B. ( -8 ) और ( -7 ) के बीच/Between ( -8 ) and ( -7 )
Step 1
Concept
\( -\sqrt{27}\approx-5.196 \), so \( -\sqrt{27}-3\approx-8.196 \). Therefore it lies between (-9) and (-8).
Step 2
Why this answer is correct
The correct answer is B. ( -8 ) और ( -7 ) के बीच / Between ( -8 ) and ( -7 ). \( -\sqrt{27}\approx-5.196 \), so \( -\sqrt{27}-3\approx-8.196 \). Therefore it lies between (-9) and (-8).
Step 3
Exam Tip
\( -\sqrt{27}-3\approx-8.196 \) नहीं, बल्कि \( -\sqrt{27}\approx-5.196 \) होने से योग लगभग (-8.196) है। इसलिए यह (-9) और (-8) के बीच है।
\( \sqrt{39}\approx6.245 \), so \(6-\sqrt{39}\approx-0.245\). Always check the sign in root subtraction.
Step 2
Why this answer is correct
The correct answer is A. ( -1 ) और (0) के बीच / Between ( -1 ) and (0). \( \sqrt{39}\approx6.245 \), so \(6-\sqrt{39}\approx-0.245\). Always check the sign in root subtraction.
Step 3
Exam Tip
\( \sqrt{39}\approx6.245 \), इसलिए \(6-\sqrt{39}\approx-0.245\) है। घटाव वाले मूल में चिह्न जरूर जाँचें।
C. ( -7 ) और ( -6 ) के बीच/Between ( -7 ) and ( -6 )
Step 1
Concept
\( -\sqrt{18}-2\approx-6.243 \), so it lies between (-7) and (-6). Estimate negative sums carefully.
Step 2
Why this answer is correct
The correct answer is C. ( -7 ) और ( -6 ) के बीच / Between ( -7 ) and ( -6 ). \( -\sqrt{18}-2\approx-6.243 \), so it lies between (-7) and (-6). Estimate negative sums carefully.
Step 3
Exam Tip
\( -\sqrt{18}-2\approx-6.243 \), इसलिए यह (-7) और (-6) के बीच है। ऋणात्मक योगों में अनुमान सावधानी से करें।
\( \sqrt{31}\approx5.568 \), so \(5-\sqrt{31}\approx-0.568\). Always check the sign in root subtraction.
Step 2
Why this answer is correct
The correct answer is B. ( -1 ) और (0) के बीच / Between ( -1 ) and (0). \( \sqrt{31}\approx5.568 \), so \(5-\sqrt{31}\approx-0.568\). Always check the sign in root subtraction.
Step 3
Exam Tip
\( \sqrt{31}\approx5.568 \), इसलिए \(5-\sqrt{31}\approx-0.568\) है। घटाव वाले मूलों में चिह्न अवश्य जाँचें।
C. ( -5 ) और ( -4 ) के बीच/Between ( -5 ) and ( -4 )
Step 1
Concept
\( \sqrt{7}\approx2.646 \), so \(u\approx-4.646\). Therefore it lies between (-5) and (-4).
Step 2
Why this answer is correct
The correct answer is C. ( -5 ) और ( -4 ) के बीच / Between ( -5 ) and ( -4 ). \( \sqrt{7}\approx2.646 \), so \(u\approx-4.646\). Therefore it lies between (-5) and (-4).
Step 3
Exam Tip
\( \sqrt{7}\approx2.646 \), इसलिए \(u\approx-4.646\) है। अतः यह (-5) और (-4) के बीच होगा।
Since \(4<\sqrt{22}<5\), \(-1<-5+\sqrt{22}<0\). Add bounds carefully in mixed expressions.
Step 2
Why this answer is correct
The correct answer is C. ( -1 ) और (0) के बीच / Between ( -1 ) and (0). Since \(4<\sqrt{22}<5\), \(-1<-5+\sqrt{22}<0\). Add bounds carefully in mixed expressions.
Step 3
Exam Tip
\(4<\sqrt{22}<5\), इसलिए \(-1<-5+\sqrt{22}<0\)। मिश्रित अभिव्यक्ति में सीमा जोड़ें।
B. ( -6 ) और ( -5 ) के बीच/Between ( -6 ) and ( -5 )
Step 1
Concept
Since \(5<\sqrt{29}<6\), \(-6<-\sqrt{29}<-5\). For negative roots, write the reversed interval carefully.
Step 2
Why this answer is correct
The correct answer is B. ( -6 ) और ( -5 ) के बीच / Between ( -6 ) and ( -5 ). Since \(5<\sqrt{29}<6\), \(-6<-\sqrt{29}<-5\). For negative roots, write the reversed interval carefully.
Step 3
Exam Tip
क्योंकि \(5<\sqrt{29}<6\), इसलिए \(-6<-\sqrt{29}<-5\)। ऋणात्मक मूलों में क्रम उलटकर लिखें।
A. ( -3 ) और ( -2 ) के बीच/Between ( -3 ) and ( -2 )
Step 1
Concept
\( -\sqrt{2}-1\approx-2.414 \), so it lies between (-3) and (-2). Estimate negative sums carefully.
