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2 results found for "number-379080" in Class 10.

Question Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^6\times5\times13\) है?

Which number has prime factorisation \(2^3\times3^6\times5\times13\)?

Explanation opens after your attempt
Correct Answer

A. 379080

Step 1

Concept

Calculate \(2^3=8\) and \(3^6=729\).

Step 2

Why this answer is correct

\(8\times729\times5\times13=379080\).

Step 3

Exam Tip

Simplify the higher-power part first. चरण 1: \(2^3=8\) और \(3^6=729\) निकालें। चरण 2: \(8\times729\times5\times13=379080\)। चरण 3: बड़े घात वाले भाग को पहले सरल करें।

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Question Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 379080 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 379080?

Explanation opens after your attempt
Correct Answer

A. \(2^3\times3^6\times5\times13\)

Step 1

Concept

Write \(379080=8\times47385\).

Step 2

Why this answer is correct

\(8=2^3\) and \(47385=3^6\times5\times13\), so the correct form is \(2^3\times3^6\times5\times13\).

Step 3

Exam Tip

Give 47385 its complete prime form. चरण 1: \(379080=8\times47385\) लिखें। चरण 2: \(8=2^3\) और \(47385=3^6\times5\times13\), इसलिए सही रूप \(2^3\times3^6\times5\times13\) है। चरण 3: 47385 को पूरी तरह अभाज्य रूप दें।

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