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19 results found for "rational-expression" in Class 10.

Question Expert Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 26

यदि (p) और (q) परिमेय संख्याएं हैं तथा \(p+q\sqrt{5}\) परिमेय है, तो (q) के बारे में क्या सही है?

If (p) and (q) are rational numbers and \(p+q\sqrt{5}\) is rational, what is true about (q)?

Explanation opens after your attempt
Correct Answer

A. (q=0)

Step 1

Concept

If \(q\ne0\), then \(q\sqrt{5}\) is irrational and the sum cannot be rational. In exams check the possibility of a zero coefficient.

Step 2

Why this answer is correct

The correct answer is A. (q=0). If \(q\ne0\), then \(q\sqrt{5}\) is irrational and the sum cannot be rational. In exams check the possibility of a zero coefficient.

Step 3

Exam Tip

यदि \(q\ne0\), तो \(q\sqrt{5}\) अपरिमेय होगा और योग परिमेय नहीं हो सकता। परीक्षा में शून्य गुणांक की संभावना देखें।

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Question Expert Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 26

यदि (x) अपरिमेय है, तो (\(x+\sqrt{2}\)-\(x-\sqrt{2}\)) किसके बराबर है?

If (x) is irrational, what is (\(x+\sqrt{2}\)-\(x-\sqrt{2}\)) equal to?

Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{2}\)

Step 1

Concept

The like (x) terms cancel and the value left is \(2\sqrt{2}\). In exams do not be confused by the type of number during algebraic simplification.

Step 2

Why this answer is correct

The correct answer is A. \(2\sqrt{2}\). The like (x) terms cancel and the value left is \(2\sqrt{2}\). In exams do not be confused by the type of number during algebraic simplification.

Step 3

Exam Tip

समान (x) पद कट जाते हैं और मान \(2\sqrt{2}\) बचता है। परीक्षा में बीजीय सरलीकरण में संख्या के प्रकार से भ्रमित न हों।

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Question Hard Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 28

यदि \(x=\sqrt{2}+\sqrt{5}\), तो (x) किस द्विघात समीकरण को संतुष्ट करता है?

If \(x=\sqrt{2}+\sqrt{5}\), which quadratic equation is satisfied by (x)?

Explanation opens after your attempt
Correct Answer

B. \(x^4-14x^2+9=0\)

Step 1

Concept

From \(x^2=7+2\sqrt{10}\), we get (\(x^2-7\)2=40). Hence \(x^4-14x^2+9=0\).

Step 2

Why this answer is correct

The correct answer is B. \(x^4-14x^2+9=0\). From \(x^2=7+2\sqrt{10}\), we get (\(x^2-7\)2=40). Hence \(x^4-14x^2+9=0\).

Step 3

Exam Tip

\(x^2=7+2\sqrt{10}\) से (\(x^2-7\)2=40) मिलता है। इसलिए \(x^4-14x^2+9=0\) है।

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Question Hard Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 25

कौन सा विकल्प \(8-\sqrt{m}\) को अपरिमेय बनाता है?

Which option makes \(8-\sqrt{m}\) irrational?

Explanation opens after your attempt
Correct Answer

A. (m=180)

Step 1

Concept

(180) is not a perfect square so \(\sqrt{180}\) is irrational. Subtracting an irrational from a rational gives an irrational result.

Step 2

Why this answer is correct

The correct answer is A. (m=180). (180) is not a perfect square so \(\sqrt{180}\) is irrational. Subtracting an irrational from a rational gives an irrational result.

Step 3

Exam Tip

(180) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{180}\) अपरिमेय है। परिमेय से अपरिमेय घटाने पर परिणाम अपरिमेय होता है।

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Question Medium Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 27

कौन सा विकल्प \(12-\sqrt{m}\) को परिमेय बनाता है?

Which option makes \(12-\sqrt{m}\) rational?

Explanation opens after your attempt
Correct Answer

A. (m=225)

Step 1

Concept

\(\sqrt{225}=15\) is rational so \(12-\sqrt{225}\) will be rational. The root of a perfect square is rational.

Step 2

Why this answer is correct

The correct answer is A. (m=225). \(\sqrt{225}=15\) is rational so \(12-\sqrt{225}\) will be rational. The root of a perfect square is rational.

