100 results found for "degree-to-radian-factor" in Class 10.
यदि अशून्य बहुपद (p(x)) की घात (6) और (q(x)) की घात (3) है, तो (p(x)q(x)) की घात क्या होगी?
If non-zero polynomial (p(x)) has degree (6) and (q(x)) has degree (3), what will be the degree of (p(x)q(x))?
#degree
#product
#polynomial
A (3)
B (6)
C (9)
D (18)
Explanation opens after your attempt
Step 1
Concept
In the product of two non-zero polynomials, degrees add, so (6+3=9). In multiplication, look at the highest-power terms.
Step 2
Why this answer is correct
The correct answer is C. (9). In the product of two non-zero polynomials, degrees add, so (6+3=9). In multiplication, look at the highest-power terms.
Step 3
Exam Tip
दो अशून्य बहुपदों के गुणन में घातें जुड़ती हैं, इसलिए (6+3=9)। गुणन में उच्चतम घातों का गुणन देखें।
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यदि (p(x)) की घात (5) और (q(x)) की घात (2) है, तो अशून्य (p(x)q(x)) की घात क्या होगी?
If the degree of (p(x)) is (5) and the degree of (q(x)) is (2), what is the degree of non-zero (p(x)q(x))?
#degree
#product
#polynomial
A (3)
B (5)
C (7)
D (10)
Explanation opens after your attempt
Step 1
Concept
In the product of two non-zero polynomials, degrees add, so (5+2=7). Remember degree addition in multiplication.
Step 2
Why this answer is correct
The correct answer is C. (7). In the product of two non-zero polynomials, degrees add, so (5+2=7). Remember degree addition in multiplication.
Step 3
Exam Tip
दो अशून्य बहुपदों के गुणन में घातें जुड़ती हैं, इसलिए (5+2=7)। गुणन में घातों का योग याद रखें।
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यदि (p(x)) की घात (4) और (q(x)) की घात (3) है, तो सामान्यतः (p(x)q(x)) की घात क्या होगी?
If the degree of (p(x)) is (4) and the degree of (q(x)) is (3), what will generally be the degree of (p(x)q(x))?
#degree
#product
#polynomial
A (1)
B (7)
C (12)
D (4)
Explanation opens after your attempt
Step 1
Concept
In the product of two non-zero polynomials, degrees add, so (4+3=7). Remember degree addition in multiplication.
Step 2
Why this answer is correct
The correct answer is B. (7). In the product of two non-zero polynomials, degrees add, so (4+3=7). Remember degree addition in multiplication.
Step 3
Exam Tip
दो अशून्य बहुपदों के गुणन में घातें जुड़ती हैं, इसलिए (4+3=7)। गुणन में घातों का योग याद रखें।
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एक छात्र \(x^2+2x+1\) की घात (3) बताता है क्योंकि इसमें (3) पद हैं। सही घात क्या है?
A student says the degree of \(x^2+2x+1\) is (3) because it has (3) terms. What is the correct degree?
#polynomials
#common-mistake
#degree
#easy
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Degree is decided by the highest power (2), not by the number of terms. Avoid this common exam mistake.
Step 2
Why this answer is correct
The correct answer is B. (2). Degree is decided by the highest power (2), not by the number of terms. Avoid this common exam mistake.
Step 3
Exam Tip
घात पदों की संख्या से नहीं, सबसे बड़ी घात (2) से तय होती है। यह सामान्य गलती परीक्षा में न करें।
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यदि (p(x)=(k-3)x-5 +2x-3 -x+9) की घात (3) है, तो (k) क्या है?
If (p(x)=(k-3)x-5 +2x-3 -x+9) has degree (3), what is (k)?
#degree
#parameter
#polynomial
A (3)
B (0)
C (2)
D (5)
Explanation opens after your attempt
Step 1
Concept
For degree (3), the coefficient of \(x^5\) must be (0). Thus (k-3=0) and (k=3).
Step 2
Why this answer is correct
The correct answer is A. (3). For degree (3), the coefficient of \(x^5\) must be (0). Thus (k-3=0) and (k=3).
Step 3
Exam Tip
घात (3) होने के लिए \(x^5\) का गुणांक (0) होना चाहिए। इसलिए (k-3=0) और (k=3)।
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यदि (p(x)=mx-5 +(m-4 )x-4 +3x-2 +1) की घात (4) है, तो (m) क्या है?
If the degree of (p(x)=mx-5 +(m-4 )x-4 +3x-2 +1) is (4), what is (m)?
#degree
#parameter
#conditions
A (0)
B (2)
C (4)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
For degree (4), the coefficient of \(x^5\) must be (0) and the coefficient of \(x^4\) must be non-zero. For (m=0), (m-4 =-4).
Step 2
Why this answer is correct
The correct answer is A. (0). For degree (4), the coefficient of \(x^5\) must be (0) and the coefficient of \(x^4\) must be non-zero. For (m=0), (m-4 =-4).
Step 3
Exam Tip
घात (4) के लिए \(x^5\) का गुणांक (0) और \(x^4\) का गुणांक अशून्य चाहिए। (m=0) पर (m-4 =-4) है।
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यदि (p(x)=ax-5 +bx-4 +cx-3 +d) में (a=0), \(b\ne0\) और \(c\ne0\), तो (p(x)) की घात क्या होगी?
If (a=0), \(b\ne0\), and \(c\ne0\) in (p(x)=ax-5 +bx-4 +cx-3 +d), what will be the degree of (p(x))?
#degree
#general polynomial
#conditions
A (3)
B (4)
C (5)
D निर्भर नहीं / Not dependent
Explanation opens after your attempt
Step 1
Concept
Since (a=0), the \(x^5\)-term vanishes, and since \(b\ne0\), the \(x^4\)-term remains. So the degree is (4).
Step 2
Why this answer is correct
The correct answer is B. (4). Since (a=0), the \(x^5\)-term vanishes, and since \(b\ne0\), the \(x^4\)-term remains. So the degree is (4).
Step 3
Exam Tip
(a=0) से \(x^5\) पद हट जाता है और \(b\ne0\) से \(x^4\) पद बचता है। इसलिए घात (4) है।
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(p(x)=6x-5 -4x-2 +1) और (q(x)=-6x-5 +3x-4 +x-9) के योग की घात क्या है?
What is the degree of the sum of (p(x)=6x-5 -4x-2 +1) and (q(x)=-6x-5 +3x-4 +x-9)?
#degree
#cancellation
#addition
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
The \(x^5\)-terms cancel and the highest remaining power is (4). Recheck the degree of the polynomial after addition.
Step 2
Why this answer is correct
The correct answer is C. (4). The \(x^5\)-terms cancel and the highest remaining power is (4). Recheck the degree of the polynomial after addition.
Step 3
Exam Tip
\(x^5\) के पद कट जाते हैं और सबसे बड़ी बची घात (4) है। जोड़ के बाद बहुपद की घात फिर से जांचें।
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यदि (p(x)=(a-1)x-6 +(a+2)x-4 -5x+7) की घात (4) है, तो (a) क्या होगा?
If the degree of (p(x)=(a-1)x-6 +(a+2)x-4 -5x+7) is (4), what will (a) be?
#degree
#parameter
#polynomial
A (-2)
B (1)
C (2)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
For degree (4), the coefficient of \(x^6\) must be (0) and the coefficient of \(x^4\) must be non-zero. Both conditions hold for (a=1).
Step 2
Why this answer is correct
The correct answer is B. (1). For degree (4), the coefficient of \(x^6\) must be (0) and the coefficient of \(x^4\) must be non-zero. Both conditions hold for (a=1).
Step 3
Exam Tip
घात (4) के लिए \(x^6\) का गुणांक (0) और \(x^4\) का गुणांक अशून्य चाहिए। (a=1) पर दोनों शर्तें पूरी होती हैं।
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किस मान के लिए (p(x)=(m-2 )x-4 +3x-2 +x+1) की घात (2) से अधिक नहीं होगी?
For which value will (p(x)=(m-2 )x-4 +3x-2 +x+1) have degree not more than (2)?
#degree
#parameter
#polynomial
A (m=2)
B (m=0)
C (m=1)
D (m=-2)
Explanation opens after your attempt
Step 1
Concept
To make the degree not more than (2), the coefficient of \(x^4\) must be (0), so (m-2 =0). Degree reduces only when the highest term vanishes.
Step 2
Why this answer is correct
The correct answer is A. (m=2). To make the degree not more than (2), the coefficient of \(x^4\) must be (0), so (m-2 =0). Degree reduces only when the highest term vanishes.
Step 3
Exam Tip
घात (2) से अधिक न हो इसके लिए \(x^4\) का गुणांक (0) चाहिए, अतः (m-2 =0)। उच्चतम पद हटाकर ही घात घटती है।
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यदि (p(x)=x-4 -5x-2 +4) है, तो (p(x)) का घात कितना है?
If (p(x)=x-4 -5x-2 +4), what is the degree of (p(x))?
#degree
#polynomial
#one-variable
A (4)
B (2)
C (5)
D (0)
Explanation opens after your attempt
Step 1
Concept
The highest power is \(x^4\), so the degree is (4). Terms with zero coefficients do not affect the degree.
Step 2
Why this answer is correct
The correct answer is A. (4). The highest power is \(x^4\), so the degree is (4). Terms with zero coefficients do not affect the degree.
Step 3
Exam Tip
सबसे बड़ी घात \(x^4\) है, इसलिए घात (4) है। शून्य गुणांक वाले पदों को घात तय करने में नहीं गिनते।
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यदि (p(x)=mx-4 +(m+2)x-3 +5x+1) की घात (3) है, तो (m) क्या है?
If the degree of (p(x)=mx-4 +(m+2)x-3 +5x+1) is (3), what is (m)?
#degree
#parameter
#conditions
A (-2)
B (0)
C (2)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
For degree (3), the coefficient of \(x^4\) must be (0) and the coefficient of \(x^3\) must be non-zero. For (m=0), (m+2=2).
Step 2
Why this answer is correct
The correct answer is B. (0). For degree (3), the coefficient of \(x^4\) must be (0) and the coefficient of \(x^3\) must be non-zero. For (m=0), (m+2=2).
Step 3
Exam Tip
घात (3) के लिए \(x^4\) का गुणांक (0) चाहिए और \(x^3\) का गुणांक अशून्य चाहिए। (m=0) पर (m+2=2) है।
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यदि (p(x)=ax-4 +bx-3 +cx-2 +d) में (a=0), (b=0) और \(c\ne0\), तो (p(x)) की घात क्या होगी?
If (a=0), (b=0), and \(c\ne0\) in (p(x)=ax-4 +bx-3 +cx-2 +d), what will be the degree of (p(x))?
#degree
#general polynomial
#conditions
A (0)
B (1)
C (2)
D (4)
Explanation opens after your attempt
Step 1
Concept
The \(x^4\)- and \(x^3\)-terms vanish, but \(c\ne0\) keeps the \(x^2\)-term. So the degree is (2).
Step 2
Why this answer is correct
The correct answer is C. (2). The \(x^4\)- and \(x^3\)-terms vanish, but \(c\ne0\) keeps the \(x^2\)-term. So the degree is (2).
