Search Class 10 Questions

2 results found for "number-1890" in Class 10.

Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

किस संख्या का अभाज्य गुणनखंडन \(2\times3^3\times5\times7\) है?

Which number has prime factorisation \(2\times3^3\times5\times7\)?

Explanation opens after your attempt
Correct Answer

A. 1890

Step 1

Concept

Calculate \(3^3=27\).

Step 2

Why this answer is correct

\(2\times27\times5\times7=1890\).

Step 3

Exam Tip

Finding the value of the power first makes calculation simple. चरण 1: \(3^3=27\) निकालें। चरण 2: \(2\times27\times5\times7=1890\)। चरण 3: घात का मान पहले निकालना गणना को सरल बनाता है।

Open Question Page
Ask Friends
Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 1890 का सही अभाज्य गुणनखंडन क्या है?

What is the correct prime factorisation of 1890?

Explanation opens after your attempt
Correct Answer

A. \(2\times3^3\times5\times7\)

Step 1

Concept

Write \(1890=27\times70\).

Step 2

Why this answer is correct

\(27=3^3\) and \(70=2\times5\times7\), so \(1890=2\times3^3\times5\times7\).

Step 3

Exam Tip

Change 27 into \(3^3\). चरण 1: \(1890=27\times70\) लिखें। चरण 2: \(27=3^3\) और \(70=2\times5\times7\), इसलिए \(1890=2\times3^3\times5\times7\)। चरण 3: 27 को \(3^3\) में बदलें।

Open Question Page
Ask Friends
Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.