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100 results found for "current-conditions" in Class 10.

नीचे में से कौन-सी स्थिति अनंत हल देती है?

Which of the following conditions gives infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (a_1a_2=b_1 / b_2=c_1 / c_2)

Step 1

Concept

For infinitely many solutions, all three ratios must be equal. Then both equations form the same line.

Step 2

Why this answer is correct

The correct answer is C. \(a_1 / a_2=b_1 / b_2=c_1 / c_2\). For infinitely many solutions, all three ratios must be equal. Then both equations form the same line.

Step 3

Exam Tip

अनंत हल के लिए तीनों अनुपात बराबर होने चाहिए। इससे दोनों समीकरण एक ही रेखा बनाते हैं।

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नीचे में से कौन-सी स्थिति कोई हल नहीं देती?

Which of the following conditions gives no solution?

Explanation opens after your attempt
Correct Answer

A. (a_1a_2=b_1 / b_2 \ne c_1 / c_2)

Step 1

Concept

No solution occurs when the first two ratios are equal and the third is different. This is the condition for parallel lines.

Step 2

Why this answer is correct

The correct answer is A. \(a_1 / a_2=b_1 / b_2 \ne c_1 / c_2\). No solution occurs when the first two ratios are equal and the third is different. This is the condition for parallel lines.

Step 3

Exam Tip

कोई हल नहीं तब होता है जब पहले दो अनुपात बराबर और तीसरा अलग हो। यह parallel lines की शर्त है।

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नीचे में से कौन-सी स्थिति एक अद्वितीय हल देती है?

Which of the following conditions gives a unique solution?

Explanation opens after your attempt
Correct Answer

C. (a_1a_2 \ne b_1 / b_2)

Step 1

Concept

For a unique solution, the ratios of (a) and (b) must be different. This is the condition for intersecting lines.

Step 2

Why this answer is correct

The correct answer is C. \(a_1 / a_2 \ne b_1 / b_2\). For a unique solution, the ratios of (a) and (b) must be different. This is the condition for intersecting lines.

Step 3

Exam Tip

अद्वितीय हल के लिए (a) और (b) के अनुपात अलग होने चाहिए। यह intersecting lines की शर्त है।

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नवउपनिवेशवाद में ऋण शर्तें संप्रभु नीति को कैसे प्रभावित कर सकती हैं?

How can loan conditions affect sovereign policy in neo colonialism?

Explanation opens after your attempt
Correct Answer

A. वे बजट व्यापार और विकास प्राथमिकताओं पर बाहरी प्रभाव डाल सकती हैंThey can create outside influence on budget trade and development priorities

Step 1

Concept

Loans and aid can influence policy even without direct rule. For exams write economic sovereignty.

Step 2

Why this answer is correct

The correct answer is A. वे बजट व्यापार और विकास प्राथमिकताओं पर बाहरी प्रभाव डाल सकती हैं / They can create outside influence on budget trade and development priorities. Loans and aid can influence policy even without direct rule. For exams write economic sovereignty.

Step 3

Exam Tip

ऋण और सहायता प्रत्यक्ष शासन के बिना भी नीति प्रभाव डाल सकते हैं। परीक्षा में आर्थिक संप्रभुता लिखें।

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समीकरण (2x+5y=9) और (4x+10y=18) के लिए हलों की संख्या क्या होगी?

What will be the number of solutions for (2x+5y=9) and (4x+10y=18)?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first so both lines are coincident. Coincident lines have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first so both lines are coincident. Coincident lines have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है इसलिए दोनों रेखाएं संपाती हैं। संपाती रेखाओं में अनंत हल होते हैं।

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यदि \(a_1/a_2=b_1/b_2=c_1/c_2\), तो रेखाओं की स्थिति क्या होगी?

If \(a_1/a_2=b_1/b_2=c_1/c_2\), what will be the position of the lines?

Explanation opens after your attempt
Correct Answer

C. संपाती रेखाएंCoincident lines

Step 1

Concept

When all three ratios are equal, both lines lie on each other. These are called coincident lines.

Step 2

Why this answer is correct

The correct answer is C. संपाती रेखाएं / Coincident lines. When all three ratios are equal, both lines lie on each other. These are called coincident lines.

Step 3

Exam Tip

तीनों अनुपात बराबर होने पर दोनों रेखाएं एक-दूसरे पर ही होती हैं। इसे coincident lines कहते हैं।

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गुडेम आंदोलन में स्थानीय परिस्थिति ने पद्धति को कैसे प्रभावित किया?

How did local conditions influence the method of the Gudem movement?

Explanation opens after your attempt
Correct Answer

A. वन नियंत्रण और जबरन श्रम ने संघर्ष को अधिक उग्र दिशा दीForest control and forced labour gave the struggle a more militant direction

Step 1

Concept

In Gudem tribal problems were deep and linked with life.

Step 2

Why this answer is correct

Therefore the method of resistance became more militant.

Step 3

Exam Tip

Understand method through local causes. चरण 1: गुडेम में आदिवासियों की समस्या गहरी और जीवन से जुड़ी थी। चरण 2: इसी कारण प्रतिरोध का तरीका अधिक उग्र हुआ। चरण 3: पद्धति को स्थानीय कारणों से जोड़कर समझें।

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गुडेम आंदोलन में स्थानीय परिस्थिति ने पद्धति को कैसे प्रभावित किया?

How did local conditions influence the method of the Gudem movement?

Explanation opens after your attempt
Correct Answer

A. वन नियंत्रण और जबरन श्रम ने संघर्ष को अधिक उग्र दिशा दीForest control and forced labour gave the struggle a more militant direction

Step 1

Concept

In Gudem tribal problems were deep and linked with life.

Step 2

Why this answer is correct

Therefore the method of resistance became more militant.

Step 3

Exam Tip

Understand method through local causes. चरण 1: गुडेम में आदिवासियों की समस्या गहरी और जीवन से जुड़ी थी। चरण 2: इसी कारण प्रतिरोध का तरीका अधिक उग्र हुआ। चरण 3: पद्धति को स्थानीय कारणों से जोड़कर समझें।

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बीजाणु निर्माण फफूंद के लिए प्रतिकूल दशाओं में भी लाभकारी क्यों है?

Why is spore formation useful for fungi even in unfavourable conditions?

Explanation opens after your attempt
Correct Answer

A. बीजाणु सुरक्षित रहकर अनुकूल दशा में अंकुरित हो सकते हैंSpores can remain protected and germinate in favourable conditions

Step 1

Concept

Fungal spores are small and can spread.

Step 2

Why this answer is correct

They can remain protected for some time in difficult conditions.

Step 3

Exam Tip

Under favourable conditions they form new fungi. चरण 1: फफूंद में बीजाणु छोटे और फैलने योग्य होते हैं। चरण 2: वे कठिन दशाओं में कुछ समय सुरक्षित रह सकते हैं। चरण 3: अनुकूल दशा मिलने पर वे नए फफूंद बना सकते हैं।

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तराई क्षेत्र में दलदली दशाएं भाबर के बाद क्यों विकसित होती हैं?

Why do marshy conditions develop in Terai after Bhabar?

Explanation opens after your attempt
Correct Answer

A. भूमिगत जल सतह के पास लौटता हैGroundwater returns near the surface

Step 1

Concept

Water that sinks in Bhabar comes near the surface in Terai creating marshy moisture. For exams remember the Bhabar Terai sequence.

Step 2

Why this answer is correct

The correct answer is A. भूमिगत जल सतह के पास लौटता है / Groundwater returns near the surface. Water that sinks in Bhabar comes near the surface in Terai creating marshy moisture. For exams remember the Bhabar Terai sequence.

Step 3

Exam Tip

भाबर में नीचे गया जल तराई में सतह के पास आ जाता है जिससे दलदली नमी बनती है। परीक्षा में भाबर तराई क्रम याद रखें।

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तराई क्षेत्र में रोगजनक दलदली दशाओं का ऐतिहासिक कारण किस भौतिक स्थिति से जुड़ा है?

The historically marshy conditions of Terai are linked with which physical condition?

Explanation opens after your attempt
Correct Answer

A. ऊंचा जलस्तर और अधिक नमीHigh water table and high moisture

Step 1

Concept

In Terai the water table remains near the surface causing moisture and marshes. For exams remember Terai as a moist foothill belt.

Step 2

Why this answer is correct

The correct answer is A. ऊंचा जलस्तर और अधिक नमी / High water table and high moisture. In Terai the water table remains near the surface causing moisture and marshes. For exams remember Terai as a moist foothill belt.

Step 3

Exam Tip

तराई में जलस्तर सतह के पास रहता है जिससे नमी और दलदल बनते हैं। परीक्षा में तराई को नम तलहटी पट्टी याद रखें।

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लद्दाख में ठंडा मरुस्थल बनने के लिए कौन सा संयोजन सबसे सटीक है?

Which combination is most accurate for the formation of cold desert conditions in Ladakh?

Explanation opens after your attempt
Correct Answer

A. ऊंचाई वर्षाछाया और कम वर्षाAltitude rain shadow and low rainfall

Step 1

Concept

Ladakh is cold and dry due to altitude and Himalayan rain shadow. For exams remember the cause of cold desert.

Step 2

Why this answer is correct

The correct answer is A. ऊंचाई वर्षाछाया और कम वर्षा / Altitude rain shadow and low rainfall. Ladakh is cold and dry due to altitude and Himalayan rain shadow. For exams remember the cause of cold desert.