Step 3
Exam Tip
\(x^4\) और \(x^3\) के पद हट जाते हैं, लेकिन \(c\ne0\) से \(x^2\) पद बचता है। इसलिए घात (2) है।
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(p(x)=5x-4 -2x-2 +1) और (q(x)=-5x-4 +3x-3 +x-6) के योग की घात क्या है?
What is the degree of the sum of (p(x)=5x-4 -2x-2 +1) and (q(x)=-5x-4 +3x-3 +x-6)?
#degree
#cancellation
#addition
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The \(x^4\)-terms cancel and the highest remaining power is (3). Recheck the degree after addition.
Step 2
Why this answer is correct
The correct answer is C. (3). The \(x^4\)-terms cancel and the highest remaining power is (3). Recheck the degree after addition.
Step 3
Exam Tip
\(x^4\) के पद कट जाते हैं और सबसे बड़ी बची घात (3) है। जोड़ के बाद घात दोबारा जांचना जरूरी है।
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यदि (p(x)=(m+2)x-5 +(m-3 )x-4 +6x-1) की घात (4) है, तो (m) क्या होगा?
If the degree of (p(x)=(m+2)x-5 +(m-3 )x-4 +6x-1) is (4), what is (m)?
#degree
#parameter
#polynomial
A (-2)
B (2)
C (3)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
For degree (4), the coefficient of \(x^5\) must be (0) and the coefficient of \(x^4\) must be non-zero. Both conditions hold for (m=-2).
Step 2
Why this answer is correct
The correct answer is A. (-2). For degree (4), the coefficient of \(x^5\) must be (0) and the coefficient of \(x^4\) must be non-zero. Both conditions hold for (m=-2).
Step 3
Exam Tip
घात (4) के लिए \(x^5\) का गुणांक (0) और \(x^4\) का गुणांक अशून्य चाहिए। (m=-2) पर दोनों शर्तें पूरी होती हैं।
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किस बहुपद की घात (4) है?
Which polynomial has degree (4)?
#polynomials
#degree
#zero_coefficient
#hard
A \(7x^4+0x^5-3x+1\)
B \(0x^6+5x^3-2\)
C \(x^2+x+1\)
D (9)
Explanation opens after your attempt
Correct Answer
A. \(7x^4+0x^5-3x+1\)
Step 1
Concept
The term \(0x^5\) does not affect degree because its coefficient is (0). The highest non-zero power is (4).
Step 2
Why this answer is correct
The correct answer is A. \(7x^4+0x^5-3x+1\). The term \(0x^5\) does not affect degree because its coefficient is (0). The highest non-zero power is (4).
Step 3
Exam Tip
\(0x^5\) पद घात नहीं बढ़ाता क्योंकि उसका गुणांक (0) है। सबसे बड़ा शून्येतर घात (4) है।
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यदि (p(x)=mx-3 +(m-1 )x-2 +2x+1) की घात (2) है, तो (m) क्या है?
If the degree of (p(x)=mx-3 +(m-1 )x-2 +2x+1) is (2), what is (m)?
#degree
#parameter
#conditions
A (0)
B (1)
C (2)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
For degree (2), the coefficient of \(x^3\) must be (0) and the coefficient of \(x^2\) must be non-zero. Both conditions hold when (m=0).
Step 2
Why this answer is correct
The correct answer is A. (0). For degree (2), the coefficient of \(x^3\) must be (0) and the coefficient of \(x^2\) must be non-zero. Both conditions hold when (m=0).
Step 3
Exam Tip
घात (2) के लिए \(x^3\) का गुणांक (0) चाहिए और \(x^2\) का गुणांक अशून्य चाहिए। (m=0) पर ये दोनों शर्तें पूरी होती हैं।
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यदि (p(x)=ax-3 +bx-2 +cx+d) में (a=0) और \(b\ne0\), तो (p(x)) की घात क्या होगी?
If (a=0) and \(b\ne0\) in (p(x)=ax-3 +bx-2 +cx+d), what will be the degree of (p(x))?
#degree
#general polynomial
#conditions
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
Since (a=0), the \(x^3\)-term vanishes, and since \(b\ne0\), the \(x^2\)-term remains. So the degree is (2).
Step 2
Why this answer is correct
The correct answer is C. (2). Since (a=0), the \(x^3\)-term vanishes, and since \(b\ne0\), the \(x^2\)-term remains. So the degree is (2).
Step 3
Exam Tip
(a=0) होने से \(x^3\) पद हट जाता है और \(b\ne0\) होने से \(x^2\) पद बचता है। इसलिए घात (2) है।
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(p(x)=4x-4 -3x-2 +2) और (q(x)=-4x-4 +5x-3 +x-8) के योग की घात क्या है?
What is the degree of the sum of (p(x)=4x-4 -3x-2 +2) and (q(x)=-4x-4 +5x-3 +x-8)?
#degree
#cancellation
#addition
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The \(x^4\)-terms cancel and the highest remaining power is (3). Recheck the degree after addition.
Step 2
Why this answer is correct
The correct answer is C. (3). The \(x^4\)-terms cancel and the highest remaining power is (3). Recheck the degree after addition.
Step 3
Exam Tip
\(x^4\) के पद कट जाते हैं और सबसे बड़ी बची घात (3) है। जोड़ के बाद घात फिर से जांचें।
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यदि (p(x)=(a-5)x-5 +2x-3 -7x+4) की घात (3) है, तो (a) क्या होगा?
If the degree of (p(x)=(a-5)x-5 +2x-3 -7x+4) is (3), what is (a)?
#degree
#parameter
#polynomial
A (0)
B (3)
C (5)
D (7)
Explanation opens after your attempt
Step 1
Concept
For the degree to be (3), the coefficient of \(x^5\) must be (0), so (a-5=0). First make the highest-degree term vanish.
Step 2
Why this answer is correct
The correct answer is C. (5). For the degree to be (3), the coefficient of \(x^5\) must be (0), so (a-5=0). First make the highest-degree term vanish.
Step 3
Exam Tip
घात (3) होने के लिए \(x^5\) का गुणांक (0) होना चाहिए, इसलिए (a-5=0)। उच्चतम घात वाले पद को पहले शून्य करें।
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यदि (p(x)=(k-4)x-4 +3x-2 -5x+2) की घात (2) है, तो (k) का मान क्या होगा?
If the degree of (p(x)=(k-4)x-4 +3x-2 -5x+2) is (2), what will be the value of (k)?
#degree
#parameter
#polynomial
A (0)
B (2)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
For the degree to be (2), the coefficient of \(x^4\) must be (0), so (k-4=0) and (k=4). Check the coefficient of the highest power first.
Step 2
Why this answer is correct
The correct answer is C. (4). For the degree to be (2), the coefficient of \(x^4\) must be (0), so (k-4=0) and (k=4). Check the coefficient of the highest power first.
Step 3
Exam Tip
घात (2) होने के लिए \(x^4\) का गुणांक (0) होना चाहिए, इसलिए (k-4=0) और (k=4)। सबसे बड़ी घात वाले पद का गुणांक पहले जांचें।
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किसी रैखिक बहुपद (mx+n) में \(m\ne0\) हो तो उसकी घात क्या है?
If \(m\ne0\) in a linear polynomial (mx+n), what is its degree?
#linear polynomial
#degree
#general form
A (0)
B (1)
C (2)
D परिभाषित नहीं / Undefined
Explanation opens after your attempt
Step 1
Concept
When \(m\ne0\), the term (mx) exists and the highest power is (1). So the degree is (1).
Step 2
Why this answer is correct
The correct answer is B. (1). When \(m\ne0\), the term (mx) exists and the highest power is (1). So the degree is (1).
Step 3
Exam Tip
\(m\ne0\) होने पर (mx) पद मौजूद रहता है और सबसे बड़ी घात (1) होती है। इसलिए घात (1) है।
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(p(x)=0x-5 +7x-3 -2x+1) की घात क्या है?
What is the degree of (p(x)=0x-5 +7x-3 -2x+1)?
#degree
#zero coefficient
#polynomial
A (1)
B (3)
C (5)
D (7)
Explanation opens after your attempt
Step 1
Concept
The coefficient of \(0x^5\) is (0), so that term is not counted. The highest effective power is (3).
Step 2
Why this answer is correct
The correct answer is B. (3). The coefficient of \(0x^5\) is (0), so that term is not counted. The highest effective power is (3).
Step 3
Exam Tip
\(0x^5\) का गुणांक (0) है इसलिए वह पद नहीं गिना जाएगा। सबसे बड़ी प्रभावी घात (3) है।
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अशून्य अचर बहुपद (p(x)=-18) की घात क्या है?
What is the degree of the non-zero constant polynomial (p(x)=-18)?
#constant polynomial
#degree
#definition
A (0)
B (1)
C (18)
D परिभाषित नहीं / Undefined
Explanation opens after your attempt
Step 1
Concept
A non-zero constant polynomial has degree (0). A constant number is linked with degree (0).
Step 2
Why this answer is correct
The correct answer is A. (0). A non-zero constant polynomial has degree (0). A constant number is linked with degree (0).
Step 3
Exam Tip
अशून्य अचर बहुपद की घात (0) होती है। अचर संख्या का अर्थ घात (0) से जुड़ा है।
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बहुपद (p(x)=11x-6 -4x-3 +x-9) की घात क्या है?
What is the degree of the polynomial (p(x)=11x-6 -4x-3 +x-9)?
#degree
#highest power
#polynomial
A (1)
B (3)
C (6)
D (11)
Explanation opens after your attempt
Step 1
Concept
The highest power is (6), so the degree is (6). Look at the highest power of the variable, not the coefficient.
Step 2
Why this answer is correct
The correct answer is C. (6). The highest power is (6), so the degree is (6). Look at the highest power of the variable, not the coefficient.
Step 3
Exam Tip
सबसे बड़ी घात (6) है इसलिए घात (6) होगी। गुणांक नहीं बल्कि चर की सबसे ऊंची घात देखें।
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कौन सा विकल्प \(2x^3-5x^2+x-4\) की घात और नियत पद को सही बताता है?
Which option correctly gives the degree and constant term of \(2x^3-5x^2+x-4\)?
#degree
#constant-term
#cubic-polynomial
A घात (3), नियत पद (-4) / Degree (3), constant term (-4)
B घात (2), नियत पद (1) / Degree (2), constant term (1)
C घात (1), नियत पद (-5) / Degree (1), constant term (-5)
D घात (4), नियत पद (2) / Degree (4), constant term (2)
Explanation opens after your attempt
Correct Answer
A. घात (3), नियत पद (-4) / Degree (3), constant term (-4)
Step 1
Concept
The highest power is (3) and the term without (x) is (-4). So the correct pair is degree (3), constant term (-4).
Step 2
Why this answer is correct
The correct answer is A. घात (3), नियत पद (-4) / Degree (3), constant term (-4). The highest power is (3) and the term without (x) is (-4). So the correct pair is degree (3), constant term (-4).
Step 3
Exam Tip
सबसे बड़ी घात (3) है और बिना (x) वाला पद (-4) है। इसलिए सही जोड़ी घात (3), नियत पद (-4) है।
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\(x^2+1\), \(x^3+x\), (5x-2) में सबसे कम घात वाला बहुपद कौन सा है?
