansion.
Step 3
Exam Tip
((x-7)(x-15)=x-2 -22x+105), इसलिए \(x^2-22x+105=26\) से \(x^2-22x+79=0\) मिलता है। परीक्षा में विस्तार के बाद सभी पद एक तरफ लाएं।
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यदि ((x-6)(x-13)=22), तो मानक द्विघात समीकरण क्या होगा?
If ((x-6)(x-13)=22), what is the standard quadratic equation?
#quadratic
#standard-form
#application
A \(x^2-19x+56=0\)
B \(x^2-19x+100=0\)
C \(x^2+19x+56=0\)
D \(x^2-7x+78=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-19x+56=0\)
Step 1
Concept
((x-6)(x-13)=x-2 -19x+78), so \(x^2-19x+78=22\) gives \(x^2-19x+56=0\). In exams, bring all terms to one side after expansion.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-19x+56=0\). ((x-6)(x-13)=x-2 -19x+78), so \(x^2-19x+78=22\) gives \(x^2-19x+56=0\). In exams, bring all terms to one side after expansion.
Step 3
Exam Tip
((x-6)(x-13)=x-2 -19x+78), इसलिए \(x^2-19x+78=22\) से \(x^2-19x+56=0\) मिलता है। परीक्षा में विस्तार के बाद सभी पद एक तरफ लाएं।
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यदि ((x-5)(x-11)=18), तो मानक द्विघात समीकरण क्या होगा?
If ((x-5)(x-11)=18), what is the standard quadratic equation?
#quadratic
#standard-form
#application
A \(x^2-16x+37=0\)
B \(x^2-16x+73=0\)
C \(x^2+16x+37=0\)
D \(x^2-6x+55=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-16x+37=0\)
Step 1
Concept
((x-5)(x-11)=x-2 -16x+55), so \(x^2-16x+55=18\) gives \(x^2-16x+37=0\). In exams, bring all terms to one side after expansion.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-16x+37=0\). ((x-5)(x-11)=x-2 -16x+55), so \(x^2-16x+55=18\) gives \(x^2-16x+37=0\). In exams, bring all terms to one side after expansion.
Step 3
Exam Tip
((x-5)(x-11)=x-2 -16x+55), इसलिए \(x^2-16x+55=18\) से \(x^2-16x+37=0\) मिलता है। परीक्षा में विस्तार के बाद सभी पद एक तरफ लाएं।
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यदि ((x-4)(x-9)=14), तो मानक द्विघात समीकरण क्या होगा?
If ((x-4)(x-9)=14), what is the standard quadratic equation?
#quadratic
#standard-form
#application
A \(x^2-13x+22=0\)
B \(x^2-13x+50=0\)
C \(x^2+13x+22=0\)
D \(x^2-5x+36=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-13x+22=0\)
Step 1
Concept
((x-4)(x-9)=x-2 -13x+36), so \(x^2-13x+36=14\) gives \(x^2-13x+22=0\). In exams, bring all terms to one side after expansion.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-13x+22=0\). ((x-4)(x-9)=x-2 -13x+36), so \(x^2-13x+36=14\) gives \(x^2-13x+22=0\). In exams, bring all terms to one side after expansion.
Step 3
Exam Tip
((x-4)(x-9)=x-2 -13x+36), इसलिए \(x^2-13x+36=14\) से \(x^2-13x+22=0\) मिलता है। परीक्षा में विस्तार के बाद सभी पद एक तरफ लाएं।
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यदि ((x-3)(x-7)=10), तो मानक द्विघात समीकरण क्या होगा?
If ((x-3)(x-7)=10), what is the standard quadratic equation?
#quadratic
#standard-form
#application
A \(x^2-10x+11=0\)
B \(x^2-10x+31=0\)
C \(x^2+10x+11=0\)
D \(x^2-4x+21=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-10x+11=0\)
Step 1
Concept
((x-3)(x-7)=x-2 -10x+21), so \(x^2-10x+21=10\) gives \(x^2-10x+11=0\). In exams, bring all terms to one side after expansion.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-10x+11=0\). ((x-3)(x-7)=x-2 -10x+21), so \(x^2-10x+21=10\) gives \(x^2-10x+11=0\). In exams, bring all terms to one side after expansion.
Step 3
Exam Tip
((x-3)(x-7)=x-2 -10x+21), इसलिए \(x^2-10x+21=10\) से \(x^2-10x+11=0\) मिलता है। परीक्षा में विस्तार के बाद सभी पद एक तरफ लाएं।
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यदि ((x-2)(x-5)=6), तो मानक द्विघात समीकरण क्या होगा?
If ((x-2)(x-5)=6), what is the standard quadratic equation?
#quadratic
#standard-form
#application
A \(x^2-7x+4=0\)
B \(x^2-7x+16=0\)
C \(x^2+7x+4=0\)
D \(x^2-3x+10=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-7x+4=0\)
Step 1
Concept
((x-2)(x-5)=x-2 -7x+10), so \(x^2-7x+10=6\) gives \(x^2-7x+4=0\). In exams, bring all terms to one side after expansion.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-7x+4=0\). ((x-2)(x-5)=x-2 -7x+10), so \(x^2-7x+10=6\) gives \(x^2-7x+4=0\). In exams, bring all terms to one side after expansion.
Step 3
Exam Tip
((x-2)(x-5)=x-2 -7x+10), इसलिए \(x^2-7x+10=6\) से \(x^2-7x+4=0\) मिलता है। परीक्षा में विस्तार के बाद सभी पद एक तरफ लाएं।
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\(3x^2+2=11x\) को मानक रूप में लिखने पर क्या मिलेगा?
What is obtained when \(3x^2+2=11x\) is written in standard form?
#quadratic
#standard-form
#transposition
A \(3x^2-11x+2=0\)
B \(3x^2+11x+2=0\)
C \(3x^2-11x-2=0\)
D \(3x^2+2=0\)
Explanation opens after your attempt
Correct Answer
A. \(3x^2-11x+2=0\)
Step 1
Concept
Bringing (11x) to the left gives \(3x^2-11x+2=0\). In exams, bring all terms to one side.
Step 2
Why this answer is correct
The correct answer is A. \(3x^2-11x+2=0\). Bringing (11x) to the left gives \(3x^2-11x+2=0\). In exams, bring all terms to one side.
Step 3
Exam Tip
(11x) को बाईं ओर लाने पर \(3x^2-11x+2=0\) बनता है। परीक्षा में सभी पदों को एक तरफ लाएं।
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यदि \(5x^2+9x=2\) है, तो मानक रूप में समीकरण क्या होगा?
If \(5x^2+9x=2\), what will be the equation in standard form?
#quadratic
#standard-form
#transposition
A \(5x^2+9x-2=0\)
B \(5x^2+9x+2=0\)
C \(5x^2-9x-2=0\)
D \(9x^2+5x-2=0\)
Explanation opens after your attempt
Correct Answer
A. \(5x^2+9x-2=0\)
Step 1
Concept
Bringing (2) to the left gives \(5x^2+9x-2=0\). In exams, make standard form before solving.
Step 2
Why this answer is correct
The correct answer is A. \(5x^2+9x-2=0\). Bringing (2) to the left gives \(5x^2+9x-2=0\). In exams, make standard form before solving.
Step 3
Exam Tip
(2) को बाईं ओर लाने पर \(5x^2+9x-2=0\) मिलता है। परीक्षा में हल करने से पहले मानक रूप बनाएं।
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\(2x^2+1=7x\) को मानक रूप में लिखने पर क्या मिलेगा?
What is obtained when \(2x^2+1=7x\) is written in standard form?
#quadratic
#standard-form
#transposition
A \(2x^2-7x+1=0\)
B \(2x^2+7x+1=0\)
C \(2x^2-7x-1=0\)
D \(2x^2+1=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2-7x+1=0\)
Step 1
Concept
Bringing (7x) to the left gives \(2x^2-7x+1=0\). In exams, bring all terms to one side.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2-7x+1=0\). Bringing (7x) to the left gives \(2x^2-7x+1=0\). In exams, bring all terms to one side.
Step 3
Exam Tip
(7x) को बाईं ओर लाने पर \(2x^2-7x+1=0\) बनता है। परीक्षा में सभी पदों को एक तरफ लाएं।
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यदि \(3x^2+7x=6\) है, तो मानक रूप में समीकरण क्या होगा?
If \(3x^2+7x=6\), what will be the equation in standard form?
#quadratic
#standard-form
#transposition
A \(3x^2+7x-6=0\)
B \(3x^2+7x+6=0\)
C \(3x^2-7x-6=0\)
D \(7x^2+3x-6=0\)
Explanation opens after your attempt
Correct Answer
A. \(3x^2+7x-6=0\)
Step 1
Concept
Bringing (6) to the left gives \(3x^2+7x-6=0\). In exams, make standard form before applying any method.
Step 2
Why this answer is correct
The correct answer is A. \(3x^2+7x-6=0\). Bringing (6) to the left gives \(3x^2+7x-6=0\). In exams, make standard form before applying any method.
Step 3
Exam Tip
(6) को बाईं ओर लाने पर \(3x^2+7x-6=0\) मिलता है। परीक्षा में सूत्र लगाने से पहले मानक रूप बनाएं।
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\(4x^2-1=8x\) को मानक रूप में लिखने पर क्या मिलेगा?
What is obtained when \(4x^2-1=8x\) is written in standard form?
#quadratic
#standard-form
#transposition
A \(4x^2-8x-1=0\)
B \(4x^2+8x-1=0\)
C \(4x^2-8x+1=0\)
D \(4x^2-1=0\)
Explanation opens after your attempt
Correct Answer
A. \(4x^2-8x-1=0\)
Step 1
Concept
Bringing (8x) to the left gives \(4x^2-8x-1=0\). In exams, do not miss any term while making standard form.
Step 2
Why this answer is correct
The correct answer is A. \(4x^2-8x-1=0\). Bringing (8x) to the left gives \(4x^2-8x-1=0\). In exams, do not miss any term while making standard form.
Step 3
Exam Tip
(8x) को बाईं तरफ लाने पर \(4x^2-8x-1=0\) बनता है। परीक्षा में मानक रूप बनाने से पहले कोई पद न छोड़ें।
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यदि \(2x^2+5x=3\) है, तो मानक रूप \(ax^2+bx+c=0\) में (a,b,c) क्या हैं?
If \(2x^2+5x=3\), what are (a,b,c) in standard form \(ax^2+bx+c=0\)?
#quadratic
#standard-form
#coefficients
A (a=2,b=5,c=-3)
B (a=2,b=5,c=3)
C (a=5,b=2,c=-3)
D (a=2,b=-5,c=3)
Explanation opens after your attempt
Correct Answer
A. (a=2,b=5,c=-3)
Step 1
Concept
The standard form is \(2x^2+5x-3=0\), so (a=2,b=5,c=-3). In exams, bring all terms to one side first.
Step 2
Why this answer is correct
The correct answer is A. (a=2,b=5,c=-3). The standard form is \(2x^2+5x-3=0\), so (a=2,b=5,c=-3). In exams, bring all terms to one side first.
Step 3
Exam Tip
मानक रूप \(2x^2+5x-3=0\) है, इसलिए (a=2,b=5,c=-3) हैं। परीक्षा में सभी पदों को पहले एक तरफ लाएं।
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समीकरण \(\frac{x+3}{x-2}+\frac{x-2}{x+3}=\frac{13}{6}\) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of \(\frac{x+3}{x-2}+\frac{x-2}{x+3}=\frac{13}{6}\)?
#quadratic-equations
#fraction-equation
#standard-form
#expert
A \(x^2+x-156=0\)
B \(x^2-x-156=0\)
C \(x^2+x+156=0\)
D \(2x^2+x-156=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+x-156=0\)
Step 1
Concept
After clearing denominators, (6{(x+3)2 +(x-2)2 }=13(x+3)(x-2)). Simplifying gives the correct form \(x^2+x-156=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+x-156=0\). After clearing denominators, (6{(x+3)2 +(x-2)2 }=13(x+3)(x-2)). Simplifying gives the correct form \(x^2+x-156=0\).