Step 2
Why this answer is correct
The correct answer is A. ( -3 ) और ( -2 ) के बीच / Between ( -3 ) and ( -2 ). \( -\sqrt{2}-1\approx-2.414 \), so it lies between (-3) and (-2). Estimate negative sums carefully.
Step 3
Exam Tip
\( -\sqrt{2}-1\approx-2.414 \), इसलिए यह (-3) और (-2) के बीच है। ऋणात्मक योगों में अनुमान सावधानी से करें।
\( \sqrt{10}\approx3.162 \), so \(2-\sqrt{10}\approx-1.162\). Estimation is important in root subtraction.
Step 2
Why this answer is correct
The correct answer is A. (-2) और (-1) के बीच / Between (-2) and (-1). \( \sqrt{10}\approx3.162 \), so \(2-\sqrt{10}\approx-1.162\). Estimation is important in root subtraction.
Step 3
Exam Tip
\( \sqrt{10}\approx3.162 \) इसलिए \(2-\sqrt{10}\approx-1.162\) है। घटाव वाले मूल में अनुमान जरूरी है।
\(x=-4+\sqrt{13}\), and \(3<\sqrt{13}<4\), so (-1<x<0). Add bounds in combined expressions.
Step 2
Why this answer is correct
The correct answer is A. (-1) और (0) के बीच / Between (-1) and (0). \(x=-4+\sqrt{13}\), and \(3<\sqrt{13}<4\), so (-1<x<0). Add bounds in combined expressions.
Step 3
Exam Tip
\(x=-4+\sqrt{13}\) और \(3<\sqrt{13}<4\), इसलिए (-1<x<0)। संयुक्त अभिव्यक्ति में सीमा जोड़ें।
\(\sqrt{5}\approx2.236\) and \(\sqrt{2}\approx1.414\), so the difference is about (0.822). Use short approximations to locate differences of irrationals.
Step 2
Why this answer is correct
The correct answer is A. ((0,1)). \(\sqrt{5}\approx2.236\) and \(\sqrt{2}\approx1.414\), so the difference is about (0.822). Use short approximations to locate differences of irrationals.
Step 3
Exam Tip
\(\sqrt{5}\approx2.236\) और \(\sqrt{2}\approx1.414\), इसलिए अंतर लगभग (0.822) है। अपरिमेयों के अंतर का स्थान निकालने के लिए छोटे अनुमान उपयोग करें।
Since \(2^2<5<3^2\), \(\sqrt{5}\) lies between (2) and (3), so \(-\sqrt{5}\) lies between (-3) and (-2). On the negative side, order reverses.
Step 2
Why this answer is correct
The correct answer is A. ((-3,-2)). Since \(2^2<5<3^2\), \(\sqrt{5}\) lies between (2) and (3), so \(-\sqrt{5}\) lies between (-3) and (-2). On the negative side, order reverses.
Step 3
Exam Tip
क्योंकि \(2^2<5<3^2\), इसलिए \(\sqrt{5}\) (2) और (3) के बीच है और ऋणात्मक मान (-3) और (-2) के बीच होगा। ऋणात्मक दिशा में क्रम उलट जाता है।
A. \(\frac{4-2\sqrt{6}}{3}<t<\frac{4+2\sqrt{6}}{3}\)
Step 1
Concept
Here (D=4(2t-1)2-4\(t^2+2\)=4\(3t^2-4t-1\)). From (D<0), the interval between the two boundary roots is obtained.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{4-2\sqrt{6}}{3}<t<\frac{4+2\sqrt{6}}{3}\). Here (D=4(2t-1)2-4\(t^2+2\)=4\(3t^2-4t-1\)). From (D<0), the interval between the two boundary roots is obtained.
Step 3
Exam Tip
यहाँ (D=4(2t-1)2-4\(t^2+2\)=4\(3t^2-4t-1\)) है। (D<0) से दिए गए दोनों मूलों के बीच का अंतराल मिलता है।
For no real roots, (D<0) is required. Here (D=4\(a^2-6a-1\)), so \(3-\sqrt{10}<a<3+\sqrt{10}\).
Step 2
Why this answer is correct
The correct answer is A. \(3-\sqrt{10}<a<3+\sqrt{10}\). For no real roots, (D<0) is required. Here (D=4\(a^2-6a-1\)), so \(3-\sqrt{10}<a<3+\sqrt{10}\).
Step 3
Exam Tip
वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (D=4\(a^2-6a-1\)), इसलिए \(3-\sqrt{10}<a<3+\sqrt{10}\)।
A. औपनिवेशिक भाषा जानने वालों को नौकरी शिक्षा और प्रशासन में लाभ मिलना/Those knowing the colonial language getting advantages in jobs education and administration
Step 1
Concept
Language could link with opportunity and power. For exams connect language policy with social hierarchy.
Step 2
Why this answer is correct
The correct answer is A. औपनिवेशिक भाषा जानने वालों को नौकरी शिक्षा और प्रशासन में लाभ मिलना / Those knowing the colonial language getting advantages in jobs education and administration. Language could link with opportunity and power. For exams connect language policy with social hierarchy.