Among \(x^2+1\), \(x^3+x\), and (5x-2), which polynomial has the least degree?
#compare-degree
#linear-polynomial
#classification
A \(x^2+1\)
B \(x^3+x\)
C (5x-2)
D तीनों की घात समान है / All three have the same degree
Explanation opens after your attempt
Step 1
Concept
Their degrees are (2), (3), and (1) respectively. The least degree is (1).
Step 2
Why this answer is correct
The correct answer is C. (5x-2). Their degrees are (2), (3), and (1) respectively. The least degree is (1).
Step 3
Exam Tip
इनकी घातें क्रमशः (2), (3) और (1) हैं। सबसे कम घात (1) है।
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यदि किसी गैर-शून्य नियत बहुपद की घात पूछी जाए, तो सही उत्तर क्या होगा?
If the degree of a non-zero constant polynomial is asked, what will be the correct answer?
#constant-polynomial
#degree
#concept
A (0)
B (1)
C परिभाषित नहीं / Not defined
D बहुपद नहीं / Not a polynomial
Explanation opens after your attempt
Step 1
Concept
The degree of a non-zero constant polynomial is (0). Keep it separate from the zero polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). The degree of a non-zero constant polynomial is (0). Keep it separate from the zero polynomial.
Step 3
Exam Tip
गैर-शून्य नियत बहुपद की घात (0) होती है। इसे शून्य बहुपद से अलग रखें।
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किस मान के लिए (p(x)=(a-2)x-3 +4x-2 +1) की घात (2) हो जाएगी?
For which value will (p(x)=(a-2)x-3 +4x-2 +1) have degree (2)?
#degree
#parameter
#highest-power
A (a=0)
B (a=1)
C (a=2)
D (a=4)
Explanation opens after your attempt
Step 1
Concept
For degree (2), the coefficient of \(x^3\) must be (0). From (a-2=0), we get (a=2).
Step 2
Why this answer is correct
The correct answer is C. (a=2). For degree (2), the coefficient of \(x^3\) must be (0). From (a-2=0), we get (a=2).
Step 3
Exam Tip
घात (2) के लिए \(x^3\) का गुणांक (0) होना चाहिए। (a-2=0) से (a=2) मिलता है।
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यदि (p(x)=ax-2 +3x+5) की घात (1) है, तो (a) का मान क्या होगा?
If (p(x)=ax-2 +3x+5) has degree (1), what will be the value of (a)?
#polynomials
#degree
#parameter
A (0)
B (1)
C (3)
D (5)
Explanation opens after your attempt
Step 1
Concept
For degree (1), the coefficient of \(x^2\) must be (0). Therefore (a=0).
Step 2
Why this answer is correct
The correct answer is A. (0). For degree (1), the coefficient of \(x^2\) must be (0). Therefore (a=0).
Step 3
Exam Tip
घात (1) होने के लिए \(x^2\) का गुणांक (0) होना चाहिए। इसलिए (a=0) है।
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यदि (p(x)=(m-2 )x-3 +4x-2 -7) की घात (2) है, तो (m) का मान क्या होगा?
If the degree of (p(x)=(m-2 )x-3 +4x-2 -7) is (2), what will be the value of (m)?
#degree
#parameter
#polynomial
A (0)
B (2)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
For the degree to be (2), the coefficient of \(x^3\) must be (0), so (m-2 =0) and (m=2). In exams, check the coefficient of the highest power first.
Step 2
Why this answer is correct
The correct answer is B. (2). For the degree to be (2), the coefficient of \(x^3\) must be (0), so (m-2 =0) and (m=2). In exams, check the coefficient of the highest power first.
Step 3
Exam Tip
घात (2) होने के लिए \(x^3\) का गुणांक (0) होना चाहिए, इसलिए (m-2 =0) और (m=2)। परीक्षा में सबसे ऊंची घात के गुणांक को पहले देखें।
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निम्न में से कौन सा (x) में बहुपद है जिसकी घात (4) है?
Which of the following is a polynomial in (x) with degree (4)?
#degree
#highest-power
#polynomial
A \(x^4-2x+7\)
B \(x^3+4\)
C \(5x^2-1\)
D (9x+6)
Explanation opens after your attempt
Correct Answer
A. \(x^4-2x+7\)
Step 1
Concept
In \(x^4-2x+7\), the highest power is (4). To identify degree, check the greatest power.
Step 2
Why this answer is correct
The correct answer is A. \(x^4-2x+7\). In \(x^4-2x+7\), the highest power is (4). To identify degree, check the greatest power.
Step 3
Exam Tip
\(x^4-2x+7\) में सबसे बड़ी घात (4) है। घात पहचानने के लिए सबसे बड़ी शक्ति देखें।
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किसी रैखिक बहुपद (ax+b) में \(a\ne0\) हो तो उसकी घात क्या है?
If \(a\ne0\) in a linear polynomial (ax+b), what is its degree?
#linear polynomial
#degree
#general form
A (0)
B (1)
C (2)
D परिभाषित नहीं / Undefined
Explanation opens after your attempt
Step 1
Concept
When \(a\ne0\) in (ax+b), the highest power of (x) is (1). So the degree is (1).
Step 2
Why this answer is correct
The correct answer is B. (1). When \(a\ne0\) in (ax+b), the highest power of (x) is (1). So the degree is (1).
Step 3
Exam Tip
(ax+b) में \(a\ne0\) होने पर (x) की सबसे बड़ी घात (1) है। इसलिए घात (1) होगी।
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\(3x^4+0x^3-2x+5\) की घात क्या है?
What is the degree of \(3x^4+0x^3-2x+5\)?
#degree
#zero coefficient
#polynomial
A (1)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
The term \(0x^3\) is ineffective, and the highest non-zero power is (4). Ignore terms with zero coefficient.
Step 2
Why this answer is correct
The correct answer is C. (4). The term \(0x^3\) is ineffective, and the highest non-zero power is (4). Ignore terms with zero coefficient.
Step 3
Exam Tip
\(0x^3\) पद प्रभावी नहीं है और सबसे बड़ी अशून्य घात (4) है। शून्य गुणांक वाले पद को नजरअंदाज करें।
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अशून्य अचर बहुपद (p(x)=12) की घात क्या होती है?
What is the degree of the non-zero constant polynomial (p(x)=12)?
#constant polynomial
#degree
#definition
A (0)
B (1)
C (12)
D परिभाषित नहीं / Undefined
Explanation opens after your attempt
Step 1
Concept
A non-zero constant polynomial has degree (0). Keep it separate from the zero polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). A non-zero constant polynomial has degree (0). Keep it separate from the zero polynomial.
Step 3
Exam Tip
अशून्य अचर बहुपद की घात (0) होती है। शून्य बहुपद से इसे अलग रखें।
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बहुपद (p(x)=4x-5 -3x-2 +9) की घात क्या है?
What is the degree of the polynomial (p(x)=4x-5 -3x-2 +9)?
#degree
#polynomial
#powers
A (2)
B (3)
C (5)
D (9)
Explanation opens after your attempt
Step 1
Concept
The highest power is (5), so the degree is (5). Always check the highest exponent.
Step 2
Why this answer is correct
The correct answer is C. (5). The highest power is (5), so the degree is (5). Always check the highest exponent.
Step 3
Exam Tip
सबसे बड़ी घात (5) है इसलिए बहुपद की घात (5) है। हमेशा सबसे ऊंची घात देखें।
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\(x^5+1\) की घात क्या है?
What is the degree of \(x^5+1\)?
#degree
#highest-power
A (1)
B (2)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
The highest power is (5), so the degree is (5). The constant term does not increase the degree.
Step 2
Why this answer is correct
The correct answer is C. (5). The highest power is (5), so the degree is (5). The constant term does not increase the degree.
Step 3
Exam Tip
सबसे बड़ी घात (5) है इसलिए बहुपद की घात (5) है। नियत पद घात को नहीं बढ़ाता।
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निम्न में से किस बहुपद की घात (2) है?
Which polynomial has degree (2)?
#degree-two
#quadratic
A \(x^2+4x\)
B \(x^4+1\)
C (6x+5)
D (3)
Explanation opens after your attempt
Correct Answer
A. \(x^2+4x\)
Step 1
Concept
The highest power in \(x^2+4x\) is (2). Therefore its degree is (2).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+4x\). The highest power in \(x^2+4x\) is (2). Therefore its degree is (2).
Step 3
Exam Tip
\(x^2+4x\) में सबसे बड़ी घात (2) है। इसलिए इसकी घात (2) है।
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निम्न में से किस बहुपद की घात (1) है?
Which polynomial has degree (1)?
#degree-one
#linear
A \(4x^2+1\)
B (9x-3)
C \(x^3+2\)
D (11)
Explanation opens after your attempt
Step 1
Concept
In (9x-3), the highest power of (x) is (1). So it is a polynomial of degree (1).
Step 2
Why this answer is correct
The correct answer is B. (9x-3). In (9x-3), the highest power of (x) is (1). So it is a polynomial of degree (1).
Step 3
Exam Tip
(9x-3) में (x) की सबसे बड़ी घात (1) है। इसलिए यह घात (1) का बहुपद है।
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शून्य बहुपद (0) की घात के बारे में सही कथन कौन सा है?
Which statement about the degree of the zero polynomial (0) is correct?
#zero-polynomial
#degree
A घात (0) है / Degree is (0)
B घात (1) है / Degree is (1)
C घात परिभाषित नहीं है / Degree is not defined
D घात (2) है / Degree is (2)
Explanation opens after your attempt
Correct Answer
C. घात परिभाषित नहीं है / Degree is not defined
Step 1
Concept
The degree of the zero polynomial is not defined. Remember it separately from a non-zero constant polynomial.
Step 2
Why this answer is correct
The correct answer is C. घात परिभाषित नहीं है / Degree is not defined. The degree of the zero polynomial is not defined. Remember it separately from a non-zero constant polynomial.
Step 3
Exam Tip
शून्य बहुपद की घात परिभाषित नहीं होती। इसे गैर-शून्य नियत बहुपद से अलग याद रखें।
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\(6x^4-2x^2+x-8\) की घात क्या है?
What is the degree of \(6x^4-2x^2+x-8\)?
#degree
#highest-power
A (1)
B (2)
C (4)
D (8)
Explanation opens after your attempt
Step 1
Concept
The highest power is (4), so the degree is (4). The degree depends on the highest power, not on the number of terms.
Step 2
Why this answer is correct
The correct answer is C. (4). The highest power is (4), so the degree is (4). The degree depends on the highest power, not on the number of terms.
Step 3
Exam Tip
सबसे बड़ी घात (4) है इसलिए घात (4) है। पदों की संख्या नहीं, सबसे बड़ी घात महत्वपूर्ण है।
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बहुपद \(7x^3-4x+9\) की घात क्या है?
What is the degree of the polynomial \(7x^3-4x+9\)?
#degree
#polynomials
#class10
A (1)
B (2)
C (3)
D (9)
Explanation opens after your attempt
Step 1
Concept
The highest power is (3), so the degree is (3). Always check the highest power of the variable.
