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Question Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

किस विकल्प में (990) का सही अभाज्य गुणनखंडन है?

Which option gives the correct prime factorisation of (990)?

Explanation opens after your attempt
Correct Answer

A. \(2\times3^2\times5\times11\)

Step 1

Concept

Write \(990=99\times10\).

Step 2

Why this answer is correct

\(99=3^2\times11\) and \(10=2\times5\), so \(990=2\times3^2\times5\times11\).

Step 3

Exam Tip

Split the number into easy parts for faster factorisation. चरण 1: \(990=99\times10\) लिखा जा सकता है। चरण 2: \(99=3^2\times11\) और \(10=2\times5\), इसलिए \(990=2\times3^2\times5\times11\)। चरण 3: संख्या को आसान भागों में तोड़ना तेज तरीका है।

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