Step 3
Exam Tip
भाषा अवसर और शक्ति से जुड़ सकती थी। परीक्षा में भाषा नीति को सामाजिक पदानुक्रम से जोड़ें।
B. क्योंकि भाषा भूमि समझ और सैन्य दबाव में असमानता हो सकती थी/Because inequality could exist in language land understanding and military pressure
Step 1
Concept
Treaties should be read not only as legal texts but in power relations. For exams use source criticism.
Step 2
Why this answer is correct
The correct answer is B. क्योंकि भाषा भूमि समझ और सैन्य दबाव में असमानता हो सकती थी / Because inequality could exist in language land understanding and military pressure. Treaties should be read not only as legal texts but in power relations. For exams use source criticism.
Step 3
Exam Tip
संधियों को केवल कानूनी पाठ नहीं बल्कि शक्ति संबंध में पढ़ना चाहिए। परीक्षा में स्रोत आलोचना करें।
A. कानून व्यवस्था घोषित होती थी पर अधिकार और दंड में नस्ली या प्रशासनिक भेद रह सकता था/Rule of law was declared but rights and punishments could remain racially or administratively unequal
Step 1
Concept
Colonial law was a tool of both control and legitimacy. For exams understand the difference between law and justice.
Step 2
Why this answer is correct
The correct answer is A. कानून व्यवस्था घोषित होती थी पर अधिकार और दंड में नस्ली या प्रशासनिक भेद रह सकता था / Rule of law was declared but rights and punishments could remain racially or administratively unequal. Colonial law was a tool of both control and legitimacy. For exams understand the difference between law and justice.
Step 3
Exam Tip
औपनिवेशिक कानून नियंत्रण और वैधता दोनों का साधन था। परीक्षा में कानून और न्याय का अंतर समझें।
A. क्योंकि राजनीतिक सत्ता परिवर्तन ने हमेशा भूमि जाति और वर्ग संबंध नहीं बदले/Because political power change did not always change land race and class relations
Step 1
Concept
Political independence was not a guarantee of social equality. For exams separate Creole leadership and social questions.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि राजनीतिक सत्ता परिवर्तन ने हमेशा भूमि जाति और वर्ग संबंध नहीं बदले / Because political power change did not always change land race and class relations. Political independence was not a guarantee of social equality. For exams separate Creole leadership and social questions.
Step 3
Exam Tip
राजनीतिक स्वतंत्रता सामाजिक समानता की गारंटी नहीं थी। परीक्षा में क्रिओल नेतृत्व और सामाजिक प्रश्न अलग रखें।
A. क्योंकि उत्पादन बढ़ा पर लाभ सभी क्षेत्रों और किसानों तक समान नहीं पहुंचा/Because production rose but benefits did not reach all regions and farmers equally
Step 1
Concept
The achievements of the Green Revolution should be understood with its limits. For exams give a balanced answer.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि उत्पादन बढ़ा पर लाभ सभी क्षेत्रों और किसानों तक समान नहीं पहुंचा / Because production rose but benefits did not reach all regions and farmers equally. The achievements of the Green Revolution should be understood with its limits. For exams give a balanced answer.
Step 3
Exam Tip
ग्रीन क्रांति की उपलब्धि के साथ उसकी सीमाएं भी समझनी चाहिए। परीक्षा में संतुलित उत्तर दें।
A. अभिजातों और आम लोगों के बीच असमानता/Inequality between aristocrats and common people
Step 1
Concept
Look at the structure of old society.
Step 2
Why this answer is correct
Aristocrats had more rights and prestige.
Step 3
Exam Tip
Nationalist and liberal ideas challenged such inequality. चरण 1: पुराने समाज की संरचना देखें। चरण 2: अभिजातों को अधिक अधिकार और प्रतिष्ठा मिली थी। चरण 3: राष्ट्रवादी और उदार विचारों ने ऐसी असमानता को चुनौती दी।
B. ( -6 ) और ( -5 ) के बीच/Between ( -6 ) and ( -5 )
Step 1
Concept
\( \sqrt{99}\approx9.95 \), so \(p\approx-5.95\). Hence it lies between (-6) and (-5).
Step 2
Why this answer is correct
The correct answer is B. ( -6 ) और ( -5 ) के बीच / Between ( -6 ) and ( -5 ). \( \sqrt{99}\approx9.95 \), so \(p\approx-5.95\). Hence it lies between (-6) and (-5).
Step 3
Exam Tip
\( \sqrt{99}\approx9.95 \), इसलिए \(p\approx-5.95\) है। अतः यह (-6) और (-5) के बीच होगा।
A. ( -6 ) और ( -5 ) के बीच/Between ( -6 ) and ( -5 )
Step 1
Concept
\( \sqrt{68}\approx8.246 \), so \(p\approx-5.246\). Hence it lies between (-6) and (-5).
