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2 results found for "number-3465" in Class 10.

Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

किस संख्या का अभाज्य गुणनखंडन \(3^2\times5\times7\times11\) है?

Which number has prime factorisation \(3^2\times5\times7\times11\)?

Explanation opens after your attempt
Correct Answer

A. 3465

Step 1

Concept

Calculate \(3^2=9\).

Step 2

Why this answer is correct

\(9\times5\times7\times11=3465\).

Step 3

Exam Tip

When there are many factors, multiply in pairs. चरण 1: \(3^2=9\) निकालें। चरण 2: \(9\times5\times7\times11=3465\)। चरण 3: कई गुणनखंड हों तो जोड़े बनाकर गुणा करें।

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Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

संख्या 3465 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 3465?

Explanation opens after your attempt
Correct Answer

A. \(3^2\times5\times7\times11\)

Step 1

Concept

Write \(3465=9\times385\).

Step 2

Why this answer is correct

\(9=3^2\) and \(385=5\times7\times11\), so \(3465=3^2\times5\times7\times11\).

Step 3

Exam Tip

Give 385 its complete prime form too. चरण 1: \(3465=9\times385\) लिखें। चरण 2: \(9=3^2\) और \(385=5\times7\times11\), इसलिए \(3465=3^2\times5\times7\times11\)। चरण 3: 385 को भी पूरा अभाज्य रूप दें।

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