Step 3

Exam Tip

लद्दाख ऊंचाई और हिमालयी वर्षाछाया के कारण ठंडा और शुष्क है। परीक्षा में शीत मरुस्थल का कारण याद रखें।

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तराई क्षेत्र में दलदली दशाओं का निर्माण भाबर से किस प्रकार संबंधित है?

How is the formation of marshy conditions in Terai related to Bhabar?

Explanation opens after your attempt
Correct Answer

A. भाबर में नीचे गया जल तराई में फिर सतह के पास आता हैWater that sinks in Bhabar reappears near the surface in Terai

Step 1

Concept

Water sinking in Bhabar comes near the surface in Terai and creates moisture and marshes. For exams remember the Bhabar Terai sequence.

Step 2

Why this answer is correct

The correct answer is A. भाबर में नीचे गया जल तराई में फिर सतह के पास आता है / Water that sinks in Bhabar reappears near the surface in Terai. Water sinking in Bhabar comes near the surface in Terai and creates moisture and marshes. For exams remember the Bhabar Terai sequence.

Step 3

Exam Tip

भाबर में समाया जल तराई में सतह के पास आने से नमी और दलदल बनते हैं। परीक्षा में भाबर तराई क्रम याद रखें।

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किस भौतिक क्षेत्र में गर्म मरुस्थलीय दशाएं और रेतीले टीलों का विस्तार प्रमुख है?

In which physical region are hot desert conditions and sand dunes dominant?

Explanation opens after your attempt
Correct Answer

A. थार मरुस्थलThar Desert

Step 1

Concept

Hot dry conditions and sandy landforms are found in the Thar Desert. For exams remember Rajasthan and Thar.

Step 2

Why this answer is correct

The correct answer is A. थार मरुस्थल / Thar Desert. Hot dry conditions and sandy landforms are found in the Thar Desert. For exams remember Rajasthan and Thar.

Step 3

Exam Tip

थार मरुस्थल में गर्म शुष्क दशाएं और रेतीले स्थलरूप मिलते हैं। परीक्षा में राजस्थान और थार याद रखें।

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तराई क्षेत्र में दलदली दशाएं किस भौतिक कारण से बनती हैं?

Which physical reason creates marshy conditions in the Terai region?

Explanation opens after your attempt
Correct Answer

A. भूमिगत जल का सतह के पास आनाGroundwater coming near the surface

Step 1

Concept

In Terai water from Bhabar appears near the surface. For exams remember the difference between Bhabar and Terai.

Step 2

Why this answer is correct

The correct answer is A. भूमिगत जल का सतह के पास आना / Groundwater coming near the surface. In Terai water from Bhabar appears near the surface. For exams remember the difference between Bhabar and Terai.

Step 3

Exam Tip

तराई में भाबर से आया जल सतह के पास मिलता है। परीक्षा में भाबर और तराई का अंतर याद रखें।

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थार मरुस्थल में मरुस्थलीय परिस्थितियों का मुख्य कारण क्या है?

What is the main reason for desert conditions in the Thar Desert?

Explanation opens after your attempt
Correct Answer

C. कम वर्षा और शुष्क जलवायुLow rainfall and dry climate

Step 1

Concept

The Thar Desert is a region of low rainfall and high dryness. For exams remember Rajasthan and lack of rainfall.

Step 2

Why this answer is correct

The correct answer is C. कम वर्षा और शुष्क जलवायु / Low rainfall and dry climate. The Thar Desert is a region of low rainfall and high dryness. For exams remember Rajasthan and lack of rainfall.

Step 3

Exam Tip

थार मरुस्थल कम वर्षा और अधिक शुष्कता वाला क्षेत्र है। परीक्षा में राजस्थान और वर्षा की कमी याद रखें।

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अफीम युद्धों के बाद चीन को किन परिस्थितियों का सामना करना पड़ा?

What conditions did China face after the Opium Wars?

Explanation opens after your attempt
Correct Answer

A. असमान संधियां और विदेशी दबावUnequal treaties and foreign pressure

Step 1

Concept

The Opium Wars increased western imperial pressure on China. For exams connect them with unequal treaties.

Step 2

Why this answer is correct

The correct answer is A. असमान संधियां और विदेशी दबाव / Unequal treaties and foreign pressure. The Opium Wars increased western imperial pressure on China. For exams connect them with unequal treaties.

Step 3

Exam Tip

अफीम युद्धों ने चीन पर पश्चिमी साम्राज्यवादी दबाव बढ़ाया। परीक्षा में इन्हें असमान संधियों से जोड़ें।

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रूसी क्रांति में मार्क्सवाद को रूस की परिस्थितियों के अनुसार ढालने का अर्थ क्या था?

What did adapting Marxism to Russian conditions mean in the Russian Revolution?

Explanation opens after your attempt
Correct Answer

A. कम औद्योगिक देश में मजदूर किसान गठबंधन और अग्रणी दल पर जोरEmphasis on worker peasant alliance and vanguard party in a less industrial country

Step 1

Concept

Russia was not industrial like Western Europe so strategy changed. For exams understand Leninism in the Russian context.

Step 2

Why this answer is correct

The correct answer is A. कम औद्योगिक देश में मजदूर किसान गठबंधन और अग्रणी दल पर जोर / Emphasis on worker peasant alliance and vanguard party in a less industrial country. Russia was not industrial like Western Europe so strategy changed. For exams understand Leninism in the Russian context.

Step 3

Exam Tip

रूस पश्चिमी यूरोप जैसा औद्योगिक देश नहीं था इसलिए रणनीति बदली। परीक्षा में लेनिनवाद को रूसी संदर्भ में समझें।

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गौरवपूर्ण क्रांति में विलियम और मैरी को सत्ता देने की शर्तों का महत्व क्या था?

What was the importance of the conditions placed on William and Mary in the Glorious Revolution?

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A. राजा की निरंकुशता के स्थान पर संवैधानिक सीमाएं स्वीकार कराई गईंConstitutional limits were accepted instead of royal absolutism

Step 1

Concept

The transfer of power occurred on Parliament's conditions. For exams treat it as a basis of constitutional monarchy.

Step 2

Why this answer is correct

The correct answer is A. राजा की निरंकुशता के स्थान पर संवैधानिक सीमाएं स्वीकार कराई गईं / Constitutional limits were accepted instead of royal absolutism. The transfer of power occurred on Parliament's conditions. For exams treat it as a basis of constitutional monarchy.

Step 3

Exam Tip

सत्ता हस्तांतरण संसद की शर्तों पर हुआ। परीक्षा में इसे संवैधानिक राजतंत्र का आधार मानें।

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ब्लिट्जक्रिग की सफलता किन परिस्थितियों पर निर्भर थी?

On which conditions did the success of Blitzkrieg depend?

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Correct Answer

C. गति आश्चर्य वायु समर्थन और विरोधी की कमजोर समन्वय परOn speed surprise air support and weak enemy coordination

Step 1

Concept

Blitzkrieg was based on combined arms and rapid decision. For exams remember both its conditions of success and limits.

Step 2

Why this answer is correct

The correct answer is C. गति आश्चर्य वायु समर्थन और विरोधी की कमजोर समन्वय पर / On speed surprise air support and weak enemy coordination. Blitzkrieg was based on combined arms and rapid decision. For exams remember both its conditions of success and limits.

Step 3

Exam Tip

ब्लिट्जक्रिग संयुक्त हथियारों और तेज निर्णय पर आधारित था। परीक्षा में इसकी सफलता की शर्तें और सीमाएं दोनों याद रखें।

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होलोकॉस्ट को केवल युद्ध के माहौल का परिणाम मानना अधूरा क्यों है?

Why is it incomplete to see the Holocaust only as a result of wartime conditions?

Explanation opens after your attempt
Correct Answer

A. यह नाजी विचारधारा राज्य नीति और प्रशासनिक योजना से भी जुड़ा थाIt was also linked with Nazi ideology state policy and administrative planning

Step 1

Concept

The Holocaust was the result of planned racist policy and state violence. For exams understand the role of ideology and administration.

Step 2

Why this answer is correct

The correct answer is A. यह नाजी विचारधारा राज्य नीति और प्रशासनिक योजना से भी जुड़ा था / It was also linked with Nazi ideology state policy and administrative planning. The Holocaust was the result of planned racist policy and state violence. For exams understand the role of ideology and administration.

Step 3

Exam Tip

होलोकॉस्ट योजनाबद्ध नस्लवादी नीति और राज्य हिंसा का परिणाम था। परीक्षा में विचारधारा और प्रशासन की भूमिका समझें।

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प्रथम विश्व युद्ध के बाद किस संधि ने जर्मनी पर कठोर शर्तें लगाईं?

Which treaty imposed harsh conditions on Germany after the First World War?

Explanation opens after your attempt
Correct Answer

B. वर्साय संधिTreaty of Versailles

Step 1

Concept

The Treaty of Versailles in 1919 imposed harsh terms on Germany. For exams connect it with the background of the Second World War.

Step 2

Why this answer is correct

The correct answer is B. वर्साय संधि / Treaty of Versailles. The Treaty of Versailles in 1919 imposed harsh terms on Germany. For exams connect it with the background of the Second World War.

Step 3

Exam Tip

वर्साय संधि 1919 में जर्मनी पर कठोर शर्तों से जुड़ी थी। परीक्षा में इसे द्वितीय विश्व युद्ध की पृष्ठभूमि से जोड़ें।

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औरंगजेब के लंबे शासन में कौन सी दो स्थितियां साथ-साथ दिखीं?

Which two conditions were seen together during Aurangzeb's long reign?

Explanation opens after your attempt
Correct Answer

D. साम्राज्य विस्तार और प्रशासनिक दबावImperial expansion and administrative pressure

Step 1

Concept

The Mughal Empire expanded under Aurangzeb but pressures also increased. Remember him as a last powerful Mughal ruler.

