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17 results found for "fraction-conversion" in Class 10.

Question Expert Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

\(0.12\overline{45}\) को सरलतम भिन्न \(\frac{p}{q}\) में लिखने पर (q) क्या होगा?

When \(0.12\overline{45}\) is written as \(\frac{p}{q}\) in lowest form, what is (q)?

Explanation opens after your attempt
Correct Answer

C. (1100)

Step 1

Concept

\(0.124545\ldots=\frac{1245-12}{9900}=\frac{1233}{9900}=\frac{137}{1100}\). Always reduce the final fraction in mixed recurring decimals.

Step 2

Why this answer is correct

The correct answer is C. (1100). \(0.124545\ldots=\frac{1245-12}{9900}=\frac{1233}{9900}=\frac{137}{1100}\). Always reduce the final fraction in mixed recurring decimals.

Step 3

Exam Tip

\(0.124545\ldots=\frac{1245-12}{9900}=\frac{1233}{9900}=\frac{137}{1100}\) है। मिश्रित आवर्ती दशमलव में अंतिम भिन्न को अवश्य सरल करें।

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Question Expert Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

\(0.4\overline{27}\) को सरलतम भिन्न \(\frac{p}{q}\) में लिखने पर (q) क्या होगा?

When \(0.4\overline{27}\) is written as \(\frac{p}{q}\) in lowest form, what is (q)?

Explanation opens after your attempt
Correct Answer

B. (110)

Step 1

Concept

\(0.4272727\ldots=\frac{423}{990}=\frac{47}{110}\), so the denominator is (110). In mixed recurring decimals, the final fraction must be reduced.

Step 2

Why this answer is correct

The correct answer is B. (110). \(0.4272727\ldots=\frac{423}{990}=\frac{47}{110}\), so the denominator is (110). In mixed recurring decimals, the final fraction must be reduced.

Step 3

Exam Tip

\(0.4272727\ldots=\frac{423}{990}=\frac{47}{110}\) है इसलिए हर (110) है। मिश्रित आवर्ती दशमलव में अंतिम भिन्न को सरल करना जरूरी है।

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Question Expert Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 20

\(0.0\overline{125}\) को सरलतम भिन्न \(\frac{p}{q}\) में लिखने पर (q) क्या होगा?

When \(0.0\overline{125}\) is written as \(\frac{p}{q}\) in lowest form, what is (q)?

Explanation opens after your attempt
Correct Answer

B. (1998)

Step 1

Concept

One non-repeating zero and three repeating digits give \(\frac{125}{9990}\), which reduces to \(\frac{25}{1998}\). In mixed recurring decimals, do not treat the first denominator as the final one.

Step 2

Why this answer is correct

The correct answer is B. (1998). One non-repeating zero and three repeating digits give \(\frac{125}{9990}\), which reduces to \(\frac{25}{1998}\). In mixed recurring decimals, do not treat the first denominator as the final one.

Step 3

Exam Tip

एक अनावर्ती शून्य और तीन आवर्ती अंकों से \(\frac{125}{9990}\) बनता है, जो \(\frac{25}{1998}\) तक सरल होता है। मिश्रित आवर्ती दशमलव में पहले बना हर अंतिम हर नहीं मानें।

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Question Expert Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 20

\(0.\overline{045}\) का सरलतम भिन्न रूप कौन-सा है?

Which is the lowest fraction form of \(0.\overline{045}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{5}{111}\)

Step 1

Concept

\(0.\overline{045}=\frac{45}{999}\), and reducing by (9) gives \(\frac{5}{111}\). First form the denominator with (9)'s according to the repeating digits.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{5}{111}\). \(0.\overline{045}=\frac{45}{999}\), and reducing by (9) gives \(\frac{5}{111}\). First form the denominator with (9)'s according to the repeating digits.

Step 3

Exam Tip

\(0.\overline{045}=\frac{45}{999}\) और (9) से सरल करने पर \(\frac{5}{111}\) मिलता है। आवर्ती अंकों की संख्या के अनुसार पहले (9) वाला हर बनाएं।

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Question Expert Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 20

\(0.2\overline{54}\) को सरलतम भिन्न \(\frac{p}{q}\) में लिखने पर (q) क्या होगा?

When \(0.2\overline{54}\) is written as \(\frac{p}{q}\) in lowest form, what is (q)?

