यदि \(\sqrt{3}\) परिमेय होती, तो प्रमाण में अंततः कौन-सी असंगति मिलती?
If \(\sqrt{3}\) were rational, what inconsistency would finally appear in the proof?
Explanation opens after your attempt
Correct Answer
A. सरलतम भिन्न का अंश और हर दोनों (3) से विभाज्य हो जातेThe numerator and denominator of a lowest-form fraction would both become divisible by (3)
Concept
In the rational assumption, the fraction is in lowest form.
Why this answer is correct
The proof shows that both numerator and denominator are divisible by (3).
Exam Tip
This inconsistency shows that the assumption was false. चरण 1: परिमेय मान्यता में भिन्न सरलतम रूप में होती है। चरण 2: प्रमाण दिखाता है कि अंश और हर दोनों (3) से विभाज्य हैं। चरण 3: यह असंगति बताती है कि मान्यता गलत थी।
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