Step 2

Why this answer is correct

The correct answer is D. साम्राज्य विस्तार और प्रशासनिक दबाव / Imperial expansion and administrative pressure. The Mughal Empire expanded under Aurangzeb but pressures also increased. Remember him as a last powerful Mughal ruler.

Step 3

Exam Tip

औरंगजेब के समय मुगल साम्राज्य विस्तृत हुआ पर दबाव भी बढ़े। उसे अंतिम शक्तिशाली मुगल शासक के रूप में याद करें।

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होम रूल आंदोलन ने युद्धकालीन परिस्थिति का उपयोग किस मांग को तेज करने में किया?

The Home Rule Movement used wartime conditions to intensify which demand?

Explanation opens after your attempt
Correct Answer

A. भारत के लिए स्वशासनSelf-government for India

Step 1

Concept

Tilak and Annie Besant popularised self-government demand during wartime. Exam tip: remember the meaning of Home Rule.

Step 2

Why this answer is correct

The correct answer is A. भारत के लिए स्वशासन / Self-government for India. Tilak and Annie Besant popularised self-government demand during wartime. Exam tip: remember the meaning of Home Rule.

Step 3

Exam Tip

युद्धकाल में स्वशासन की मांग को तिलक और एनी बेसेंट ने लोकप्रिय बनाया। परीक्षा में होम रूल का अर्थ याद रखें।

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होम रूल आंदोलन के दौरान युद्धकालीन परिस्थिति ने स्वशासन की मांग को क्यों मजबूत किया?

Why did wartime conditions strengthen the demand for self-government during the Home Rule Movement?

Explanation opens after your attempt
Correct Answer

A. ब्रिटेन भारतीय संसाधन चाहता था और भारतीय नेता राजनीतिक अधिकार चाहते थेBritain wanted Indian resources and Indian leaders wanted political rights

Step 1

Concept

The First World War created a situation of political bargaining. Exam tip is to link Home Rule with wartime politics.

Step 2

Why this answer is correct

The correct answer is A. ब्रिटेन भारतीय संसाधन चाहता था और भारतीय नेता राजनीतिक अधिकार चाहते थे / Britain wanted Indian resources and Indian leaders wanted political rights. The First World War created a situation of political bargaining. Exam tip is to link Home Rule with wartime politics.

Step 3

Exam Tip

प्रथम विश्व युद्ध ने राजनीतिक सौदेबाजी की स्थिति बनाई। परीक्षा में होम रूल को युद्धकालीन राजनीति से जोड़ें।

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उत्तरमेरूर अभिलेख में भूमि स्वामित्व और आयु जैसी पात्रता शर्तें किस चोल विशेषता को दिखाती हैं?

Eligibility conditions like landholding and age in the Uttaramerur inscription show which Chola feature?

Explanation opens after your attempt
Correct Answer

A. स्थानीय प्रशासन में सामाजिक आर्थिक चयन मानदंडSocio-economic selection criteria in local administration

Step 1

Concept

Uttaramerur rules show a limited and rule based selection process. For exams, do not equate it directly with modern democracy.

Step 2

Why this answer is correct

The correct answer is A. स्थानीय प्रशासन में सामाजिक आर्थिक चयन मानदंड / Socio-economic selection criteria in local administration. Uttaramerur rules show a limited and rule based selection process. For exams, do not equate it directly with modern democracy.

Step 3

Exam Tip

उत्तरमेरूर नियम चयन प्रक्रिया को सीमित और नियमबद्ध दिखाते हैं। परीक्षा में इसे आधुनिक लोकतंत्र जैसा सीधे न मानें।

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कुडवोलै प्रणाली में पात्रता और अयोग्यता शर्तें किस चोल प्रशासनिक विशेषता को दिखाती हैं?

Eligibility and disqualification conditions in the Kudavolai system show which Chola administrative feature?

Explanation opens after your attempt
Correct Answer

A. स्थानीय निकायों का नियमबद्ध संचालनRule based functioning of local bodies

Step 1

Concept

The Uttaramerur record shows rule based functioning of village assemblies. For exams, do not equate it directly with modern elections.

Step 2

Why this answer is correct

The correct answer is A. स्थानीय निकायों का नियमबद्ध संचालन / Rule based functioning of local bodies. The Uttaramerur record shows rule based functioning of village assemblies. For exams, do not equate it directly with modern elections.

Step 3

Exam Tip

उत्तरमेरूर लेख ग्रामसभा संचालन में नियमबद्धता दिखाता है। परीक्षा में इसे आधुनिक चुनाव से सीधे समान न मानें।

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युग्म ((y+1)x+2y=3) और (5x+(y-2)y=4) के अद्वितीय हल की सही शर्त कौन-सी है?

Which condition gives a unique solution for ((y+1)x+2y=3) and (5x+(y-2)y=4)?

Explanation opens after your attempt
Correct Answer

B. \(y^2-y-12\neq0\)

Step 1

Concept

The determinant is (D=(y+1)(y-2)-10=y-2-y-12). For a unique solution, \(D\neq0\) is required.

Step 2

Why this answer is correct

The correct answer is B. \(y^2-y-12\neq0\). The determinant is (D=(y+1)(y-2)-10=y-2-y-12). For a unique solution, \(D\neq0\) is required.

Step 3

Exam Tip

सारणिक (D=(y+1)(y-2)-10=y-2-y-12) है। अद्वितीय हल के लिए \(D\neq0\) चाहिए।

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युग्म (tx+9y=6) और (20x+15y=10) के अनंत हलों के लिए (t) का मान क्या होगा?

What is the value of (t) for infinitely many solutions of (tx+9y=6) and (20x+15y=10)?

Explanation opens after your attempt
Correct Answer

C. (t=12)

Step 1

Concept

All three ratios must be \(\frac{3}{5}\). Therefore, \(\frac{t}{20}=\frac{3}{5}\) gives (t=12).

Step 2

Why this answer is correct

The correct answer is C. (t=12). All three ratios must be \(\frac{3}{5}\). Therefore, \(\frac{t}{20}=\frac{3}{5}\) gives (t=12).

Step 3

Exam Tip

तीनों अनुपात \(\frac{3}{5}\) होने चाहिए। इसलिए \(\frac{t}{20}=\frac{3}{5}\) से (t=12)।

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युग्म (sx+4y=12) और (21x+12y=40) में कोई हल न होने के लिए (s) क्या होगा?

What is (s) for no solution in (sx+4y=12) and (21x+12y=40)?

Explanation opens after your attempt
Correct Answer

C. (s=7)

Step 1

Concept

Equating coefficient ratios, \(\frac{s}{21}=\frac{4}{12}\) gives (s=7). The constant ratio is not equal.

Step 2

Why this answer is correct

The correct answer is C. (s=7). Equating coefficient ratios, \(\frac{s}{21}=\frac{4}{12}\) gives (s=7). The constant ratio is not equal.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर \(\frac{s}{21}=\frac{4}{12}\) से (s=7) है। स्थिर पद अनुपात समान नहीं है।

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युग्म (rx+2y=5) और (9x+3y=8) का अद्वितीय हल कब होगा?

When will (rx+2y=5) and (9x+3y=8) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(r\neq6\)

Step 1

Concept

For a unique solution, \(\frac{r}{9}\neq\frac{2}{3}\) is required. Hence \(r\neq6\).

Step 2

Why this answer is correct

The correct answer is B. \(r\neq6\). For a unique solution, \(\frac{r}{9}\neq\frac{2}{3}\) is required. Hence \(r\neq6\).

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{r}{9}\neq\frac{2}{3}\) चाहिए। इसलिए \(r\neq6\) होगा।

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युग्म (qx+11y=22) और (18x+33y=66) के अनंत हलों के लिए (q) का मान क्या है?

What is the value of (q) for infinitely many solutions of (qx+11y=22) and (18x+33y=66)?

Explanation opens after your attempt
Correct Answer

C. (q=6)

Step 1

Concept

For infinitely many solutions, \(\frac{q}{18}=\frac{11}{33}=\frac{22}{66}\). Therefore, (q=6) is correct.

Step 2

Why this answer is correct

The correct answer is C. (q=6). For infinitely many solutions, \(\frac{q}{18}=\frac{11}{33}=\frac{22}{66}\). Therefore, (q=6) is correct.

Step 3

Exam Tip

अनंत हलों में \(\frac{q}{18}=\frac{11}{33}=\frac{22}{66}\) होता है। इसलिए (q=6) सही मान है।

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युग्म (px-5y=7) और (12x-15y=19) में कोई हल न होने के लिए (p) क्या होगा?

What is (p) for no solution in (px-5y=7) and (12x-15y=19)?

Explanation opens after your attempt
Correct Answer

A. (p=4)

Step 1

Concept

Equating coefficient ratios, \(\frac{p}{12}=\frac{-5}{-15}\) gives (p=4). The constant ratio is different.

Step 2

Why this answer is correct

The correct answer is A. (p=4). Equating coefficient ratios, \(\frac{p}{12}=\frac{-5}{-15}\) gives (p=4). The constant ratio is different.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर \(\frac{p}{12}=\frac{-5}{-15}\) से (p=4) है। स्थिर अनुपात अलग है।

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युग्म (3x+ny=18) और (5x+10y=30) के अनंत हलों के लिए (n) क्या होगा?

For infinitely many solutions of (3x+ny=18) and (5x+10y=30), what is (n)?

