10 results found for "root-verification" in Class 10.
Question
Expert Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
(x-2 -(a+8)x+8a=0) के बारे में कौन-सा कथन हमेशा सही है?
Which statement is always correct about (x-2 -(a+8)x+8a=0)?
#quadratic-roots
#parametric-equation
#root-verification
A (8) हमेशा एक जड़ है / (8) is always one root
B (a+8) हमेशा एक जड़ है / (a+8) is always one root
C दोनों जड़ें हमेशा (8) हैं / Both roots are always (8)
D जड़ें कभी वास्तविक नहीं हैं / The roots are never real
Explanation opens after your attempt
Correct Answer
A. (8) हमेशा एक जड़ है / (8) is always one root
Step 1
Concept
Putting (x=8) gives (64-8(a+8)+8a=0). Hence (8) is always one root and the other root is (a).
Step 2
Why this answer is correct
The correct answer is A. (8) हमेशा एक जड़ है / (8) is always one root. Putting (x=8) gives (64-8(a+8)+8a=0). Hence (8) is always one root and the other root is (a).
Step 3
Exam Tip
(x=8) रखने पर (64-8(a+8)+8a=0) मिलता है। इसलिए (8) हमेशा एक जड़ है और दूसरी जड़ (a) है।
Login to save your score, XP, coins and progress.
Question
Expert Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
(x-2 -(a+6)x+6a=0) के लिए कौन-सा कथन हमेशा सत्य है?
Which statement is always true for (x-2 -(a+6)x+6a=0)?
#quadratic-roots
#root-verification
#parametric-equation
A (a+6) हमेशा जड़ है / (a+6) is always a root
B (6) हमेशा जड़ है / (6) is always a root
C दोनों जड़ें हमेशा समान हैं / Both roots are always equal
D जड़ें कभी वास्तविक नहीं हैं / The roots are never real
Explanation opens after your attempt
Correct Answer
B. (6) हमेशा जड़ है / (6) is always a root
Step 1
Concept
Putting (x=6) gives (36-6(a+6)+6a=0). Hence (6) is always one root and the other root is (a).
Step 2
Why this answer is correct
The correct answer is B. (6) हमेशा जड़ है / (6) is always a root. Putting (x=6) gives (36-6(a+6)+6a=0). Hence (6) is always one root and the other root is (a).
Step 3
Exam Tip
(x=6) रखने पर (36-6(a+6)+6a=0) मिलता है। इसलिए (6) हमेशा एक जड़ है और दूसरी जड़ (a) है।
Login to save your score, XP, coins and progress.
Question
Expert Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
(x-2 -(a+4)x+4a=0) के लिए कौन-सा कथन हमेशा सत्य है?
Which statement is always true for (x-2 -(a+4)x+4a=0)?
#quadratic-roots
#root-verification
#identity
A (4) हमेशा एक जड़ है / (4) is always a root
B (a+4) हमेशा एक जड़ है / (a+4) is always a root
C दोनों जड़ें हमेशा समान हैं / Both roots are always equal
D जड़ें कभी वास्तविक नहीं हैं / The roots are never real
Explanation opens after your attempt
Correct Answer
A. (4) हमेशा एक जड़ है / (4) is always a root
Step 1
Concept
Putting (x=4) gives (16-4(a+4)+4a=0). Hence (4) is always one root and the other root is (a).
Step 2
Why this answer is correct
The correct answer is A. (4) हमेशा एक जड़ है / (4) is always a root. Putting (x=4) gives (16-4(a+4)+4a=0). Hence (4) is always one root and the other root is (a).
Step 3
Exam Tip
(x=4) रखने पर (16-4(a+4)+4a=0) मिलता है। अतः (4) हमेशा एक जड़ है और दूसरी जड़ (a) होती है।
Login to save your score, XP, coins and progress.
Question
Hard Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
यदि (x=0), \(ax^2+bx+c=0\) की जड़ है, तो कौन-सी शर्त निश्चित रूप से सही है?
If (x=0) is a root of \(ax^2+bx+c=0\), which condition must be true?
#quadratic-roots
#zero-root
#root-verification
A (c=0)
B (b=0)
C (a=0)
D (a+b=0)
Explanation opens after your attempt
Step 1
Concept
Putting (x=0) gives (c=0). Thus the direct condition for zero to be a root is (c=0).
Step 2
Why this answer is correct
The correct answer is A. (c=0). Putting (x=0) gives (c=0). Thus the direct condition for zero to be a root is (c=0).
Step 3
Exam Tip
(x=0) रखने पर समीकरण (c=0) बनता है। इसलिए शून्य जड़ होने की सीधी शर्त (c=0) है।
Login to save your score, XP, coins and progress.
Question
Hard Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
(x-2 -(a+3)x+3a=0) के बारे में कौन-सा कथन हमेशा सही है?
Which statement is always true about (x-2 -(a+3)x+3a=0)?