Step 3
Exam Tip
हर हटाने पर (6{(x+3)2 +(x-2)2 }=13(x+3)(x-2)) मिलता है। सरल करने पर \(x^2+x-156=0\) सही रूप है।
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समीकरण ((x+6)2 +(x-7)2 =(x+3)2 ) का मानक रूप कौन-सा है?
What is the standard form of ((x+6)2 +(x-7)2 =(x+3)2 )?
#quadratic-equations
#identity
#standard-form
#expert
A \(x^2-14x+76=0\)
B \(x^2+14x+76=0\)
C \(x^2-20x+76=0\)
D \(x^2-14x-76=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-14x+76=0\)
Step 1
Concept
Expanding gives left side \(2x^2-2x+85\) and right side \(x^2+6x+9\). Subtracting gives \(x^2-8x+76=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-14x+76=0\). Expanding gives left side \(2x^2-2x+85\) and right side \(x^2+6x+9\). Subtracting gives \(x^2-8x+76=0\).
Step 3
Exam Tip
विस्तार करने पर बाईं ओर \(2x^2-2x+85\) और दाईं ओर \(x^2+6x+9\) है। घटाने पर \(x^2-8x+76=0\) नहीं बल्कि \(x^2-8x+76=0\) मिलता है।
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समीकरण ((x+5)(x+8)+(x-4)(x+7)=110) का मानक रूप कौन-सा है?
What is the standard form of ((x+5)(x+8)+(x-4)(x+7)=110)?
#quadratic-equations
#expansion
#standard-form
#expert
A \(2x^2+16x-98=0\)
B \(2x^2+16x+12=0\)
C \(x^2+8x-98=0\)
D \(2x^2+8x-110=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2+16x-98=0\)
Step 1
Concept
The left side is \(x^2+13x+40+x^2+3x-28=2x^2+16x+12\). Subtracting (110) gives \(2x^2+16x-98=0\).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2+16x-98=0\). The left side is \(x^2+13x+40+x^2+3x-28=2x^2+16x+12\). Subtracting (110) gives \(2x^2+16x-98=0\).
Step 3
Exam Tip
बाईं ओर \(x^2+13x+40+x^2+3x-28=2x^2+16x+12\) है। (110) घटाने पर \(2x^2+16x-98=0\) मिलता है।
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समीकरण \(\frac{4x^2-3}{5}+\frac{x-2}{4}=3\) का पूर्णांक गुणांकों वाला मानक रूप कौन-सा है?
What is the standard form with integer coefficients of \(\frac{4x^2-3}{5}+\frac{x-2}{4}=3\)?
#quadratic-equations
#fractions
#standard-form
#expert
A \(16x^2+5x-74=0\)
B \(16x^2-5x-74=0\)
C \(4x^2+5x-74=0\)
D \(16x^2+5x+74=0\)
Explanation opens after your attempt
Correct Answer
A. \(16x^2+5x-74=0\)
Step 1
Concept
Multiplying the whole equation by (20) gives \(16x^2-12+5x-10=60\). Therefore the standard form is \(16x^2+5x-82=0\).
Step 2
Why this answer is correct
The correct answer is A. \(16x^2+5x-74=0\). Multiplying the whole equation by (20) gives \(16x^2-12+5x-10=60\). Therefore the standard form is \(16x^2+5x-82=0\).
Step 3
Exam Tip
पूरे समीकरण को (20) से गुणा करने पर \(16x^2-12+5x-10=60\) मिलता है। इसलिए \(16x^2+5x-82=0\) नहीं बल्कि \(16x^2+5x-82=0\) मिलेगा।
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समीकरण ((4x-3)(x+5)=2(3x-1)) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of ((4x-3)(x+5)=2(3x-1))?
#quadratic-equations
#standard-form
#expansion
#expert
A \(4x^2+11x-13=0\)
B \(4x^2+17x-13=0\)
C \(4x^2+11x+13=0\)
D \(4x^2+23x-17=0\)
Explanation opens after your attempt
Correct Answer
A. \(4x^2+11x-13=0\)
Step 1
Concept
Here ((4x-3)(x+5)=4x-2 +17x-15) and (2(3x-1)=6x-2). Bringing all terms to one side gives \(4x^2+11x-13=0\).
Step 2
Why this answer is correct
The correct answer is A. \(4x^2+11x-13=0\). Here ((4x-3)(x+5)=4x-2 +17x-15) and (2(3x-1)=6x-2). Bringing all terms to one side gives \(4x^2+11x-13=0\).
Step 3
Exam Tip
((4x-3)(x+5)=4x-2 +17x-15) और (2(3x-1)=6x-2) है। सभी पद एक ओर लाने पर \(4x^2+11x-13=0\) मिलता है।
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समीकरण \(\frac{x+2}{x-1}+\frac{x-1}{x+2}=\frac{5}{2}\) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of \(\frac{x+2}{x-1}+\frac{x-1}{x+2}=\frac{5}{2}\)?
#quadratic-equations
#fraction-equation
#standard-form
#expert
A \(x^2+x-20=0\)
B \(x^2-x-20=0\)
C \(x^2+x+20=0\)
D \(2x^2+x-20=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+x-20=0\)
Step 1
Concept
After clearing denominators, (2(x+2)2 +2(x-1)2 =5(x-1)(x+2)). Simplifying gives the correct form \(x^2+x-20=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+x-20=0\). After clearing denominators, (2(x+2)2 +2(x-1)2 =5(x-1)(x+2)). Simplifying gives the correct form \(x^2+x-20=0\).
Step 3
Exam Tip
हर हटाने पर (2(x+2)2 +2(x-1)2 =5(x-1)(x+2)) मिलता है। सरल करने पर \(x^2+x-20=0\) सही रूप है।
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समीकरण ((x+5)2 +(x-6)2 =(x+2)2 ) का मानक रूप कौन-सा है?
What is the standard form of ((x+5)2 +(x-6)2 =(x+2)2 )?
#quadratic-equations
#identity
#standard-form
#expert
A \(x^2-10x+57=0\)
B \(x^2+10x+57=0\)
C \(x^2-14x+57=0\)
D \(x^2-10x-57=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-10x+57=0\)
Step 1
Concept
Expanding gives left side \(2x^2-2x+61\) and right side \(x^2+4x+4\). Subtracting gives \(x^2-6x+57=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-10x+57=0\). Expanding gives left side \(2x^2-2x+61\) and right side \(x^2+4x+4\). Subtracting gives \(x^2-6x+57=0\).
Step 3
Exam Tip
विस्तार करने पर बाईं ओर \(2x^2-2x+61\) और दाईं ओर \(x^2+4x+4\) है। घटाने पर \(x^2-6x+57=0\) नहीं बल्कि \(x^2-6x+57=0\) मिलता है।
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समीकरण ((x+4)(x+7)+(x-3)(x+6)=88) का मानक रूप कौन-सा है?
What is the standard form of ((x+4)(x+7)+(x-3)(x+6)=88)?
#quadratic-equations
#expansion
#standard-form
#expert
A \(2x^2+14x-78=0\)
B \(2x^2+14x+10=0\)
C \(x^2+7x-78=0\)
D \(2x^2+7x-88=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2+14x-78=0\)
Step 1
Concept
The left side is \(x^2+11x+28+x^2+3x-18=2x^2+14x+10\). Subtracting (88) gives \(2x^2+14x-78=0\).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2+14x-78=0\). The left side is \(x^2+11x+28+x^2+3x-18=2x^2+14x+10\). Subtracting (88) gives \(2x^2+14x-78=0\).
Step 3
Exam Tip
बाईं ओर \(x^2+11x+28+x^2+3x-18=2x^2+14x+10\) है। (88) घटाने पर \(2x^2+14x-78=0\) मिलता है।
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समीकरण \(\frac{3x^2+2}{4}-\frac{x-5}{3}=6\) का पूर्णांक गुणांकों वाला मानक रूप कौन-सा है?
What is the standard form with integer coefficients of \(\frac{3x^2+2}{4}-\frac{x-5}{3}=6\)?
#quadratic-equations
#fractions
#standard-form
#expert
A \(9x^2-4x-42=0\)
B \(9x^2+4x-42=0\)
C \(3x^2-4x-42=0\)
D \(9x^2-4x+42=0\)
Explanation opens after your attempt
Correct Answer
A. \(9x^2-4x-42=0\)
Step 1
Concept
Multiplying the whole equation by (12) gives \(9x^2+6-4x+20=72\). Therefore the standard form is \(9x^2-4x-46=0\).
Step 2
Why this answer is correct
The correct answer is A. \(9x^2-4x-42=0\). Multiplying the whole equation by (12) gives \(9x^2+6-4x+20=72\). Therefore the standard form is \(9x^2-4x-46=0\).
Step 3
Exam Tip
पूरे समीकरण को (12) से गुणा करने पर \(9x^2+6-4x+20=72\) मिलता है। इसलिए मानक रूप \(9x^2-4x-46=0\) नहीं बल्कि \(9x^2-4x-46=0\) होगा।
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समीकरण ((3x-2)(2x+5)=4(x+1)) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of ((3x-2)(2x+5)=4(x+1))?
#quadratic-equations
#standard-form
#expansion
#expert
A \(6x^2+7x-14=0\)
B \(6x^2+15x-14=0\)
C \(6x^2+7x+14=0\)
D \(6x^2+11x-10=0\)
Explanation opens after your attempt
Correct Answer
A. \(6x^2+7x-14=0\)
Step 1
Concept
Here ((3x-2)(2x+5)=6x-2 +11x-10) and (4(x+1)=4x+4). Bringing all terms to one side gives \(6x^2+7x-14=0\).
Step 2
Why this answer is correct
The correct answer is A. \(6x^2+7x-14=0\). Here ((3x-2)(2x+5)=6x-2 +11x-10) and (4(x+1)=4x+4). Bringing all terms to one side gives \(6x^2+7x-14=0\).
Step 3
Exam Tip
((3x-2)(2x+5)=6x-2 +11x-10) और (4(x+1)=4x+4) है। सभी पद एक ओर लाने पर \(6x^2+7x-14=0\) मिलता है।
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समीकरण (\frac{(x+1)2 }{2}+\frac{(x-3)2 }{3}=10) का पूर्णांक गुणांकों वाला मानक रूप कौन-सा है?
What is the standard form with integer coefficients of (\frac{(x+1)2 }{2}+\frac{(x-3)2 }{3}=10)?
#quadratic-equations
#fractions
#standard-form
#expert
A \(5x^2-6x-39=0\)
B \(5x^2+6x-39=0\)
C \(6x^2-5x-39=0\)
D \(5x^2-6x+39=0\)
Explanation opens after your attempt
Correct Answer
A. \(5x^2-6x-39=0\)
Step 1
Concept
Multiplying the whole equation by (6) gives (3(x+1)2 +2(x-3)2 =60). Simplifying gives the correct form \(5x^2-6x-39=0\).
Step 2
Why this answer is correct
The correct answer is A. \(5x^2-6x-39=0\). Multiplying the whole equation by (6) gives (3(x+1)2 +2(x-3)2 =60). Simplifying gives the correct form \(5x^2-6x-39=0\).
Step 3
Exam Tip
पूरे समीकरण को (6) से गुणा करने पर (3(x+1)2 +2(x-3)2 =60) मिलता है। सरल करने पर \(5x^2-6x-39=0\) सही रूप है।
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समीकरण ((x-3)2 +(x+4)2 =(x-1)2 ) का मानक रूप कौन-सा है?
What is the standard form of ((x-3)2 +(x+4)2 =(x-1)2 )?