Explanation opens after your attempt
Correct Answer

A. (110)

Step 1

Concept

\(0.254545\ldots=\frac{252}{990}=\frac{14}{55}\), so the denominator is (55). In such questions, reduce the final fraction fully.

Step 2

Why this answer is correct

The correct answer is A. (110). \(0.254545\ldots=\frac{252}{990}=\frac{14}{55}\), so the denominator is (55). In such questions, reduce the final fraction fully.

Step 3

Exam Tip

\(0.254545\ldots=\frac{252}{990}=\frac{14}{55}\) है इसलिए हर (55) है। ऐसे प्रश्न में अंतिम भिन्न को सरल करना जरूरी है।

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Question Expert Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 19

\(0.3\overline{18}\) को सरलतम भिन्न \(\frac{p}{q}\) में लिखने पर (q) क्या होगा?

When \(0.3\overline{18}\) is written as \(\frac{p}{q}\) in lowest form, what is (q)?

Explanation opens after your attempt
Correct Answer

A. (110)

Step 1

Concept

Taking \(x=0.31818\ldots\), subtracting (10x) from (1000x) gives \(\frac{315}{990}=\frac{7}{22}\). The reduced denominator is (22), so none of the listed denominators is correct.

Step 2

Why this answer is correct

The correct answer is A. (110). Taking \(x=0.31818\ldots\), subtracting (10x) from (1000x) gives \(\frac{315}{990}=\frac{7}{22}\). The reduced denominator is (22), so none of the listed denominators is correct.

Step 3

Exam Tip

\(x=0.31818\ldots\) लेने पर (10x) और (1000x) घटाने से \(\frac{315}{990}=\frac{7}{22}\) मिलता है। सरलतम हर (22) है, इसलिए दिए विकल्पों में सही हर नहीं है।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

\(0.02\overline{7}\) को सरलतम भिन्न \(\frac{p}{q}\) में लिखने पर (q) क्या होगा?

When \(0.02\overline{7}\) is written as \(\frac{p}{q}\) in lowest form, what is (q)?

Explanation opens after your attempt
Correct Answer

A. (36)

Step 1

Concept

Let \(x=0.027777\ldots\).

Step 2

Why this answer is correct

\(100x=2.7777\ldots\) and \(1000x=27.7777\ldots\), so (900x=25) and \(x=\frac{25}{900}=\frac{1}{36}\).

Step 3

Exam Tip

For a mixed recurring decimal, separate the non-repeating and repeating parts before multiplying. चरण 1: मान लें \(x=0.027777\ldots\)। चरण 2: \(100x=2.7777\ldots\) और \(1000x=27.7777\ldots\), इसलिए (900x=25) और \(x=\frac{25}{900}=\frac{1}{36}\)। चरण 3: मिश्रित आवर्ती दशमलव में अनावर्ती और आवर्ती भाग को अलग करके गुणा करें।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

यदि \(0.00\overline{45}\) को सरलतम भिन्न \(\frac{p}{q}\) में लिखा जाए, तो (q) क्या होगा?

If \(0.00\overline{45}\) is written as \(\frac{p}{q}\) in lowest form, what is (q)?

Explanation opens after your attempt
Correct Answer

D. (2200)

Step 1

Concept

\(0.00\overline{45}=0.00454545\ldots\).

Step 2

Why this answer is correct

It equals \(\frac{45}{9900}=\frac{1}{220}\). So the denominator is (220).

Step 3

Exam Tip

Choose the denominator only after reducing. चरण 1: \(0.00\overline{45}=0.00454545\ldots\) है। चरण 2: यह \(\frac{45}{9900}=\frac{1}{220}\) होता है। इसलिए हर (220) है। चरण 3: सरल करने के बाद ही हर चुनें।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

\(2.4\overline{6}\) को सरलतम भिन्न में लिखने पर हर क्या होगा?

What is the denominator when \(2.4\overline{6}\) is written as a fraction in lowest form?

Explanation opens after your attempt
Correct Answer

A. (15)

Step 1

Concept

Let \(x=2.4666\ldots\).

Step 2

Why this answer is correct

\(10x=24.666\ldots\) and \(100x=246.666\ldots\), so (90x=222) and \(x=\frac{222}{90}=\frac{37}{15}\).