Step 2
Why this answer is correct
The correct answer is A. ( -6 ) और ( -5 ) के बीच / Between ( -6 ) and ( -5 ). \( \sqrt{68}\approx8.246 \), so \(p\approx-5.246\). Hence it lies between (-6) and (-5).
Step 3
Exam Tip
\( \sqrt{68}\approx8.246 \), इसलिए \(p\approx-5.246\) है। इसलिए यह (-6) और (-5) के बीच है।
A. ( -5 ) और ( -4 ) के बीच/Between ( -5 ) and ( -4 )
Step 1
Concept
\( \sqrt{45}\approx6.708 \), so \(p\approx-4.708\). Hence it lies between (-5) and (-4).
Step 2
Why this answer is correct
The correct answer is A. ( -5 ) और ( -4 ) के बीच / Between ( -5 ) and ( -4 ). \( \sqrt{45}\approx6.708 \), so \(p\approx-4.708\). Hence it lies between (-5) and (-4).
Step 3
Exam Tip
\( \sqrt{45}\approx6.708 \), इसलिए \(p\approx-4.708\) है। इसलिए यह (-5) और (-4) के बीच है।
Since \(2=\frac{8}{4}\), the interval from (0) to (2) has (8) fourth-parts and \(\frac{7}{4}\) is at the seventh part. Use the denominator to make equal units.
Step 2
Why this answer is correct
The correct answer is A. (8) भाग / (8) parts. Since \(2=\frac{8}{4}\), the interval from (0) to (2) has (8) fourth-parts and \(\frac{7}{4}\) is at the seventh part. Use the denominator to make equal units.
Step 3
Exam Tip
क्योंकि \(2=\frac{8}{4}\), इसलिए (0) से (2) तक (8) चौथाई भाग बनेंगे और \(\frac{7}{4}\) सातवें भाग पर होगा। हर को समान इकाई बनाने में प्रयोग करें।
From (4x+6=0), \(x=-\frac{3}{2}\), which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.
Step 2
Why this answer is correct
The correct answer is A. (-2) और (-1) / (-2) and (-1). From (4x+6=0), \(x=-\frac{3}{2}\), which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.
Step 3
Exam Tip
(4x+6=0) से \(x=-\frac{3}{2}\), जो (-2) और (-1) के बीच है। परीक्षा में ऋणात्मक भिन्न का अंतराल सावधानी से पहचानें।
\(-\frac{3}{4}\) is negative and greater than (-1). In exams, show such fractions between (-1) and (0).
Step 2
Why this answer is correct
The correct answer is B. (-1) और (0) के बीच / Between (-1) and (0). \(-\frac{3}{4}\) is negative and greater than (-1). In exams, show such fractions between (-1) and (0).
Step 3
Exam Tip
\(-\frac{3}{4}\) ऋणात्मक है और (-1) से बड़ा है। परीक्षा में ऐसे भिन्न को (-1) और (0) के बीच दिखाएं।
\(-\frac{1}{4}=-0.25\), so it lies between (-1) and (0). Small negative fractions are close to (0) on the left.
Step 2
Why this answer is correct
The correct answer is A. (-1) और (0) के बीच / between (-1) and (0). \(-\frac{1}{4}=-0.25\), so it lies between (-1) and (0). Small negative fractions are close to (0) on the left.
Step 3
Exam Tip
\(-\frac{1}{4}=-0.25\), इसलिए यह (-1) और (0) के बीच है। छोटे ऋणात्मक भिन्न (0) के बाईं ओर पास होते हैं।
A. विदेशियों को स्थानीय कानून से छूट या विशेष कानूनी संरक्षण मिल सकता था/Foreigners could get exemption from local law or special legal protection
Step 1
Concept
Extraterritoriality could weaken sovereignty. For exams connect it with unequal treaties.
Step 2
Why this answer is correct
The correct answer is A. विदेशियों को स्थानीय कानून से छूट या विशेष कानूनी संरक्षण मिल सकता था / Foreigners could get exemption from local law or special legal protection. Extraterritoriality could weaken sovereignty. For exams connect it with unequal treaties.
Step 3
Exam Tip
अतिरिक्त क्षेत्राधिकार संप्रभुता को कमजोर कर सकता था। परीक्षा में असमान संधियों से जोड़ें।
A. अधिशेष उत्पादन और संपत्ति संचय/Surplus production and accumulation of property
Step 1
Concept
Surplus production increased property and division of labor. Exam tip: connect agriculture not only with food but with social change.
Step 2
Why this answer is correct
The correct answer is A. अधिशेष उत्पादन और संपत्ति संचय / Surplus production and accumulation of property. Surplus production increased property and division of labor. Exam tip: connect agriculture not only with food but with social change.
Step 3
Exam Tip
अधिशेष उत्पादन से संपत्ति और श्रम विभाजन बढ़ा। परीक्षा में कृषि को केवल भोजन नहीं बल्कि समाज परिवर्तन से जोड़ें।
D. स्थायी और अस्थायी सदस्यों की शक्ति असमानता/Power inequality between permanent and non-permanent members
Step 1
Concept
Veto power belongs only to permanent members so it shows power inequality. Exam tip: connect it with UN reform debates.