Step 3

Exam Tip

\(\sqrt{225}=15\) परिमेय है इसलिए \(12-\sqrt{225}\) परिमेय होगा। पूर्ण वर्ग की जड़ परिमेय होती है।

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Question Medium Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 27

कौन सा विकल्प \(4+\sqrt{m}\) को अपरिमेय बनाता है?

Which option makes \(4+\sqrt{m}\) irrational?

Explanation opens after your attempt
Correct Answer

A. (m=98)

Step 1

Concept

(98) is not a perfect square so \(\sqrt{98}\) is irrational. Adding rational (4) still gives an irrational result.

Step 2

Why this answer is correct

The correct answer is A. (m=98). (98) is not a perfect square so \(\sqrt{98}\) is irrational. Adding rational (4) still gives an irrational result.

Step 3

Exam Tip

(98) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{98}\) अपरिमेय है। परिमेय संख्या (4) जोड़ने पर भी परिणाम अपरिमेय रहता है।

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Question Medium Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 26

कौन सा विकल्प \(5+\sqrt{m}\) को परिमेय बनाता है?

Which option makes \(5+\sqrt{m}\) rational?

Explanation opens after your attempt
Correct Answer

A. (m=121)

Step 1

Concept

\(\sqrt{121}=11\) is rational so \(5+\sqrt{121}\) will be rational. The root of a perfect square is rational.

Step 2

Why this answer is correct

The correct answer is A. (m=121). \(\sqrt{121}=11\) is rational so \(5+\sqrt{121}\) will be rational. The root of a perfect square is rational.

Step 3

Exam Tip

\(\sqrt{121}=11\) परिमेय है इसलिए \(5+\sqrt{121}\) परिमेय होगा। पूर्ण वर्ग वाली जड़ परिमेय होती है।

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Question Medium Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 26

कौन सा विकल्प \(9-\sqrt{m}\) को परिमेय बनाता है?

Which option makes \(9-\sqrt{m}\) rational?

Explanation opens after your attempt
Correct Answer

A. (m=100)

Step 1

Concept

\(\sqrt{100}=10\) is rational so \(9-\sqrt{100}\) will be rational. The root of a perfect square is rational.

Step 2

Why this answer is correct

The correct answer is A. (m=100). \(\sqrt{100}=10\) is rational so \(9-\sqrt{100}\) will be rational. The root of a perfect square is rational.

Step 3

Exam Tip

\(\sqrt{100}=10\) परिमेय है इसलिए \(9-\sqrt{100}\) परिमेय होगा। पूर्ण वर्ग वाली जड़ परिमेय होती है।

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Question Medium Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 26

कौन सा विकल्प \(2+\sqrt{m}\) को अपरिमेय बनाता है?

Which option makes \(2+\sqrt{m}\) irrational?

Explanation opens after your attempt
Correct Answer

A. (m=45)

Step 1

Concept

(45) is not a perfect square so \(\sqrt{45}\) is irrational. Adding rational (2) keeps it irrational.

Step 2

Why this answer is correct

The correct answer is A. (m=45). (45) is not a perfect square so \(\sqrt{45}\) is irrational. Adding rational (2) keeps it irrational.

Step 3

Exam Tip

(45) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{45}\) अपरिमेय है। परिमेय (2) जोड़ने पर परिणाम अपरिमेय रहता है।

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Question Medium Mathematics Polynomials Irrational numbers and real numbers Class 10 Level 25

यदि \(2+\sqrt{m}\) अपरिमेय है और (m) धनात्मक पूर्णांक है तो कौन सा (m) हो सकता है?

If \(2+\sqrt{m}\) is irrational and (m) is a positive integer, which (m) can be correct?

Explanation opens after your attempt
Correct Answer

A. (18)

Step 1

Concept

(18) is not a perfect square so \(\sqrt{18}\) is irrational. The roots of the other options are rational.

Step 2

Why this answer is correct

The correct answer is A. (18). (18) is not a perfect square so \(\sqrt{18}\) is irrational. The roots of the other options are rational.

