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6 results found for "number-5292" in Class 10.

Question Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस विकल्प में \(2^4\times3^3\times5^2\times7^2\) का सही मान है?

Which option gives the correct value of \(2^4\times3^3\times5^2\times7^2\)?

Explanation opens after your attempt
Correct Answer

A. 529200

Step 1

Concept

Calculate \(2^4=16\), \(3^3=27\), \(5^2=25\), and \(7^2=49\).

Step 2

Why this answer is correct

\(16\times27\times25\times49=529200\).

Step 3

Exam Tip

Do the multiplication step by step. चरण 1: \(2^4=16\), \(3^3=27\), \(5^2=25\) और \(7^2=49\) निकालें। चरण 2: \(16\times27\times25\times49=529200\)। चरण 3: गुणा को चरणों में करें।

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Question Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

यदि \(529200=2^4\times3^3\times5^2\times7^q\), तो (q) का मान क्या है?

If \(529200=2^4\times3^3\times5^2\times7^q\), what is the value of (q)?

Explanation opens after your attempt
Correct Answer

A. 2

Step 1

Concept

\(529200=16\times33075\).

Step 2

Why this answer is correct

\(33075=3^3\times5^2\times7^2\), so the power of 7 is 2.

Step 3

Exam Tip

Comparing gives (q=2). चरण 1: \(529200=16\times33075\) है। चरण 2: \(33075=3^3\times5^2\times7^2\), इसलिए 7 की घात 2 है। चरण 3: तुलना करने पर (q=2) मिलता है।

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Question Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 529200 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 529200?

Explanation opens after your attempt
Correct Answer

A. \(2^4\times3^3\times5^2\times7^2\)

Step 1

Concept

Write \(529200=16\times33075\).

Step 2

Why this answer is correct

\(33075=3^3\times5^2\times7^2\), so \(529200=2^4\times3^3\times5^2\times7^2\).

Step 3

Exam Tip

Do not leave 33075 in the final form. चरण 1: \(529200=16\times33075\) लिखें। चरण 2: \(33075=3^3\times5^2\times7^2\), इसलिए \(529200=2^4\times3^3\times5^2\times7^2\)। चरण 3: 33075 को अंतिम रूप में न छोड़ें।

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Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

संख्या 52920 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 52920?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3^3\times5\times7^2\)

Step 1

Concept

Write \(52920=8\times6615\).

Step 2

Why this answer is correct

\(6615=3^3\times5\times7^2\), so \(52920=2^3\times3^3\times5\times7^2\).

Step 3

Exam Tip

Give 6615 its complete prime form. चरण 1: \(52920=8\times6615\) लिखें। चरण 2: \(6615=3^3\times5\times7^2\), इसलिए \(52920=2^3\times3^3\times5\times7^2\)। चरण 3: 6615 को पूरा अभाज्य रूप दें।

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Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^3\times7^2\) है?

Which number has prime factorisation \(2^2\times3^3\times7^2\)?

Explanation opens after your attempt
Correct Answer

A. 5292

Step 1

Concept

Calculate \(2^2=4\), \(3^3=27\), and \(7^2=49\).

Step 2

Why this answer is correct

\(4\times27\times49=5292\).

Step 3

Exam Tip

Simplify all three powers separately. चरण 1: \(2^2=4\), \(3^3=27\) और \(7^2=49\) निकालें। चरण 2: \(4\times27\times49=5292\)। चरण 3: तीनों घातों को अलग-अलग सरल करें।

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Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

संख्या 5292 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 5292?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3^3\times7^2\)

Step 1

Concept

Write \(5292=4\times1323\).

Step 2

Why this answer is correct

\(4=2^2\) and \(1323=3^3\times7^2\), so \(5292=2^2\times3^3\times7^2\).

Step 3

Exam Tip

Convert 1323 into powers of 3 and 7. चरण 1: \(5292=4\times1323\) लिखें। चरण 2: \(4=2^2\) और \(1323=3^3\times7^2\), इसलिए \(5292=2^2\times3^3\times7^2\)। चरण 3: 1323 को 3 और 7 की घातों में बदलें।

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