Step 2
Why this answer is correct
The correct answer is C. (3). The highest power is (3), so the degree is (3). Always check the highest power of the variable.
Step 3
Exam Tip
सबसे बड़ी घात (3) है इसलिए बहुपद की घात (3) है। हमेशा चर की सबसे बड़ी घात देखें।
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यदि किसी बहुपद की घात (3) है, तो उसे क्या कहते हैं?
If a polynomial has degree (3), what is it called?
#polynomials
#cubic
#easy
#degree
A घन बहुपद / Cubic polynomial
B द्विघात बहुपद / Quadratic polynomial
C रैखिक बहुपद / Linear polynomial
D नियत बहुपद / Constant polynomial
Explanation opens after your attempt
Correct Answer
A. घन बहुपद / Cubic polynomial
Step 1
Concept
A degree (3) polynomial is called a cubic polynomial. The highest power decides the name.
Step 2
Why this answer is correct
The correct answer is A. घन बहुपद / Cubic polynomial. A degree (3) polynomial is called a cubic polynomial. The highest power decides the name.
Step 3
Exam Tip
घात (3) वाला बहुपद घन बहुपद कहलाता है। सबसे बड़ी घात ही नाम तय करती है।
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यदि किसी बहुपद की घात (2) है, तो उसे क्या कहते हैं?
If a polynomial has degree (2), what is it called?
#polynomials
#quadratic
#easy
#degree
A रैखिक बहुपद / Linear polynomial
B द्विघात बहुपद / Quadratic polynomial
C घन बहुपद / Cubic polynomial
D शून्य बहुपद / Zero polynomial
Explanation opens after your attempt
Correct Answer
B. द्विघात बहुपद / Quadratic polynomial
Step 1
Concept
A degree (2) polynomial is called quadratic. A non-zero \(x^2\)-term must be present.
Step 2
Why this answer is correct
The correct answer is B. द्विघात बहुपद / Quadratic polynomial. A degree (2) polynomial is called quadratic. A non-zero \(x^2\)-term must be present.
Step 3
Exam Tip
घात (2) वाला बहुपद द्विघात कहलाता है। \(x^2\) का अशून्य पद होना जरूरी है।
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यदि किसी बहुपद की घात (1) है, तो उसे क्या कहते हैं?
If a polynomial has degree (1), what is it called?
#polynomials
#degree
#type
#easy
A नियत बहुपद / Constant polynomial
B रैखिक बहुपद / Linear polynomial
C द्विघात बहुपद / Quadratic polynomial
D घन बहुपद / Cubic polynomial
Explanation opens after your attempt
Correct Answer
B. रैखिक बहुपद / Linear polynomial
Step 1
Concept
A polynomial of degree (1) is called a linear polynomial. Link the name with the degree.
Step 2
Why this answer is correct
The correct answer is B. रैखिक बहुपद / Linear polynomial. A polynomial of degree (1) is called a linear polynomial. Link the name with the degree.
Step 3
Exam Tip
घात (1) वाले बहुपद को रैखिक बहुपद कहते हैं। नाम हमेशा घात से जोड़कर याद करें।
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(p(x)=ax+b) में यदि \(a\ne0\) है, तो इसकी घात क्या होती है?
In (p(x)=ax+b), if \(a\ne0\), what is its degree?
#polynomials
#linear-form
#easy
#degree
A (0)
B (1)
C (2)
D परिभाषित नहीं / Not defined
Explanation opens after your attempt
Step 1
Concept
When \(a\ne0\), the (x)-term exists, so the degree is (1). This is the form of a linear polynomial.
Step 2
Why this answer is correct
The correct answer is B. (1). When \(a\ne0\), the (x)-term exists, so the degree is (1). This is the form of a linear polynomial.
Step 3
Exam Tip
\(a\ne0\) होने पर (x) वाला पद मौजूद है, इसलिए घात (1) है। यही रैखिक बहुपद का रूप है।
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बहुपद \(11x^5-3x^2+8\) की घात क्या है?
What is the degree of \(11x^5-3x^2+8\)?
#polynomials
#degree
#easy
#highest-power
A (2)
B (3)
C (5)
D (8)
Explanation opens after your attempt
Step 1
Concept
The highest power is (5), so the degree is (5). Look at the greatest power, not the number of terms.
Step 2
Why this answer is correct
The correct answer is C. (5). The highest power is (5), so the degree is (5). Look at the greatest power, not the number of terms.
Step 3
Exam Tip
सबसे बड़ी घात (5) है इसलिए घात (5) होगी। पदों की संख्या नहीं बल्कि सबसे बड़ी घात देखें।
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बहुपद (5) की घात क्या है?
What is the degree of the polynomial (5)?
#polynomials
#constant-polynomial
#easy
#degree
A (0)
B (1)
C (5)
D परिभाषित नहीं / Not defined
Explanation opens after your attempt
Step 1
Concept
A non-zero constant polynomial has degree (0). Remember \(5=5x^0\) may be considered.
Step 2
Why this answer is correct
The correct answer is A. (0). A non-zero constant polynomial has degree (0). Remember \(5=5x^0\) may be considered.
Step 3
Exam Tip
अशून्य नियत बहुपद की घात (0) होती है। याद रखें \(5=5x^0\) माना जा सकता है।
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बहुपद \(7x^3-2x+9\) की घात क्या है?
What is the degree of the polynomial \(7x^3-2x+9\)?
#polynomials
#degree
#easy
#level48
A (1)
B (2)
C (3)
D (9)
Explanation opens after your attempt
Step 1
Concept
The highest power is (3), so the degree is (3). In exams identify the greatest exponent.
Step 2
Why this answer is correct
The correct answer is C. (3). The highest power is (3), so the degree is (3). In exams identify the greatest exponent.
Step 3
Exam Tip
सबसे बड़ी घात (3) है इसलिए बहुपद की घात (3) होगी। परीक्षा में सबसे बड़े घातांक को पहचानें।
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यदि (p(x)=ax+b) और \(a\neq0\), तो (p(x)) की घात क्या है?
If (p(x)=ax+b) and \(a\neq0\), what is the degree of (p(x))?
#linear_form
#degree
#polynomials
A (0)
B (1)
C (2)
D परिभाषित नहीं / Undefined
Explanation opens after your attempt
Step 1
Concept
Since \(a\neq0\), the (x)-term is present. Therefore the degree of the polynomial is (1).
Step 2
Why this answer is correct
The correct answer is B. (1). Since \(a\neq0\), the (x)-term is present. Therefore the degree of the polynomial is (1).
Step 3
Exam Tip
\(a\neq0\) होने से (x) वाला पद मौजूद है। इसलिए बहुपद की घात (1) है।
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बहुपद \(4x^3-2x^3+x+5\) को सरल करने पर घात क्या होगी?
After simplifying \(4x^3-2x^3+x+5\), what is its degree?
#like_terms
#degree
#simplification
A (1)
B (2)
C (3)
D (5)
Explanation opens after your attempt
Step 1
Concept
Combining like terms gives \(2x^3+x+5\). The highest power is (3).
Step 2
Why this answer is correct
The correct answer is C. (3). Combining like terms gives \(2x^3+x+5\). The highest power is (3).
Step 3
Exam Tip
समान पद मिलाकर \(2x^3+x+5\) मिलता है। सबसे बड़ी घात (3) है।
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बहुपद \(3x^3+0x^2-2x+5\) की घात क्या है?
What is the degree of \(3x^3+0x^2-2x+5\)?
#degree
#zero_coefficient
#polynomials
A (1)
B (2)
C (3)
D (5)
Explanation opens after your attempt
Step 1
Concept
The highest non-zero power term is \(3x^3\). So the degree is (3).
Step 2
Why this answer is correct
The correct answer is C. (3). The highest non-zero power term is \(3x^3\). So the degree is (3).
Step 3
Exam Tip
सबसे बड़ी शून्य से भिन्न घात वाला पद \(3x^3\) है। इसलिए घात (3) है।
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शून्य बहुपद (p(x)=0) की घात के बारे में सही कथन कौन-सा है?
Which statement is correct about the degree of the zero polynomial (p(x)=0)?
#zero_polynomial
#degree
#concept
A घात (0) है / Degree is (0)
B घात (1) है / Degree is (1)
C घात परिभाषित नहीं है / Degree is undefined
D घात (2) है / Degree is (2)
Explanation opens after your attempt
Correct Answer
C. घात परिभाषित नहीं है / Degree is undefined
Step 1
Concept
The degree of the zero polynomial is undefined. In exams, keep it separate from a non-zero constant polynomial.
Step 2
Why this answer is correct
The correct answer is C. घात परिभाषित नहीं है / Degree is undefined. The degree of the zero polynomial is undefined. In exams, keep it separate from a non-zero constant polynomial.
Step 3
Exam Tip
शून्य बहुपद की घात परिभाषित नहीं होती। परीक्षा में इसे स्थिर शून्य से भिन्न बहुपद से अलग रखें।
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स्थिर बहुपद (p(x)=9) की घात क्या है?
What is the degree of the constant polynomial (p(x)=9)?
#constant_polynomial
#degree
#basics
A (0)
B (1)
C (9)
D परिभाषित नहीं / Undefined
Explanation opens after your attempt
Step 1
Concept
A non-zero constant polynomial has degree (0). The number (9) may be written as \(9x^0\).
Step 2
Why this answer is correct
The correct answer is A. (0). A non-zero constant polynomial has degree (0). The number (9) may be written as \(9x^0\).
Step 3
Exam Tip
शून्य से भिन्न स्थिर बहुपद की घात (0) होती है। (9) को \(9x^0\) माना जा सकता है।
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बहुपद (p(x)=4x-3 -2x+9) की घात क्या है?
What is the degree of the polynomial (p(x)=4x-3 -2x+9)?
#degree
#polynomials
#one_variable
A (3)
B (2)
C (1)
D (9)
Explanation opens after your attempt
Step 1
Concept
The highest power is (3), so the degree of the polynomial is (3). In exams, look at the highest power of the variable.
Step 2
Why this answer is correct
The correct answer is A. (3). The highest power is (3), so the degree of the polynomial is (3). In exams, look at the highest power of the variable.
Step 3
Exam Tip
सबसे बड़ी घात (3) है इसलिए बहुपद की घात (3) है। परीक्षा में सबसे बड़ी चर घात देखें।
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समीकरण \(x^2+1=0\) की घात क्या है?
What is the degree of \(x^2+1=0\)?
#quadratic-equations
#degree
#constant-term
A (1)
B (2)
C (0)
D (4)
Explanation opens after your attempt
Step 1
Concept
The highest power of (x) is (2). The constant term does not change the degree.
Step 2
Why this answer is correct
The correct answer is B. (2). The highest power of (x) is (2). The constant term does not change the degree.
Step 3
Exam Tip
इसमें (x) की सबसे बड़ी घात (2) है। स्थिर पद घात को नहीं बदलता।
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समीकरण \(7x^2-4x+9=0\) की घात क्या है?
What is the degree of the equation \(7x^2-4x+9=0\)?