Explanation opens after your attempt
Correct Answer

C. (n=6)

Step 1

Concept

For infinitely many solutions, \(\frac{3}{5}=\frac{n}{10}=\frac{18}{30}\) is needed. This gives (n=6).

Step 2

Why this answer is correct

The correct answer is C. (n=6). For infinitely many solutions, \(\frac{3}{5}=\frac{n}{10}=\frac{18}{30}\) is needed. This gives (n=6).

Step 3

Exam Tip

अनंत हलों के लिए \(\frac{3}{5}=\frac{n}{10}=\frac{18}{30}\) चाहिए। इससे (n=6) मिलता है।

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युग्म (mx+7y=13) और (16x+14y=26) का अद्वितीय हल कब होगा?

When will (mx+7y=13) and (16x+14y=26) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(m\neq8\)

Step 1

Concept

For a unique solution, \(\frac{m}{16}\neq\frac{7}{14}\) must hold. Therefore, \(m\neq8\).

Step 2

Why this answer is correct

The correct answer is B. \(m\neq8\). For a unique solution, \(\frac{m}{16}\neq\frac{7}{14}\) must hold. Therefore, \(m\neq8\).

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{m}{16}\neq\frac{7}{14}\) होना चाहिए। इसलिए \(m\neq8\)।

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युग्म (2x+3y=4) और (kx+6y=11) में कोई हल न होने के लिए (k) का मान क्या है?

What is the value of (k) for no solution in (2x+3y=4) and (kx+6y=11)?

Explanation opens after your attempt
Correct Answer

C. (k=4)

Step 1

Concept

Equating coefficient ratios, \(\frac{2}{k}=\frac{3}{6}\) gives (k=4). The constant ratio is different.

Step 2

Why this answer is correct

The correct answer is C. (k=4). Equating coefficient ratios, \(\frac{2}{k}=\frac{3}{6}\) gives (k=4). The constant ratio is different.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर \(\frac{2}{k}=\frac{3}{6}\) से (k=4) है। स्थिर पद अनुपात अलग है।

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युग्म (jx+5y=10) और (14x+7y=14) के अनंत हलों के लिए (j) क्या होगा?

For infinitely many solutions of (jx+5y=10) and (14x+7y=14), what is (j)?

Explanation opens after your attempt
Correct Answer

C. (j=10)

Step 1

Concept

All three ratios must be \(\frac{5}{7}\). Therefore, \(\frac{j}{14}=\frac{5}{7}\) gives (j=10).

Step 2

Why this answer is correct

The correct answer is C. (j=10). All three ratios must be \(\frac{5}{7}\). Therefore, \(\frac{j}{14}=\frac{5}{7}\) gives (j=10).

Step 3

Exam Tip

तीनों अनुपात \(\frac{5}{7}\) होने चाहिए। इसलिए \(\frac{j}{14}=\frac{5}{7}\) से (j=10)।

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युग्म (6x+iy=12) और (18x+27y=50) में कोई हल न होने के लिए (i) का मान क्या है?

What is the value of (i) for no solution in (6x+iy=12) and (18x+27y=50)?

Explanation opens after your attempt
Correct Answer

D. (i=9)

Step 1

Concept

Equating coefficient ratios, \(\frac{6}{18}=\frac{i}{27}\) gives (i=9). The constant ratio is not equal.

Step 2

Why this answer is correct

The correct answer is D. (i=9). Equating coefficient ratios, \(\frac{6}{18}=\frac{i}{27}\) gives (i=9). The constant ratio is not equal.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर \(\frac{6}{18}=\frac{i}{27}\) से (i=9) आता है। स्थिर पद अनुपात समान नहीं है।

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युग्म (hx+12y=6) और (10x+15y=20) का अद्वितीय हल कब होगा?

When will (hx+12y=6) and (10x+15y=20) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(h\neq8\)

Step 1

Concept

For a unique solution, \(\frac{h}{10}\neq\frac{12}{15}\) must hold. Hence \(h\neq8\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(h\neq8\). For a unique solution, \(\frac{h}{10}\neq\frac{12}{15}\) must hold. Hence \(h\neq8\) is correct.

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{h}{10}\neq\frac{12}{15}\) होना चाहिए। इसलिए \(h\neq8\) सही है।

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युग्म ((g-1)x+10y=15) और (8x+20y=30) के अनंत हलों के लिए (g) क्या होगा?

For infinitely many solutions of ((g-1)x+10y=15) and (8x+20y=30), what is (g)?

Explanation opens after your attempt
Correct Answer

B. (g=5)

Step 1

Concept

For infinitely many solutions, \(\frac{g-1}{8}=\frac{10}{20}=\frac{15}{30}\) must hold. This gives (g=5).

Step 2

Why this answer is correct

The correct answer is B. (g=5). For infinitely many solutions, \(\frac{g-1}{8}=\frac{10}{20}=\frac{15}{30}\) must hold. This gives (g=5).

Step 3

Exam Tip

अनंत हलों के लिए \(\frac{g-1}{8}=\frac{10}{20}=\frac{15}{30}\) होना चाहिए। इससे (g=5) मिलता है।

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युग्म (7x+fy=2) और (28x+20y=13) में कोई हल न होने के लिए (f) क्या होगा?

What is (f) for no solution in (7x+fy=2) and (28x+20y=13)?

Explanation opens after your attempt
Correct Answer

B. (f=5)

Step 1

Concept

To make the coefficient ratio \(\frac{1}{4}\), (f=5) is required. The different constant ratio gives no solution.

Step 2

Why this answer is correct

The correct answer is B. (f=5). To make the coefficient ratio \(\frac{1}{4}\), (f=5) is required. The different constant ratio gives no solution.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{4}\) बनाने के लिए (f=5) चाहिए। स्थिर पद अनुपात अलग होने से कोई हल नहीं होगा।

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युग्म (ex-4y=9) और (18x-12y=27) का अद्वितीय हल कब होगा?

When will (ex-4y=9) and (18x-12y=27) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(e\neq6\)

Step 1

Concept

For a unique solution, \(\frac{e}{18}\neq\frac{-4}{-12}\) is needed. Hence \(e\neq6\).

Step 2

Why this answer is correct

The correct answer is B. \(e\neq6\). For a unique solution, \(\frac{e}{18}\neq\frac{-4}{-12}\) is needed. Hence \(e\neq6\).

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{e}{18}\neq\frac{-4}{-12}\) चाहिए। अतः \(e\neq6\)।

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युग्म (4x+dy=7) और (12x+15y=21) के अनंत हलों के लिए (d) का मान क्या है?

What is the value of (d) for infinitely many solutions of (4x+dy=7) and (12x+15y=21)?

Explanation opens after your attempt
Correct Answer

C. (d=5)

Step 1

Concept

For infinitely many solutions, \(\frac{4}{12}=\frac{d}{15}=\frac{7}{21}\) must hold. So (d=5) is correct.

Step 2

Why this answer is correct

The correct answer is C. (d=5). For infinitely many solutions, \(\frac{4}{12}=\frac{d}{15}=\frac{7}{21}\) must hold. So (d=5) is correct.

Step 3

Exam Tip

अनंत हलों में \(\frac{4}{12}=\frac{d}{15}=\frac{7}{21}\) होना चाहिए। इसलिए (d=5) सही है।

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युग्म (cx+6y=5) और (9x+18y=10) में कोई हल न होने के लिए (c) क्या होगा?

What is (c) for no solution in (cx+6y=5) and (9x+18y=10)?

Explanation opens after your attempt
Correct Answer

B. (c=3)

Step 1

Concept

Equating coefficient ratios, \(\frac{c}{9}=\frac{6}{18}\) gives (c=3). The constant ratio \(\frac{5}{10}\) is different.

Step 2

Why this answer is correct

The correct answer is B. (c=3). Equating coefficient ratios, \(\frac{c}{9}=\frac{6}{18}\) gives (c=3). The constant ratio \(\frac{5}{10}\) is different.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर \(\frac{c}{9}=\frac{6}{18}\) से (c=3) आता है। स्थिर अनुपात \(\frac{5}{10}\) अलग है।

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युग्म (2x+by=6) और (bx+8y=24) के अनंत हलों के लिए (b) का मान क्या होगा?

What is the value of (b) for infinitely many solutions of (2x+by=6) and (bx+8y=24)?

Explanation opens after your attempt
Correct Answer

C. (b=4)

Step 1

Concept

For infinitely many solutions, \(\frac{2}{b}=\frac{b}{8}=\frac{6}{24}\) must hold. This gives (b=4).

Step 2

Why this answer is correct

The correct answer is C. (b=4). For infinitely many solutions, \(\frac{2}{b}=\frac{b}{8}=\frac{6}{24}\) must hold. This gives (b=4).

Step 3

Exam Tip

अनंत हलों के लिए \(\frac{2}{b}=\frac{b}{8}=\frac{6}{24}\) होना चाहिए। इससे (b=4) मिलता है।

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युग्म (ax+2y=3) और (4x+ay=9) के अद्वितीय हल की शर्त क्या है?

What is the condition for a unique solution of (ax+2y=3) and (4x+ay=9)?

Explanation opens after your attempt
Correct Answer

B. \(a^2\neq8\)

Step 1

Concept

The determinant is \(D=a^2-8\). For a unique solution, \(D\neq0\), so \(a^2\neq8\).

Step 2

Why this answer is correct

The correct answer is B. \(a^2\neq8\). The determinant is \(D=a^2-8\). For a unique solution, \(D\neq0\), so \(a^2\neq8\).

Step 3

Exam Tip

सारणिक \(D=a^2-8\) है। अद्वितीय हल के लिए \(D\neq0\) यानी \(a^2\neq8\)।

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युग्म ((z+2)x+3y=5) और (6x+(z-1)y=7) अद्वितीय न हो, इसके लिए (z) के संभावित मान कौन-से हैं?

