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8 results found for "parametric-roots" in Class 10.

Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

(x-2-2(a+2)x+a-2+4a=0) की जड़ें कौन-सी हैं?

What are the roots of (x-2-2(a+2)x+a-2+4a=0)?

Explanation opens after your attempt
Correct Answer

A. (a) और (a+4)(a) and (a+4)

Step 1

Concept

The sum of roots is (2a+4) and the product is \(a^2+4a\). These match (a) and (a+4).

Step 2

Why this answer is correct

The correct answer is A. (a) और (a+4) / (a) and (a+4). The sum of roots is (2a+4) and the product is \(a^2+4a\). These match (a) and (a+4).

Step 3

Exam Tip

जड़ों का योग (2a+4) और गुणनफल \(a^2+4a\) है। ये (a) और (a+4) से मेल खाते हैं।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि (4x-2-(5t+3)x+t(t+3)=0) की जड़ें (t) और \(\frac{t+3}{4}\) बताई गई हैं, तो यह कथन कब सत्य है?

If the roots of (4x-2-(5t+3)x+t(t+3)=0) are said to be (t) and \(\frac{t+3}{4}\), when is this statement true?

Explanation opens after your attempt
Correct Answer

A. हर (t) के लिएFor every (t)

Step 1

Concept

The sum of these roots is \(\frac{5t+3}{4}\), and the product is (\frac{t(t+3)}{4}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) of the given equation.

Step 2

Why this answer is correct

The correct answer is A. हर (t) के लिए / For every (t). The sum of these roots is \(\frac{5t+3}{4}\), and the product is (\frac{t(t+3)}{4}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) of the given equation.

Step 3

Exam Tip

इन जड़ों का योग \(\frac{5t+3}{4}\) और गुणनफल (\frac{t(t+3)}{4}) है। ये दिए गए समीकरण के \(-\frac{b}{a}\) और \(\frac{c}{a}\) से मेल खाते हैं।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि (x-2-2(a+3)x+a-2+6a+5=0) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha-\beta\) का धनात्मक मान क्या है?

If \(\alpha,\beta\) are the roots of (x-2-2(a+3)x+a-2+6a+5=0), what is the positive value of \(\alpha-\beta\)?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

The equation becomes ((x-(a+1))(x-(a+5))=0). So the roots are (a+1) and (a+5), hence the positive difference is (4).

Step 2

Why this answer is correct

The correct answer is A. (4). The equation becomes ((x-(a+1))(x-(a+5))=0). So the roots are (a+1) and (a+5), hence the positive difference is (4).

Step 3

Exam Tip

यहाँ समीकरण ((x-(a+1))(x-(a+5))=0) बनता है। इसलिए जड़ें (a+1) और (a+5) हैं, अतः धनात्मक अंतर (4) है।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

(x-2-2(a+1)x+a-2+2a=0) की जड़ें कौन-सी हैं?

What are the roots of (x-2-2(a+1)x+a-2+2a=0)?

Explanation opens after your attempt
Correct Answer

A. (a) और (a+2)(a) and (a+2)

Step 1

Concept

The sum of roots is (2a+2) and the product is \(a^2+2a\). These match (a) and (a+2).

Step 2

Why this answer is correct

The correct answer is A. (a) और (a+2) / (a) and (a+2). The sum of roots is (2a+2) and the product is \(a^2+2a\). These match (a) and (a+2).

Step 3

Exam Tip

जड़ों का योग (2a+2) और गुणनफल \(a^2+2a\) है। ये (a) और (a+2) से मिलते हैं।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि (3x-2-(4t+2)x+t(t+2)=0) की जड़ें (t) और \(\frac{t+2}{3}\) बताई गई हैं, तो यह कथन कब सत्य है?

If the roots of (3x-2-(4t+2)x+t(t+2)=0) are said to be (t) and \(\frac{t+2}{3}\), when is this statement true?

Explanation opens after your attempt
Correct Answer

C. हर (t) परFor every (t)

Step 1

Concept

The sum of these two roots is \(\frac{4t+2}{3}\), and the product is (\frac{t(t+2)}{3}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) of the given equation.

Step 2

Why this answer is correct

The correct answer is C. हर (t) पर / For every (t). The sum of these two roots is \(\frac{4t+2}{3}\), and the product is (\frac{t(t+2)}{3}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) of the given equation.

Step 3

Exam Tip

इन दोनों जड़ों का योग \(\frac{4t+2}{3}\) और गुणनफल (\frac{t(t+2)}{3}) है। ये दिए गए समीकरण के \(-\frac{b}{a}\) और \(\frac{c}{a}\) से मेल खाते हैं।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि (x-2-(2r+5)x+\(r^2+5r+6\)=0) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha-\beta\) का धनात्मक मान क्या है?

If \(\alpha,\beta\) are the roots of (x-2-(2r+5)x+\(r^2+5r+6\)=0), what is the positive value of \(\alpha-\beta\)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

In the given equation, the sum of roots is (2r+5) and the product is (r-2+5r+6=(r+2)(r+3)). Hence the roots are (r+2) and (r+3), so the positive difference is (1).

Step 2

Why this answer is correct

The correct answer is A. (1). In the given equation, the sum of roots is (2r+5) and the product is (r-2+5r+6=(r+2)(r+3)). Hence the roots are (r+2) and (r+3), so the positive difference is (1).

Step 3

Exam Tip

दिए गए समीकरण में जड़ों का योग (2r+5) और गुणनफल (r-2+5r+6=(r+2)(r+3)) है। इसलिए जड़ें (r+2) और (r+3) हैं, अतः धनात्मक अंतर (1) है।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

(x-2-(2a+1)x+a(a+1)=0) की जड़ों के बारे में सही निष्कर्ष क्या है?

What is the correct conclusion about the roots of (x-2-(2a+1)x+a(a+1)=0)?

Explanation opens after your attempt
Correct Answer

A. जड़ें (a) और (a+1) हैंThe roots are (a) and (a+1)

Step 1

Concept

The sum of roots is (2a+1) and the product is (a(a+1)). These match the pair (a) and (a+1).

Step 2

Why this answer is correct

The correct answer is A. जड़ें (a) और (a+1) हैं / The roots are (a) and (a+1). The sum of roots is (2a+1) and the product is (a(a+1)). These match the pair (a) and (a+1).

Step 3

Exam Tip

जड़ों का योग (2a+1) और गुणनफल (a(a+1)) है। ये (a) और (a+1) की योग-गुणनफल जोड़ी से मेल खाते हैं।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि (2x-2-(3t+1)x+t-2+t=0) की जड़ें (t) और \(\frac{t+1}{2}\) हैं, तो यह कथन किसके लिए सही है?

If the roots of (2x-2-(3t+1)x+t-2+t=0) are (t) and \(\frac{t+1}{2}\), for which values is this statement true?

Explanation opens after your attempt
Correct Answer

A. हर (t) के लिएFor every (t)

Step 1

Concept

The sum is \(\frac{3t+1}{2}\) and the product is (\frac{t(t+1)}{2}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) for every (t).

Step 2

Why this answer is correct

The correct answer is A. हर (t) के लिए / For every (t). The sum is \(\frac{3t+1}{2}\) and the product is (\frac{t(t+1)}{2}). These match \(-\frac{b}{a}\) and \(\frac{c}{a}\) for every (t).

Step 3

Exam Tip

इन जड़ों का योग \(\frac{3t+1}{2}\) और गुणनफल (\frac{t(t+1)}{2}) है। ये दिए गए समीकरण के \(-\frac{b}{a}\) और \(\frac{c}{a}\) से हर (t) पर मेल खाते हैं।

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