Step 3

Exam Tip

(18) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{18}\) अपरिमेय है। बाकी विकल्पों की जड़ परिमेय है।

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Question Medium Mathematics Real Numbers 5: Irrational numbers Class 10 Level 15

\(\sqrt{7}+\sqrt{28}+\sqrt{63}\) की प्रकृति क्या है?

What is the nature of \(\sqrt{7}+\sqrt{28}+\sqrt{63}\)?

Explanation opens after your attempt
Correct Answer

B. अपरिमेयIrrational

Step 1

Concept

\(\sqrt{28}=2\sqrt{7}\) and \(\sqrt{63}=3\sqrt{7}\).

Step 2

Why this answer is correct

The total is \(6\sqrt{7}\), which is irrational.

Step 3

Exam Tip

Simplify an expression before deciding its nature. चरण 1: \(\sqrt{28}=2\sqrt{7}\) और \(\sqrt{63}=3\sqrt{7}\)। चरण 2: कुल योग \(6\sqrt{7}\) है, जो अपरिमेय है। चरण 3: किसी अभिव्यक्ति की प्रकृति तय करने से पहले उसे सरल करें।

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Question Medium Mathematics Real Numbers 5: Irrational numbers Class 10 Level 15

(\left\(\sqrt{11}+2\right\)2) का मान क्या है?

What is the value of (\left\(\sqrt{11}+2\right\)2)?

Explanation opens after your attempt
Correct Answer

A. \(15+4\sqrt{11}\)

Step 1

Concept

Use ((a+b)2=a-2+2ab+b-2).

Step 2

Why this answer is correct

(\(\sqrt{11}\)2+2\sqrt{11}\times2+22=11+4\sqrt{11}+4=15+4\sqrt{11}).

Step 3

Exam Tip

Forgetting the middle term (2ab) is a common mistake. चरण 1: ((a+b)2=a-2+2ab+b-2) लगाएं। चरण 2: (\(\sqrt{11}\)2+2\sqrt{11}\times2+22=11+4\sqrt{11}+4=15+4\sqrt{11})। चरण 3: मध्य पद (2ab) को भूलना सामान्य गलती है।

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Question Medium Mathematics Real Numbers 5: Irrational numbers Class 10 Level 15

यदि \(x=7+\sqrt{13}\), तो (x-7) कैसी संख्या है?

If \(x=7+\sqrt{13}\), what type of number is (x-7)?

Explanation opens after your attempt
Correct Answer

B. अपरिमेयIrrational

Step 1

Concept

(x-7=\(7+\sqrt{13}\)-7).

Step 2

Why this answer is correct

This leaves \(\sqrt{13}\), which is irrational.

Step 3

Exam Tip

In such expressions, first subtract the matching rational part. चरण 1: (x-7=\(7+\sqrt{13}\)-7) होगा। चरण 2: इससे \(\sqrt{13}\) बचता है, जो अपरिमेय है। चरण 3: ऐसी अभिव्यक्तियों में पहले समान परिमेय भाग घटाएं।

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Question Medium Mathematics Real Numbers 5: Irrational numbers Class 10 Level 14

\(\sqrt{5}+\sqrt{20}+\sqrt{45}\) की प्रकृति क्या है?

What is the nature of \(\sqrt{5}+\sqrt{20}+\sqrt{45}\)?

Explanation opens after your attempt
Correct Answer

B. अपरिमेयIrrational

Step 1

Concept

\(\sqrt{20}=2\sqrt{5}\) and \(\sqrt{45}=3\sqrt{5}\).

Step 2

Why this answer is correct

The total is \(6\sqrt{5}\), which is irrational.

Step 3

Exam Tip

Simplify an expression before deciding its nature. चरण 1: \(\sqrt{20}=2\sqrt{5}\) और \(\sqrt{45}=3\sqrt{5}\)। चरण 2: कुल योग \(6\sqrt{5}\) है, जो अपरिमेय है। चरण 3: किसी अभिव्यक्ति की प्रकृति तय करने से पहले उसे सरल करें।

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Question Medium Mathematics Real Numbers 5: Irrational numbers Class 10 Level 14

(\left\(\sqrt{7}+1\right\)2) का मान क्या है?

What is the value of (\left\(\sqrt{7}+1\right\)2)?

Explanation opens after your attempt
Correct Answer

A. \(8+2\sqrt{7}\)

Step 1

Concept

Use ((a+b)2=a-2+2ab+b-2).

