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4 results found for "number-792" in Class 10.

Question Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 79200 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 79200?

Explanation opens after your attempt
Correct Answer

A. \(2^5\times3^2\times5^2\times11\)

Step 1

Concept

Write \(79200=32\times2475\).

Step 2

Why this answer is correct

\(2475=3^2\times5^2\times11\), so \(79200=2^5\times3^2\times5^2\times11\).

Step 3

Exam Tip

Give 2475 its complete prime form. चरण 1: \(79200=32\times2475\) लिखें। चरण 2: \(2475=3^2\times5^2\times11\), इसलिए \(79200=2^5\times3^2\times5^2\times11\)। चरण 3: 2475 को पूरा अभाज्य रूप दें।

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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times11\) है?

Which number has prime factorisation \(2^3\times3^2\times11\)?

Explanation opens after your attempt
Correct Answer

A. 792

Step 1

Concept

Calculate \(2^3=8\) and \(3^2=9\).

Step 2

Why this answer is correct

\(8\times9\times11=792\).

Step 3

Exam Tip

First solve the powers, then multiply by 11. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times11=792\)। चरण 3: पहले घातों को हल करें, फिर 11 से गुणा करें।

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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times11\) है?

Which number has prime factorisation \(2^3\times3^2\times11\)?

Explanation opens after your attempt
Correct Answer

A. 792

Step 1

Concept

Calculate \(2^3=8\) and \(3^2=9\).

Step 2

Why this answer is correct

\(8\times9\times11=792\).

Step 3

Exam Tip

Solve prime powers first, then multiply. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times11=792\)। चरण 3: अभाज्य घातों को पहले हल करें, फिर गुणा करें।

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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 792 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 792?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3^2\times11\)

Step 1

Concept

Write \(792=8\times99\).

Step 2

Why this answer is correct

\(8=2^3\) and \(99=3^2\times11\), so \(792=2^3\times3^2\times11\).

Step 3

Exam Tip

Do not leave 99 in the final answer. चरण 1: \(792=8\times99\) लिखें। चरण 2: \(8=2^3\) और \(99=3^2\times11\), इसलिए \(792=2^3\times3^2\times11\)। चरण 3: 99 को अंतिम उत्तर में न छोड़ें।

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