For ((z+2)x+3y=5) and (6x+(z-1)y=7) to be non-unique, what are the possible values of (z)?

Explanation opens after your attempt
Correct Answer

A. (z=4,-3)

Step 1

Concept

For non-unique solutions, ((z+2)(z-1)-18=0) must hold. This gives (z=4) or (z=-3).

Step 2

Why this answer is correct

The correct answer is A. (z=4,-3). For non-unique solutions, ((z+2)(z-1)-18=0) must hold. This gives (z=4) or (z=-3).

Step 3

Exam Tip

अद्वितीय न होने के लिए ((z+2)(z-1)-18=0) होना चाहिए। इससे (z=4) या (z=-3) मिलता है।

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यदि (D=0), \(D_x=0\) और \(D_y=0\) हैं, तो दो रैखिक समीकरणों के युग्म में क्या होगा?

If (D=0), \(D_x=0\), and \(D_y=0\), what happens in a pair of two linear equations?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

When all three determinants are zero, the equations may be dependent. In Class (10), link this with infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. When all three determinants are zero, the equations may be dependent. In Class (10), link this with infinitely many solutions.

Step 3

Exam Tip

तीनों सारणिक शून्य होने पर समीकरण आश्रित हो सकते हैं। कक्षा (10) में इसे अनंत हल की स्थिति से जोड़कर देखें।

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यदि \(a_1b_2-a_2b_1\neq0\) है, तो युग्म के बारे में सही कथन क्या है?

If \(a_1b_2-a_2b_1\neq0\), what is the correct statement about the pair?

Explanation opens after your attempt
Correct Answer

C. युग्म का अद्वितीय हल हैThe pair has a unique solution

Step 1

Concept

When the determinant is non-zero, the lines intersect at one point. Hence there is a unique solution.

Step 2

Why this answer is correct

The correct answer is C. युग्म का अद्वितीय हल है / The pair has a unique solution. When the determinant is non-zero, the lines intersect at one point. Hence there is a unique solution.

Step 3

Exam Tip

सारणिक शून्य नहीं होने पर रेखाएँ एक बिंदु पर कटती हैं। इसलिए अद्वितीय हल होता है।

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यदि दो रेखाएँ अलग-अलग समांतर हैं, तो अनुपातों की सही स्थिति कौन-सी होगी?

If two lines are distinct and parallel, what is the correct ratio condition?

Explanation opens after your attempt
Correct Answer

B. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}\)

Step 1

Concept

For distinct parallel lines, coefficient ratios are equal and the constant ratio is different. This is the condition for no solution.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}\). For distinct parallel lines, coefficient ratios are equal and the constant ratio is different. This is the condition for no solution.

Step 3

Exam Tip

अलग समांतर रेखाओं में गुणांक अनुपात समान और स्थिर पद अनुपात अलग होता है। यही कोई हल नहीं की शर्त है।

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यदि दो रेखाओं की ढाल समान और अवरोध भी समान हो, तो उनके समीकरणों के युग्म में कितने हल होंगे?

If two lines have the same slope and the same intercept, how many solutions will their pair of equations have?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

Same slope and same intercept mean the same line. Therefore, such a pair has infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. Same slope and same intercept mean the same line. Therefore, such a pair has infinitely many solutions.

Step 3

Exam Tip

समान ढाल और समान अवरोध का अर्थ एक ही रेखा है। इसलिए ऐसे युग्म में अनंत हल होते हैं।

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यदि \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\) है, तो युग्म की हल-स्थिति क्या होगी?

If \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), what is the solution status of the pair?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

When all three ratios are equal, the lines are coincident. Therefore, infinitely many solutions occur.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. When all three ratios are equal, the lines are coincident. Therefore, infinitely many solutions occur.

Step 3

Exam Tip

तीनों अनुपात समान होने पर रेखाएँ संपाती होती हैं। इसलिए अनंत हल मिलते हैं।

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सामान्य युग्म \(a_1x+b_1y+c_1=0\) और \(a_2x+b_2y+c_2=0\) में अद्वितीय हल की शर्त क्या है?

For the general pair \(a_1x+b_1y+c_1=0\) and \(a_2x+b_2y+c_2=0\), what is the condition for a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\)

Step 1

Concept

A unique solution occurs when the lines intersect at one point. Its ratio form is \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\).

Step 2

Why this answer is correct

The correct answer is B. \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\). A unique solution occurs when the lines intersect at one point. Its ratio form is \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\).

Step 3

Exam Tip

अद्वितीय हल तब मिलता है जब रेखाएँ एक बिंदु पर कटती हैं। इसका अनुपात रूप \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\) है।

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युग्म \(5x+\gamma y=1\) और (25x+15y=11) में कोई हल न होने के लिए \(\gamma\) का मान क्या होगा?

What is the value of \(\gamma\) for no solution in \(5x+\gamma y=1\) and (25x+15y=11)?

Explanation opens after your attempt
Correct Answer

B. \(\gamma=3\)

Step 1

Concept

Equating coefficient ratios, \(\frac{5}{25}=\frac{\gamma}{15}\) gives \(\gamma=3\). The constant ratio is different.

Step 2

Why this answer is correct

The correct answer is B. \(\gamma=3\). Equating coefficient ratios, \(\frac{5}{25}=\frac{\gamma}{15}\) gives \(\gamma=3\). The constant ratio is different.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर \(\frac{5}{25}=\frac{\gamma}{15}\) से \(\gamma=3\) मिलता है। स्थिर अनुपात अलग है।

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युग्म (9x+\(\beta+4\)y=15) और (27x+18y=45) के अनंत हलों के लिए \(\beta\) क्या होगा?

For infinitely many solutions of (9x+\(\beta+4\)y=15) and (27x+18y=45), what is \(\beta\)?

Explanation opens after your attempt
Correct Answer

B. \(\beta=2\)

Step 1

Concept

For infinitely many solutions, \(\frac{9}{27}=\frac{\beta+4}{18}=\frac{15}{45}\) must hold. This gives \(\beta=2\).

Step 2

Why this answer is correct

The correct answer is B. \(\beta=2\). For infinitely many solutions, \(\frac{9}{27}=\frac{\beta+4}{18}=\frac{15}{45}\) must hold. This gives \(\beta=2\).

Step 3

Exam Tip

अनंत हलों में \(\frac{9}{27}=\frac{\beta+4}{18}=\frac{15}{45}\) होना चाहिए। इससे \(\beta=2\) मिलता है।

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युग्म (\(\alpha-1\)x+5y=2) और (8x+10y=6) का अद्वितीय हल कब होगा?

When will (\(\alpha-1\)x+5y=2) and (8x+10y=6) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(\alpha\neq5\)

Step 1

Concept

For a unique solution, \(\frac{\alpha-1}{8}\neq\frac{5}{10}\) is required. Hence \(\alpha\neq5\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(\alpha\neq5\). For a unique solution, \(\frac{\alpha-1}{8}\neq\frac{5}{10}\) is required. Hence \(\alpha\neq5\) is correct.

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{\alpha-1}{8}\neq\frac{5}{10}\) चाहिए। इसलिए \(\alpha\neq5\) सही है।

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युग्म \(14x+\mu y=9\) और (21x+6y=20) में कोई हल न होने के लिए \(\mu\) क्या होगा?

What is \(\mu\) for no solution in \(14x+\mu y=9\) and (21x+6y=20)?

Explanation opens after your attempt
Correct Answer

B. \(\mu=4\)

Step 1

Concept

\(\frac{14}{21}=\frac{2}{3}\). Equating coefficient ratios, \(\frac{\mu}{6}=\frac{2}{3}\) gives \(\mu=4\).

Step 2

Why this answer is correct

The correct answer is B. \(\mu=4\). \(\frac{14}{21}=\frac{2}{3}\). Equating coefficient ratios, \(\frac{\mu}{6}=\frac{2}{3}\) gives \(\mu=4\).

Step 3

Exam Tip

\(\frac{14}{21}=\frac{2}{3}\) है। गुणांक अनुपात समान करने पर \(\frac{\mu}{6}=\frac{2}{3}\) से \(\mu=4\)।

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युग्म \(3x+2y=\lambda\) और (18x+12y=48) के अनंत हलों के लिए \(\lambda\) क्या होगा?

For infinitely many solutions of \(3x+2y=\lambda\) and (18x+12y=48), what is \(\lambda\)?

Explanation opens after your attempt
Correct Answer

B. \(\lambda=8\)

Step 1

Concept

The coefficient ratio is \(\frac{1}{6}\). For infinitely many solutions, \(\frac{\lambda}{48}=\frac{1}{6}\), so \(\lambda=8\).

Step 2

Why this answer is correct

The correct answer is B. \(\lambda=8\). The coefficient ratio is \(\frac{1}{6}\). For infinitely many solutions, \(\frac{\lambda}{48}=\frac{1}{6}\), so \(\lambda=8\).

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{6}\) है। अनंत हलों के लिए \(\frac{\lambda}{48}=\frac{1}{6}\) इसलिए \(\lambda=8\)।

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युग्म (wx-6y=4) और (16x-24y=12) का अद्वितीय हल कब होगा?

When will (wx-6y=4) and (16x-24y=12) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(w\neq4\)

Step 1

Concept

For a unique solution, \(\frac{w}{16}\neq\frac{-6}{-24}\) must hold. Therefore, \(w\neq4\).

