11 results found for "mixed_signs" in Class 10.
समीकरण \(x^2+2x-35=0\) के मूल कौन से हैं?
What are the roots of \(x^2+2x-35=0\)?
#roots
#factorisation
#mixed_signs
A (5) और (-7) / (5) and (-7)
B (7) और (-5) / (7) and (-5)
C (5) और (7) / (5) and (7)
D (-5) और (-7) / (-5) and (-7)
Explanation opens after your attempt
Correct Answer
A. (5) और (-7) / (5) and (-7)
Step 1
Concept
(x-2 +2x-35=(x+7)(x-5)). Therefore the roots are (-7) and (5).
Step 2
Why this answer is correct
The correct answer is A. (5) और (-7) / (5) and (-7). (x-2 +2x-35=(x+7)(x-5)). Therefore the roots are (-7) and (5).
Step 3
Exam Tip
(x-2 +2x-35=(x+7)(x-5)) है। इसलिए मूल (-7) और (5) हैं।
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किस समीकरण के मूल (3) और (-8) हैं?
Which equation has roots (3) and (-8)?
#roots
#equation_from_roots
#mixed_signs
A \(x^2+5x-24=0\)
B \(x^2-5x-24=0\)
C \(x^2+11x+24=0\)
D \(x^2-11x+24=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+5x-24=0\)
Step 1
Concept
With roots (3) and (-8), we get ((x-3)(x+8)=0). Expanding gives \(x^2+5x-24=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+5x-24=0\). With roots (3) and (-8), we get ((x-3)(x+8)=0). Expanding gives \(x^2+5x-24=0\).
Step 3
Exam Tip
मूल (3) और (-8) होने पर ((x-3)(x+8)=0) होगा। खोलने पर \(x^2+5x-24=0\) मिलता है।
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समीकरण \(x^2+x-20=0\) के मूल कौन से हैं?
What are the roots of \(x^2+x-20=0\)?
#roots
#factorisation
#mixed_signs
A (4) और (-5) / (4) and (-5)
B (5) और (-4) / (5) and (-4)
C (4) और (5) / (4) and (5)
D (-4) और (-5) / (-4) and (-5)
Explanation opens after your attempt
Correct Answer
A. (4) और (-5) / (4) and (-5)
Step 1
Concept
(x-2 +x-20=(x+5)(x-4)). Therefore the roots are (-5) and (4).
Step 2
Why this answer is correct
The correct answer is A. (4) और (-5) / (4) and (-5). (x-2 +x-20=(x+5)(x-4)). Therefore the roots are (-5) and (4).
Step 3
Exam Tip
(x-2 +x-20=(x+5)(x-4)) है। इसलिए मूल (-5) और (4) हैं।
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किस समीकरण के मूल (-3) और (6) हैं?
Which equation has roots (-3) and (6)?
#roots
#equation_from_roots
#mixed_signs
A \(x^2-3x-18=0\)
B \(x^2+3x-18=0\)
C \(x^2-9x+18=0\)
D \(x^2+9x+18=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x-18=0\)
Step 1
Concept
With roots (-3) and (6), we get ((x+3)(x-6)=0). Expanding it gives \(x^2-3x-18=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x-18=0\). With roots (-3) and (6), we get ((x+3)(x-6)=0). Expanding it gives \(x^2-3x-18=0\).
Step 3
Exam Tip
मूल (-3) और (6) होने पर ((x+3)(x-6)=0) होगा। इसे खोलने पर \(x^2-3x-18=0\) मिलता है।
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समीकरण \(x^2-2x-15=0\) के मूल कौन से हैं?
What are the roots of \(x^2-2x-15=0\)?
#roots
#factorisation
#mixed_signs
A (5) और (-3) / (5) and (-3)
B (3) और (-5) / (3) and (-5)
C (5) और (3) / (5) and (3)
D (-5) और (-3) / (-5) and (-3)
Explanation opens after your attempt
Correct Answer
A. (5) और (-3) / (5) and (-3)
Step 1
Concept
(x-2 -2x-15=(x-5)(x+3)). Therefore the roots are (5) and (-3).
Step 2
Why this answer is correct
The correct answer is A. (5) और (-3) / (5) and (-3). (x-2 -2x-15=(x-5)(x+3)). Therefore the roots are (5) and (-3).
Step 3
Exam Tip
(x-2 -2x-15=(x-5)(x+3)) है। इसलिए मूल (5) और (-3) हैं।
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समीकरण \(x^2+x-12=0\) के मूल कौन से हैं?
What are the roots of \(x^2+x-12=0\)?
#roots
#factorisation
#mixed_signs
A (3) और (-4) / (3) and (-4)
B (4) और (-3) / (4) and (-3)
C (-3) और (-4) / (-3) and (-4)
D (3) और (4) / (3) and (4)
Explanation opens after your attempt
Correct Answer
A. (3) और (-4) / (3) and (-4)
Step 1
Concept
(x-2 +x-12=(x+4)(x-3)). Therefore the roots are (-4) and (3).