Step 2

Why this answer is correct

(\(\sqrt{7}\)2+2\sqrt{7}\times1+12=7+2\sqrt{7}+1=8+2\sqrt{7}).

Step 3

Exam Tip

Forgetting the middle term (2ab) is a common mistake. चरण 1: ((a+b)2=a-2+2ab+b-2) लगाएं। चरण 2: (\(\sqrt{7}\)2+2\sqrt{7}\times1+12=7+2\sqrt{7}+1=8+2\sqrt{7})। चरण 3: मध्य पद (2ab) को भूलना सामान्य गलती है।

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Question Medium Mathematics Real Numbers 5: Irrational numbers Class 10 Level 14

यदि \(x=4+\sqrt{7}\), तो (x-4) कैसी संख्या है?

If \(x=4+\sqrt{7}\), what type of number is (x-4)?

Explanation opens after your attempt
Correct Answer

C. अपरिमेयIrrational

Step 1

Concept

(x-4=\(4+\sqrt{7}\)-4).

Step 2

Why this answer is correct

This leaves \(\sqrt{7}\), which is irrational.

Step 3

Exam Tip

First simplify the expression, then identify the nature of the number. चरण 1: (x-4=\(4+\sqrt{7}\)-4) होगा। चरण 2: इससे \(\sqrt{7}\) बचता है, जो अपरिमेय है। चरण 3: पहले अभिव्यक्ति को सरल करें, फिर संख्या की प्रकृति बताएं।

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Question Medium Mathematics Real Numbers 5: Irrational numbers Class 10 Level 13

\(\sqrt{3}+\sqrt{12}+\sqrt{27}\) की प्रकृति क्या है?

What is the nature of \(\sqrt{3}+\sqrt{12}+\sqrt{27}\)?

Explanation opens after your attempt
Correct Answer

B. अपरिमेयIrrational

Step 1

Concept

\(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\).

Step 2

Why this answer is correct

The total is \(6\sqrt{3}\), which is irrational.

Step 3

Exam Tip

Decide the nature of the number only after simplification. चरण 1: \(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\)। चरण 2: कुल योग \(6\sqrt{3}\) है, जो अपरिमेय है। चरण 3: सरलीकरण के बाद ही संख्या की प्रकृति तय करें।

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Question Medium Mathematics Real Numbers 5: Irrational numbers Class 10 Level 13

(\left\(\sqrt{5}+2\right\)2) का मान क्या है?

What is the value of (\left\(\sqrt{5}+2\right\)2)?

Explanation opens after your attempt
Correct Answer

A. \(9+4\sqrt{5}\)

Step 1

Concept

Use ((a+b)2=a-2+2ab+b-2).

Step 2

Why this answer is correct

(\(\sqrt{5}\)2+2\(\sqrt{5}\)(2)+22=5+4\sqrt{5}+4=9+4\sqrt{5}).

Step 3

Exam Tip

Missing the middle term (2ab) is a common mistake. चरण 1: ((a+b)2=a-2+2ab+b-2) लगाएं। चरण 2: (\(\sqrt{5}\)2+2\(\sqrt{5}\)(2)+22=5+4\sqrt{5}+4=9+4\sqrt{5})। चरण 3: मध्य पद (2ab) को छोड़ना सामान्य गलती है।

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Question Medium Mathematics Real Numbers 5: Irrational numbers Class 10 Level 13

यदि \(x=3+\sqrt{5}\), तो (x-3) किस प्रकार की संख्या है?

If \(x=3+\sqrt{5}\), what type of number is (x-3)?

Explanation opens after your attempt
Correct Answer

B. अपरिमेयIrrational

Step 1

Concept

(x-3=\(3+\sqrt{5}\)-3).

Step 2

Why this answer is correct

This leaves \(\sqrt{5}\), which is irrational.

Step 3

Exam Tip

Simplify the expression before deciding the nature of the number. चरण 1: (x-3=\(3+\sqrt{5}\)-3) होगा। चरण 2: इससे \(\sqrt{5}\) बचता है, जो अपरिमेय है। चरण 3: अभिव्यक्ति को सरल करके संख्या की प्रकृति तय करें।

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