Step 3

Exam Tip

Align the recurring parts before subtracting. चरण 1: मान लें \(x=2.4666\ldots\)। चरण 2: \(10x=24.666\ldots\) और \(100x=246.666\ldots\), इसलिए (90x=222) और \(x=\frac{222}{90}=\frac{37}{15}\)। चरण 3: घटाने से पहले आवर्ती भाग को एक जैसी स्थिति में लाएँ।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

\(0.\overline{36}\) को सरलतम रूप में लिखने पर हर क्या होगा?

What is the denominator when \(0.\overline{36}\) is written in lowest form?

Explanation opens after your attempt
Correct Answer

B. (11)

Step 1

Concept

\(0.\overline{36}=\frac{36}{99}\).

Step 2

Why this answer is correct

\(\frac{36}{99}=\frac{4}{11}\), so the reduced denominator is (11).

Step 3

Exam Tip

For a purely recurring decimal, first use a denominator of (9)'s and then reduce. चरण 1: \(0.\overline{36}=\frac{36}{99}\) है। चरण 2: \(\frac{36}{99}=\frac{4}{11}\), इसलिए सरलतम हर (11) है। चरण 3: पूर्ण आवर्ती दशमलव में पहले (9) वाला हर बनाइए, फिर सरल कीजिए।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

\(0.1\overline{24}\) को सरलतम भिन्न \(\frac{p}{q}\) में लिखने पर (q) क्या होगा?

When \(0.1\overline{24}\) is written as \(\frac{p}{q}\) in lowest form, what is (q)?

Explanation opens after your attempt
Correct Answer

A. (330)

Step 1

Concept

Let \(x=0.1242424\ldots\).

Step 2

Why this answer is correct

\(10x=1.242424\ldots\) and \(1000x=124.242424\ldots\), so (990x=123) and \(x=\frac{123}{990}=\frac{41}{330}\).

Step 3

Exam Tip

First identify the lengths of the non-repeating and repeating parts. चरण 1: मान लें \(x=0.1242424\ldots\)। चरण 2: \(10x=1.242424\ldots\) और \(1000x=124.242424\ldots\), इसलिए (990x=123) और \(x=\frac{123}{990}=\frac{41}{330}\)। चरण 3: पहले सांत भाग और आवर्ती भाग की लंबाई पहचानें।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 20

\(2.37\overline{5}\) को भिन्न में बदलने के लिए कौन-सा समीकरण-जोड़ा सबसे उपयुक्त है?

Which pair of equations is most suitable for converting \(2.37\overline{5}\) into a fraction?

Explanation opens after your attempt
Correct Answer

A. \(100x=237.555\ldots\), \(1000x=2375.555\ldots\)

Step 1

Concept

In \(x=2.37555\ldots\), (37) is the non-repeating part and (5) is repeating.

Step 2

Why this answer is correct

Taking (100x) and (1000x) aligns the repeating parts. Subtracting then gives the fraction.

Step 3

Exam Tip

First note the length of the non-repeating part and then the repeating part. चरण 1: \(x=2.37555\ldots\) में दशमलव के बाद (37) सांत भाग है और (5) आवर्ती है। चरण 2: (100x) और (1000x) लेने से आवर्ती भाग एक जैसी स्थिति में आ जाता है। फिर घटाने से भिन्न मिलती है। चरण 3: पहले सांत भाग की लंबाई और फिर आवर्ती भाग की लंबाई देखें।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 20

\(0.\overline{09}\) को सरलतम भिन्न में लिखने पर हर क्या होगा?

What is the denominator when \(0.\overline{09}\) is written as a fraction in lowest form?

Explanation opens after your attempt
Correct Answer

B. (11)

Step 1

Concept

\(0.\overline{09}=\frac{09}{99}=\frac{9}{99}\).

Step 2

Why this answer is correct

\(\frac{9}{99}=\frac{1}{11}\), so the reduced denominator is (11).

Step 3

Exam Tip

If a zero is part of the repeating block, count it as a digit. चरण 1: \(0.\overline{09}=\frac{09}{99}=\frac{9}{99}\) है। चरण 2: \(\frac{9}{99}=\frac{1}{11}\), इसलिए सरलतम हर (11) है। चरण 3: आवर्ती भाग में शून्य हो तो भी उसे अंकों में गिनें।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 20

\(0.00\overline{27}\) को सरलतम भिन्न \(\frac{p}{q}\) में लिखने पर (q) क्या होगा?