#quadratic-roots
#root-verification
#parameter
A (3) हमेशा एक जड़ है / (3) is always a root
B (a) कभी जड़ नहीं है / (a) is never a root
C दोनों जड़ें हमेशा समान हैं / Both roots are always equal
D कोई वास्तविक जड़ नहीं है / There is no real root
Explanation opens after your attempt
Correct Answer
A. (3) हमेशा एक जड़ है / (3) is always a root
Step 1
Concept
Putting (x=3) gives (9-3(a+3)+3a=0). Hence (3) is always one root, and the other root is (a).
Step 2
Why this answer is correct
The correct answer is A. (3) हमेशा एक जड़ है / (3) is always a root. Putting (x=3) gives (9-3(a+3)+3a=0). Hence (3) is always one root, and the other root is (a).
Step 3
Exam Tip
(x=3) रखने पर (9-3(a+3)+3a=0) मिलता है। इसलिए (3) हमेशा एक जड़ है और दूसरी जड़ (a) होती है।
Login to save your score, XP, coins and progress.
Question
Hard Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
यदि (x=2), \(kx^2-6x+4=0\) की जड़ है, तो (k) का मान क्या है?
If (x=2) is a root of \(kx^2-6x+4=0\), what is (k)?
#quadratic-roots
#root-verification
#parameter
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=2), we get (4k-12+4=0). Hence (4k=8) and (k=2).
Step 2
Why this answer is correct
The correct answer is B. (2). Putting (x=2), we get (4k-12+4=0). Hence (4k=8) and (k=2).
Step 3
Exam Tip
(x=2) रखने पर (4k-12+4=0) मिलता है। इसलिए (4k=8) और (k=2)।
Login to save your score, XP, coins and progress.
Question
Medium Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30
यदि \(x^2-15x+56=0\), तो (x=7) रखने पर बायां पक्ष क्या बनेगा?
If \(x^2-15x+56=0\), what will the left side become when (x=7)?
#quadratic-equations
#substitution
#root-verification
#medium
A (0)
B (7)
C (-7)
D (14)
Explanation opens after your attempt
Step 1
Concept
\(7^2-15\cdot7+56=49-105+56=0\). If the left side becomes (0), the given value is a root.
Step 2
Why this answer is correct
The correct answer is A. (0). \(7^2-15\cdot7+56=49-105+56=0\). If the left side becomes (0), the given value is a root.
Step 3
Exam Tip
\(7^2-15\cdot7+56=49-105+56=0\) है। बायां पक्ष (0) हो तो दिया मान मूल है।
Login to save your score, XP, coins and progress.
Question
Medium Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29
यदि \(x^2-12x+35=0\), तो (x=5) रखने पर बायां पक्ष क्या बनेगा?
If \(x^2-12x+35=0\), what will the left side become when (x=5)?
#quadratic-equations
#substitution
#root-verification
#medium
A (0)
B (5)
C (-5)
D (10)
Explanation opens after your attempt
Step 1
Concept
\(5^2-12\cdot5+35=25-60+35=0\). If the left side becomes (0), the given value is a root.
Step 2
Why this answer is correct
The correct answer is A. (0). \(5^2-12\cdot5+35=25-60+35=0\). If the left side becomes (0), the given value is a root.
Step 3
Exam Tip
\(5^2-12\cdot5+35=25-60+35=0\) है। बायां पक्ष (0) हो तो दिया मान मूल है।
Login to save your score, XP, coins and progress.
Question
Medium Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28
यदि \(x^2-9x+20=0\), तो (x=4) रखने पर बायां पक्ष क्या बनेगा?
If \(x^2-9x+20=0\), what will the left side become when (x=4)?
#quadratic-equations
#substitution
#root-verification
#medium
A (0)
B (4)
C (-4)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(4^2-9\cdot4+20=16-36+20=0\). If the left side becomes (0), the given value is a root.
Step 2
Why this answer is correct
The correct answer is A. (0). \(4^2-9\cdot4+20=16-36+20=0\). If the left side becomes (0), the given value is a root.
Step 3
Exam Tip
\(4^2-9\cdot4+20=16-36+20=0\) है। यदि बायां पक्ष (0) हो तो दिया मान मूल होता है।
Login to save your score, XP, coins and progress.
Question
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30
क्या (x=0) समीकरण \(x^2+5x=0\) का मूल है?
Is (x=0) a root of \(x^2+5x=0\)?
#quadratic-equations
#root-verification
#easy
A हाँ / Yes
B नहीं / No
C केवल (x=5) मूल है / Only (x=5) is a root
D केवल (x=-5) मूल है / Only (x=-5) is a root
Explanation opens after your attempt
Correct Answer
A. हाँ / Yes
Step 1
Concept
Putting (x=0) gives \(0^2+5\cdot0=0\). Substitution is the easiest way to check a root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=0) gives \(0^2+5\cdot0=0\). Substitution is the easiest way to check a root.
Step 3
Exam Tip
(x=0) रखने पर \(0^2+5\cdot0=0\) मिलता है। मूल जांचने में प्रतिस्थापन सबसे आसान तरीका है।
Login to save your score, XP, coins and progress.
