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2 results found for "number-21168" in Class 10.

Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस विकल्प में \(2^4\times3^3\times7^2\) का सही मान है?

Which option gives the correct value of \(2^4\times3^3\times7^2\)?

Explanation opens after your attempt
Correct Answer

A. 21168

Step 1

Concept

Calculate \(2^4=16\), \(3^3=27\), and \(7^2=49\).

Step 2

Why this answer is correct

\(16\times27\times49=21168\).

Step 3

Exam Tip

Solve all three powers separately first. चरण 1: \(2^4=16\), \(3^3=27\) और \(7^2=49\) निकालें। चरण 2: \(16\times27\times49=21168\)। चरण 3: तीनों घातों को पहले अलग-अलग हल करें।

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Question Hard Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 21168 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 21168?

Explanation opens after your attempt
Correct Answer

A. \(2^4\times3^3\times7^2\)

Step 1

Concept

Write \(21168=16\times1323\).

Step 2

Why this answer is correct

\(1323=3^3\times7^2\), so \(21168=2^4\times3^3\times7^2\).

Step 3

Exam Tip

Convert 1323 into powers of 3 and 7. चरण 1: \(21168=16\times1323\) लिखें। चरण 2: \(1323=3^3\times7^2\), इसलिए \(21168=2^4\times3^3\times7^2\)। चरण 3: 1323 को 3 और 7 की घातों में बदलें।

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