Step 2

Why this answer is correct

The correct answer is B. \(w\neq4\). For a unique solution, \(\frac{w}{16}\neq\frac{-6}{-24}\) must hold. Therefore, \(w\neq4\).

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{w}{16}\neq\frac{-6}{-24}\) होना चाहिए। इसलिए \(w\neq4\) होगा।

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युग्म (5x+(v-2)y=3) और (15x+9y=14) में कोई हल न होने के लिए (v) का मान क्या है?

What is the value of (v) for no solution in (5x+(v-2)y=3) and (15x+9y=14)?

Explanation opens after your attempt
Correct Answer

C. (v=5)

Step 1

Concept

Equating coefficient ratios gives (v-2=3). Thus (v=5), and the different constant ratio gives no solution.

Step 2

Why this answer is correct

The correct answer is C. (v=5). Equating coefficient ratios gives (v-2=3). Thus (v=5), and the different constant ratio gives no solution.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर (v-2=3) मिलता है। इसलिए (v=5) और स्थिर अनुपात अलग होने से कोई हल नहीं।

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युग्म ((u+3)x+8y=16) और (10x+20y=40) के अनंत हलों के लिए (u) क्या होगा?

For infinitely many solutions of ((u+3)x+8y=16) and (10x+20y=40), what is (u)?

Explanation opens after your attempt
Correct Answer

A. (u=1)

Step 1

Concept

For infinitely many solutions, \(\frac{u+3}{10}=\frac{8}{20}=\frac{16}{40}\) is needed. This gives (u=1).

Step 2

Why this answer is correct

The correct answer is A. (u=1). For infinitely many solutions, \(\frac{u+3}{10}=\frac{8}{20}=\frac{16}{40}\) is needed. This gives (u=1).

Step 3

Exam Tip

अनंत हलों के लिए \(\frac{u+3}{10}=\frac{8}{20}=\frac{16}{40}\) चाहिए। इससे (u=1) मिलता है।

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युग्म (12x-7y=5) और (18x-11y=8) की हल-संख्या क्या है?

What is the number of solutions of (12x-7y=5) and (18x-11y=8)?

Explanation opens after your attempt
Correct Answer

C. अद्वितीय हलUnique solution

Step 1

Concept

Since \(\frac{12}{18}\neq\frac{-7}{-11}\), the lines intersect. Hence a unique solution is obtained.

Step 2

Why this answer is correct

The correct answer is C. अद्वितीय हल / Unique solution. Since \(\frac{12}{18}\neq\frac{-7}{-11}\), the lines intersect. Hence a unique solution is obtained.

Step 3

Exam Tip

\(\frac{12}{18}\neq\frac{-7}{-11}\) होने से रेखाएँ काटती हैं। इसलिए अद्वितीय हल मिलेगा।

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युग्म (13x+4y=6) और (26x+8y=12) के लिए सही विकल्प चुनिए।

Choose the correct option for (13x+4y=6) and (26x+8y=12).

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

All three ratios are equal. Thus the lines are coincident and the pair has infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. All three ratios are equal. Thus the lines are coincident and the pair has infinitely many solutions.

Step 3

Exam Tip

तीनों अनुपात समान हैं। अतः रेखाएँ संपाती हैं और युग्म के अनंत हल हैं।

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युग्म (4x+9y=2) और (8x+18y=7) की हल-स्थिति क्या है?

What is the solution status of (4x+9y=2) and (8x+18y=7)?

Explanation opens after your attempt
Correct Answer

B. कोई हल नहींNo solution

Step 1

Concept

The coefficient ratio is equal but \(\frac{2}{7}\) is different. Hence both are distinct parallel lines.

Step 2

Why this answer is correct

The correct answer is B. कोई हल नहीं / No solution. The coefficient ratio is equal but \(\frac{2}{7}\) is different. Hence both are distinct parallel lines.

Step 3

Exam Tip

गुणांक अनुपात समान है लेकिन \(\frac{2}{7}\) अलग है। इसलिए दोनों अलग समांतर रेखाएँ हैं।

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युग्म (10x+3y=17) और (20x+9y=31) में कितने हल होंगे?

How many solutions will the pair (10x+3y=17) and (20x+9y=31) have?

Explanation opens after your attempt
Correct Answer

C. अद्वितीय हलUnique solution

Step 1

Concept

Here \(\frac{10}{20}\neq\frac{3}{9}\). Therefore, the lines meet at one point.

Step 2

Why this answer is correct

The correct answer is C. अद्वितीय हल / Unique solution. Here \(\frac{10}{20}\neq\frac{3}{9}\). Therefore, the lines meet at one point.

Step 3

Exam Tip

यहाँ \(\frac{10}{20}\neq\frac{3}{9}\) है। इसलिए रेखाएँ एक बिंदु पर मिलती हैं।

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रेखाएँ (9x-5y=13) और (18x-10y=26) के लिए सही निष्कर्ष क्या है?

What is the correct conclusion for the lines (9x-5y=13) and (18x-10y=26)?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first. So both lines are coincident and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (2) times the first. So both lines are coincident and give infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों रेखाएँ संपाती हैं और अनंत हल देती हैं।

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रेखाएँ (7x+2y=9) और (21x+6y=25) किस प्रकार का युग्म बनाती हैं?

What type of pair is formed by the lines (7x+2y=9) and (21x+6y=25)?

Explanation opens after your attempt
Correct Answer

C. असंगतInconsistent

Step 1

Concept

Coefficient ratios are equal but the constant ratio is different. Hence the lines are parallel and the pair is inconsistent.

Step 2

Why this answer is correct

The correct answer is C. असंगत / Inconsistent. Coefficient ratios are equal but the constant ratio is different. Hence the lines are parallel and the pair is inconsistent.

Step 3

Exam Tip

गुणांक अनुपात समान है पर स्थिर पद का अनुपात अलग है। इसलिए रेखाएँ समांतर हैं और युग्म असंगत है।

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युग्म (6x-ty=18) और (14x-21y=42) के अनंत हलों के लिए (t) का मान क्या होगा?

What is the value of (t) for infinitely many solutions of (6x-ty=18) and (14x-21y=42)?

Explanation opens after your attempt
Correct Answer

C. (t=9)

Step 1

Concept

For infinitely many solutions, \(\frac{6}{14}=\frac{-t}{-21}=\frac{18}{42}\) must hold. This gives (t=9).

Step 2

Why this answer is correct

The correct answer is C. (t=9). For infinitely many solutions, \(\frac{6}{14}=\frac{-t}{-21}=\frac{18}{42}\) must hold. This gives (t=9).

Step 3

Exam Tip

अनंत हलों के लिए \(\frac{6}{14}=\frac{-t}{-21}=\frac{18}{42}\) होना चाहिए। इससे (t=9) मिलता है।

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युग्म (11x+3y=4) और (22x+sy=10) का अद्वितीय हल कब होगा?

When will (11x+3y=4) and (22x+sy=10) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(s\neq6\)

Step 1

Concept

For a unique solution, \(\frac{11}{22}\neq\frac{3}{s}\) must hold. Hence \(s\neq6\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(s\neq6\). For a unique solution, \(\frac{11}{22}\neq\frac{3}{s}\) must hold. Hence \(s\neq6\) is correct.

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{11}{22}\neq\frac{3}{s}\) होना चाहिए। अतः \(s\neq6\) सही है।

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युग्म (2x+ny=7) और (6x+15y=19) में कोई हल न होने के लिए (n) का मान क्या है?

What is the value of (n) for no solution in (2x+ny=7) and (6x+15y=19)?

Explanation opens after your attempt
Correct Answer

C. (n=5)

Step 1

Concept

Equating coefficient ratios, \(\frac{2}{6}=\frac{n}{15}\) gives (n=5). The constant ratio is different, so the pair is inconsistent.

Step 2

Why this answer is correct

The correct answer is C. (n=5). Equating coefficient ratios, \(\frac{2}{6}=\frac{n}{15}\) gives (n=5). The constant ratio is different, so the pair is inconsistent.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर \(\frac{2}{6}=\frac{n}{15}\) से (n=5) मिलता है। स्थिर अनुपात अलग है इसलिए युग्म असंगत है।

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युग्म (5x+(r+1)y=11) और (15x+18y=33) के अनंत हलों के लिए (r) क्या होगा?

For infinitely many solutions of (5x+(r+1)y=11) and (15x+18y=33), what is (r)?

Explanation opens after your attempt
Correct Answer

B. (r=5)

Step 1

Concept

For infinitely many solutions, \(\frac{5}{15}=\frac{r+1}{18}=\frac{11}{33}\) is needed. This gives (r=5).

Step 2

Why this answer is correct

The correct answer is B. (r=5). For infinitely many solutions, \(\frac{5}{15}=\frac{r+1}{18}=\frac{11}{33}\) is needed. This gives (r=5).

Step 3

Exam Tip

अनंत हलों के लिए \(\frac{5}{15}=\frac{r+1}{18}=\frac{11}{33}\) चाहिए। इससे (r=5) मिलता है।

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युग्म (qx+4y=9) और (15x+10y=18) का अद्वितीय हल कब होगा?

When will (qx+4y=9) and (15x+10y=18) have a unique solution?

Explanation opens after your attempt
Correct Answer

A. \(q\neq6\)

Step 1

Concept

For a unique solution, \(\frac{q}{15}\neq\frac{4}{10}\) must hold. Hence \(q\neq6\) is correct.

Step 2

Why this answer is correct

The correct answer is A. \(q\neq6\). For a unique solution, \(\frac{q}{15}\neq\frac{4}{10}\) must hold. Hence \(q\neq6\) is correct.