Step 2
Why this answer is correct
The correct answer is D. स्थायी और अस्थायी सदस्यों की शक्ति असमानता / Power inequality between permanent and non-permanent members. Veto power belongs only to permanent members so it shows power inequality. Exam tip: connect it with UN reform debates.
Step 3
Exam Tip
वीटो शक्ति केवल स्थायी सदस्यों को मिलती है इसलिए शक्ति असमानता दिखती है। परीक्षा में इसे संयुक्त राष्ट्र सुधार बहस से जोड़ें।
A. पहले और दूसरे एस्टेट को कई कर विशेषाधिकार मिलते थे/First and Second Estates enjoyed many tax privileges
Step 1
Concept
In the Old Regime the tax burden mainly fell on the Third Estate. For exams treat tax inequality as a major cause of the French Revolution.
Step 2
Why this answer is correct
The correct answer is A. पहले और दूसरे एस्टेट को कई कर विशेषाधिकार मिलते थे / First and Second Estates enjoyed many tax privileges. In the Old Regime the tax burden mainly fell on the Third Estate. For exams treat tax inequality as a major cause of the French Revolution.
Step 3
Exam Tip
पुराने शासन में कर भार मुख्यतः तीसरे एस्टेट पर था। परीक्षा में कर असमानता को फ्रांसीसी क्रांति का प्रमुख कारण मानें।
The AP is \(56,63,\ldots,245\) with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.
Step 2
Why this answer is correct
The correct answer is C. (4214). The AP is \(56,63,\ldots,245\) with (28) terms, and the sum is (4214). Choose the first and last multiples within the limits correctly.
Step 3
Exam Tip
श्रेढ़ी \(56,63,\ldots,245\) है जिसमें (28) पद हैं और योग (4214) है। सीमा के अंदर पहला और अंतिम गुणज सही चुनें।
Moving \( \frac{13}{6} \) to the right of (-5) gives \( -5+\frac{13}{6}=-\frac{17}{6} \). Use the given interval to choose direction.
Step 2
Why this answer is correct
The correct answer is A. \( -\frac{17}{6} \). Moving \( \frac{13}{6} \) to the right of (-5) gives \( -5+\frac{13}{6}=-\frac{17}{6} \). Use the given interval to choose direction.
Step 3
Exam Tip
(-5) से दाईं ओर \( \frac{13}{6} \) जाने पर \( -5+\frac{13}{6}=-\frac{17}{6} \) मिलता है। दिए गए अंतराल से दिशा चुनें।
\( -\frac{43}{11}\approx-3.909 \), so it lies between (-4) and (-3). Convert negative fractions to decimals.
Step 2
Why this answer is correct
The correct answer is C. ( -4 ) और ( -3 ) / ( -4 ) and ( -3 ). \( -\frac{43}{11}\approx-3.909 \), so it lies between (-4) and (-3). Convert negative fractions to decimals.
Step 3
Exam Tip
\( -\frac{43}{11}\approx-3.909 \), इसलिए यह (-4) और (-3) के बीच है। ऋणात्मक भिन्नों को दशमलव में बदलें।
Moving \( \frac{7}{5} \) to the right of (-3) gives \( -3+\frac{7}{5}=-\frac{8}{5} \). Use the given interval to choose direction.
Step 2
Why this answer is correct
The correct answer is A. \( -\frac{8}{5} \). Moving \( \frac{7}{5} \) to the right of (-3) gives \( -3+\frac{7}{5}=-\frac{8}{5} \). Use the given interval to choose direction.
Step 3
Exam Tip
(-3) से दाईं ओर \( \frac{7}{5} \) जाने पर \( -3+\frac{7}{5}=-\frac{8}{5} \) मिलता है। दिए गए अंतराल से दिशा चुनें।
\( -\frac{31}{9}\approx-3.444 \), so it lies between (-4) and (-3). Convert negative fractions to decimals.
Step 2
Why this answer is correct
The correct answer is C. ( -4 ) और ( -3 ) / ( -4 ) and ( -3 ). \( -\frac{31}{9}\approx-3.444 \), so it lies between (-4) and (-3). Convert negative fractions to decimals.
Step 3
Exam Tip
\( -\frac{31}{9}\approx-3.444 \), इसलिए यह (-4) और (-3) के बीच है। ऋणात्मक भिन्नों को दशमलव में बदलें।
\( -\sqrt{10}\approx-3.162 \) and \( -\frac{19}{6}\approx-3.167 \). (-3.20) is not between them, so recheck direction for close negative values.
Step 2
Why this answer is correct
The correct answer is A. ( -3.20 ). \( -\sqrt{10}\approx-3.162 \) and \( -\frac{19}{6}\approx-3.167 \). (-3.20) is not between them, so recheck direction for close negative values.
Step 3
Exam Tip
\( -\sqrt{10}\approx-3.162 \) और \( -\frac{19}{6}\approx-3.167 \) है। (-3.20) इनके बीच नहीं है, इसलिए निकट ऋणात्मक मानों में दिशा दोबारा जाँचें।
\( \sqrt{18}\approx4.243 \), so \(4-\sqrt{18}\approx-0.243\). The sign can change when subtracting a root.
