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9 results found for "room layout" in Class 10.

Question Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक आयताकार कमरे की लंबाई चौड़ाई से (4 m) अधिक है। फर्श का क्षेत्रफल \(96 m^2\) है। कमरे की परिधि क्या है?

The length of a rectangular room is (4 m) more than its breadth. The floor area is (96 m\(^2). What is the perimeter of the room\)?

Explanation opens after your attempt
Correct Answer

B. (40 m)

Step 1

Concept

\(Let breadth be (x), then (x(x+4)=96), so (x=8) and length is (12). The perimeter is (2(8+12)=40\) m).

Step 2

Why this answer is correct

The correct answer is B. (40 m\(). Let breadth be (x), then (x(x+4)=96), so (x=8) and length is (12). The perimeter is (2(8+12)=40\) m).

Step 3

Exam Tip

चौड़ाई (x) हो, तो (x(x+4)=96), इसलिए (x=8) और लंबाई (12) है। \(परिधि (2(8+12)=40\) m) है।

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Question Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक आयताकार कमरे का क्षेत्रफल (432) है और लंबाई चौड़ाई से (6) अधिक है। कमरे की चौड़ाई क्या है?

A rectangular room has area (432) and length (6) more than breadth. What is the breadth of the room?

Explanation opens after your attempt
Correct Answer

A. (18)

Step 1

Concept

If the breadth is (x), then (x(x+6)=432). This gives (x=18).

Step 2

Why this answer is correct

The correct answer is A. (18). If the breadth is (x), then (x(x+6)=432). This gives (x=18).

Step 3

Exam Tip

यदि चौड़ाई (x) है, तो (x(x+6)=432)। इससे (x=18) मिलता है।

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Question Medium Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक आयताकार कमरे का क्षेत्रफल (300) है और लंबाई चौड़ाई से (10) अधिक है। कमरे की चौड़ाई क्या है?

A rectangular room has area (300) and length (10) more than breadth. What is the breadth of the room?

Explanation opens after your attempt
Correct Answer

A. (15)

Step 1

Concept

If the breadth is (x), then (x(x+10)=300). This gives (x=15).

Step 2

Why this answer is correct

The correct answer is A. (15). If the breadth is (x), then (x(x+10)=300). This gives (x=15).

Step 3

Exam Tip

यदि चौड़ाई (x) है, तो (x(x+10)=300)। इससे (x=15) मिलता है।

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Question Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक छात्रावास में (60) छात्रों के लिए कमरे हैं। यदि प्रत्येक कमरे में (2) छात्र अधिक रखे जाएँ, तो (5) कमरे कम चाहिए। मूल रूप से प्रत्येक कमरे में कितने छात्र रखे गए थे?

A hostel has rooms for (60) students. If (2) more students are put in each room, (5) fewer rooms are needed. How many students were originally put in each room?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

Let students per room be (x), then \(\frac{60}{x}-\frac{60}{x+2}=5\). This gives \(5x^2+10x-120=0\), so (x=4).

Step 2

Why this answer is correct

The correct answer is A. (4). Let students per room be (x), then \(\frac{60}{x}-\frac{60}{x+2}=5\). This gives \(5x^2+10x-120=0\), so (x=4).

Step 3

Exam Tip

प्रति कमरा (x) छात्र हों, तो \(\frac{60}{x}-\frac{60}{x+2}=5\)। इससे \(5x^2+10x-120=0\), इसलिए (x=4)।

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Question Easy Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक आयताकार कमरा लंबाई में चौड़ाई से (14) मीटर अधिक है और क्षेत्रफल (480) वर्ग मीटर है। चौड़ाई क्या है?

A rectangular room has length (14) m more than its breadth and area (480) square m. What is its breadth?

Explanation opens after your attempt
Correct Answer

B. (20) मीटर(20) m

Step 1

Concept

If breadth is (x), then (x(x+14)=480), giving (x=20). For area, multiply both dimensions.

Step 2

Why this answer is correct

The correct answer is B. (20) मीटर / (20) m. If breadth is (x), then (x(x+14)=480), giving (x=20). For area, multiply both dimensions.

Step 3

Exam Tip

चौड़ाई (x) हो तो (x(x+14)=480), जिससे (x=20) है। क्षेत्रफल में दोनों आयामों को गुणा करें।

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Question Easy Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक आयताकार कमरे की परिमाप (90) मीटर है और लंबाई चौड़ाई से (9) मीटर अधिक है। लंबाई क्या है?

A rectangular room has perimeter (90) m and length (9) m more than breadth. What is its length?

Explanation opens after your attempt
Correct Answer

C. (27) मीटर(27) m

Step 1

Concept

If breadth is (x), then (2(x+x+9)=90), giving (x=18) and length (27). Choose the dimension asked carefully.

Step 2

Why this answer is correct

The correct answer is C. (27) मीटर / (27) m. If breadth is (x), then (2(x+x+9)=90), giving (x=18) and length (27). Choose the dimension asked carefully.

Step 3

Exam Tip

चौड़ाई (x) हो तो (2(x+x+9)=90), जिससे (x=18) और लंबाई (27) है। पूछा गया आयाम ध्यान से चुनें।

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Question Hard Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 9

यदि मुख्य विषय और टेक्स्ट के बीच स्थान बहुत कम है तो क्या समस्या होगी?

If space between main subject and text is too little what problem occurs?

Explanation opens after your attempt
Correct Answer

A. पठनीयता और दृश्य आराम कम होगाReadability and visual rest will reduce

Step 1

Concept

Spacing makes layout clear. Exam tip: observe text image spacing.

Step 2

Why this answer is correct

The correct answer is A. पठनीयता और दृश्य आराम कम होगा / Readability and visual rest will reduce. Spacing makes layout clear. Exam tip: observe text image spacing.

Step 3

Exam Tip

अंतराल layout को साफ बनाता है। परीक्षा में text image spacing देखें।

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Question Hard Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 6

यदि किसी पेज पर सब तत्व किनारों से चिपके हैं तो कौन सी समस्या होगी?

If all elements are stuck to edges on a page what problem occurs?

Explanation opens after your attempt
Correct Answer

A. सांस लेने की जगह और संतुलन कम होगाBreathing space and balance will reduce

Step 1

Concept

Crowding at edges makes composition tight. Exam tip: remember margin and negative space.

Step 2

Why this answer is correct

The correct answer is A. सांस लेने की जगह और संतुलन कम होगा / Breathing space and balance will reduce. Crowding at edges makes composition tight. Exam tip: remember margin and negative space.

Step 3

Exam Tip

किनारों पर भीड़ से रचना तंग लगती है। परीक्षा में margin और negative space याद रखें।

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Question Medium Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 7

यदि किसी पोस्टर में टेक्स्ट और चित्र बहुत पास पास हों तो किस तत्व की समस्या है?

If text and picture are too close in a poster which element has a problem?

Explanation opens after your attempt
Correct Answer

B. स्थानSpace

Step 1

Concept

Too little space can make poster crowded and hard to read. Exam tip: observe space in poster layout.

Step 2

Why this answer is correct

The correct answer is B. स्थान / Space. Too little space can make poster crowded and hard to read. Exam tip: observe space in poster layout.

Step 3

Exam Tip

कम स्थान से पोस्टर भीड़भाड़ वाला और पढ़ने में कठिन हो सकता है। परीक्षा में poster layout में space देखें।

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