#quadratic-equations
#identity
#standard-form
#expert
A \(x^2+4x+24=0\)
B \(x^2-4x+24=0\)
C \(x^2+8x+24=0\)
D \(x^2+4x-24=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+4x+24=0\)
Step 1
Concept
Expanding gives left side \(2x^2+2x+25\) and right side \(x^2-2x+1\). Subtracting gives \(x^2+4x+24=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+4x+24=0\). Expanding gives left side \(2x^2+2x+25\) and right side \(x^2-2x+1\). Subtracting gives \(x^2+4x+24=0\).
Step 3
Exam Tip
विस्तार करने पर बाईं ओर \(2x^2+2x+25\) और दाईं ओर \(x^2-2x+1\) है। घटाने पर \(x^2+4x+24=0\) मिलता है।
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समीकरण ((x+3)(x+6)+(x-2)(x+5)=70) का मानक रूप कौन-सा है?
What is the standard form of ((x+3)(x+6)+(x-2)(x+5)=70)?
#quadratic-equations
#expansion
#standard-form
#expert
A \(2x^2+12x-62=0\)
B \(2x^2+12x+8=0\)
C \(x^2+6x-62=0\)
D \(2x^2+6x-70=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2+12x-62=0\)
Step 1
Concept
The left side is \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\). Subtracting (70) gives \(2x^2+12x-62=0\).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2+12x-62=0\). The left side is \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\). Subtracting (70) gives \(2x^2+12x-62=0\).
Step 3
Exam Tip
बाईं ओर \(x^2+9x+18+x^2+3x-10=2x^2+12x+8\) है। (70) घटाने पर \(2x^2+12x-62=0\) मिलता है।
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समीकरण \(\frac{2x^2-1}{5}+\frac{x+3}{2}=7\) का पूर्णांक गुणांकों वाला मानक रूप कौन-सा है?
What is the standard form with integer coefficients of \(\frac{2x^2-1}{5}+\frac{x+3}{2}=7\)?
#quadratic-equations
#fractions
#standard-form
#expert
A \(4x^2+5x-59=0\)
B \(4x^2+5x+59=0\)
C \(2x^2+5x-59=0\)
D \(4x^2-5x-59=0\)
Explanation opens after your attempt
Correct Answer
A. \(4x^2+5x-59=0\)
Step 1
Concept
Multiplying the whole equation by (10) gives \(4x^2-2+5x+15=70\). Therefore the standard form is \(4x^2+5x-57=0\).
Step 2
Why this answer is correct
The correct answer is A. \(4x^2+5x-59=0\). Multiplying the whole equation by (10) gives \(4x^2-2+5x+15=70\). Therefore the standard form is \(4x^2+5x-57=0\).
Step 3
Exam Tip
पूरे समीकरण को (10) से गुणा करने पर \(4x^2-2+5x+15=70\) मिलता है। इसलिए \(4x^2+5x-57=0\) नहीं बल्कि \(4x^2+5x-57=0\) मिलेगा।
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समीकरण ((2x+5)(3x-4)=4(x-1)) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of ((2x+5)(3x-4)=4(x-1))?
#quadratic-equations
#expansion
#standard-form
#expert
A \(6x^2+7x-16=0\)
B \(6x^2+15x-20=0\)
C \(6x^2+11x-24=0\)
D \(6x^2+7x-24=0\)
Explanation opens after your attempt
Correct Answer
A. \(6x^2+7x-16=0\)
Step 1
Concept
Here ((2x+5)(3x-4)=6x-2 +7x-20) and (4(x-1)=4x-4). Bringing all terms to one side gives \(6x^2+3x-16=0\).
Step 2
Why this answer is correct
The correct answer is A. \(6x^2+7x-16=0\). Here ((2x+5)(3x-4)=6x-2 +7x-20) and (4(x-1)=4x-4). Bringing all terms to one side gives \(6x^2+3x-16=0\).
Step 3
Exam Tip
((2x+5)(3x-4)=6x-2 +7x-20) और (4(x-1)=4x-4) है। सभी पद एक ओर लाने पर \(6x^2+3x-16=0\) नहीं बल्कि सही रूप \(6x^2+3x-16=0\) मिलता है।
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समीकरण ((x-2)(x+3)+(2x-1)(x-4)=0) का मानक रूप कौन-सा है?
What is the standard form of ((x-2)(x+3)+(2x-1)(x-4)=0)?
#quadratic-equations
#expansion
#standard-form
#hard
A \(3x^2-8x-2=0\)
B \(3x^2+8x-2=0\)
C \(3x^2-2x-8=0\)
D \(2x^2-8x-3=0\)
Explanation opens after your attempt
Correct Answer
A. \(3x^2-8x-2=0\)
Step 1
Concept
Here ((x-2)(x+3)=x-2 +x-6) and ((2x-1)(x-4)=2x-2 -9x+4). Adding them gives \(3x^2-8x-2=0\).
Step 2
Why this answer is correct
The correct answer is A. \(3x^2-8x-2=0\). Here ((x-2)(x+3)=x-2 +x-6) and ((2x-1)(x-4)=2x-2 -9x+4). Adding them gives \(3x^2-8x-2=0\).
Step 3
Exam Tip
((x-2)(x+3)=x-2 +x-6) और ((2x-1)(x-4)=2x-2 -9x+4) है। जोड़ने पर \(3x^2-8x-2=0\) मिलता है।
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समीकरण ((x+2)2 +(x-5)2 =(x+1)2 ) का मानक रूप कौन-सा है?
What is the standard form of ((x+2)2 +(x-5)2 =(x+1)2 )?
#quadratic-equations
#identity
#standard-form
#hard
A \(x^2-8x+28=0\)
B \(x^2+8x+28=0\)
C \(x^2-6x+28=0\)
D \(x^2-8x-28=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-8x+28=0\)
Step 1
Concept
Expanding gives left side \(2x^2-6x+29\) and right side \(x^2+2x+1\). Subtracting gives \(x^2-8x+28=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-8x+28=0\). Expanding gives left side \(2x^2-6x+29\) and right side \(x^2+2x+1\). Subtracting gives \(x^2-8x+28=0\).
Step 3
Exam Tip
विस्तार करने पर बाईं ओर \(2x^2-6x+29\) और दाईं ओर \(x^2+2x+1\) है। घटाने पर \(x^2-8x+28=0\) मिलता है।
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समीकरण ((x+2)(x+5)+(x-1)(x+4)=60) का मानक रूप कौन-सा है?
What is the standard form of ((x+2)(x+5)+(x-1)(x+4)=60)?
#quadratic-equations
#expansion
#standard-form
#hard
A \(2x^2+10x-54=0\)
B \(2x^2+10x+6=0\)
C \(x^2+5x-54=0\)
D \(2x^2+5x-60=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2+10x-54=0\)
Step 1
Concept
The left side is \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\). Subtracting (60) gives \(2x^2+10x-54=0\).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2+10x-54=0\). The left side is \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\). Subtracting (60) gives \(2x^2+10x-54=0\).
Step 3
Exam Tip
बाईं ओर \(x^2+7x+10+x^2+3x-4=2x^2+10x+6\) है। (60) घटाने पर \(2x^2+10x-54=0\) मिलता है।
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समीकरण \(\frac{x^2+1}{3}-\frac{x-2}{2}=5\) को पूर्णांक गुणांकों वाले मानक रूप में लिखिए।
Write \(\frac{x^2+1}{3}-\frac{x-2}{2}=5\) in standard form with integer coefficients.
#quadratic-equations
#fractions
#standard-form
#hard
A \(2x^2-3x-22=0\)
B \(2x^2-3x+22=0\)
C \(3x^2-2x-22=0\)
D \(2x^2+3x-22=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2-3x-22=0\)
Step 1
Concept
Multiplying the whole equation by (6) gives \(2x^2+2-3x+6=30\). Therefore the standard form is \(2x^2-3x-22=0\).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2-3x-22=0\). Multiplying the whole equation by (6) gives \(2x^2+2-3x+6=30\). Therefore the standard form is \(2x^2-3x-22=0\).
Step 3
Exam Tip
पूरे समीकरण को (6) से गुणा करने पर \(2x^2+2-3x+6=30\) मिलता है। इसलिए मानक रूप \(2x^2-3x-22=0\) है।
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समीकरण ((6x+1)(x-4)=5x) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of ((6x+1)(x-4)=5x)?
#quadratic-equations
#standard-form
#expansion
#hard
A \(6x^2-28x-4=0\)
B \(6x^2-18x-4=0\)
C \(6x^2-23x-4=0\)
D \(6x^2+28x-4=0\)
Explanation opens after your attempt
Correct Answer
A. \(6x^2-28x-4=0\)
Step 1
Concept
Here ((6x+1)(x-4)=6x-2 -23x-4), and subtracting (5x) gives \(6x^2-28x-4=0\). First expand and then bring all terms to one side.
Step 2
Why this answer is correct
The correct answer is A. \(6x^2-28x-4=0\). Here ((6x+1)(x-4)=6x-2 -23x-4), and subtracting (5x) gives \(6x^2-28x-4=0\). First expand and then bring all terms to one side.
Step 3
Exam Tip
((6x+1)(x-4)=6x-2 -23x-4) है और (5x) घटाने पर \(6x^2-28x-4=0\) मिलता है। पहले विस्तार करें फिर सभी पद एक ओर लाएं।
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समीकरण ((x-1)2 +(x-2)2 =(x-3)2 ) का मानक रूप कौन-सा है?
What is the standard form of ((x-1)2 +(x-2)2 =(x-3)2 )?
#quadratic-equations
#identity
#standard-form
#hard
A \(x^2+6x-4=0\)
B \(x^2-2x-4=0\)
C \(x^2+2x-4=0\)
D \(x^2-6x+4=0\)
Explanation opens after your attempt
Correct Answer
B. \(x^2-2x-4=0\)
Step 1
Concept
Expanding gives left side \(2x^2-6x+5\) and right side \(x^2-6x+9\). Subtracting gives \(x^2-4=0\).
Step 2
Why this answer is correct
The correct answer is B. \(x^2-2x-4=0\). Expanding gives left side \(2x^2-6x+5\) and right side \(x^2-6x+9\). Subtracting gives \(x^2-4=0\).
Step 3
Exam Tip
विस्तार करने पर बाईं ओर \(2x^2-6x+5\) और दाईं ओर \(x^2-6x+9\) है। घटाने पर \(x^2-4=0\) नहीं बल्कि \(x^2-4=0\) मिलता है।
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समीकरण ((x+1)(x+2)+(x+3)(x+4)=50) का मानक रूप कौन-सा है?
What is the standard form of ((x+1)(x+2)+(x+3)(x+4)=50)?
#quadratic-equations
#expansion
#standard-form
#hard
A \(2x^2+10x-36=0\)
B \(2x^2+10x+14=0\)
C \(x^2+5x-36=0\)
D \(2x^2+5x-50=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2+10x-36=0\)
Step 1
Concept
The left side is \(x^2+3x+2+x^2+7x+12=2x^2+10x+14\). Subtracting (50) gives \(2x^2+10x-36=0\).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2+10x-36=0\). The left side is \(x^2+3x+2+x^2+7x+12=2x^2+10x+14\). Subtracting (50) gives \(2x^2+10x-36=0\).
Step 3
Exam Tip
बाईं ओर \(x^2+3x+2+x^2+7x+12=2x^2+10x+14\) है। (50) घटाने पर \(2x^2+10x-36=0\) मिलता है।
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समीकरण \(\frac{x^2-3}{2}+\frac{x-1}{3}=4\) को पूर्णांक गुणांकों वाले मानक रूप में लिखिए।
Write \(\frac{x^2-3}{2}+\frac{x-1}{3}=4\) in standard form with integer coefficients.
#quadratic-equations
#fractions
#standard-form
#hard
A \(3x^2+2x-29=0\)
B \(3x^2+2x-35=0\)
C \(x^2+2x-29=0\)
D \(3x^2-2x-29=0\)
Explanation opens after your attempt
Correct Answer
A. \(3x^2+2x-29=0\)
Step 1
Concept
Multiplying the whole equation by (6) gives \(3x^2-9+2x-2=24\). Thus the standard form is \(3x^2+2x-35=0\).