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{q}{15}\neq\frac{4}{10}\) होना चाहिए। इसलिए \(q\neq6\) सही शर्त है।

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युग्म (3x-2y=5) और (12x-8y=c) में कोई हल न हो इसके लिए (c) पर कौन-सी शर्त होगी?

For (3x-2y=5) and (12x-8y=c) to have no solution, what condition is required on (c)?

Explanation opens after your attempt
Correct Answer

B. \(c\neq20\)

Step 1

Concept

The coefficient ratio is \(\frac{1}{4}\). For no solution, \(\frac{5}{c}\neq\frac{1}{4}\), so \(c\neq20\).

Step 2

Why this answer is correct

The correct answer is B. \(c\neq20\). The coefficient ratio is \(\frac{1}{4}\). For no solution, \(\frac{5}{c}\neq\frac{1}{4}\), so \(c\neq20\).

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{4}\) है। कोई हल नहीं के लिए \(\frac{5}{c}\neq\frac{1}{4}\) इसलिए \(c\neq20\)।

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युग्म (8x+ay=12) और (20x+10y=30) के अनंत हलों के लिए (a) का मान बताइए।

Find the value of (a) for infinitely many solutions of (8x+ay=12) and (20x+10y=30).

Explanation opens after your attempt
Correct Answer

B. (a=4)

Step 1

Concept

Here \(\frac{8}{20}=\frac{12}{30}\). Thus \(\frac{a}{10}=\frac{2}{5}\) gives (a=4).

Step 2

Why this answer is correct

The correct answer is B. (a=4). Here \(\frac{8}{20}=\frac{12}{30}\). Thus \(\frac{a}{10}=\frac{2}{5}\) gives (a=4).

Step 3

Exam Tip

यहाँ \(\frac{8}{20}=\frac{12}{30}\) है। अतः \(\frac{a}{10}=\frac{2}{5}\) से (a=4) होगा।

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युग्म ((p-2)x+7y=14) और (9x+21y=42) के अनंत हलों के लिए (p) क्या होगा?

For infinitely many solutions of ((p-2)x+7y=14) and (9x+21y=42), what is (p)?

Explanation opens after your attempt
Correct Answer

C. (p=5)

Step 1

Concept

For infinitely many solutions, all three ratios must be equal. From \(\frac{p-2}{9}=\frac{7}{21}\), (p=5).

Step 2

Why this answer is correct

The correct answer is C. (p=5). For infinitely many solutions, all three ratios must be equal. From \(\frac{p-2}{9}=\frac{7}{21}\), (p=5).

Step 3

Exam Tip

अनंत हलों के लिए तीनों अनुपात समान होने चाहिए। \(\frac{p-2}{9}=\frac{7}{21}\) से (p=5) मिलता है।

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युग्म (4x+my=8) और (10x+15y=21) में कोई हल न होने के लिए (m) का मान क्या है?

What is the value of (m) for no solution in (4x+my=8) and (10x+15y=21)?

Explanation opens after your attempt
Correct Answer

C. (m=6)

Step 1

Concept

Equating coefficient ratios gives (m=6). The constant ratio is different, so there is no solution.

Step 2

Why this answer is correct

The correct answer is C. (m=6). Equating coefficient ratios gives (m=6). The constant ratio is different, so there is no solution.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर (m=6) मिलता है। स्थिर पद का अनुपात अलग है इसलिए कोई हल नहीं होगा।

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युग्म (kx+5y=10) और (6x+15y=18) का अद्वितीय हल कब होगा?

When will the pair (kx+5y=10) and (6x+15y=18) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(k\neq2\)

Step 1

Concept

For a unique solution, \(\frac{k}{6}\neq\frac{5}{15}\) must hold. Therefore, \(k\neq2\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(k\neq2\). For a unique solution, \(\frac{k}{6}\neq\frac{5}{15}\) must hold. Therefore, \(k\neq2\) is correct.

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{k}{6}\neq\frac{5}{15}\) होना चाहिए। इसलिए \(k\neq2\) सही है।

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समीकरणों (21x+8y=97) और (42x+16y=194) को देखकर कौन-सा कथन सही है?

Which statement is correct by observing the equations (21x+8y=97) and (42x+16y=194)?

Explanation opens after your attempt
Correct Answer

B. रेखाएं एक ही हैंLines are the same

Step 1

Concept

The second equation is (2) times the first. Therefore, both lines are the same and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is B. रेखाएं एक ही हैं / Lines are the same. The second equation is (2) times the first. Therefore, both lines are the same and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों रेखाएं एक ही हैं और अनंत हल हैं।

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दो वस्तुओं की कीमतों के लिए (10x+3y=470) और (20x+6y=955) समीकरण बने। यह प्रणाली कैसी है?

For prices of two items, the equations (10x+3y=470) and (20x+6y=955) are formed. What type of system is this?

Explanation opens after your attempt
Correct Answer

C. असंगतInconsistent

Step 1

Concept

The first two ratios are equal but (470/955) is different. Therefore, the system is inconsistent.

Step 2

Why this answer is correct

The correct answer is C. असंगत / Inconsistent. The first two ratios are equal but (470/955) is different. Therefore, the system is inconsistent.

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं लेकिन (470/955) अलग है। इसलिए प्रणाली असंगत है।

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समीकरणों (7x+19y=86) और (13x+35y=158) में (a) और (b) के अनुपातों की तुलना से क्या निष्कर्ष निकलेगा?

What conclusion follows from comparing the ratios of (a) and (b) in the equations (7x+19y=86) and (13x+35y=158)?

Explanation opens after your attempt
Correct Answer

C. (713 \ne 19 / 35), इसलिए एक अद्वितीय हल / 35), so one unique solution

Step 1

Concept

The first two ratios are different. Therefore, the lines intersect at one point and give one unique solution.

Step 2

Why this answer is correct

The correct answer is C. \(7 / 13 \ne 19 / 35\), इसलिए एक अद्वितीय हल / 35), so one unique solution. The first two ratios are different. Therefore, the lines intersect at one point and give one unique solution.

Step 3

Exam Tip

पहले दो अनुपात अलग हैं। इसलिए रेखाएं एक बिंदु पर कटती हैं और एक अद्वितीय हल देती हैं।

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समीकरणों (12x-7y+29=0) और (36x-21y+91=0) के लिए सही हल-स्थिति क्या है?

What is the correct solution status for the equations (12x-7y+29=0) and (36x-21y+91=0)?

Explanation opens after your attempt
Correct Answer

C. कोई हल नहींNo solution

Step 1

Concept

Here (12/36=(-7)/(-21)) but (29/91) is different. Therefore, the lines are parallel and distinct.

Step 2

Why this answer is correct

The correct answer is C. कोई हल नहीं / No solution. Here (12/36=(-7)/(-21)) but (29/91) is different. Therefore, the lines are parallel and distinct.

Step 3

Exam Tip

यहां (12/36=(-7)/(-21)) लेकिन (29/91) अलग है। इसलिए रेखाएं समानांतर और अलग हैं।

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समीकरणों (11x+ky=70) और (5x+4y=31) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for the equations (11x+ky=70) and (5x+4y=31) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. (k\ne445)

Step 1

Concept

For a unique solution, \(11/5 \ne k/4\) must hold. Therefore, \(k\ne44/5\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is B. \(k\ne44 / 5\). For a unique solution, \(11/5 \ne k/4\) must hold. Therefore, \(k\ne44/5\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(11/5 \ne k/4\) होना चाहिए। इसलिए \(k\ne44/5\) सही शर्त है।

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समीकरणों (px+10y=50) और (14x+35y=122) का कोई हल न होने के लिए (p) का मान क्या होगा?

What is the value of (p) for the equations (px+10y=50) and (14x+35y=122) to have no solution?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

For no solution, (p/14=10/35) and (50/122) must be different. Therefore, (p=4).

Step 2

Why this answer is correct

The correct answer is B. (4). For no solution, (p/14=10/35) and (50/122) must be different. Therefore, (p=4).

Step 3

Exam Tip

कोई हल नहीं के लिए (p/14=10/35) और (50/122) अलग होना चाहिए। इसलिए (p=4)।

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समीकरणों (6x+ay=42) और (18x+33y=126) के अनंत हल होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (6x+ay=42) and (18x+33y=126) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (11)

Step 1

Concept

For infinitely many solutions, (6/18=a/33=42/126) must hold. Therefore, (a=11) is correct.

Step 2

Why this answer is correct

The correct answer is C. (11). For infinitely many solutions, (6/18=a/33=42/126) must hold. Therefore, (a=11) is correct.

Step 3

Exam Tip

अनंत हल के लिए (6/18=a/33=42/126) होना चाहिए। इसलिए (a=11) सही है।

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समीकरणों (5x+9y=64) और (15x+27y=t) के असंगत होने के लिए (t) के लिए सही शर्त क्या है?

What is the correct condition on (t) for the equations (5x+9y=64) and (15x+27y=t) to be inconsistent?

Explanation opens after your attempt
Correct Answer

B. \(t\ne192\)

Step 1

Concept

The first two ratios are equal. For inconsistency, the constant ratio must be different so \(t\ne192\).

Step 2

Why this answer is correct

The correct answer is B. \(t\ne192\). The first two ratios are equal. For inconsistency, the constant ratio must be different so \(t\ne192\).

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं। असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए इसलिए \(t\ne192\)।

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युग्म ((s+2)x+3y=1) और (5x+(s-1)y=4) के अद्वितीय हल की सही शर्त कौन-सी है?

Which condition gives a unique solution for ((s+2)x+3y=1) and (5x+(s-1)y=4)?

