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2 results found for "number-1188" in Class 10.

Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3^3\times11\) है, तो वह संख्या कौन सी है?

If the prime factorisation of a number is \(2^2\times3^3\times11\), which number is it?

Explanation opens after your attempt
Correct Answer

A. 1188

Step 1

Concept

Calculate \(2^2=4\) and \(3^3=27\).

Step 2

Why this answer is correct

\(4\times27\times11=1188\).

Step 3

Exam Tip

Finding the value of powers first is the right method. चरण 1: \(2^2=4\) और \(3^3=27\) निकालें। चरण 2: \(4\times27\times11=1188\)। चरण 3: पहले घातों का मान निकालना ठीक तरीका है।

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Question Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8

संख्या 1188 का अभाज्य गुणनखंडन कौन सा है?

Which is the prime factorisation of 1188?

Explanation opens after your attempt
Correct Answer

A. \(2^2\times3^3\times11\)

Step 1

Concept

Write \(1188=4\times297\).

Step 2

Why this answer is correct

\(4=2^2\) and \(297=3^3\times11\), so \(1188=2^2\times3^3\times11\).

Step 3

Exam Tip

Break 297 into 3 and 11 form. चरण 1: \(1188=4\times297\) लिखें। चरण 2: \(4=2^2\) और \(297=3^3\times11\), इसलिए \(1188=2^2\times3^3\times11\)। चरण 3: 297 को 3 और 11 के रूप में तोड़ें।

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