Step 2
Why this answer is correct
The correct answer is A. (3) और (-4) / (3) and (-4). (x-2 +x-12=(x+4)(x-3)). Therefore the roots are (-4) and (3).
Step 3
Exam Tip
(x-2 +x-12=(x+4)(x-3)) है। इसलिए मूल (-4) और (3) हैं।
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किस समीकरण के मूल (-4) और (2) हैं?
Which equation has roots (-4) and (2)?
#roots
#equation_from_roots
#mixed_signs
A \(x^2+2x-8=0\)
B \(x^2-2x-8=0\)
C \(x^2+6x+8=0\)
D \(x^2-6x+8=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+2x-8=0\)
Step 1
Concept
With roots (-4) and (2), we get ((x+4)(x-2)=0). Expanding it gives \(x^2+2x-8=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+2x-8=0\). With roots (-4) and (2), we get ((x+4)(x-2)=0). Expanding it gives \(x^2+2x-8=0\).
Step 3
Exam Tip
मूल (-4) और (2) होने पर ((x+4)(x-2)=0) होगा। इसे खोलने पर \(x^2+2x-8=0\) मिलता है।
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समीकरण \(x^2-3x-10=0\) के मूल कौन से हैं?
What are the roots of \(x^2-3x-10=0\)?
#roots
#factorisation
#mixed_signs
A (5) और (-2) / (5) and (-2)
B (2) और (-5) / (2) and (-5)
C (-5) और (-2) / (-5) and (-2)
D (5) और (2) / (5) and (2)
Explanation opens after your attempt
Correct Answer
A. (5) और (-2) / (5) and (-2)
Step 1
Concept
(x-2 -3x-10=(x-5)(x+2)). Therefore the roots are (5) and (-2).
Step 2
Why this answer is correct
The correct answer is A. (5) और (-2) / (5) and (-2). (x-2 -3x-10=(x-5)(x+2)). Therefore the roots are (5) and (-2).
Step 3
Exam Tip
(x-2 -3x-10=(x-5)(x+2)) है। इसलिए मूल (5) और (-2) हैं।
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किस समीकरण के मूल (-2) और (6) हैं?
Which equation has roots (-2) and (6)?
#roots
#equation_from_roots
#mixed_signs
A \(x^2-4x-12=0\)
B \(x^2+4x-12=0\)
C \(x^2-8x+12=0\)
D \(x^2+8x+12=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x-12=0\)
Step 1
Concept
With roots (-2) and (6), we get ((x+2)(x-6)=0). Expanding it gives \(x^2-4x-12=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4x-12=0\). With roots (-2) and (6), we get ((x+2)(x-6)=0). Expanding it gives \(x^2-4x-12=0\).
Step 3
Exam Tip
मूल (-2) और (6) होने पर ((x+2)(x-6)=0) होगा। इसे खोलने पर \(x^2-4x-12=0\) मिलता है।
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समीकरण \(x^2+2x-8=0\) के मूल कौन से हैं?
What are the roots of \(x^2+2x-8=0\)?
#roots
#factorisation
#mixed_signs
A (4) और (-2) / (4) and (-2)
B (2) और (-4) / (2) and (-4)
C (-2) और (-4) / (-2) and (-4)
D (2) और (4) / (2) and (4)
Explanation opens after your attempt
Correct Answer
B. (2) और (-4) / (2) and (-4)
Step 1
Concept
(x-2 +2x-8=(x+4)(x-2)) so the roots are (-4) and (2). Roots have opposite signs to the factor constants.
Step 2
Why this answer is correct
The correct answer is B. (2) और (-4) / (2) and (-4). (x-2 +2x-8=(x+4)(x-2)) so the roots are (-4) and (2). Roots have opposite signs to the factor constants.
Step 3
Exam Tip
(x-2 +2x-8=(x+4)(x-2)) इसलिए मूल (-4) और (2) हैं। गुणनखंड के चिन्ह उलटकर मूल मिलते हैं।
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किस समीकरण के मूल (4) और (-1) हैं?
Which equation has roots (4) and (-1)?
#roots
#equation_from_roots
#mixed_signs
A \(x^2-3x-4=0\)
B \(x^2+3x-4=0\)
C \(x^2-5x+4=0\)
D \(x^2+x-4=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x-4=0\)
Step 1
Concept
With roots (4) and (-1) we get ((x-4)(x+1)=0). Expanding it gives \(x^2-3x-4=0\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x-4=0\). With roots (4) and (-1) we get ((x-4)(x+1)=0). Expanding it gives \(x^2-3x-4=0\).
Step 3
Exam Tip
मूल (4) और (-1) होने पर ((x-4)(x+1)=0) मिलता है। इसे खोलने पर \(x^2-3x-4=0\) है।
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