#quadratic-equations
#degree
#easy
A (1)
B (2)
C (3)
D (0)
Explanation opens after your attempt
Step 1
Concept
The highest power of (x) in this equation is (2). Degree is decided by the greatest power of the variable.
Step 2
Why this answer is correct
The correct answer is B. (2). The highest power of (x) in this equation is (2). Degree is decided by the greatest power of the variable.
Step 3
Exam Tip
इस समीकरण में (x) की सबसे बड़ी घात (2) है। घात हमेशा चर की सबसे बड़ी शक्ति से तय होती है।
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\(6x^2-5x+2=0\) की घात क्या है?
What is the degree of \(6x^2-5x+2=0\)?
#quadratic equations
#degree
#identification
A (0)
B (1)
C (2)
D (6)
Explanation opens after your attempt
Step 1
Concept
The highest power is (2). Therefore it is a quadratic equation.
Step 2
Why this answer is correct
The correct answer is C. (2). The highest power is (2). Therefore it is a quadratic equation.
Step 3
Exam Tip
सबसे बड़ी घात (2) है। इसलिए यह द्विघात समीकरण है।
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\(5x^2+2x-1=0\) की घात क्या है?
What is the degree of \(5x^2+2x-1=0\)?
#quadratic equations
#degree
#identification
A (0)
B (1)
C (2)
D (5)
Explanation opens after your attempt
Step 1
Concept
The highest power is (2). Therefore the equation is quadratic.
Step 2
Why this answer is correct
The correct answer is C. (2). The highest power is (2). Therefore the equation is quadratic.
Step 3
Exam Tip
सबसे बड़ी घात (2) है। इसलिए समीकरण द्विघात है।
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यदि किसी समीकरण की घात (2) है और वह (x) में है तो उसे क्या कहते हैं?
If an equation in (x) has degree (2), what is it called?
#quadratic equations
#definition
#degree
A रैखिक समीकरण / Linear equation
B द्विघात समीकरण / Quadratic equation
C घन समीकरण / Cubic equation
D स्थिर समीकरण / Constant equation
Explanation opens after your attempt
Correct Answer
B. द्विघात समीकरण / Quadratic equation
Step 1
Concept
An equation of degree (2) is called a quadratic equation. Remember that quadratic means degree (2).
Step 2
Why this answer is correct
The correct answer is B. द्विघात समीकरण / Quadratic equation. An equation of degree (2) is called a quadratic equation. Remember that quadratic means degree (2).
Step 3
Exam Tip
घात (2) वाले समीकरण को द्विघात समीकरण कहते हैं। नाम याद रखने के लिए द्वि का अर्थ (2) समझें।
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एक ग्राफ (x)-अक्ष को तीन बार काटता है। उस बहुपद की न्यूनतम संभावित डिग्री क्या हो सकती है?
A graph cuts the (x)-axis three times. What can be the minimum possible degree of that polynomial?
#degree
#maximum-zeroes
#graph
A (3)
B (2)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
The number of real zeroes cannot exceed the degree of the polynomial. Three crossings need minimum degree (3).
Step 2
Why this answer is correct
The correct answer is A. (3). The number of real zeroes cannot exceed the degree of the polynomial. Three crossings need minimum degree (3).
Step 3
Exam Tip
किसी बहुपद के वास्तविक शून्यकों की संख्या उसकी डिग्री से अधिक नहीं हो सकती। तीन कटान के लिए न्यूनतम डिग्री (3) है।
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यदि कोई बहुपद (x)-अक्ष को छह अलग बिंदुओं पर काटता है तो न्यूनतम संभावित घात क्या होगी?
If a polynomial cuts the (x)-axis at six distinct points, what is the minimum possible degree?
#minimum degree
#distinct zeroes
#graph
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
For six distinct real zeroes, the degree must be at least (6). Tip: the number of distinct zeroes cannot exceed the degree.
Step 2
Why this answer is correct
The correct answer is C. (6). For six distinct real zeroes, the degree must be at least (6). Tip: the number of distinct zeroes cannot exceed the degree.
Step 3
Exam Tip
छह अलग वास्तविक शून्यकों के लिए घात कम से कम (6) होनी चाहिए। टिप: अलग शून्यकों की संख्या घात से अधिक नहीं हो सकती।
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यदि किसी बहुपद का ग्राफ (x)-अक्ष को तीन अलग बिंदुओं पर काटता है, तो बहुपद की न्यूनतम संभावित घात क्या हो सकती है?
If a polynomial graph cuts the (x)-axis at three distinct points, what can be the minimum possible degree of the polynomial?
#degree
#minimum degree
#zeroes
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
For three distinct real zeroes, the degree must be at least (3). Tip: the number of distinct zeroes cannot exceed the degree.
Step 2
Why this answer is correct
The correct answer is C. (3). For three distinct real zeroes, the degree must be at least (3). Tip: the number of distinct zeroes cannot exceed the degree.
Step 3
Exam Tip
तीन अलग वास्तविक शून्यकों के लिए घात कम से कम (3) होनी चाहिए। टिप: अलग शून्यकों की संख्या घात से अधिक नहीं हो सकती।
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यदि (p(x)=x-3 -4x-2 -7x+10) और (x-1) इसका गुणनखंड है, तो शेष द्विघात गुणनखंड क्या है?
If (p(x)=x-3 -4x-2 -7x+10) and (x-1) is a factor, what is the remaining quadratic factor?
#division
#factorisation
#cubic
A \(x^2-3x-10\)
B \(x^2+3x-10\)
C \(x^2-5x+10\)
D \(x^2-4x-7\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x-10\)
Step 1
Concept
Dividing (p(x)) by (x-1) gives \(x^2-3x-10\). Verify by multiplying ((x-1)\(x^2-3x-10\)=p(x)).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x-10\). Dividing (p(x)) by (x-1) gives \(x^2-3x-10\). Verify by multiplying ((x-1)\(x^2-3x-10\)=p(x)).
Step 3
Exam Tip
(p(x)) को (x-1) से भाग देने पर \(x^2-3x-10\) मिलता है। गुणा करके जाँचें कि ((x-1)\(x^2-3x-10\)=p(x))।
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\(x^4-1\) के रैखिक गुणनखंडों में से कौन सा गलत है?
Which one is not a linear factor of \(x^4-1\)?
#polynomials
#factors
#degree
#hard
A (x-1)
B (x+1)
C \(x^2+1\)
D (x-i)
Explanation opens after your attempt
Correct Answer
C. \(x^2+1\)
Step 1
Concept
\(x^2+1\) is not linear because its degree is (2). Over real numbers, it is not a linear factor.
Step 2
Why this answer is correct
The correct answer is C. \(x^2+1\). \(x^2+1\) is not linear because its degree is (2). Over real numbers, it is not a linear factor.
Step 3
Exam Tip
\(x^2+1\) रैखिक नहीं है क्योंकि उसकी घात (2) है। वास्तविक संख्याओं में इसे रैखिक गुणनखंड नहीं माना जाता।
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यदि (p(x)=x-3 -5x-2 +ax+12) में (x-3) गुणनखंड है, तो (a) का मान क्या है?
If (x-3) is a factor of (p(x)=x-3 -5x-2 +ax+12), what is the value of (a)?
#factor-theorem
#polynomials
#parameter
A (2)
B (4)
C (6)
D (8)
Explanation opens after your attempt
Step 1
Concept
By the factor theorem (p(3)=0), so (27-45+3a+12=0) and (a=2). In exams, substitute the zero from the given factor directly.
Step 2
Why this answer is correct
The correct answer is A. (2). By the factor theorem (p(3)=0), so (27-45+3a+12=0) and (a=2). In exams, substitute the zero from the given factor directly.
Step 3
Exam Tip
गुणनखंड प्रमेय से (p(3)=0), इसलिए (27-45+3a+12=0) और (a=2)। परीक्षा में दिए गए गुणनखंड से मूल तुरंत रखिए।
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यदि (p(x)=x-3 -7x+6), तो इनमें से कौन-सा (p(x)) का गुणनखंड नहीं है?
If (p(x)=x-3 -7x+6), which of the following is not a factor of (p(x))?
#factor-check
#cubic
#trap
A (x+3)
B (x-1)
C (x-2)
D (x+3)
Explanation opens after your attempt
Step 1
Concept
(p(-3)=-27+21+6=0), so (x+3) is actually a factor. This reveals an option error, so check each option using (p(a)).
Step 2
Why this answer is correct
The correct answer is A. (x+3). (p(-3)=-27+21+6=0), so (x+3) is actually a factor. This reveals an option error, so check each option using (p(a)).
Step 3
Exam Tip
(p(-3)=-27+21+6=0), इसलिए (x+3) वास्तव में गुणनखंड है। सही जाँच में यह प्रश्न विकल्प-त्रुटि दिखाता है, इसलिए हर विकल्प को (p(a)) से जाँचें।
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यदि (p(x)=x-3 +3x-2 -4x-12), तो निम्न में से कौन-सा गुणनखंड है?
If (p(x)=x-3 +3x-2 -4x-12), which of the following is a factor?
#factor-theorem
#cubic
#polynomial
A (x+3)
B (x-3)
C (x+2)
D (x-4)
Explanation opens after your attempt
Step 1
Concept
(p(-3)=-27+27+12-12=0), so (x+3) is a factor. For (x+a), test (x=-a).
Step 2
Why this answer is correct
The correct answer is A. (x+3). (p(-3)=-27+27+12-12=0), so (x+3) is a factor. For (x+a), test (x=-a).
Step 3
Exam Tip
(p(-3)=-27+27+12-12=0), इसलिए (x+3) गुणनखंड है। (x+a) के लिए (x=-a) रखकर जाँचें।
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यदि (x-2) बहुपद (p(x)=x-3 +kx-2 -4x-4) का गुणनखंड है, तो (k) का मान क्या है?
If (x-2) is a factor of (p(x)=x-3 +kx-2 -4x-4), what is the value of (k)?
#factor-theorem
#polynomials
#expert
A (1)
B (2)
C (-1)
D (-2)
Explanation opens after your attempt
Step 1
Concept
By factor theorem (p(2)=0), so (8+4k-8-4=0) and (k=1). In exams, substitute the given zero directly.
Step 2
Why this answer is correct
The correct answer is A. (1). By factor theorem (p(2)=0), so (8+4k-8-4=0) and (k=1). In exams, substitute the given zero directly.
Step 3
Exam Tip
गुणनखंड प्रमेय से (p(2)=0), इसलिए (8+4k-8-4=0) और (k=1)। परीक्षा में पहले दिए गए मूल को सीधे रखिए।
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\(4x^5+12x^4\) का सामान्य गुणनखंड निकालने पर क्या मिलेगा?
What is obtained by taking the common factor from \(4x^5+12x^4\)?
#polynomials
#common factor
#factorization
A (4x-4 (x+3))
B (4x\(x^4+3\))
C (x-4 (4x+12x))
D (12x-4 (x+1))
Explanation opens after your attempt
Correct Answer
A. (4x-4 (x+3))
Step 1
Concept
The common factor in both terms is \(4x^4\). Hence the form is (4x-4 (x+3)).
