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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times5\times7\times11\) है?

Which number has prime factorisation \(2^2\times3\times5\times7\times11\)?

Explanation opens after your attempt
Correct Answer

A. 4620

Step 1

Concept

Calculate \(2^2=4\).

Step 2

Why this answer is correct

\(4\times3\times5\times7\times11=4620\).

Step 3

Exam Tip

When there are many factors, multiply in pairs. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times3\times5\times7\times11=4620\)। चरण 3: कई गुणनखंड हों तो जोड़े बनाकर गुणा करें।

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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 4620 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 4620?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3\times5\times7\times11\)

Step 1

Concept

Write \(4620=42\times110\).

Step 2

Why this answer is correct

\(42=2\times3\times7\) and \(110=2\times5\times11\), so \(4620=2^2\times3\times5\times7\times11\).

Step 3

Exam Tip

Since 2 appears twice, write \(2^2\). चरण 1: \(4620=42\times110\) लिखें। चरण 2: \(42=2\times3\times7\) और \(110=2\times5\times11\), इसलिए \(4620=2^2\times3\times5\times7\times11\)। चरण 3: 2 दो बार आता है, इसलिए \(2^2\) लिखें।

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