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2 results found for "number-825" in Class 10.

Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

किस संख्या का अभाज्य गुणनखंडन \(3\times5^2\times11\) है?

Which number has prime factorisation \(3\times5^2\times11\)?

Explanation opens after your attempt
Correct Answer

A. 825

Step 1

Concept

Calculate \(5^2=25\).

Step 2

Why this answer is correct

\(3\times25\times11=825\).

Step 3

Exam Tip

It is useful to simplify the power part first. चरण 1: \(5^2=25\) निकालें। चरण 2: \(3\times25\times11=825\)। चरण 3: घात वाले भाग को पहले सरल करना उपयोगी है।

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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 825 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 825?

Explanation opens after your attempt
Correct Answer

A. \(3\times5^2\times11\)

Step 1

Concept

Write \(825=25\times33\).

Step 2

Why this answer is correct

\(25=5^2\) and \(33=3\times11\), so \(825=3\times5^2\times11\).

Step 3

Exam Tip

Both 25 and 33 are composite, so convert them into prime form. चरण 1: \(825=25\times33\) लिखें। चरण 2: \(25=5^2\) और \(33=3\times11\), इसलिए \(825=3\times5^2\times11\)। चरण 3: 25 और 33 दोनों संयुक्त हैं, इसलिए उन्हें अभाज्य रूप में बदलें।

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