Step 2
Why this answer is correct
The correct answer is A. (4x-4 (x+3)). The common factor in both terms is \(4x^4\). Hence the form is (4x-4 (x+3)).
Step 3
Exam Tip
दोनों पदों में सामान्य गुणनखंड \(4x^4\) है। इसलिए रूप (4x-4 (x+3)) है।
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\(3x^4+9x^3\) का सामान्य गुणनखंड निकालने पर क्या मिलेगा?
What is obtained by taking the common factor from \(3x^4+9x^3\)?
#polynomials
#common factor
#factorization
A (3x-3 (x+3))
B (3x\(x^3+3\))
C (x-3 (3x+9x))
D (9x-3 (x+1))
Explanation opens after your attempt
Correct Answer
A. (3x-3 (x+3))
Step 1
Concept
The common factor in both terms is \(3x^3\). Hence the form is (3x-3 (x+3)).
Step 2
Why this answer is correct
The correct answer is A. (3x-3 (x+3)). The common factor in both terms is \(3x^3\). Hence the form is (3x-3 (x+3)).
Step 3
Exam Tip
दोनों पदों में सामान्य गुणनखंड \(3x^3\) है। इसलिए रूप (3x-3 (x+3)) है।
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\(2x^3+6x^2\) का सामान्य गुणनखंड निकालने पर क्या मिलेगा?
What is obtained by taking the common factor from \(2x^3+6x^2\)?
#polynomials
#common factor
#factorization
A (2x-2 (x+3))
B (2x\(x^2+3\))
C (x-2 (2x+6x))
D (6x-2 (x+1))
Explanation opens after your attempt
Correct Answer
A. (2x-2 (x+3))
Step 1
Concept
The common factor in both terms is \(2x^2\). Hence the form is (2x-2 (x+3)).
Step 2
Why this answer is correct
The correct answer is A. (2x-2 (x+3)). The common factor in both terms is \(2x^2\). Hence the form is (2x-2 (x+3)).
Step 3
Exam Tip
दोनों पदों में सामान्य गुणनखंड \(2x^2\) है। इसलिए रूप (2x-2 (x+3)) है।
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सामान्य गुणनखंड निकालकर \(4x^2+28x=0\) को कैसे लिखा जाएगा?
By taking common factor, how will \(4x^2+28x=0\) be written?
#quadratic
#common-factor
#factorisation
A (4x(x+7)=0)
B (4(x+7)=0)
C (x(4x-28)=0)
D (4x(x-7)=0)
Explanation opens after your attempt
Correct Answer
A. (4x(x+7)=0)
Step 1
Concept
(4x) is the common factor, so (4x(x+7)=0). In exams, take out the greatest common factor.
Step 2
Why this answer is correct
The correct answer is A. (4x(x+7)=0). (4x) is the common factor, so (4x(x+7)=0). In exams, take out the greatest common factor.
Step 3
Exam Tip
(4x) सामान्य गुणनखंड है, इसलिए (4x(x+7)=0) मिलता है। परीक्षा में सबसे बड़ा सामान्य गुणनखंड निकालें।
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सामान्य गुणनखंड निकालकर \(5x^2+15x=0\) को कैसे लिखा जाएगा?
By taking common factor, how will \(5x^2+15x=0\) be written?
#quadratic
#common-factor
#factorisation
A (5x(x+3)=0)
B (5(x+3)=0)
C (x(5x-15)=0)
D (5x(x-3)=0)
Explanation opens after your attempt
Correct Answer
A. (5x(x+3)=0)
Step 1
Concept
(5x) is the common factor, so (5x(x+3)=0). In exams, take out the greatest common factor.
Step 2
Why this answer is correct
The correct answer is A. (5x(x+3)=0). (5x) is the common factor, so (5x(x+3)=0). In exams, take out the greatest common factor.
Step 3
Exam Tip
(5x) सामान्य गुणनखंड है, इसलिए (5x(x+3)=0) मिलता है। परीक्षा में सबसे बड़ा सामान्य गुणनखंड निकालें।
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समीकरण \(x^2+11x+30=0\) को गुणनखंड रूप में कौन-सा लिखा जा सकता है?
Which factor form can represent \(x^2+11x+30=0\)?
#quadratic-equations
#factor-form
#medium
A ((x+5)(x+6)=0)
B ((x-5)(x-6)=0)
C ((x+3)(x+10)=0)
D ((x-1)(x+30)=0)
Explanation opens after your attempt
Correct Answer
A. ((x+5)(x+6)=0)
Step 1
Concept
\(5\cdot6=30\) and (5+6=11). Therefore the correct factors are ((x+5)(x+6)).
Step 2
Why this answer is correct
The correct answer is A. ((x+5)(x+6)=0). \(5\cdot6=30\) and (5+6=11). Therefore the correct factors are ((x+5)(x+6)).
Step 3
Exam Tip
\(5\cdot6=30\) और (5+6=11) है। इसलिए सही गुणनखंड ((x+5)(x+6)) हैं।
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समीकरण \(x^2+9x+20=0\) को गुणनखंड रूप में कौन-सा लिखा जा सकता है?
Which factor form can represent \(x^2+9x+20=0\)?
#quadratic-equations
#factor-form
#medium
A ((x+4)(x+5)=0)
B ((x-4)(x-5)=0)
C ((x+2)(x+10)=0)
D ((x-1)(x+20)=0)
Explanation opens after your attempt
Correct Answer
A. ((x+4)(x+5)=0)
Step 1
Concept
\(4\cdot5=20\) and (4+5=9). Therefore the correct factors are ((x+4)(x+5)).
Step 2
Why this answer is correct
The correct answer is A. ((x+4)(x+5)=0). \(4\cdot5=20\) and (4+5=9). Therefore the correct factors are ((x+4)(x+5)).
Step 3
Exam Tip
\(4\cdot5=20\) और (4+5=9) है। इसलिए सही गुणनखंड ((x+4)(x+5)) हैं।
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समीकरण \(x^2+7x+12=0\) को गुणनखंड रूप में कौन-सा लिखा जा सकता है?
Which factor form can represent \(x^2+7x+12=0\)?
#quadratic-equations
#factor-form
#medium
A ((x+3)(x+4)=0)
B ((x-3)(x-4)=0)
C ((x+2)(x+6)=0)
D ((x-1)(x+12)=0)
Explanation opens after your attempt
Correct Answer
A. ((x+3)(x+4)=0)
Step 1
Concept
The product of (3) and (4) is (12), and their sum is (7). Therefore ((x+3)(x+4)=0) is correct.
Step 2
Why this answer is correct
The correct answer is A. ((x+3)(x+4)=0). The product of (3) and (4) is (12), and their sum is (7). Therefore ((x+3)(x+4)=0) is correct.
Step 3
Exam Tip
(3) और (4) का गुणनफल (12) और योग (7) है। इसलिए ((x+3)(x+4)=0) सही है।
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कौन सा विकल्प \(x^2+x-12=0\) का गुणनखंड रूप है?
Which option is the factor form of \(x^2+x-12=0\)?
#quadratic equations
#factor form
#verification
A ((x+4)(x-3)=0)
B ((x-4)(x+3)=0)
C ((x+4)(x+3)=0)
D ((x-4)(x-3)=0)
Explanation opens after your attempt
Correct Answer
A. ((x+4)(x-3)=0)
Step 1
Concept
Expanding ((x+4)(x-3)) gives \(x^2+x-12\). To check factors, expand them.
Step 2
Why this answer is correct
The correct answer is A. ((x+4)(x-3)=0). Expanding ((x+4)(x-3)) gives \(x^2+x-12\). To check factors, expand them.
Step 3
Exam Tip
((x+4)(x-3)) फैलाने पर \(x^2+x-12\) मिलता है। गुणनखंड जांचने के लिए विस्तार करें।
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\(x^2-49=0\) को गुणनखंड रूप में कैसे लिखेंगे?
How do we write \(x^2-49=0\) in factor form?
#quadratic equations
#difference of squares
#factor form
A ((x-7)(x+7)=0)
B ((x-49)(x+1)=0)
C ((x+7)(x+7)=0)
D ((x-7)(x-7)=0)
Explanation opens after your attempt
Correct Answer
A. ((x-7)(x+7)=0)
Step 1
Concept
\(x^2-49\) is a difference of squares. Hence it becomes ((x-7)(x+7)).
Step 2
Why this answer is correct
The correct answer is A. ((x-7)(x+7)=0). \(x^2-49\) is a difference of squares. Hence it becomes ((x-7)(x+7)).
Step 3
Exam Tip
\(x^2-49\) वर्गों का अंतर है। इसलिए यह ((x-7)(x+7)) बनता है।
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कौन सा विकल्प \(x^2+10x+25=0\) को गुणनखंड रूप में दिखाता है?
Which option shows \(x^2+10x+25=0\) in factor form?
#quadratic equations
#factor form
#perfect square
A ((x+5)2 =0)
B ((x-5)2 =0)
C ((x+10)2 =0)
D ((x+25)2 =0)
Explanation opens after your attempt
Correct Answer
A. ((x+5)2 =0)
Step 1
Concept
\(x^2+10x+25\) is a perfect square. It equals ((x+5)2 ).
Step 2
Why this answer is correct
The correct answer is A. ((x+5)2 =0). \(x^2+10x+25\) is a perfect square. It equals ((x+5)2 ).
Step 3
Exam Tip
\(x^2+10x+25\) पूर्ण वर्ग है। यह ((x+5)2 ) के बराबर है।
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कौन सा विकल्प \(x^2-2x-15=0\) का गुणनखंड रूप है?
Which option is the factor form of \(x^2-2x-15=0\)?
#quadratic equations
#factor form
#verification
A \((x-5)(x+3)=0\)
B \((x+5)(x-3)=0\)
C \((x-5)(x-3)=0\)
D \((x+5)(x+3)=0\)
Explanation opens after your attempt
Correct Answer
A. \((x-5)(x+3)=0\)
Step 1
Concept
Expanding ((x-5)(x+3)) gives \(x^2-2x-15\). To check factors, expand them.
Step 2
Why this answer is correct
The correct answer is A. \((x-5)(x+3)=0\). Expanding ((x-5)(x+3)) gives \(x^2-2x-15\). To check factors, expand them.
Step 3
Exam Tip
((x-5)(x+3)) फैलाने पर \(x^2-2x-15\) मिलता है। गुणनखंड जांचने के लिए विस्तार करें।
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\(x^2-16=0\) को गुणनखंड रूप में कैसे लिखेंगे?
How do we write \(x^2-16=0\) in factor form?
#quadratic equations
#difference of squares
#factor form
A \((x-4)(x+4)=0\)
B \((x-8)(x+2)=0\)
C \((x+4)(x+4)=0\)
D \((x-4)(x-4)=0\)
Explanation opens after your attempt
Correct Answer
A. \((x-4)(x+4)=0\)
Step 1
Concept
\(x^2-16\) is a difference of squares. Hence it becomes ((x-4)(x+4)).
Step 2
Why this answer is correct
The correct answer is A. \((x-4)(x+4)=0\). \(x^2-16\) is a difference of squares. Hence it becomes ((x-4)(x+4)).