Step 2
Why this answer is correct
The correct answer is A. \(3x^2+2x-29=0\). Multiplying the whole equation by (6) gives \(3x^2-9+2x-2=24\). Thus the standard form is \(3x^2+2x-35=0\).
Step 3
Exam Tip
पूरे समीकरण को (6) से गुणा करने पर \(3x^2-9+2x-2=24\) मिलता है। इसलिए \(3x^2+2x-35=0\) नहीं बल्कि सही रूप \(3x^2+2x-35=0\) होगा।
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समीकरण ((5x-2)(2x+3)=7x) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of ((5x-2)(2x+3)=7x)?
#quadratic-equations
#standard-form
#expansion
#hard
A \(10x^2+4x-6=0\)
B \(10x^2+18x-6=0\)
C \(10x^2-4x-6=0\)
D \(10x^2+11x+6=0\)
Explanation opens after your attempt
Correct Answer
A. \(10x^2+4x-6=0\)
Step 1
Concept
Here ((5x-2)(2x+3)=10x-2 +11x-6) and subtracting (7x) gives \(10x^2+4x-6=0\). First expand and then bring all terms to one side.
Step 2
Why this answer is correct
The correct answer is A. \(10x^2+4x-6=0\). Here ((5x-2)(2x+3)=10x-2 +11x-6) and subtracting (7x) gives \(10x^2+4x-6=0\). First expand and then bring all terms to one side.
Step 3
Exam Tip
((5x-2)(2x+3)=10x-2 +11x-6) है और (7x) घटाने पर \(10x^2+4x-6=0\) मिलता है। पहले विस्तार करें फिर सभी पद एक ओर लाएं।
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समीकरण ((3x+4)2 =7x+16) का मानक रूप कौन-सा है?
What is the standard form of ((3x+4)2 =7x+16)?
#quadratic-equations
#standard-form
#identity
#medium
A \(9x^2+17x=0\)
B \(9x^2+31x=0\)
C \(9x^2+17x+32=0\)
D \(9x^2+24x-16=0\)
Explanation opens after your attempt
Correct Answer
A. \(9x^2+17x=0\)
Step 1
Concept
((3x+4)2 =9x-2 +24x+16). Subtracting (7x+16) gives \(9x^2+17x=0\).
Step 2
Why this answer is correct
The correct answer is A. \(9x^2+17x=0\). ((3x+4)2 =9x-2 +24x+16). Subtracting (7x+16) gives \(9x^2+17x=0\).
Step 3
Exam Tip
((3x+4)2 =9x-2 +24x+16) है। (7x+16) घटाने पर \(9x^2+17x=0\) मिलता है।
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समीकरण ((x-4)(x+9)=5x) का मानक रूप क्या है?
What is the standard form of ((x-4)(x+9)=5x)?
#quadratic-equations
#standard-form
#expansion
#medium
A \(x^2-36=0\)
B \(x^2+5x-36=0\)
C \(x^2-5x-36=0\)
D \(x^2+14x-36=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-36=0\)
Step 1
Concept
The left side gives \(x^2+5x-36\). Subtracting (5x) gives \(x^2-36=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-36=0\). The left side gives \(x^2+5x-36\). Subtracting (5x) gives \(x^2-36=0\).
Step 3
Exam Tip
बाईं ओर \(x^2+5x-36\) मिलता है। (5x) घटाने पर \(x^2-36=0\) बनता है।
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समीकरण ((x-6)2 =4x+5) का मानक रूप कौन-सा है?
What is the standard form of ((x-6)2 =4x+5)?
#quadratic-equations
#identity
#standard-form
#medium
A \(x^2-16x+31=0\)
B \(x^2-8x+31=0\)
C \(x^2-12x+41=0\)
D \(x^2+16x+31=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-16x+31=0\)
Step 1
Concept
((x-6)2 =x-2 -12x+36). Subtracting (4x+5) gives \(x^2-16x+31=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-16x+31=0\). ((x-6)2 =x-2 -12x+36). Subtracting (4x+5) gives \(x^2-16x+31=0\).
Step 3
Exam Tip
((x-6)2 =x-2 -12x+36) है। (4x+5) को घटाने पर \(x^2-16x+31=0\) मिलता है।
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समीकरण ((4x-1)(x+3)=0) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of ((4x-1)(x+3)=0)?
#quadratic-equations
#standard-form
#expansion
#medium
A \(4x^2+11x-3=0\)
B \(4x^2-11x-3=0\)
C \(4x^2+12x-1=0\)
D \(4x^2-13x+3=0\)
Explanation opens after your attempt
Correct Answer
A. \(4x^2+11x-3=0\)
Step 1
Concept
Expanding ((4x-1)(x+3)) gives \(4x^2+12x-x-3\). So the standard form is \(4x^2+11x-3=0\).
Step 2
Why this answer is correct
The correct answer is A. \(4x^2+11x-3=0\). Expanding ((4x-1)(x+3)) gives \(4x^2+12x-x-3\). So the standard form is \(4x^2+11x-3=0\).
Step 3
Exam Tip
((4x-1)(x+3)) को फैलाने पर \(4x^2+12x-x-3\) मिलता है। इसलिए मानक रूप \(4x^2+11x-3=0\) है।
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समीकरण ((2x-1)2 =3x+5) का मानक रूप कौन-सा है?
What is the standard form of ((2x-1)2 =3x+5)?
#quadratic-equations
#standard-form
#identity
#medium
A \(4x^2-7x-4=0\)
B \(4x^2+x-4=0\)
C \(4x^2-7x+6=0\)
D \(4x^2-x-6=0\)
Explanation opens after your attempt
Correct Answer
A. \(4x^2-7x-4=0\)
Step 1
Concept
Here ((2x-1)2 =4x-2 -4x+1), and bringing all terms to one side gives \(4x^2-7x-4=0\). Apply the square identity and signs carefully.
Step 2
Why this answer is correct
The correct answer is A. \(4x^2-7x-4=0\). Here ((2x-1)2 =4x-2 -4x+1), and bringing all terms to one side gives \(4x^2-7x-4=0\). Apply the square identity and signs carefully.
Step 3
Exam Tip
((2x-1)2 =4x-2 -4x+1) है और सभी पद एक ओर लाने पर \(4x^2-7x-4=0\) मिलता है। वर्ग सूत्र और चिन्ह दोनों ध्यान से लगाएं।
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समीकरण ((x+2)(x-7)=3x) का मानक रूप क्या है?
What is the standard form of ((x+2)(x-7)=3x)?
#quadratic-equations
#standard-form
#expansion
#medium
A \(x^2-8x-14=0\)
B \(x^2-5x-14=0\)
C \(x^2-2x-14=0\)
D \(x^2+8x-14=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-8x-14=0\)
Step 1
Concept
The left side gives \(x^2-5x-14\). Subtracting (3x) gives \(x^2-8x-14=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-8x-14=0\). The left side gives \(x^2-5x-14\). Subtracting (3x) gives \(x^2-8x-14=0\).
Step 3
Exam Tip
बाईं ओर \(x^2-5x-14\) मिलता है। (3x) को घटाने पर \(x^2-8x-14=0\) बनता है।
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समीकरण ((x+4)2 =5x+10) का मानक रूप कौन-सा है?
What is the standard form of ((x+4)2 =5x+10)?
#quadratic-equations
#identity
#standard-form
#medium
A \(x^2+3x+6=0\)
B \(x^2+8x+26=0\)
C \(x^2+13x+6=0\)
D \(x^2+3x-6=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+3x+6=0\)
Step 1
Concept
((x+4)2 =x-2 +8x+16), and subtracting (5x+10) gives \(x^2+3x+6=0\). Keep the middle term correct in square identities.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+3x+6=0\). ((x+4)2 =x-2 +8x+16), and subtracting (5x+10) gives \(x^2+3x+6=0\). Keep the middle term correct in square identities.
Step 3
Exam Tip
((x+4)2 =x-2 +8x+16) है और (5x+10) हटाने पर \(x^2+3x+6=0\) मिलता है। वर्ग सूत्र में मध्य पद सही रखें।
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कौन-सा समीकरण द्विघात है लेकिन अभी मानक रूप में नहीं है?
Which equation is quadratic but not yet in standard form?
#quadratic-equations
#identify
#standard-form
#medium
A \(4x^2-3x+1=0\)
B \(4x^2+1=3x\)
C (4x+1=3)
D \(x^3+1=3x\)
Explanation opens after your attempt
Correct Answer
B. \(4x^2+1=3x\)
Step 1
Concept
\(4x^2+1=3x\) can be written as \(4x^2-3x+1=0\). In standard form, all terms are on one side and (0) is on the other.
Step 2
Why this answer is correct
The correct answer is B. \(4x^2+1=3x\). \(4x^2+1=3x\) can be written as \(4x^2-3x+1=0\). In standard form, all terms are on one side and (0) is on the other.
Step 3
Exam Tip
\(4x^2+1=3x\) को \(4x^2-3x+1=0\) लिखा जा सकता है। मानक रूप में सभी पद एक ओर और दूसरी ओर (0) होता है।
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समीकरण \(8x-x^2=15\) का मानक रूप कौन-सा है जिसमें \(x^2\) का गुणांक धनात्मक हो?
What is the standard form of \(8x-x^2=15\) with positive coefficient of \(x^2\)?
#quadratic-equations
#standard-form
#transposition
#medium
A \(x^2-8x+15=0\)
B \(x^2+8x-15=0\)
C \(x^2-8x-15=0\)
D \(x^2+8x+15=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-8x+15=0\)
Step 1
Concept
Bringing all terms to one side gives \(-x^2+8x-15=0\). Multiplying by (-1) gives \(x^2-8x+15=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-8x+15=0\). Bringing all terms to one side gives \(-x^2+8x-15=0\). Multiplying by (-1) gives \(x^2-8x+15=0\).
Step 3
Exam Tip
सभी पद एक ओर लाने पर \(-x^2+8x-15=0\) मिलता है। (-1) से गुणा करने पर \(x^2-8x+15=0\) मिलता है।
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समीकरण ((3x+2)(x-5)=0) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of ((3x+2)(x-5)=0)?
#quadratic-equations
#standard-form
#expansion
#medium
A \(3x^2-13x-10=0\)
B \(3x^2+13x-10=0\)
C \(3x^2-15x+2=0\)
D \(3x^2+17x+10=0\)
Explanation opens after your attempt
Correct Answer
A. \(3x^2-13x-10=0\)
Step 1
Concept
Expanding ((3x+2)(x-5)) gives \(3x^2-15x+2x-10\). So the standard form is \(3x^2-13x-10=0\).
Step 2
Why this answer is correct
The correct answer is A. \(3x^2-13x-10=0\). Expanding ((3x+2)(x-5)) gives \(3x^2-15x+2x-10\). So the standard form is \(3x^2-13x-10=0\).
Step 3
Exam Tip
((3x+2)(x-5)) को फैलाने पर \(3x^2-15x+2x-10\) मिलता है। इसलिए मानक रूप \(3x^2-13x-10=0\) है।
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समीकरण ((x+3)2 =2x+15) का मानक रूप कौन-सा है?
What is the standard form of ((x+3)2 =2x+15)?
#quadratic-equations
#standard-form
#identity
#medium
A \(x^2+4x-6=0\)
B \(x^2+8x-6=0\)
C \(x^2+4x+6=0\)
D \(x^2+6x-15=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+4x-6=0\)
Step 1
Concept
Here ((x+3)2 =x-2 +6x+9), and bringing all terms to one side gives \(x^2+4x-6=0\). Use the square identity and transposition carefully.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+4x-6=0\). Here ((x+3)2 =x-2 +6x+9), and bringing all terms to one side gives \(x^2+4x-6=0\). Use the square identity and transposition carefully.