Step 2
Why this answer is correct
The correct answer is A. ( -1 ) और (0) के बीच / Between ( -1 ) and (0). \( \sqrt{18}\approx4.243 \), so \(4-\sqrt{18}\approx-0.243\). The sign can change when subtracting a root.
Step 3
Exam Tip
\( \sqrt{18}\approx4.243 \), इसलिए \(4-\sqrt{18}\approx-0.243\)। मूल घटाने पर चिह्न बदल सकता है।
B. (0) से (1) तक (12) बराबर भागों में (11)वाँ बिंदु/The (11)th point among (12) equal parts from (0) to (1)
Step 1
Concept
\( \frac{11}{12} \) means (11) parts out of (12) equal parts. The denominator gives the number of equal parts.
Step 2
Why this answer is correct
The correct answer is B. (0) से (1) तक (12) बराबर भागों में (11)वाँ बिंदु / The (11)th point among (12) equal parts from (0) to (1). \( \frac{11}{12} \) means (11) parts out of (12) equal parts. The denominator gives the number of equal parts.
Step 3
Exam Tip
\( \frac{11}{12} \) का अर्थ (12) बराबर भागों में (11) भाग है। हर बराबर भागों की संख्या बताता है।
C. यह (-4) और (-3) के बीच है/It lies between (-4) and (-3)
Step 1
Concept
\( -\frac{19}{6}\approx-3.167 \), so it lies between (-4) and (-3). Converting a negative fraction to decimal is useful.
Step 2
Why this answer is correct
The correct answer is C. यह (-4) और (-3) के बीच है / It lies between (-4) and (-3). \( -\frac{19}{6}\approx-3.167 \), so it lies between (-4) and (-3). Converting a negative fraction to decimal is useful.
Step 3
Exam Tip
\( -\frac{19}{6}\approx-3.167 \), इसलिए यह (-4) और (-3) के बीच है। ऋणात्मक भिन्न को दशमलव में बदलना उपयोगी है।
Moving \( \frac{5}{4} \) to the right of (-2) gives \( -2+\frac{5}{4}=-\frac{3}{4} \). Use the given interval to choose the direction.
Step 2
Why this answer is correct
The correct answer is A. \( -\frac{3}{4} \). Moving \( \frac{5}{4} \) to the right of (-2) gives \( -2+\frac{5}{4}=-\frac{3}{4} \). Use the given interval to choose the direction.
Step 3
Exam Tip
(-2) से दाईं ओर \( \frac{5}{4} \) जाने पर \( -2+\frac{5}{4}=-\frac{3}{4} \) मिलता है। दिए गए अंतराल से सही दिशा चुनें।
\( \sqrt{5}\approx2.236\), so \(2-\sqrt{5}\approx-0.236\). Estimation is fastest for subtraction with roots.
Step 2
Why this answer is correct
The correct answer is A. (-1) और (0) के बीच / Between (-1) and (0). \( \sqrt{5}\approx2.236\), so \(2-\sqrt{5}\approx-0.236\). Estimation is fastest for subtraction with roots.
Step 3
Exam Tip
\( \sqrt{5}\approx2.236\), इसलिए \(2-\sqrt{5}\approx-0.236\)। घटाव वाले मूलों में अनुमान सबसे तेज होता है।
Since \(6<\sqrt{48}<7\), \(-7<-\sqrt{48}<-6\). Write the interval carefully for negative square roots.
Step 2
Why this answer is correct
The correct answer is A. (-7) और (-6) / (-7) and (-6). Since \(6<\sqrt{48}<7\), \(-7<-\sqrt{48}<-6\). Write the interval carefully for negative square roots.
Step 3
Exam Tip
\(6<\sqrt{48}<7\), इसलिए \(-7<-\sqrt{48}<-6\)। ऋणात्मक वर्गमूल में अंतराल उल्टा लिखें।
A. यह (0) से (1) तक के आठ बराबर भागों में सातवें भाग पर है/It is at the seventh of eight equal parts from (0) to (1)
Step 1
Concept
\( \frac{7}{8}\) means (7) parts out of (8) equal parts from (0) to (1). The denominator gives the number of equal parts.
Step 2
Why this answer is correct
The correct answer is A. यह (0) से (1) तक के आठ बराबर भागों में सातवें भाग पर है / It is at the seventh of eight equal parts from (0) to (1). \( \frac{7}{8}\) means (7) parts out of (8) equal parts from (0) to (1). The denominator gives the number of equal parts.
Step 3
Exam Tip
\( \frac{7}{8}\) का अर्थ (0) से (1) तक (8) बराबर भागों में (7) भाग है। हर बराबर भागों की संख्या बताता है।
Since \(6^2<37<7^2\), \(6<\sqrt{37}<7\) and \(0<\sqrt{37}-6<1\). Subtract the same number from a root interval to locate the value.
Step 2
Why this answer is correct
The correct answer is A. (0) और (1) / (0) and (1). Since \(6^2<37<7^2\), \(6<\sqrt{37}<7\) and \(0<\sqrt{37}-6<1\). Subtract the same number from a root interval to locate the value.
