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9 results found for "parallel distinct" in Class 10.

Question Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

किस मान पर (5x+9y=45) और (10x+18y=k) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (5x+9y=45) and (10x+18y=k) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (k=88)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=90). For (k=88), the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=88). The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=90). For (k=88), the lines are distinct and parallel.

Step 3

Exam Tip

गुणांक का अनुपात \(\frac{1}{2}\) है, इसलिए संपाती होने के लिए (k=90) चाहिए। (k=88) पर रेखाएं समांतर अलग-अलग हैं।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

किस मान पर (3x+ay=15) और (9x+12y=47) की रेखाएं समांतर अलग-अलग होंगी?

For which value will the lines (3x+ay=15) and (9x+12y=47) be distinct and parallel?

Explanation opens after your attempt
Correct Answer

C. (a=4)

Step 1

Concept

For parallel lines, \(\frac{3}{9}=\frac{a}{12}\), so (a=4). Since \(\frac{15}{47}\neq\frac{1}{3}\), they will not be coincident.

Step 2

Why this answer is correct

The correct answer is C. (a=4). For parallel lines, \(\frac{3}{9}=\frac{a}{12}\), so (a=4). Since \(\frac{15}{47}\neq\frac{1}{3}\), they will not be coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{3}{9}=\frac{a}{12}\), इसलिए (a=4)। चूंकि \(\frac{15}{47}\neq\frac{1}{3}\), वे संपाती नहीं होंगी।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

किस मान पर (3x+7y=21) और (6x+14y=k) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (3x+7y=21) and (6x+14y=k) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (k=40)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=42). For (k=40), the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=40). The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=42). For (k=40), the lines are distinct and parallel.

Step 3

Exam Tip

गुणांक का अनुपात \(\frac{1}{2}\) है, इसलिए संपाती होने के लिए (k=42) चाहिए। (k=40) पर रेखाएं समांतर अलग-अलग हैं।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

किस मान पर (4x+ay=16) और (8x+10y=35) की रेखाएं समांतर अलग-अलग होंगी?

For which value will the lines (4x+ay=16) and (8x+10y=35) be distinct and parallel?

Explanation opens after your attempt
Correct Answer

B. (a=5)

Step 1

Concept

For parallel lines, \(\frac{4}{8}=\frac{a}{10}\), so (a=5). Since \(\frac{16}{35}\neq\frac{1}{2}\), they will not be coincident.

Step 2

Why this answer is correct

The correct answer is B. (a=5). For parallel lines, \(\frac{4}{8}=\frac{a}{10}\), so (a=5). Since \(\frac{16}{35}\neq\frac{1}{2}\), they will not be coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{4}{8}=\frac{a}{10}\), इसलिए (a=5)। चूंकि \(\frac{16}{35}\neq\frac{1}{2}\), वे संपाती नहीं होंगी।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

किस मान पर (x+4y=12) और (2x+8y=k) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (x+4y=12) and (2x+8y=k) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (k=20)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=24). For (k=20), the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=20). The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=24). For (k=20), the lines are distinct and parallel.

Step 3

Exam Tip

गुणांक का अनुपात \(\frac{1}{2}\) है, इसलिए संपाती होने के लिए (k=24) चाहिए। (k=20) पर रेखाएं समांतर अलग-अलग हैं।

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Question Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

किस मान पर (2x+ay=10) और (6x+9y=31) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (2x+ay=10) and (6x+9y=31) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (a=3)

Step 1

Concept

For parallel lines, \(\frac{2}{6}=\frac{a}{9}\), so (a=3). Since \(\frac{10}{31}\neq\frac{1}{3}\), the lines are not coincident.

Step 2

Why this answer is correct

The correct answer is B. (a=3). For parallel lines, \(\frac{2}{6}=\frac{a}{9}\), so (a=3). Since \(\frac{10}{31}\neq\frac{1}{3}\), the lines are not coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{2}{6}=\frac{a}{9}\), इसलिए (a=3)। चूंकि \(\frac{10}{31}\neq\frac{1}{3}\), रेखाएं संपाती नहीं होंगी।

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Question Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

ग्राफ में रेखाएं (2x+y=7) और (6x+3y=20) कैसी होंगी?

How will the lines (2x+y=7) and (6x+3y=20) appear on a graph?

Explanation opens after your attempt
Correct Answer

B. समांतर अलग-अलगParallel distinct

Step 1

Concept

\(\frac{2}{6}=\frac{1}{3}\neq\frac{7}{20}\), so the lines are distinct and parallel. This case gives no solution.

Step 2

Why this answer is correct

The correct answer is B. समांतर अलग-अलग / Parallel distinct. \(\frac{2}{6}=\frac{1}{3}\neq\frac{7}{20}\), so the lines are distinct and parallel. This case gives no solution.

Step 3

Exam Tip

\(\frac{2}{6}=\frac{1}{3}\neq\frac{7}{20}\), इसलिए रेखाएं समांतर अलग-अलग हैं। यह स्थिति कोई समाधान नहीं देती।

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Question Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि (3x+2y=7) और (6x+4y=k) की रेखाएं समांतर अलग-अलग हों, तो (k) के लिए कौन सा विकल्प सही है?

If the lines (3x+2y=7) and (6x+4y=k) are parallel and distinct, which option is correct for (k)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

The coefficient ratio is \(\frac{3}{6}=\frac{2}{4}=\frac{1}{2}\); for coincidence, (k=14) is needed. With (k=7), the lines are parallel and distinct.

Step 2

Why this answer is correct

The correct answer is B. (7). The coefficient ratio is \(\frac{3}{6}=\frac{2}{4}=\frac{1}{2}\); for coincidence, (k=14) is needed. With (k=7), the lines are parallel and distinct.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{3}{6}=\frac{2}{4}=\frac{1}{2}\) है; संपाती होने के लिए (k=14) चाहिए। (k=7) होने पर रेखाएं समांतर अलग-अलग होंगी।

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Question Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (3x-2y=6) और (6x-4y=12) ग्राफ पर कैसी दिखेंगी?

How will the lines (3x-2y=6) and (6x-4y=12) appear on a graph?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

The second equation is (2) times the first, so both lines are the same. If one line overlaps the other, there are infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. The second equation is (2) times the first, so both lines are the same. If one line overlaps the other, there are infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं एक ही हैं। ग्राफ में एक ही रेखा दिखे तो अनंत समाधान होते हैं।

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