Step 3
Exam Tip
((x+3)2 =x-2 +6x+9) है और सभी पद एक ओर लाने पर \(x^2+4x-6=0\) मिलता है। वर्ग सूत्र और स्थानांतरण दोनों सावधानी से करें।
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समीकरण ((x-1)(x+6)=2x) का मानक रूप क्या है?
What is the standard form of ((x-1)(x+6)=2x)?
#quadratic-equations
#standard-form
#expansion
#medium
A \(x^2+3x-6=0\)
B \(x^2+5x-6=0\)
C \(x^2+7x-6=0\)
D \(x^2-3x-6=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+3x-6=0\)
Step 1
Concept
The left side gives \(x^2+5x-6\), and subtracting (2x) gives \(x^2+3x-6=0\). First expand and then bring all terms to one side.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+3x-6=0\). The left side gives \(x^2+5x-6\), and subtracting (2x) gives \(x^2+3x-6=0\). First expand and then bring all terms to one side.
Step 3
Exam Tip
बाईं ओर \(x^2+5x-6\) मिलता है, फिर (2x) घटाने पर \(x^2+3x-6=0\) बनता है। पहले फैलाएं फिर सभी पद एक ओर लाएं।
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समीकरण \(\frac{x^2}{2}+3x-5=0\) को बिना भिन्न के मानक रूप में कौन-सा लिखा जाएगा?
How will \(\frac{x^2}{2}+3x-5=0\) be written in standard form without fractions?
#quadratic-equations
#fractions
#standard-form
#medium
A \(x^2+6x-10=0\)
B \(x^2+3x-5=0\)
C \(2x^2+3x-5=0\)
D \(x^2+6x+10=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+6x-10=0\)
Step 1
Concept
Multiplying the whole equation by (2) gives \(x^2+6x-10=0\). To remove fractions, multiply by the denominator.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+6x-10=0\). Multiplying the whole equation by (2) gives \(x^2+6x-10=0\). To remove fractions, multiply by the denominator.
Step 3
Exam Tip
पूरे समीकरण को (2) से गुणा करने पर \(x^2+6x-10=0\) मिलता है। भिन्न हटाने के लिए हर से गुणा करें।
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समीकरण ((x-5)2 =16) का मानक रूप कौन-सा है?
What is the standard form of ((x-5)2 =16)?
#quadratic-equations
#identity
#standard-form
#medium
A \(x^2-10x+9=0\)
B \(x^2-10x+41=0\)
C \(x^2+10x+9=0\)
D \(x^2-5x+16=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-10x+9=0\)
Step 1
Concept
((x-5)2 =x-2 -10x+25), so \(x^2-10x+25-16=0\). Do not forget the middle term while using square identities.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-10x+9=0\). ((x-5)2 =x-2 -10x+25), so \(x^2-10x+25-16=0\). Do not forget the middle term while using square identities.
Step 3
Exam Tip
((x-5)2 =x-2 -10x+25), इसलिए \(x^2-10x+25-16=0\) मिलता है। वर्ग सूत्र लगाते समय मध्य पद न भूलें।
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कौन-सा समीकरण द्विघात है लेकिन मानक रूप में नहीं लिखा गया है?
Which equation is quadratic but not written in standard form?
#quadratic-equations
#identify
#standard-form
#medium
A \(x^2+2x+1=0\)
B \(x^2=5x-4\)
C (3x+7=0)
D \(x^3+x=0\)
Explanation opens after your attempt
Correct Answer
B. \(x^2=5x-4\)
Step 1
Concept
\(x^2=5x-4\) can be written as \(x^2-5x+4=0\), so it is quadratic. In standard form, the right side must be (0).
Step 2
Why this answer is correct
The correct answer is B. \(x^2=5x-4\). \(x^2=5x-4\) can be written as \(x^2-5x+4=0\), so it is quadratic. In standard form, the right side must be (0).
Step 3
Exam Tip
\(x^2=5x-4\) को \(x^2-5x+4=0\) बनाया जा सकता है, इसलिए यह द्विघात है। मानक रूप में दायां पक्ष (0) होना चाहिए।
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समीकरण \(5x-2x^2=9\) का मानक रूप कौन-सा है जिसमें \(x^2\) का गुणांक धनात्मक हो?
What is the standard form of \(5x-2x^2=9\) with positive coefficient of \(x^2\)?
#quadratic-equations
#standard-form
#signs
#medium
A \(2x^2-5x+9=0\)
B \(2x^2+5x-9=0\)
C \(2x^2-5x-9=0\)
D \(2x^2+5x+9=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2-5x+9=0\)
Step 1
Concept
Bringing all terms to one side gives \(-2x^2+5x-9=0\), and multiplying by (-1) gives \(2x^2-5x+9=0\). Change signs carefully in standard form.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2-5x+9=0\). Bringing all terms to one side gives \(-2x^2+5x-9=0\), and multiplying by (-1) gives \(2x^2-5x+9=0\). Change signs carefully in standard form.
Step 3
Exam Tip
सभी पद एक ओर लाकर \(-2x^2+5x-9=0\) मिलता है और (-1) से गुणा करने पर \(2x^2-5x+9=0\) मिलता है। मानक रूप में चिन्ह सावधानी से बदलें।
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समीकरण ((2x-3)(x+4)=0) का मानक द्विघात रूप कौन-सा है?
What is the standard quadratic form of ((2x-3)(x+4)=0)?
#quadratic-equations
#standard-form
#expansion
#medium
A \(2x^2+5x-12=0\)
B \(2x^2-5x-12=0\)
C \(2x^2+8x-3=0\)
D \(2x^2-11x+12=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2+5x-12=0\)
Step 1
Concept
Multiplying gives \(2x^2+8x-3x-12=0\), so \(2x^2+5x-12=0\). Adding middle terms correctly is important in exams.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2+5x-12=0\). Multiplying gives \(2x^2+8x-3x-12=0\), so \(2x^2+5x-12=0\). Adding middle terms correctly is important in exams.
Step 3
Exam Tip
गुणा करने पर \(2x^2+8x-3x-12=0\), इसलिए \(2x^2+5x-12=0\) मिलता है। मध्य पदों को सही जोड़ना परीक्षा में जरूरी है।
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मानक द्विघात समीकरण \(ax^2+bx+c=0\) में अधिकतम कितने अलग-अलग पद हो सकते हैं?
In the standard quadratic equation \(ax^2+bx+c=0\), what is the maximum number of different terms?
#quadratic-equations
#terms
#standard-form
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The standard form may contain the \(x^2\) term, the (x) term, and the constant term. So the maximum number of terms is (3).
Step 2
Why this answer is correct
The correct answer is C. (3). The standard form may contain the \(x^2\) term, the (x) term, and the constant term. So the maximum number of terms is (3).
Step 3
Exam Tip
मानक रूप में \(x^2\) पद, (x) पद और स्थिर पद हो सकते हैं। इसलिए अधिकतम (3) पद होते हैं।
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मानक रूप \(ax^2+bx+c=0\) में \(x^2\) का गुणांक किससे दर्शाया जाता है?
In the standard form \(ax^2+bx+c=0\), which symbol denotes the coefficient of \(x^2\)?
#quadratic-equations
#standard-form
#coefficient-a
A (b)
B (a)
C (c)
D (x)
Explanation opens after your attempt
Step 1
Concept
In standard form, the coefficient of \(x^2\) is (a). This coefficient must not be (0).
Step 2
Why this answer is correct
The correct answer is B. (a). In standard form, the coefficient of \(x^2\) is (a). This coefficient must not be (0).
Step 3
Exam Tip
मानक रूप में \(x^2\) का गुणांक (a) होता है। यही गुणांक (0) नहीं होना चाहिए।
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((x+1)2 =0) का मानक रूप क्या है?
What is the standard form of ((x+1)2 =0)?
#quadratic-equations
#identity
#standard-form
A \(x^2+x+1=0\)
B \(x^2-2x+1=0\)
C \(x^2+2x+1=0\)
D \(x^2+1=0\)
Explanation opens after your attempt
Correct Answer
C. \(x^2+2x+1=0\)
Step 1
Concept
((x+1)2 =x-2 +2x+1). Remember the formula ((a+b)2 =a-2 +2ab+b-2 ).
Step 2
Why this answer is correct
The correct answer is C. \(x^2+2x+1=0\). ((x+1)2 =x-2 +2x+1). Remember the formula ((a+b)2 =a-2 +2ab+b-2 ).
Step 3
Exam Tip
((x+1)2 =x-2 +2x+1) होता है। सूत्र ((a+b)2 =a-2 +2ab+b-2 ) याद रखें।
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समीकरण \(x^2=6x\) का मानक रूप कौन-सा है?
What is the standard form of \(x^2=6x\)?
#quadratic-equations
#standard-form
#transposition
A \(x^2+6x=0\)
B \(x^2-6x=0\)
C \(6x^2-x=0\)
D \(x^2-6=0\)
Explanation opens after your attempt
Correct Answer
B. \(x^2-6x=0\)
Step 1
Concept
Bringing (6x) to the left gives \(x^2-6x=0\). The sign changes during transposition.
Step 2
Why this answer is correct
The correct answer is B. \(x^2-6x=0\). Bringing (6x) to the left gives \(x^2-6x=0\). The sign changes during transposition.
Step 3
Exam Tip
(6x) को बाईं ओर लाने पर \(x^2-6x=0\) मिलता है। स्थानांतरण करते समय चिन्ह बदलता है।
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समीकरण (x(x-5)=0) का मानक रूप कौन-सा है?
What is the standard form of (x(x-5)=0)?
#quadratic-equations
#expansion
#standard-form
A \(x^2+5x=0\)
B \(x^2-5x=0\)
C \(5x^2-x=0\)
D \(x^2-5=0\)
Explanation opens after your attempt
Correct Answer
B. \(x^2-5x=0\)
Step 1
Concept
Expanding (x(x-5)) gives \(x^2-5x\). Keep signs correct while removing brackets.
Step 2
Why this answer is correct
The correct answer is B. \(x^2-5x=0\). Expanding (x(x-5)) gives \(x^2-5x\). Keep signs correct while removing brackets.
Step 3
Exam Tip
(x(x-5)) को फैलाने पर \(x^2-5x\) मिलता है। कोष्ठक हटाते समय चिन्ह सही रखें।
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समीकरण \(x^2=7\) का मानक रूप कौन-सा है?
What is the standard form of \(x^2=7\)?
#quadratic-equations
#standard-form
#easy
A \(x^2+7=0\)
B \(7x^2=0\)
C \(x^2-7x=0\)
D \(x^2-7=0\)
Explanation opens after your attempt
Correct Answer
D. \(x^2-7=0\)
Step 1
Concept
Bringing (7) to the left gives \(x^2-7=0\). In standard form, all terms are on one side.
Step 2
Why this answer is correct
The correct answer is D. \(x^2-7=0\). Bringing (7) to the left gives \(x^2-7=0\). In standard form, all terms are on one side.
Step 3
Exam Tip
(7) को बाईं ओर लाने पर \(x^2-7=0\) मिलता है। मानक रूप में सभी पद एक तरफ होते हैं।
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समीकरण \(4=3x-x^2\) का मानक रूप क्या है?
What is the standard form of \(4=3x-x^2\)?
#quadratic-equations
#standard-form
#transposition
A \(x^2-3x+4=0\)
B \(x^2+3x+4=0\)
C \(x^2-3x-4=0\)
D \(x^2+3x-4=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x+4=0\)
Step 1
Concept
Bringing all terms to one side gives \(x^2-3x+4=0\). In standard form, keep the right side as (0).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x+4=0\). Bringing all terms to one side gives \(x^2-3x+4=0\). In standard form, keep the right side as (0).
Step 3
Exam Tip
सभी पद एक तरफ लाने पर \(x^2-3x+4=0\) मिलता है। मानक रूप में दायां पक्ष (0) रखें।
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((x+3)2 =25) को मानक रूप में लिखने पर कौन सा समीकरण मिलेगा?