Step 3
Exam Tip
क्योंकि \(6^2<37<7^2\), इसलिए \(6<\sqrt{37}<7\) और \(0<\sqrt{37}-6<1\) है। वर्गमूल वाले अंतराल में समान संख्या घटाकर स्थिति पाएं।
\(\sqrt{11}\) lies between (3) and (4), so \(-\sqrt{11}\) lies between (-4) and (-3). The negative sign changes the side.
Step 2
Why this answer is correct
The correct answer is C. (-4) और (-3) / (-4) and (-3). \(\sqrt{11}\) lies between (3) and (4), so \(-\sqrt{11}\) lies between (-4) and (-3). The negative sign changes the side.
Step 3
Exam Tip
\(\sqrt{11}\) (3) और (4) के बीच है इसलिए \(-\sqrt{11}\) (-4) और (-3) के बीच होगा। ऋणात्मक चिन्ह दिशा बदल देता है।
Since \(7^2<50<8^2\), \(\sqrt{50}\) lies between (7) and (8). Use perfect squares to decide the interval.
Step 2
Why this answer is correct
The correct answer is C. (7) और (8) / (7) and (8). Since \(7^2<50<8^2\), \(\sqrt{50}\) lies between (7) and (8). Use perfect squares to decide the interval.
Step 3
Exam Tip
क्योंकि \(7^2<50<8^2\), इसलिए \(\sqrt{50}\) (7) और (8) के बीच है। पूर्ण वर्गों से अंतराल तय करें।
\(-\frac{3}{2}=-1.5\), so it lies between (-2) and (-1). In exams, the decimal form of a negative fraction helps.
Step 2
Why this answer is correct
The correct answer is B. \(-\frac{3}{2}\). \(-\frac{3}{2}=-1.5\), so it lies between (-2) and (-1). In exams, the decimal form of a negative fraction helps.
Step 3
Exam Tip
\(-\frac{3}{2}=-1.5\), इसलिए यह (-2) और (-1) के बीच है। परीक्षा में ऋणात्मक भिन्न का दशमलव रूप मदद करता है।
\(-\frac{5}{4}=-1.25\), which is to the left of (-1). In exams, convert negative fractions into decimals to check.
Step 2
Why this answer is correct
The correct answer is C. \(-\frac{5}{4}\). \(-\frac{5}{4}=-1.25\), which is to the left of (-1). In exams, convert negative fractions into decimals to check.
Step 3
Exam Tip
\(-\frac{5}{4}=-1.25\), जो (-1) से बाईं ओर है। परीक्षा में ऋणात्मक भिन्न को दशमलव में बदलकर जांच सकते हैं।
Since \(\sqrt{30}\) lies between (5) and (6), \(-\sqrt{30}\) lies between (-6) and (-5). In exams, keep the negative direction in mind.
Step 2
Why this answer is correct
The correct answer is B. (-6) और (-5) / (-6) and (-5). Since \(\sqrt{30}\) lies between (5) and (6), \(-\sqrt{30}\) lies between (-6) and (-5). In exams, keep the negative direction in mind.
Step 3
Exam Tip
क्योंकि \(\sqrt{30}\) (5) और (6) के बीच है, इसलिए \(-\sqrt{30}\) (-6) और (-5) के बीच होगा। परीक्षा में ऋणात्मक दिशा को ध्यान रखें।
Since \(5^2=25\) and \(6^2=36\), \(\sqrt{27}\) lies between (5) and (6). In exams, remember nearby perfect squares.
Step 2
Why this answer is correct
The correct answer is C. (5) और (6) / (5) and (6). Since \(5^2=25\) and \(6^2=36\), \(\sqrt{27}\) lies between (5) and (6). In exams, remember nearby perfect squares.
Step 3
Exam Tip
क्योंकि \(5^2=25\) और \(6^2=36\), इसलिए \(\sqrt{27}\) (5) और (6) के बीच है। परीक्षा में निकट पूर्ण वर्गों को याद रखें।
A. यह (-2) और (-3) के बीच है/It is between (-2) and (-3)
Step 1
Concept
\(\frac{-13}{6}\approx -2.17\), so it lies between (-3) and (-2). Intervals with negative numbers can be tricky.
Step 2
Why this answer is correct
The correct answer is A. यह (-2) और (-3) के बीच है / It is between (-2) and (-3). \(\frac{-13}{6}\approx -2.17\), so it lies between (-3) and (-2). Intervals with negative numbers can be tricky.
Step 3
Exam Tip
\(\frac{-13}{6}\approx -2.17\), इसलिए यह (-3) और (-2) के बीच है। ऋणात्मक संख्या में पूर्णांक अंतराल उलझा सकता है।
A. तीन बराबर भागों में पहला निशान/first mark among three equal parts
Step 1
Concept
For \(\frac{1}{3}\), divide (0) to (1) into (3) equal parts and take the first mark. The denominator tells the number of parts.