When \(0.00\overline{27}\) is written as a fraction \(\frac{p}{q}\) in lowest form, what is (q)?

Explanation opens after your attempt
Correct Answer

B. (1100)

Step 1

Concept

\(0.00\overline{27}=0.00272727\ldots\).

Step 2

Why this answer is correct

Converting gives \(\frac{27}{9900}=\frac{3}{1100}\). Hence (q=1100).

Step 3

Exam Tip

Include the zeros before the repeating block carefully in the denominator. चरण 1: \(0.00\overline{27}=0.00272727\ldots\) है। चरण 2: इसे भिन्न में बदलने पर \(\frac{27}{9900}=\frac{3}{1100}\) मिलता है। इसलिए (q=1100)। चरण 3: आवर्ती भाग से पहले आए शून्यों को हर में ध्यान से शामिल करें।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 19

\(0.2\overline{18}\) को भिन्न में बदलने के लिए कौन-सा समीकरण-जोड़ा सबसे उपयुक्त है?

Which pair of equations is most suitable for converting \(0.2\overline{18}\) into a fraction?

Explanation opens after your attempt
Correct Answer

A. \(10x=2.1818\ldots\), \(1000x=218.1818\ldots\)

Step 1

Concept

In \(x=0.21818\ldots\), the non-repeating part is (2) and the repeating part is (18).

Step 2

Why this answer is correct

First use \(10x=2.1818\ldots\), then \(1000x=218.1818\ldots\) so the recurring parts align.

Step 3

Exam Tip

Choose powers of (10) based on the lengths of the non-repeating and repeating parts. चरण 1: \(x=0.21818\ldots\) में पहले (2) सांत भाग है और (18) आवर्ती भाग है। चरण 2: पहले \(10x=2.1818\ldots\) से आवर्ती भाग दशमलव के तुरंत बाद आता है, फिर \(1000x=218.1818\ldots\) से वही आवर्ती भाग मिलाया जाता है। चरण 3: सांत भाग के अंकों और आवर्ती भाग के अंकों के अनुसार (10) की घात चुनें।

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Question Hard Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 19

\(0.12\overline{3}\) का परिमेय रूप किसके बराबर है?

Which rational form is equal to \(0.12\overline{3}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{37}{300}\)

Step 1

Concept

Let \(x=0.12333\ldots\).

Step 2

Why this answer is correct

Then \(100x=12.333\ldots\) and \(1000x=123.333\ldots\). Subtracting gives (900x=111), so \(x=\frac{111}{900}=\frac{37}{300}\).

Step 3

Exam Tip

Separate the non-repeating and repeating parts before multiplying. चरण 1: मान लें \(x=0.12333\ldots\)। चरण 2: \(100x=12.333\ldots\) और \(1000x=123.333\ldots\)। घटाने पर (900x=111), इसलिए \(x=\frac{111}{900}=\frac{37}{300}\)। चरण 3: सांत और आवर्ती भाग अलग-अलग देखकर गुणा करें।

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Question Medium Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 19

\(0.12\overline{3}\) को सरल भिन्न के रूप में लिखिए।

Write \(0.12\overline{3}\) as a fraction in simplest form.

Explanation opens after your attempt
Correct Answer

A. \(\frac{37}{300}\)

Step 1

Concept

In \(0.12\overline{3}=0.123333\ldots\), (12) is the non-repeating part and (3) is the repeating part.

Step 2

Why this answer is correct

The fraction is \(\frac{123-12}{900}=\frac{111}{900}=\frac{37}{300}\).

Step 3

Exam Tip

Exam tip: Identify the non-repeating and repeating parts before placing (9) and (0) in the denominator. चरण 1: \(0.12\overline{3}=0.123333\ldots\) में (12) स्थिर भाग है और (3) आवर्ती भाग है। चरण 2: भिन्न \(\frac{123-12}{900}=\frac{111}{900}=\frac{37}{300}\) मिलेगी। चरण 3: परीक्षा सुझाव: स्थिर और आवर्ती भाग अलग पहचानकर ही हर में (9) और (0) लगाएं।

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