Which equation is obtained when ((x+3)2 =25) is written in standard form?
#quadratic equations
#standard form
#perfect square
A \(x^2+6x-16=0\)
B \(x^2+6x+16=0\)
C \(x^2+3x-25=0\)
D \(x^2+9x-25=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+6x-16=0\)
Step 1
Concept
Here ((x+3)2 =x-2 +6x+9), and moving (25) left gives (-25). So \(x^2+6x-16=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+6x-16=0\). Here ((x+3)2 =x-2 +6x+9), and moving (25) left gives (-25). So \(x^2+6x-16=0\) is correct.
Step 3
Exam Tip
((x+3)2 =x-2 +6x+9) है और (25) को बाईं ओर लाने पर (-25) बनता है। इसलिए \(x^2+6x-16=0\) सही है।
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किस विकल्प में गलती है जब \(x^2=6x+7\) को मानक रूप में बदला जाता है?
Which option shows the mistake while converting \(x^2=6x+7\) to standard form?
#quadratic equations
#common mistake
#standard form
A \(x^2-6x-7=0\)
B \(x^2+6x+7=0\)
C \(x^2-6x=7\)
D \(x^2=6x+7\)
Explanation opens after your attempt
Correct Answer
B. \(x^2+6x+7=0\)
Step 1
Concept
The correct standard form is \(x^2-6x-7=0\). In option (B), the signs of the right-side terms were not changed.
Step 2
Why this answer is correct
The correct answer is B. \(x^2+6x+7=0\). The correct standard form is \(x^2-6x-7=0\). In option (B), the signs of the right-side terms were not changed.
Step 3
Exam Tip
सही मानक रूप \(x^2-6x-7=0\) है। विकल्प (B) में दाईं ओर के पदों के चिन्ह नहीं बदले गए।
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कौन सा समीकरण मानक रूप में लाने पर \(x^2+2x-8=0\) बनता है?
Which equation becomes \(x^2+2x-8=0\) after writing in standard form?
#quadratic equations
#standard form
#reverse form
A \(x^2+2x=8\)
B \(x^2+2x=-8\)
C \(x^2-2x=8\)
D \(x^2-2x=-8\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+2x=8\)
Step 1
Concept
Moving (8) to the left makes it (-8). So we get \(x^2+2x-8=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+2x=8\). Moving (8) to the left makes it (-8). So we get \(x^2+2x-8=0\).
Step 3
Exam Tip
(8) को बाईं ओर लाने पर (-8) बनता है। इसलिए \(x^2+2x-8=0\) मिलता है।
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(4x(x-3)=0) का मानक रूप क्या है?
What is the standard form of (4x(x-3)=0)?
#quadratic equations
#expansion
#standard form
A \(4x^2-12x=0\)
B \(4x^2+12x=0\)
C \(x^2-12x=0\)
D (4x-12=0)
Explanation opens after your attempt
Correct Answer
A. \(4x^2-12x=0\)
Step 1
Concept
Multiplying (4x) by both terms gives \(4x^2-12x=0\). Pay attention to the negative sign.
Step 2
Why this answer is correct
The correct answer is A. \(4x^2-12x=0\). Multiplying (4x) by both terms gives \(4x^2-12x=0\). Pay attention to the negative sign.
Step 3
Exam Tip
(4x) को दोनों पदों से गुणा करने पर \(4x^2-12x=0\) मिलता है। ऋण चिन्ह पर ध्यान दें।
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((x-6)(x+2)=0) का मानक रूप कौन सा है?
Which is the standard form of ((x-6)(x+2)=0)?
#quadratic equations
#expansion
#standard form
A \(x^2-4x-12=0\)
B \(x^2+4x-12=0\)
C \(x^2-8x+12=0\)
D \(x^2+8x+12=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x-12=0\)
Step 1
Concept
Expansion gives \(x^2+2x-6x-12=0\). So \(x^2-4x-12=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4x-12=0\). Expansion gives \(x^2+2x-6x-12=0\). So \(x^2-4x-12=0\) is correct.
Step 3
Exam Tip
विस्तार से \(x^2+2x-6x-12=0\) मिलता है। इसलिए \(x^2-4x-12=0\) सही है।
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(2x(x+7)=0) को मानक रूप में लिखिए।
Write (2x(x+7)=0) in standard form.
#quadratic equations
#expansion
#standard form
A \(2x^2+14x=0\)
B \(2x^2-14x=0\)
C \(14x^2+2x=0\)
D (2x+7=0)
Explanation opens after your attempt
Correct Answer
A. \(2x^2+14x=0\)
Step 1
Concept
Multiply (2x) by both terms inside the bracket. This gives \(2x^2+14x=0\).
Step 2
Why this answer is correct
The correct answer is A. \(2x^2+14x=0\). Multiply (2x) by both terms inside the bracket. This gives \(2x^2+14x=0\).
Step 3
Exam Tip
(2x) को कोष्ठक के दोनों पदों से गुणा करें। इससे \(2x^2+14x=0\) मिलता है।
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समीकरण \(2x^2=5x+3\) का मानक रूप कौन सा है?
Which is the standard form of \(2x^2=5x+3\)?
#quadratic equations
#standard form
#sign change
A \(2x^2-5x-3=0\)
B \(2x^2+5x+3=0\)
C \(2x^2-5x+3=0\)
D \(2x^2+5x-3=0\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2-5x-3=0\)
Step 1
Concept
Bringing all terms to one side gives \(2x^2-5x-3=0\). Changing signs is important.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2-5x-3=0\). Bringing all terms to one side gives \(2x^2-5x-3=0\). Changing signs is important.
Step 3
Exam Tip
सभी पद एक तरफ लाने पर \(2x^2-5x-3=0\) मिलता है। चिन्ह बदलना जरूरी है।
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समीकरण \(4x^2+7x=9\) का मानक रूप क्या है?
What is the standard form of \(4x^2+7x=9\)?
#quadratic equations
#standard form
#transposition
A \(4x^2+7x+9=0\)
B \(4x^2+7x-9=0\)
C \(4x^2-7x-9=0\)
D \(4x^2-7x+9=0\)
Explanation opens after your attempt
Correct Answer
B. \(4x^2+7x-9=0\)
Step 1
Concept
Moving (9) to the left makes it (-9). So the standard form is \(4x^2+7x-9=0\).
Step 2
Why this answer is correct
The correct answer is B. \(4x^2+7x-9=0\). Moving (9) to the left makes it (-9). So the standard form is \(4x^2+7x-9=0\).
Step 3
Exam Tip
दाईं ओर के (9) को बाईं ओर लाने पर (-9) बनता है। इसलिए मानक रूप \(4x^2+7x-9=0\) है।
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किस विकल्प में सामान्य गलती है जब \(x^2=5x-6\) को मानक रूप में बदला जाता है?
Which option shows the common mistake while converting \(x^2=5x-6\) to standard form?
#quadratic equations
#common mistake
#standard form
A \(x^2-5x+6=0\)
B \(x^2-5x-6=0\)
C \(x^2+0x=5x-6\)
D \(x^2=5x-6\)
Explanation opens after your attempt
Correct Answer
B. \(x^2-5x-6=0\)
Step 1
Concept
The correct form is \(x^2-5x+6=0\). In option (B), the sign of (-6) was not changed.
Step 2
Why this answer is correct
The correct answer is B. \(x^2-5x-6=0\). The correct form is \(x^2-5x+6=0\). In option (B), the sign of (-6) was not changed.
Step 3
Exam Tip
सही रूप \(x^2-5x+6=0\) है। विकल्प (B) में (-6) का चिन्ह नहीं बदला गया।
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कौन सा समीकरण मानक रूप में लाने पर \(x^2-7x+10=0\) बनता है?
Which equation becomes \(x^2-7x+10=0\) after writing in standard form?
#quadratic equations
#standard form
#reverse thinking
A \(x^2-7x=-10\)
B \(x^2-7x=10\)
C \(x^2+7x=-10\)
D \(x^2+7x=10\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-7x=-10\)
Step 1
Concept
In \(x^2-7x=-10\), moving (-10) to the left gives (+10). So the standard form is \(x^2-7x+10=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-7x=-10\). In \(x^2-7x=-10\), moving (-10) to the left gives (+10). So the standard form is \(x^2-7x+10=0\).
Step 3
Exam Tip
\(x^2-7x=-10\) में (-10) को बाईं ओर लाने पर (+10) बनता है। इसलिए मानक रूप \(x^2-7x+10=0\) है।
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(3x(x-2)=0) का मानक रूप क्या है?
What is the standard form of (3x(x-2)=0)?
#quadratic equations
#expansion
#standard form
A \(3x^2-6x=0\)
B \(3x^2+6x=0\)
C \(x^2-6x=0\)
D (3x-6=0)
Explanation opens after your attempt
Correct Answer
A. \(3x^2-6x=0\)
Step 1
Concept
Multiplying (3x) by both terms gives \(3x^2-6x=0\). Watch the sign.
Step 2
Why this answer is correct
The correct answer is A. \(3x^2-6x=0\). Multiplying (3x) by both terms gives \(3x^2-6x=0\). Watch the sign.
Step 3
Exam Tip
(3x) को दोनों पदों से गुणा करने पर \(3x^2-6x=0\) मिलता है। चिन्ह पर ध्यान दें।
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((x-4)(x+1)=0) का मानक रूप कौन सा है?
Which is the standard form of ((x-4)(x+1)=0)?
#quadratic equations
#expansion
#standard form
A \(x^2-3x-4=0\)
B \(x^2+3x-4=0\)
C \(x^2-5x+4=0\)
D \(x^2+5x+4=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x-4=0\)
Step 1
Concept
Expanding gives \(x^2+x-4x-4=0\). So \(x^2-3x-4=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x-4=0\). Expanding gives \(x^2+x-4x-4=0\). So \(x^2-3x-4=0\) is correct.
Step 3
Exam Tip
विस्तार करने पर \(x^2+x-4x-4=0\) मिलता है। इसलिए \(x^2-3x-4=0\) सही है।
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(x(x+5)=0) को मानक रूप में लिखिए।
Write (x(x+5)=0) in standard form.
#quadratic equations
#expansion
#standard form
A \(x^2+5x=0\)
B \(x^2-5x=0\)
C \(5x^2+x=0\)
D (x+5=0)
Explanation opens after your attempt
Correct Answer
A. \(x^2+5x=0\)
Step 1
Concept
Multiplying gives \(x^2+5x=0\). While opening brackets, multiply each term.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+5x=0\). Multiplying gives \(x^2+5x=0\). While opening brackets, multiply each term.
Step 3
Exam Tip
गुणा करने पर \(x^2+5x=0\) मिलता है। कोष्ठक खोलते समय हर पद से गुणा करें।
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कौन सा समीकरण \(ax^2+bx+c=0\) के मानक रूप में है?
Which equation is in the standard form \(ax^2+bx+c=0\)?
#quadratic equations
#standard form
#recognition
A \(x^2+2x+1=0\)
B \(x^2+2x=1\)
C \(x^2=2x+1\)
D (2x+1=0)
Explanation opens after your attempt
Correct Answer
A. \(x^2+2x+1=0\)
Step 1
Concept
In standard form the right side is (0). Option (A) matches this form.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+2x+1=0\). In standard form the right side is (0). Option (A) matches this form.
Step 3
Exam Tip
मानक रूप में दाईं ओर (0) होता है। विकल्प (A) इसी रूप में है।
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समीकरण \(x^2=4x+12\) का मानक रूप कौन सा है?
Which is the standard form of \(x^2=4x+12\)?
#quadratic equations
#standard form
#signs
A \(x^2-4x-12=0\)
B \(x^2+4x+12=0\)
C \(x^2-4x+12=0\)
D \(x^2+4x-12=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x-12=0\)
Step 1
Concept
When terms from the right side move left, their signs change. Thus \(x^2-4x-12=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4x-12=0\). When terms from the right side move left, their signs change. Thus \(x^2-4x-12=0\) is correct.