Step 2
Why this answer is correct
The correct answer is A. तीन बराबर भागों में पहला निशान / first mark among three equal parts. For \(\frac{1}{3}\), divide (0) to (1) into (3) equal parts and take the first mark. The denominator tells the number of parts.
Step 3
Exam Tip
\(\frac{1}{3}\) के लिए (0) से (1) तक (3) बराबर भाग करें और पहला निशान लें। हर भागों की संख्या बताता है।
The denominator of \(\frac{3}{4}\) is (4), so divide (0) to (1) into (4) equal parts. Then move (3) parts to the right.
Step 2
Why this answer is correct
The correct answer is A. (4) भाग / (4) parts. The denominator of \(\frac{3}{4}\) is (4), so divide (0) to (1) into (4) equal parts. Then move (3) parts to the right.
Step 3
Exam Tip
\(\frac{3}{4}\) में हर (4) है, इसलिए (0) से (1) को (4) बराबर भागों में बाँटते हैं। फिर (3) भाग दाईं ओर जाते हैं।
A. \(k<2-4\sqrt{3}\) या \(k>2+4\sqrt{3}\)/\(k<2-4\sqrt{3}\) or \(k>2+4\sqrt{3}\)
Step 1
Concept
Here (D=(k-2)2-48). For distinct real roots (D>0), so ((k-2)2>48).
Step 2
Why this answer is correct
The correct answer is A. \(k<2-4\sqrt{3}\) या \(k>2+4\sqrt{3}\) / \(k<2-4\sqrt{3}\) or \(k>2+4\sqrt{3}\). Here (D=(k-2)2-48). For distinct real roots (D>0), so ((k-2)2>48).
Step 3
Exam Tip
यहाँ (D=(k-2)2-48) है। असमान वास्तविक मूलों के लिए (D>0), इसलिए ((k-2)2>48)।
For real and distinct roots, (D>0) is required. From ((s-2)(s+5)>0), we get (s<-5) or (s>2).
Step 2
Why this answer is correct
The correct answer is A. (s<-5) या (s>2) / (s<-5) or (s>2). For real and distinct roots, (D>0) is required. From ((s-2)(s+5)>0), we get (s<-5) or (s>2).
Step 3
Exam Tip
वास्तविक और भिन्न मूलों के लिए (D>0) चाहिए। ((s-2)(s+5)>0) से (s<-5) या (s>2) मिलता है।
A. \(p\le -2\) या \(p\ge \frac{9}{2}\)/\(p\le -2\) or \(p\ge \frac{9}{2}\)
Step 1
Concept
For real roots, \(D\ge0\) is required. Here (D=4(p+2)(2p-9)), so \(p\le -2\) or \(p\ge \frac{9}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(p\le -2\) या \(p\ge \frac{9}{2}\) / \(p\le -2\) or \(p\ge \frac{9}{2}\). For real roots, \(D\ge0\) is required. Here (D=4(p+2)(2p-9)), so \(p\le -2\) or \(p\ge \frac{9}{2}\).
Step 3
Exam Tip
वास्तविक मूलों के लिए \(D\ge0\) चाहिए। यहाँ (D=4(p+2)(2p-9)), इसलिए \(p\le -2\) या \(p\ge \frac{9}{2}\)।
A. \(k<-1-2\sqrt{6}\) या \(k>-1+2\sqrt{6}\)/\(k<-1-2\sqrt{6}\) or \(k>-1+2\sqrt{6}\)
Step 1
Concept
Here (D=(k+1)2-24). For distinct real roots (D>0), so ((k+1)2>24).
Step 2
Why this answer is correct
The correct answer is A. \(k<-1-2\sqrt{6}\) या \(k>-1+2\sqrt{6}\) / \(k<-1-2\sqrt{6}\) or \(k>-1+2\sqrt{6}\). Here (D=(k+1)2-24). For distinct real roots (D>0), so ((k+1)2>24).
Step 3
Exam Tip
यहाँ (D=(k+1)2-24) है। असमान वास्तविक मूलों के लिए (D>0), इसलिए ((k+1)2>24)।
In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check the sign of each factor separately.
Step 2
Why this answer is correct
The correct answer is B. ऋणात्मक / Negative. In this interval the first two factors are positive and the third is negative, so the product is negative. Tip: check the sign of each factor separately.
Step 3
Exam Tip
इस अंतराल में पहले दो कारक धनात्मक और तीसरा ऋणात्मक है, इसलिए गुणनफल ऋणात्मक है। टिप: प्रत्येक कारक का चिह्न अलग जांचें।
In this interval the factor signs are (+), (+), (-), and the outside negative makes the value positive. Tip: apply the outside sign at the end.
Step 2
Why this answer is correct
The correct answer is A. ऊपर / Above. In this interval the factor signs are (+), (+), (-), and the outside negative makes the value positive. Tip: apply the outside sign at the end.
Step 3
Exam Tip
इस अंतराल में कारकों के चिह्न (+), (+), (-) हैं और बाहर का ऋण चिन्ह मान को धनात्मक बनाता है। टिप: बाहरी चिन्ह को अंत में लगाएं।