Step 3
Exam Tip
\(x^2-16\) वर्गों का अंतर है। इसलिए यह ((x-4)(x+4)) बनता है।
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कौन सा विकल्प \(x^2+6x+9=0\) को गुणनखंड रूप में दिखाता है?
Which option shows \(x^2+6x+9=0\) in factor form?
#quadratic equations
#factor form
#perfect square
A \((x+3)^2=0\)
B \((x-3)^2=0\)
C \((x+6)^2=0\)
D \((x+9)^2=0\)
Explanation opens after your attempt
Correct Answer
A. \((x+3)^2=0\)
Step 1
Concept
\(x^2+6x+9\) is a perfect square. It equals ((x+3)2 ).
Step 2
Why this answer is correct
The correct answer is A. \((x+3)^2=0\). \(x^2+6x+9\) is a perfect square. It equals ((x+3)2 ).
Step 3
Exam Tip
\(x^2+6x+9\) एक पूर्ण वर्ग है। यह ((x+3)2 ) के बराबर है।
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यदि \(2+\sqrt{3}\) किसी परिमेय गुणांक वाले बहुपद का शून्यक है, तो किस रैखिक गुणनखंड का साथ आना अपेक्षित है?
If \(2+\sqrt{3}\) is a zero of a polynomial with rational coefficients, which linear factor is expected to accompany it?
#factor-theorem
#conjugate-zeroes
#polynomials
A (x-\(2-\sqrt{3}\))
B (x-\(2+\sqrt{3}\)) ही केवल / (x-\(2+\sqrt{3}\)) only
C (x-\(\sqrt{3}-2\))
D (x+\(2+\sqrt{3}\))
Explanation opens after your attempt
Correct Answer
A. (x-\(2-\sqrt{3}\))
Step 1
Concept
The companion zero is \(2-\sqrt{3}\), so the factor is (x-\(2-\sqrt{3}\)). In exams remember the relation between a zero and factor as \(x-\alpha\).
Step 2
Why this answer is correct
The correct answer is A. (x-\(2-\sqrt{3}\)). The companion zero is \(2-\sqrt{3}\), so the factor is (x-\(2-\sqrt{3}\)). In exams remember the relation between a zero and factor as \(x-\alpha\).
Step 3
Exam Tip
साथी शून्यक \(2-\sqrt{3}\) होगा, इसलिए गुणनखंड (x-\(2-\sqrt{3}\)) है। परीक्षा में शून्यक और गुणनखंड का संबंध \(x-\alpha\) याद रखें।
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यदि \(\frac{a}{2^6\cdot 3\cdot 5^4\cdot 7\cdot 13}\) का दशमलव सांत हो तो (a) में कम से कम कौन-सा गुणनखंड होना चाहिए?
If \(\frac{a}{2^6\cdot 3\cdot 5^4\cdot 7\cdot 13}\) is to have a terminating decimal, what factor must (a) contain at minimum?
#minimum-factor
#terminating-condition
#prime-factorisation
#expert
A (91)
B (273)
C (546)
D (819)
Explanation opens after your attempt
Step 1
Concept
The factors (3), (7), and (13) must be removed from the reduced denominator, so the minimum factor is \(3\cdot 7\cdot 13=273\). Factors (2) and (5) may remain.
Step 2
Why this answer is correct
The correct answer is B. (273). The factors (3), (7), and (13) must be removed from the reduced denominator, so the minimum factor is \(3\cdot 7\cdot 13=273\). Factors (2) and (5) may remain.
Step 3
Exam Tip
सरलतम हर से (3), (7) और (13) हटने चाहिए इसलिए न्यूनतम गुणनखंड \(3\cdot 7\cdot 13=273\) है। (2) और (5) हर में रह सकते हैं।
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यदि \(\frac{a}{2^5\cdot 3^4\cdot 5^2\cdot 19}\) का दशमलव सांत हो तो (a) में कम से कम कौन-सा गुणनखंड होना चाहिए?
If \(\frac{a}{2^5\cdot 3^4\cdot 5^2\cdot 19}\) is to have a terminating decimal, what factor must (a) contain at minimum?
#minimum-factor
#prime-factorisation
#terminating-condition
#expert
A (171)
B (1539)
C (3078)
D (7695)
Explanation opens after your attempt
Step 1
Concept
The factors \(3^4\) and (19) must be removed from the reduced denominator, so the minimum factor is \(81\cdot 19=1539\). Factors (2) and (5) may remain.
Step 2
Why this answer is correct
The correct answer is B. (1539). The factors \(3^4\) and (19) must be removed from the reduced denominator, so the minimum factor is \(81\cdot 19=1539\). Factors (2) and (5) may remain.
Step 3
Exam Tip
सरलतम हर से \(3^4\) और (19) हटने चाहिए इसलिए न्यूनतम गुणनखंड \(81\cdot 19=1539\) है। (2) और (5) हर में रह सकते हैं।
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यदि \(\frac{a}{2^4\cdot 3^3\cdot 5^2\cdot 23}\) का दशमलव सांत हो तो (a) में कम से कम कौन-सा गुणनखंड होना चाहिए?
If \(\frac{a}{2^4\cdot 3^3\cdot 5^2\cdot 23}\) is to have a terminating decimal, what factor must (a) contain at minimum?
#minimum-factor
#prime-factorisation
#terminating-condition
#expert
A (69)
B (621)
C (138)
D (2484)
Explanation opens after your attempt
Step 1
Concept
The factors \(3^3\) and (23) must be removed from the reduced denominator, so the minimum factor is \(27\cdot 23=621\). Factors (2) and (5) may remain.
Step 2
Why this answer is correct
The correct answer is B. (621). The factors \(3^3\) and (23) must be removed from the reduced denominator, so the minimum factor is \(27\cdot 23=621\). Factors (2) and (5) may remain.
Step 3
Exam Tip
सरलतम हर से \(3^3\) और (23) हटने चाहिए इसलिए न्यूनतम गुणनखंड \(27\cdot 23=621\) है। (2) और (5) हर में रह सकते हैं।
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यदि \(\frac{a}{2^3\cdot 3^2\cdot 5^4\cdot 17}\) का दशमलव सांत हो, तो (a) में कम से कम कौन-सा गुणनखंड होना चाहिए?
If \(\frac{a}{2^3\cdot 3^2\cdot 5^4\cdot 17}\) is to have a terminating decimal, what factor must (a) contain at minimum?
#minimum-factor
#prime-factorisation
#terminating-condition
#expert
A (153)
B (306)
C (765)
D (1224)
Explanation opens after your attempt
Step 1
Concept
The factors \(3^2\) and (17) must be removed from the reduced denominator, so the minimum factor is \(3^2\cdot 17=153\). Factors (2) and (5) may remain.
Step 2
Why this answer is correct
The correct answer is A. (153). The factors \(3^2\) and (17) must be removed from the reduced denominator, so the minimum factor is \(3^2\cdot 17=153\). Factors (2) and (5) may remain.
Step 3
Exam Tip
सरलतम हर से \(3^2\) और (17) हटने चाहिए, इसलिए न्यूनतम गुणनखंड \(3^2\cdot 17=153\) है। (2) और (5) हर में रह सकते हैं।
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यदि \(\frac{a}{2^2\cdot 3\cdot 5\cdot 19}\) का दशमलव सांत हो, तो (a) में कम से कम कौन-सा गुणनखंड होना चाहिए?
If \(\frac{a}{2^2\cdot 3\cdot 5\cdot 19}\) is to have a terminating decimal, what factor must (a) contain at minimum?
#minimum-factor
#terminating-decimal
#prime-factorisation
#hard
A (19)
B (57)
C (95)
D (285)
Explanation opens after your attempt
Step 1
Concept
The denominator contains (2), (5), (3), and (19).
Step 2
Why this answer is correct
For a terminating decimal, (3) and (19) must cancel. So the minimum factor is \(3\cdot 19=57\).
Step 3
Exam Tip
Only (2) and (5) may remain in the denominator. चरण 1: हर में (2), (5), (3), और (19) हैं। चरण 2: सांत दशमलव के लिए (3) और (19) कटने चाहिए। इसलिए न्यूनतम गुणनखंड \(3\cdot 19=57\) है। चरण 3: केवल (2) और (5) हर में रह सकते हैं।
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यदि \(\frac{x}{540}\) का दशमलव प्रसार सांत है, तो (x) में कम से कम कौन-सा गुणनखंड अवश्य होगा?
If \(\frac{x}{540}\) has a terminating decimal expansion, what factor must (x) contain at minimum?
#minimum-factor
#terminating-condition
#prime-factorisation
#exam
A (9)
B (27)
C (54)
D (108)
Explanation opens after your attempt
Step 1
Concept
\(540=2^2\cdot 3^3\cdot 5\).
Step 2
Why this answer is correct
For a terminating decimal, \(3^3\) must cancel completely from the denominator. So (x) must contain (27).
Step 3
Exam Tip
(2) and (5) may remain, but (3) must not. चरण 1: \(540=2^2\cdot 3^3\cdot 5\) है। चरण 2: सांत दशमलव के लिए सरलतम हर से \(3^3\) पूरी तरह कटना चाहिए। इसलिए (x) में (27) अवश्य होना चाहिए। चरण 3: (2) और (5) रह सकते हैं, पर (3) नहीं।
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\(\frac{a}{2310}\) का दशमलव प्रसार सांत हो, इसके लिए (a) में कम से कम कौन-सा गुणनखंड होना चाहिए?
For \(\frac{a}{2310}\) to have a terminating decimal expansion, what factor must (a) contain at minimum?
#minimum-factor
#terminating-condition
#prime-factorisation
#advanced
A (77)
B (210)
C (231)
D (462)
Explanation opens after your attempt
Step 1
Concept
\(2310=2\cdot 3\cdot 5\cdot 7\cdot 11\).
Step 2
Why this answer is correct
For a terminating decimal, (3), (7), and (11) must cancel from the denominator. So the minimum factor is \(3\cdot 7\cdot 11=231\).
Step 3
Exam Tip
(2) and (5) may remain, but other prime factors must not. चरण 1: \(2310=2\cdot 3\cdot 5\cdot 7\cdot 11\) है। चरण 2: सांत दशमलव के लिए (3), (7), और (11) हर से कटने चाहिए। इसलिए न्यूनतम गुणनखंड \(3\cdot 7\cdot 11=231\) है। चरण 3: (2) और (5) रह सकते हैं, पर अन्य अभाज्य गुणनखंड नहीं।
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यदि \(\frac{m}{735}\) का दशमलव प्रसार सांत है, तो (m) में कम से कम कौन-सा गुणनखंड अवश्य होना चाहिए?
If \(\frac{m}{735}\) has a terminating decimal expansion, what factor must (m) contain at minimum?
#minimum-factor
#terminating-condition
#prime-factorisation
#hard
A (21)
B (49)
C (147)
D (735)
Explanation opens after your attempt
Step 1
Concept
\(735=3\cdot 5\cdot 7^2\).
Step 2
Why this answer is correct
For a terminating decimal, (3) and \(7^2\) must not remain in the reduced denominator. So (m) must contain \(3\cdot 7^2=147\).