Step 3
Exam Tip
दाईं ओर के पदों को बाईं ओर लाने पर चिन्ह बदलते हैं। इसलिए \(x^2-4x-12=0\) सही है।
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समीकरण \(2x^2+5x=3\) का मानक रूप क्या है?
What is the standard form of \(2x^2+5x=3\)?
#quadratic equations
#standard form
#transposition
A \(2x^2+5x+3=0\)
B \(2x^2+5x-3=0\)
C \(2x^2-5x-3=0\)
D \(2x^2-5x+3=0\)
Explanation opens after your attempt
Correct Answer
B. \(2x^2+5x-3=0\)
Step 1
Concept
Bringing all terms to one side gives \(2x^2+5x-3=0\). Do not forget the sign change.
Step 2
Why this answer is correct
The correct answer is B. \(2x^2+5x-3=0\). Bringing all terms to one side gives \(2x^2+5x-3=0\). Do not forget the sign change.
Step 3
Exam Tip
सभी पद एक तरफ लाने पर \(2x^2+5x-3=0\) मिलता है। चिन्ह बदलना न भूलें।
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किसी धनात्मक पूर्णांक को (9) से भाग देने पर कौन-सा रूप मानक रूप नहीं है?
When a positive integer is divided by (9), which form is not a standard form?
#real-numbers
#not-standard-form
#remainder-condition
A (9q+7)
B (9q+8)
C (9q+9)
D (9q)
Explanation opens after your attempt
Step 1
Concept
On division by (9), remainders can be from (0) to (8).
Step 2
Why this answer is correct
In (9q+9), the remainder is (9), which equals the divisor.
Step 3
Exam Tip
It should be written correctly as (9(q+1)). चरण 1: (9) से भाग देने पर शेषफल (0) से (8) तक हो सकते हैं। चरण 2: (9q+9) में शेषफल (9) है, जो भाजक के बराबर है। चरण 3: इसे सही रूप में (9(q+1)) लिखा जाना चाहिए।
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किसी धनात्मक पूर्णांक को (3) से भाग देने पर कौन-सा रूप मानक रूप नहीं है?
When a positive integer is divided by (3), which form is not a standard form?
#real-numbers
#not-standard-form
#remainder-condition
A (3q)
B (3q+1)
C (3q+2)
D (3q+3)
Explanation opens after your attempt
Step 1
Concept
On division by (3), possible remainders are (0,1,2).
Step 2
Why this answer is correct
In (3q+3), the remainder is (3), which equals the divisor.
Step 3
Exam Tip
It should be written correctly as (3(q+1)). चरण 1: (3) से भाग देने पर शेषफल (0,1,2) हो सकते हैं। चरण 2: (3q+3) में शेषफल (3) है, जो भाजक के बराबर है। चरण 3: इसे सही रूप में (3(q+1)) लिखना चाहिए।
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यूक्लिड विभाजन प्रमेयिका का मानक रूप कौन सा है?
Which is the standard form of Euclid’s Division Lemma?
#standard form
#euclid lemma
#class 10 maths
A \(a=bq+r,\ 0 \le r < b\)
B (a=b+r+q)
C (a=q-r)
D (b=aq+r)
Explanation opens after your attempt
Correct Answer
A. \(a=bq+r,\ 0 \le r < b\)
Step 1
Concept
The lemma uses dividend (a), divisor (b), quotient (q), and remainder (r).
Step 2
Why this answer is correct
The correct relation is (a=bq+r).
Step 3
Exam Tip
Do not forget the condition \(0 \le r < b\). चरण 1: प्रमेयिका में भाज्य (a), भाजक (b), भागफल (q) और शेषफल (r) होते हैं। चरण 2: सही संबंध (a=bq+r) है। चरण 3: साथ में \(0 \le r < b\) लिखना न भूलें।
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बेसनगर का गरुड़ ध्वज किस धर्म के प्रारंभिक विकास से जुड़ा है?
The Garuda standard at Besnagar is linked with the early development of which religion?
#ancient-history
#besnagar
#vaishnavism
A वैष्णव धर्म / Vaishnavism
B बौद्ध धर्म / Buddhism
C जैन धर्म / Jainism
D आजीविक संप्रदाय / Ajivika sect
Explanation opens after your attempt
Correct Answer
A. वैष्णव धर्म / Vaishnavism
Step 1
Concept
The Garuda standard at Besnagar is evidence linked with Vasudeva Vishnu devotion. For exams, understand religious development through symbols.
Step 2
Why this answer is correct
The correct answer is A. वैष्णव धर्म / Vaishnavism. The Garuda standard at Besnagar is evidence linked with Vasudeva Vishnu devotion. For exams, understand religious development through symbols.
Step 3
Exam Tip
बेसनगर का गरुड़ ध्वज वासुदेव विष्णु भक्ति से जुड़ा प्रमाण है। परीक्षा में प्रतीकों से धर्म के विकास को समझें।
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हड़प्पाई ईंटों का मानक अनुपात सामान्यतः किस रूप में बताया जाता है?
The standard ratio of Harappan bricks is generally stated as what?
#ancient-history
#harappan-bricks
#urban-planning
A 1:1:1
B 1:2:4
C 2:3:5
D 3:4:5
Explanation opens after your attempt
Step 1
Concept
Harappan bricks are famous for the 1:2:4 ratio. For exams, connect it with standardization and town planning.
Step 2
Why this answer is correct
The correct answer is B. 1:2:4. Harappan bricks are famous for the 1:2:4 ratio. For exams, connect it with standardization and town planning.
Step 3
Exam Tip
हड़प्पाई ईंटों में 1:2:4 का अनुपात प्रसिद्ध है। परीक्षा में इसे मानकीकरण और नगर योजना से जोड़ें।
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कौन-सा व्यंजक मानक बहुपद रूप में लिखा है?
Which expression is written in standard polynomial form?
#standard_form
#arrangement
#polynomials
A \(5+2x+x^3\)
B \(x^3+2x+5\)
C \(2x+5+x^3\)
D \(5+x^3+2x\)
Explanation opens after your attempt
Correct Answer
B. \(x^3+2x+5\)
Step 1
Concept
In standard form, terms are written from higher power to lower power. The expression \(x^3+2x+5\) follows this order.
Step 2
Why this answer is correct
The correct answer is B. \(x^3+2x+5\). In standard form, terms are written from higher power to lower power. The expression \(x^3+2x+5\) follows this order.
Step 3
Exam Tip
मानक रूप में पद बड़ी घात से छोटी घात की ओर लिखे जाते हैं। \(x^3+2x+5\) इसी क्रम में है।
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बहुपद \(4x^2+3x^4-x+2\) को मानक रूप में कैसे लिखा जाएगा?
How is \(4x^2+3x^4-x+2\) written in standard form?
#standard_form
#polynomials
#arrangement
A \(3x^4+4x^2-x+2\)
B \(2-x+4x^2+3x^4\)
C \(4x^2+3x^4-x+2\)
D \(3x^4-x+4x^2+2\)
Explanation opens after your attempt
Correct Answer
A. \(3x^4+4x^2-x+2\)
Step 1
Concept
In standard form, terms are written in decreasing powers. Therefore \(3x^4+4x^2-x+2\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(3x^4+4x^2-x+2\). In standard form, terms are written in decreasing powers. Therefore \(3x^4+4x^2-x+2\) is correct.
Step 3
Exam Tip
मानक रूप में पद घटती घातों में लिखे जाते हैं। इसलिए \(3x^4+4x^2-x+2\) सही है।
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समीकरण (3(x+1)2 +2(x-4)2 =74) का मानक रूप कौन-सा है?
What is the standard form of (3(x+1)2 +2(x-4)2 =74)?
#quadratic-equations
#identity
#simplification
#expert
A \(5x^2-10x-39=0\)
B \(5x^2+10x-39=0\)
C \(5x^2-10x+39=0\)
D \(5x^2-16x-74=0\)
Explanation opens after your attempt
Correct Answer
A. \(5x^2-10x-39=0\)
Step 1
Concept
Expanding gives \(3x^2+6x+3+2x^2-16x+32=74\). Simplifying gives \(5x^2-10x-39=0\).
Step 2
Why this answer is correct
The correct answer is A. \(5x^2-10x-39=0\). Expanding gives \(3x^2+6x+3+2x^2-16x+32=74\). Simplifying gives \(5x^2-10x-39=0\).
Step 3
Exam Tip
विस्तार करने पर \(3x^2+6x+3+2x^2-16x+32=74\) मिलता है। सरल करने पर \(5x^2-10x-39=0\) सही है।
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समीकरण (2(x-1)2 +3(x+2)2 =65) का मानक रूप कौन-सा है?
What is the standard form of (2(x-1)2 +3(x+2)2 =65)?
#quadratic-equations
#identity
#simplification
#expert
A \(5x^2+8x-51=0\)
B \(5x^2-8x-51=0\)
C \(5x^2+8x+51=0\)
D \(5x^2+10x-65=0\)
Explanation opens after your attempt
Correct Answer
A. \(5x^2+8x-51=0\)
Step 1
Concept
Expanding gives \(2x^2-4x+2+3x^2+12x+12=65\). Simplifying gives \(5x^2+8x-51=0\).
Step 2
Why this answer is correct
The correct answer is A. \(5x^2+8x-51=0\). Expanding gives \(2x^2-4x+2+3x^2+12x+12=65\). Simplifying gives \(5x^2+8x-51=0\).
Step 3
Exam Tip
विस्तार करने पर \(2x^2-4x+2+3x^2+12x+12=65\) मिलता है। सरल करने पर \(5x^2+8x-51=0\) सही है।
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समीकरण ((x+2)2 +2(x-3)2 =35) का मानक रूप कौन-सा है?
What is the standard form of ((x+2)2 +2(x-3)2 =35)?
#quadratic-equations
#identity
#simplification
#expert
A \(3x^2-8x-13=0\)
B \(3x^2+8x-13=0\)
C \(3x^2-8x+13=0\)
D \(2x^2-8x-13=0\)
Explanation opens after your attempt
Correct Answer
A. \(3x^2-8x-13=0\)
Step 1
Concept
Expanding gives \(x^2+4x+4+2x^2-12x+18=35\). Hence \(3x^2-8x-13=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(3x^2-8x-13=0\). Expanding gives \(x^2+4x+4+2x^2-12x+18=35\). Hence \(3x^2-8x-13=0\) is correct.
Step 3
Exam Tip
विस्तार करने पर \(x^2+4x+4+2x^2-12x+18=35\) मिलता है। इसलिए \(3x^2-8x-13=0\) सही है।
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समीकरण ((2x-3)2 +(x+5)2 =34) का मानक रूप कौन-सा है?
What is the standard form of ((2x-3)2 +(x+5)2 =34)?
#quadratic-equations
#identity
#simplification
#hard
A \(5x^2-2x=0\)
B \(5x^2+2x=0\)
C \(5x^2-2x+34=0\)
D \(3x^2-2x=0\)
Explanation opens after your attempt
Correct Answer
A. \(5x^2-2x=0\)
Step 1
Concept
Expanding gives \(4x^2-12x+9+x^2+10x+25=34\). Simplifying gives \(5x^2-2x=0\).
Step 2
Why this answer is correct
The correct answer is A. \(5x^2-2x=0\). Expanding gives \(4x^2-12x+9+x^2+10x+25=34\). Simplifying gives \(5x^2-2x=0\).
Step 3
Exam Tip
विस्तार करने पर \(4x^2-12x+9+x^2+10x+25=34\) मिलता है। सरल करने पर \(5x^2-2x=0\) बनता है।
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समीकरण ((x-2)2 +(2x+1)2 =25) का मानक रूप कौन-सा है?
What is the standard form of ((x-2)2 +(2x+1)2 =25)?
