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2 results found for "number-2268" in Class 10.

Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3^4\times7\) है, तो वह संख्या कौन सी है?

If the prime factorisation of a number is \(2^2\times3^4\times7\), which number is it?

Explanation opens after your attempt
Correct Answer

A. 2268

Step 1

Concept

Calculate \(2^2=4\) and \(3^4=81\).

Step 2

Why this answer is correct

\(4\times81\times7=2268\).

Step 3

Exam Tip

Simplifying the higher power first is the right method. चरण 1: \(2^2=4\) और \(3^4=81\) निकालें। चरण 2: \(4\times81\times7=2268\)। चरण 3: बड़ी घात को पहले सरल करना सही तरीका है।

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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

संख्या 2268 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 2268?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3^4\times7\)

Step 1

Concept

Write \(2268=4\times567\).

Step 2

Why this answer is correct

\(4=2^2\) and \(567=3^4\times7\), so \(2268=2^2\times3^4\times7\).

Step 3

Exam Tip

Convert 567 into complete prime form. चरण 1: \(2268=4\times567\) लिखें। चरण 2: \(4=2^2\) और \(567=3^4\times7\), इसलिए \(2268=2^2\times3^4\times7\)। चरण 3: 567 को पूरा अभाज्य रूप में बदलें।

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