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2 results found for "number-5544" in Class 10.

Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times7\times11\) है?

Which number has prime factorisation \(2^3\times3^2\times7\times11\)?

Explanation opens after your attempt
Correct Answer

A. 5544

Step 1

Concept

Calculate \(2^3=8\) and \(3^2=9\).

Step 2

Why this answer is correct

\(8\times9\times7\times11=5544\).

Step 3

Exam Tip

Simplify powers first and then multiply. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times7\times11=5544\)। चरण 3: घातों को पहले सरल करके गुणा करें।

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Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 5544 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 5544?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3^2\times7\times11\)

Step 1

Concept

Write \(5544=8\times693\).

Step 2

Why this answer is correct

\(8=2^3\) and \(693=3^2\times7\times11\), so \(5544=2^3\times3^2\times7\times11\).

Step 3

Exam Tip

Do not leave 693 in the final form. चरण 1: \(5544=8\times693\) लिखें। चरण 2: \(8=2^3\) और \(693=3^2\times7\times11\), इसलिए \(5544=2^3\times3^2\times7\times11\)। चरण 3: 693 को अंतिम रूप में न छोड़ें।

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