#quadratic-equations
#identity
#simplification
#hard
A \(5x^2+1=25\)
B \(5x^2+1=0\)
C \(5x^2+20=0\)
D \(5x^2-20=0\)
Explanation opens after your attempt
Correct Answer
D. \(5x^2-20=0\)
Step 1
Concept
Expanding gives \(x^2-4x+4+4x^2+4x+1=25\). This gives \(5x^2-20=0\).
Step 2
Why this answer is correct
The correct answer is D. \(5x^2-20=0\). Expanding gives \(x^2-4x+4+4x^2+4x+1=25\). This gives \(5x^2-20=0\).
Step 3
Exam Tip
विस्तार करने पर \(x^2-4x+4+4x^2+4x+1=25\) मिलता है। इससे \(5x^2-20=0\) बनता है।
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किसी धनात्मक पूर्णांक को (8) से भाग देने पर मानक सामान्य रूप कौन-सा हो सकता है?
What can be the standard general forms of a positive integer when divided by (8)?
#real-numbers
#general-form
#possible-remainders
A (8q,8q+1,8q+2,8q+3,8q+4,8q+5,8q+6,8q+7)
B (8q+1,8q+2,8q+3,8q+4,8q+5,8q+6,8q+7,8q+8)
C (q,q+1,q+2,q+3,q+4,q+5,q+6,q+7)
D (8q-1,8q,8q+1,8q+8)
Explanation opens after your attempt
Correct Answer
A. (8q,8q+1,8q+2,8q+3,8q+4,8q+5,8q+6,8q+7)
Step 1
Concept
On division by (8), remainders can be from (0) to (7).
Step 2
Why this answer is correct
So in (8q+r), (r=0,1,2,3,4,5,6,7).
Step 3
Exam Tip
Do not include (8q+8) while writing standard forms. चरण 1: (8) से भाग देने पर शेषफल (0) से (7) तक हो सकते हैं। चरण 2: इसलिए रूप (8q+r) में (r=0,1,2,3,4,5,6,7) होगा। चरण 3: सामान्य रूप लिखते समय (8q+8) शामिल न करें।
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किसी धनात्मक पूर्णांक को (3) से भाग देने पर कौन-सा रूप संभव नहीं है?
Which form is not possible as a standard form when a positive integer is divided by (3)?
#real-numbers
#general-form
#not-possible
A (3q)
B (3q+1)
C (3q+2)
D (3q+3)
Explanation opens after your attempt
Step 1
Concept
On division by (3), possible remainders are (0,1,2).
Step 2
Why this answer is correct
In (3q+3), the remainder is (3), which equals the divisor.
Step 3
Exam Tip
It should be written as (3(q+1)). चरण 1: (3) से भाग देने पर शेषफल (0,1,2) हो सकते हैं। चरण 2: (3q+3) में शेषफल (3) है, जो भाजक के बराबर है। चरण 3: इसे (3(q+1)) के रूप में लिखना चाहिए।
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किसी धनात्मक पूर्णांक को (4) से भाग देने पर वह किस रूप में नहीं लिखा जा सकता?
When a positive integer is divided by (4), which form cannot be a standard remainder form?
#real-numbers
#general-form
#remainder-condition
A (4q)
B (4q+1)
C (4q+2)
D (4q+4)
Explanation opens after your attempt
Step 1
Concept
On division by (4), possible remainders are (0,1,2,3).
Step 2
Why this answer is correct
In (4q+4), the remainder is (4), which equals the divisor.
Step 3
Exam Tip
Such a form should be written as (4(q+1)). चरण 1: (4) से भाग देने पर शेषफल (0,1,2,3) हो सकते हैं। चरण 2: (4q+4) में शेषफल (4) है, जो भाजक के बराबर है। चरण 3: ऐसे रूप को (4(q+1)) लिखना चाहिए।
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फ्रांसीसी क्रांति के बाद पुराने शाही ध्वज के स्थान पर कौन सा ध्वज अपनाया गया?
Which flag replaced the old royal standard after the French Revolution?
#tricolour
#flag
#revolutionary-symbols
A काला लाल सुनहरा ध्वज / Black red gold flag
B सफेद शाही ध्वज / White royal standard
C त्रिवर्ण ध्वज / Tricolour flag
D यूनियन ध्वज / Union flag
Explanation opens after your attempt
Correct Answer
C. त्रिवर्ण ध्वज / Tricolour flag
Step 1
Concept
The royal standard represented the old monarchy.
Step 2
Why this answer is correct
The tricolour became a symbol of new civic authority and national unity.
Step 3
Exam Tip
Link the change of flag with the change of power. चरण 1: शाही ध्वज पुराने राजतंत्र का प्रतीक था। चरण 2: त्रिवर्ण ध्वज नई नागरिक सत्ता और राष्ट्रीय एकता का प्रतीक बना। चरण 3: ध्वज परिवर्तन को सत्ता परिवर्तन से जोड़कर याद करें।
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क्रांति के बाद फ्रांस में पुराने राजचिह्न की जगह किस झंडे को अपनाया गया?
After the revolution, which flag replaced the old royal standard in France?
#tricolour flag
#symbols
#france
#nationalism
A त्रिरंगा झंडा / Tricolour flag
B काला झंडा / Black flag
C सफेद राजसी झंडा / White royal flag
D पीला झंडा / Yellow flag
Explanation opens after your attempt
Correct Answer
A. त्रिरंगा झंडा / Tricolour flag
Step 1
Concept
The old royal standard represented monarchy.
Step 2
Why this answer is correct
The tricolour flag became a symbol of the new nation.
Step 3
Exam Tip
Remember the flag as a symbol of national unity. चरण 1: पुराने राजचिह्न राजशाही का प्रतीक था। चरण 2: क्रांति के बाद त्रिरंगा झंडा नए राष्ट्र का प्रतीक बना। चरण 3: झंडे को राष्ट्रीय एकता के चिन्ह के रूप में याद रखें।
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मानवाधिकारों की सार्वभौम घोषणा को बाध्यकारी संधि न होते हुए भी प्रभावशाली क्यों माना जाता है?
Why is the Universal Declaration of Human Rights influential even though it is not a binding treaty?
#udhr
#human-rights
#moral-standard
A इसने मानव गरिमा और अधिकारों का वैश्विक मानक बनाया / It created a global standard of human dignity and rights
B इसने सुरक्षा परिषद समाप्त की / It abolished the Security Council
C इसने संयुक्त राष्ट्र ध्वज बदला / It changed the UN flag
D इसने वीटो शक्ति बनाई / It created veto power
Explanation opens after your attempt
Correct Answer
A. इसने मानव गरिमा और अधिकारों का वैश्विक मानक बनाया / It created a global standard of human dignity and rights
Step 1
Concept
The UDHR strengthened international human rights language. For exams remember the difference between a moral standard and a legal treaty.
Step 2
Why this answer is correct
The correct answer is A. इसने मानव गरिमा और अधिकारों का वैश्विक मानक बनाया / It created a global standard of human dignity and rights. The UDHR strengthened international human rights language. For exams remember the difference between a moral standard and a legal treaty.
Step 3
Exam Tip
यू डी एच आर ने अंतरराष्ट्रीय मानवाधिकार भाषा को मजबूत किया। परीक्षा में नैतिक मानक और कानूनी संधि का अंतर याद रखें।
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मानवाधिकारों की सार्वभौम घोषणा को हार्ड स्तर पर किस रूप में समझना उचित है?
At hard level how should the Universal Declaration of Human Rights be understood?
#udhr
#human rights
#global standard
A नैतिक मानक स्थापित करने वाला गैर संधि दस्तावेज / A non-treaty document setting moral standards
B सुरक्षा परिषद का युद्ध आदेश / A Security Council war order
C विश्व बैंक का ऋण अनुबंध / A World Bank loan contract
D न्यास परिषद की संपत्ति सूची / A Trusteeship Council property list
Explanation opens after your attempt
Correct Answer
A. नैतिक मानक स्थापित करने वाला गैर संधि दस्तावेज / A non-treaty document setting moral standards
Step 1
Concept
The declaration itself was not a treaty but created global human rights standards. Exam tip: link it with standard-setting.
Step 2
Why this answer is correct
The correct answer is A. नैतिक मानक स्थापित करने वाला गैर संधि दस्तावेज / A non-treaty document setting moral standards. The declaration itself was not a treaty but created global human rights standards. Exam tip: link it with standard-setting.
Step 3
Exam Tip
घोषणा स्वयं संधि नहीं थी पर उसने मानवाधिकारों के वैश्विक मानक बनाए। परीक्षा में इसे मानक निर्माण से जोड़ें।
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मानवाधिकारों की सार्वभौम घोषणा को विश्व इतिहास में मील का पत्थर क्यों माना जाता है?
Why is the Universal Declaration of Human Rights considered a milestone in world history?
#udhr
#human rights
#global standard
A क्योंकि उसने मानव गरिमा और अधिकारों का वैश्विक मानक दिया / Because it gave a global standard of human dignity and rights
B क्योंकि उसने सुरक्षा परिषद समाप्त की / Because it ended the Security Council
C क्योंकि उसने सभी भाषाएं बंद कीं / Because it banned all languages
D क्योंकि उसने युद्ध को अनिवार्य बनाया / Because it made war compulsory
Explanation opens after your attempt
Correct Answer
A. क्योंकि उसने मानव गरिमा और अधिकारों का वैश्विक मानक दिया / Because it gave a global standard of human dignity and rights
Step 1
Concept
The human rights declaration emphasized dignity and rights of all people. Exam tip: link it with 1948 and 10 December.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि उसने मानव गरिमा और अधिकारों का वैश्विक मानक दिया / Because it gave a global standard of human dignity and rights. The human rights declaration emphasized dignity and rights of all people. Exam tip: link it with 1948 and 10 December.
Step 3
Exam Tip
मानवाधिकार घोषणा ने सभी लोगों की गरिमा और अधिकारों पर जोर दिया। परीक्षा में इसे उन्नीस सौ अड़तालीस और दस दिसंबर से जोड़ें।
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यदि \(a\neq0\), तो (ax+b) के बारे में सही कथन कौन सा है?
If \(a\neq0\), which statement is correct about (ax+b)?
#linear-polynomial
#standard-form
#degree
A यह नियत बहुपद है / It is a constant polynomial
B यह रैखिक बहुपद है / It is a linear polynomial
C यह द्विघात बहुपद है / It is a quadratic polynomial
D यह शून्य बहुपद है / It is the zero polynomial
Explanation opens after your attempt
Correct Answer
B. यह रैखिक बहुपद है / It is a linear polynomial
Step 1
Concept
When \(a\neq0\), the (x)-term is present. So (ax+b) has degree (1).
Step 2
Why this answer is correct
The correct answer is B. यह रैखिक बहुपद है / It is a linear polynomial. When \(a\neq0\), the (x)-term is present. So (ax+b) has degree (1).
Step 3
Exam Tip
\(a\neq0\) होने पर (x) का पद मौजूद रहता है। इसलिए (ax+b) की घात (1) होती है।
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\(ax^2+bx+c\) में यदि \(a\neq0\), तो यह किस प्रकार का बहुपद है?
In \(ax^2+bx+c\), if \(a\neq0\), what type of polynomial is it?
#standard-form
#quadratic
A रैखिक बहुपद / Linear polynomial
B द्विघात बहुपद / Quadratic polynomial
C त्रिघात बहुपद / Cubic polynomial
D नियत बहुपद / Constant polynomial
Explanation opens after your attempt
Correct Answer
B. द्विघात बहुपद / Quadratic polynomial
Step 1
Concept
When \(a\neq0\), the \(x^2\) term is present. So the degree of the polynomial is (2).
Step 2
Why this answer is correct
The correct answer is B. द्विघात बहुपद / Quadratic polynomial. When \(a\neq0\), the \(x^2\) term is present. So the degree of the polynomial is (2).
Step 3
Exam Tip
\(a\neq0\) होने पर \(x^2\) का पद मौजूद रहता है। इसलिए बहुपद की घात (2) होती है।
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