Step 3
Exam Tip
The factor (5) may remain, but (3) and (7) must cancel. चरण 1: \(735=3\cdot 5\cdot 7^2\) है। चरण 2: सांत दशमलव के लिए सरलतम हर में (3) और \(7^2\) नहीं बचने चाहिए। इसलिए (m) में \(3\cdot 7^2=147\) अवश्य होना चाहिए। चरण 3: (5) हर में रह सकता है, पर (3) और (7) कटने चाहिए।
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यदि \(\frac{m}{56}\) का दशमलव प्रसार सांत है, तो (m) में कौन-सा गुणनखंड अवश्य होना चाहिए?
If \(\frac{m}{56}\) has a terminating decimal expansion, which factor must (m) contain?
#factor-condition
#terminating-decimal
#prime-factorisation
#real-numbers
A (2)
B (5)
C (7)
D (14)
Explanation opens after your attempt
Step 1
Concept
\(56=2^3\cdot 7\).
Step 2
Why this answer is correct
For a terminating decimal, (7) must not remain in the reduced denominator. Therefore (m) must contain (7).
Step 3
Exam Tip
Cancel all denominator primes other than (2) and (5). चरण 1: \(56=2^3\cdot 7\) है। चरण 2: सांत दशमलव के लिए सरलतम हर में (7) नहीं बचना चाहिए। इसलिए (m) में (7) अवश्य होना चाहिए। चरण 3: हर से (2) और (5) के अलावा बाकी अभाज्य गुणनखंड कटवाएँ।
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यदि सरलतम हर में (17) का गुणनखंड है, तो दशमलव प्रसार कैसा होगा?
If the reduced denominator contains the factor (17), what type of decimal expansion will occur?
#prime factor
#recurring decimal
#real numbers
A समाप्त / Terminating
B असमाप्त आवर्ती / Non-terminating recurring
C असमाप्त अनावर्ती / Non-terminating non-recurring
D निर्धारित नहीं / Cannot be decided
Explanation opens after your attempt
Correct Answer
B. असमाप्त आवर्ती / Non-terminating recurring
Step 1
Concept
(17) is a prime other than (2) and (5).
Step 2
Why this answer is correct
If (17) remains in the reduced denominator, the decimal will not terminate.
Step 3
Exam Tip
Such a non-terminating decimal of a rational number is recurring. चरण 1: (17) एक ऐसा अभाज्य है जो (2) या (5) नहीं है। चरण 2: सरलतम हर में (17) होने पर दशमलव समाप्त नहीं होगा। चरण 3: परिमेय संख्या का ऐसा असमाप्त दशमलव आवर्ती होता है।
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यदि सरलतम हर में (3) का गुणनखंड बचता है, तो परिमेय संख्या का दशमलव प्रसार कैसा होगा?
If the reduced denominator still has the factor (3), what type of decimal expansion will the rational number have?
#recurring decimal
#prime factor
#concept clarity
A समाप्त / Terminating
B असमाप्त आवर्ती / Non-terminating recurring
C असमाप्त अनावर्ती / Non-terminating non-recurring
D शून्य / Zero
Explanation opens after your attempt
Correct Answer
B. असमाप्त आवर्ती / Non-terminating recurring
Step 1
Concept
In the reduced denominator, (3) is a prime other than (2) and (5).
Step 2
Why this answer is correct
So the decimal will not terminate but will repeat.
Step 3
Exam Tip
A non-terminating decimal of a rational number is recurring. चरण 1: सरलतम हर में (3) एक ऐसा अभाज्य है जो (2) या (5) नहीं है। चरण 2: इसलिए दशमलव समाप्त नहीं होगा, पर दोहराव आएगा। चरण 3: परिमेय संख्या का असमाप्त दशमलव हमेशा आवर्ती होता है।
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कथन: \(\frac{p}{q}\) सरल रूप में हो और (q) में (7) का गुणनखंड हो, तो दशमलव समाप्त नहीं होगा। कारण: समाप्त दशमलव के लिए सरल रूप का भाजक केवल (2) और (5) से बनना चाहिए। सही विकल्प चुनिए।
Assertion: If \(\frac{p}{q}\) is in lowest form and (q) has a factor (7), the decimal will not terminate. Reason: For a terminating decimal, the denominator in lowest form must be made only of (2) and (5). Choose the correct option.
#real numbers
#assertion reason
#denominator factor
#class 10
A कथन और कारण दोनों सही हैं, और कारण कथन को समझाता है / Both assertion and reason are true, and the reason explains the assertion
B कथन और कारण दोनों सही हैं, पर कारण कथन को नहीं समझाता / Both are true, but the reason does not explain the assertion
C कथन सही है, कारण गलत है / Assertion is true, reason is false
D कथन गलत है, कारण सही है / Assertion is false, reason is true
Explanation opens after your attempt
Correct Answer
A. कथन और कारण दोनों सही हैं, और कारण कथन को समझाता है / Both assertion and reason are true, and the reason explains the assertion
Step 1
Concept
For a terminating decimal, the denominator in lowest form must be made only of (2) and (5).
Step 2
Why this answer is correct
If (7) remains, this condition fails and the decimal will not terminate.
Step 3
Exam Tip
The reason correctly explains the assertion, so the first option is correct. चरण 1: समाप्त दशमलव के लिए सरल रूप का भाजक केवल (2) और (5) से बना होना चाहिए। चरण 2: यदि (7) बचा है, तो यह शर्त पूरी नहीं होती और दशमलव समाप्त नहीं होगा। चरण 3: कारण कथन को ठीक से समझा रहा है, इसलिए पहला विकल्प सही है।
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यदि सरल रूप में भाजक में (3) का गुणनखंड बचा है, तो परिमेय संख्या का दशमलव विस्तार कैसा होगा?
If a factor (3) remains in the denominator in lowest form, what type of decimal expansion will the rational number have?
#real numbers
#denominator factor 3
#recurring decimal
#class 10
A समाप्त / Terminating
B असमाप्त आवर्ती / Non-terminating recurring
C असमाप्त अनावर्ती / Non-terminating non-recurring
D हमेशा ऋणात्मक / Always negative
Explanation opens after your attempt
Correct Answer
B. असमाप्त आवर्ती / Non-terminating recurring
Step 1
Concept
For a terminating decimal, the denominator should have only (2) and (5).
Step 2
Why this answer is correct
If (3) remains, the decimal will not terminate and will be recurring because the number is rational.
Step 3
Exam Tip
The remaining factors in lowest form decide the result. चरण 1: समाप्त दशमलव के लिए भाजक में केवल (2) और (5) होने चाहिए। चरण 2: (3) बचने पर दशमलव समाप्त नहीं होगा और परिमेय होने से आवर्ती होगा। चरण 3: सरल रूप में बचे गुणनखंड ही निर्णय करते हैं।
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\(\sqrt{5}\) को परिमेय मानकर \(a^2=5b^2\) मिलने पर (a) और (b) में साझा गुणनखंड कैसे बनता है?
After assuming \(\sqrt{5}\) rational and getting \(a^2=5b^2\), how does a common factor appear in (a) and (b)?
#real-numbers
#root5
#common-factor
#proof-flow
A पहले \(5\mid a\), फिर (a=5k) रखने से \(5\mid b\) / First \(5\mid a\), then substituting (a=5k) gives \(5\mid b\)
B पहले (b=0), फिर (a=0) / First (b=0), then (a=0)
C पहले (a=b), फिर (5=1) / First (a=b), then (5=1)
D पहले \(\sqrt{5}=5\), फिर (a=b) / First \(\sqrt{5}=5\), then (a=b)
Explanation opens after your attempt
Correct Answer
A. पहले \(5\mid a\), फिर (a=5k) रखने से \(5\mid b\) / First \(5\mid a\), then substituting (a=5k) gives \(5\mid b\)
Step 1
Concept
From \(a^2=5b^2\), \(5\mid a\).
Step 2
Why this answer is correct
Putting (a=5k) gives \(b^2=5k^2\), so \(5\mid b\).
Step 3
Exam Tip
Now (5) becomes a common factor and gives the contradiction. चरण 1: \(a^2=5b^2\) से \(5\mid a\) मिलता है। चरण 2: (a=5k) रखने पर \(b^2=5k^2\), इसलिए \(5\mid b\)। चरण 3: अब (5) दोनों में साझा गुणनखंड बनकर विरोधाभास देता है।
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कौन सा कथन \(\sqrt{2}\) की सिद्धि में (2) के गुणनखंड की भूमिका सही बताता है?
Which statement correctly tells the role of factor (2) in the proof of \(\sqrt{2}\)?
#sqrt2 proof
#factor 2
#class 10
A यह (p) और (q) दोनों में साझा गुणनखंड बनकर विरोधाभास देता है / It becomes a common factor of both (p) and (q) and gives contradiction
B यह (q=0) बना देता है / It makes (q=0)
C यह \(\sqrt{2}=2\) सिद्ध करता है / It proves \(\sqrt{2}=2\)
D यह (p=q) सिद्ध करता है / It proves (p=q)
Explanation opens after your attempt
Correct Answer
A. यह (p) और (q) दोनों में साझा गुणनखंड बनकर विरोधाभास देता है / It becomes a common factor of both (p) and (q) and gives contradiction
Step 1
Concept
From \(p^2=2q^2\), factor (2) first appears in (p).
Step 2
Why this answer is correct
Later factor (2) also appears in (q).
Step 3
Exam Tip
Common factor (2) contradicts the coprime condition. चरण 1: \(p^2=2q^2\) से पहले (p) में (2) का गुणनखंड आता है। चरण 2: बाद में (q) में भी (2) का गुणनखंड मिलता है। चरण 3: दोनों में (2) साझा होना सहअभाज्य शर्त से टकराता है।
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कौन सा कथन अभाज्य गुणनखंड के नियम को सही बताता है?
Which statement correctly states the prime factor rule?
#prime factor rule
#irrationality proof
#class 10
A यदि अभाज्य संख्या किसी वर्ग को विभाजित करे, तो वह मूल संख्या को भी विभाजित करती है / If a prime divides a square, it also divides the original number
B हर अभाज्य संख्या पूर्ण वर्ग होती है / Every prime number is a perfect square
C हर वर्गमूल परिमेय होता है / Every square root is rational
D यदि संख्या धनात्मक है, तो वह अभाज्य है / If a number is positive, it is prime
Explanation opens after your attempt
Correct Answer
A. यदि अभाज्य संख्या किसी वर्ग को विभाजित करे, तो वह मूल संख्या को भी विभाजित करती है / If a prime divides a square, it also divides the original number
Step 1
Concept
Prime factors in a square occur in pairs.
Step 2
Why this answer is correct
If a prime divides \(p^2\), it also divides (p).
Step 3
Exam Tip
This rule is needed in the proofs of \(\sqrt{3}\) and \(\sqrt{5}\). चरण 1: अभाज्य गुणनखंड वर्ग में जोड़े में आते हैं। चरण 2: यदि कोई अभाज्य \(p^2\) को विभाजित करता है, तो वह (p) को भी विभाजित करेगा। चरण 3: \(\sqrt{3}\) और \(\sqrt{5}\) के प्रमाण में यह नियम जरूरी है।
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