Explanation opens after your attempt
Correct Answer

B. \(s^2+s-17\neq0\)

Step 1

Concept

The determinant is (D=(s+2)(s-1)-15=s-2+s-17). For a unique solution, \(D\neq0\) is required.

Step 2

Why this answer is correct

The correct answer is B. \(s^2+s-17\neq0\). The determinant is (D=(s+2)(s-1)-15=s-2+s-17). For a unique solution, \(D\neq0\) is required.

Step 3

Exam Tip

सारणिक (D=(s+2)(s-1)-15=s-2+s-17) है। अद्वितीय हल के लिए \(D\neq0\) चाहिए।

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युग्म \(5x-2y=\gamma\) और (20x-8y=36) के अनंत हलों के लिए \(\gamma\) का मान क्या है?

What is \(\gamma\) for infinitely many solutions of \(5x-2y=\gamma\) and (20x-8y=36)?

Explanation opens after your attempt
Correct Answer

C. \(\gamma=9\)

Step 1

Concept

The coefficient ratio is \(\frac{1}{4}\). For infinitely many solutions, \(\frac{\gamma}{36}=\frac{1}{4}\), so \(\gamma=9\).

Step 2

Why this answer is correct

The correct answer is C. \(\gamma=9\). The coefficient ratio is \(\frac{1}{4}\). For infinitely many solutions, \(\frac{\gamma}{36}=\frac{1}{4}\), so \(\gamma=9\).

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{4}\) है। अनंत हलों के लिए \(\frac{\gamma}{36}=\frac{1}{4}\), इसलिए \(\gamma=9\)।

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युग्म (3x+\(\beta-1\)y=10) और (6x+4y=18) में कोई हल न होने के लिए \(\beta\) क्या होगा?

For no solution in (3x+\(\beta-1\)y=10) and (6x+4y=18), what is \(\beta\)?

Explanation opens after your attempt
Correct Answer

C. \(\beta=3\)

Step 1

Concept

Equating coefficient ratios gives \(\beta=3\). The constant ratio \(\frac{5}{9}\) is different, so there is no solution.

Step 2

Why this answer is correct

The correct answer is C. \(\beta=3\). Equating coefficient ratios gives \(\beta=3\). The constant ratio \(\frac{5}{9}\) is different, so there is no solution.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर \(\beta=3\) मिलता है। स्थिर अनुपात \(\frac{5}{9}\) अलग है, इसलिए कोई हल नहीं।

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युग्म \(\alpha x+4y=7\) और (9x+12y=21) का अद्वितीय हल कब होगा?

When will \(\alpha x+4y=7\) and (9x+12y=21) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(\alpha\neq3\)

Step 1

Concept

For a unique solution, \(\frac{\alpha}{9}\neq\frac{4}{12}\) must hold. Thus \(\alpha\neq3\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(\alpha\neq3\). For a unique solution, \(\frac{\alpha}{9}\neq\frac{4}{12}\) must hold. Thus \(\alpha\neq3\) is correct.

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{\alpha}{9}\neq\frac{4}{12}\) होना चाहिए। इसलिए \(\alpha\neq3\) सही शर्त है।

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युग्म \(rx+\frac{3}{2}y=6\) और (8x+6y=24) के अनंत हलों के लिए (r) का मान क्या है?

What is (r) for infinitely many solutions of \(rx+\frac{3}{2}y=6\) and (8x+6y=24)?

Explanation opens after your attempt
Correct Answer

B. (r=2)

Step 1

Concept

All three ratios must be \(\frac{1}{4}\). Therefore, (r=2) is the correct value.

Step 2

Why this answer is correct

The correct answer is B. (r=2). All three ratios must be \(\frac{1}{4}\). Therefore, (r=2) is the correct value.

Step 3

Exam Tip

तीनों अनुपात \(\frac{1}{4}\) होने चाहिए। इसलिए (r=2) सही मान है।

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युग्म \(\frac{1}{2}x+qy=3\) और (2x+8y=5) के लिए कोई हल न होने पर (q) क्या होगा?

For no solution in \(\frac{1}{2}x+qy=3\) and (2x+8y=5), what is (q)?

Explanation opens after your attempt
Correct Answer

B. (q=2)

Step 1

Concept

Equating coefficient ratios gives (q=2). The constant ratio is not equal, so there is no solution.

Step 2

Why this answer is correct

The correct answer is B. (q=2). Equating coefficient ratios gives (q=2). The constant ratio is not equal, so there is no solution.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर (q=2) मिलता है। स्थिर पद अनुपात समान नहीं है, इसलिए कोई हल नहीं।

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युग्म ((p+4)x-9y=2) और (5x-15y=6) का अद्वितीय हल कब होगा?

When will ((p+4)x-9y=2) and (5x-15y=6) have a unique solution?

Explanation opens after your attempt
Correct Answer

C. \(p\neq-1\)

Step 1

Concept

For a unique solution, \(\frac{p+4}{5}\neq\frac{-9}{-15}\) must hold. Hence \(p\neq-1\).

Step 2

Why this answer is correct

The correct answer is C. \(p\neq-1\). For a unique solution, \(\frac{p+4}{5}\neq\frac{-9}{-15}\) must hold. Hence \(p\neq-1\).

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{p+4}{5}\neq\frac{-9}{-15}\) होना चाहिए। इसलिए \(p\neq-1\)।

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युग्म (4x+(m-5)y=9) और (12x+6y=27) के अनंत हलों के लिए (m) कितना है?

What is (m) for infinitely many solutions of (4x+(m-5)y=9) and (12x+6y=27)?

Explanation opens after your attempt
Correct Answer

C. (m=7)

Step 1

Concept

For infinitely many solutions, \(\frac{4}{12}=\frac{m-5}{6}=\frac{9}{27}\) is required. This gives (m=7).

Step 2

Why this answer is correct

The correct answer is C. (m=7). For infinitely many solutions, \(\frac{4}{12}=\frac{m-5}{6}=\frac{9}{27}\) is required. This gives (m=7).

Step 3

Exam Tip

अनंत हलों के लिए \(\frac{4}{12}=\frac{m-5}{6}=\frac{9}{27}\) चाहिए। इससे (m=7) मिलता है।

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युग्म ((k+1)x+6y=3) और (2x+12y=8) के लिए कोई हल न होने पर (k) का मान क्या होगा?

For no solution in ((k+1)x+6y=3) and (2x+12y=8), what is (k)?

Explanation opens after your attempt
Correct Answer

B. (k=0)

Step 1

Concept

Equating coefficient ratios gives (k=0). The constant ratio \(\frac{3}{8}\) is different, so there is no solution.

Step 2

Why this answer is correct

The correct answer is B. (k=0). Equating coefficient ratios gives (k=0). The constant ratio \(\frac{3}{8}\) is different, so there is no solution.

Step 3

Exam Tip

गुणांक अनुपात समान करने पर (k=0) मिलता है। स्थिर अनुपात \(\frac{3}{8}\) अलग है, इसलिए कोई हल नहीं।

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युग्म ((k-3)x+2y=5) और (4x+ky=11) अद्वितीय न हो, इसके लिए (k) क्या हो सकता है?

For ((k-3)x+2y=5) and (4x+ky=11) to be non-unique, what can (k) be?

Explanation opens after your attempt
Correct Answer

A. \(k=\frac{3\pm\sqrt{41}}{2}\)

Step 1

Concept

For non-unique solutions, the determinant must be zero. From ((k-3)k-8=0), \(k=\frac{3\pm\sqrt{41}}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(k=\frac{3\pm\sqrt{41}}{2}\). For non-unique solutions, the determinant must be zero. From ((k-3)k-8=0), \(k=\frac{3\pm\sqrt{41}}{2}\).

Step 3

Exam Tip

अद्वितीय न होने के लिए सारणिक शून्य होना चाहिए। ((k-3)k-8=0) से \(k=\frac{3\pm\sqrt{41}}{2}\) मिलता है।

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यदि दो रेखाओं की ढाल अलग-अलग हों, तो उनके युग्म के लिए कौन-सा निष्कर्ष सही है?

If two lines have different slopes, which conclusion is correct for their pair?

Explanation opens after your attempt
Correct Answer

C. अद्वितीय हलUnique solution

Step 1

Concept

Lines with different slopes meet at exactly one point. Hence the pair is consistent and independent.

Step 2

Why this answer is correct

The correct answer is C. अद्वितीय हल / Unique solution. Lines with different slopes meet at exactly one point. Hence the pair is consistent and independent.

Step 3

Exam Tip

अलग ढाल वाली रेखाएँ केवल एक बिंदु पर मिलती हैं। इसलिए युग्म संगत और स्वतंत्र होता है।

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यदि दो रेखाओं की ढाल समान और (y)-अवरोध अलग हों, तो उनके समीकरणों के युग्म में कितने हल होंगे?

If two lines have the same slope and different (y)-intercepts, how many solutions will their pair of equations have?

Explanation opens after your attempt
Correct Answer

C. कोई हल नहींNo solution

Step 1

Concept

Same slope and different intercepts mean distinct parallel lines. Therefore, they never intersect.

Step 2

Why this answer is correct

The correct answer is C. कोई हल नहीं / No solution. Same slope and different intercepts mean distinct parallel lines. Therefore, they never intersect.

Step 3

Exam Tip

समान ढाल और अलग अवरोध का अर्थ अलग समांतर रेखाएँ है। इसलिए वे कभी नहीं कटतीं।

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यदि (D=0) और कम से कम एक सहायक सारणिक शून्य नहीं है, तो युग्म की हल-स्थिति क्या होगी?

If (D=0) and at least one auxiliary determinant is non-zero, what is the solution status of the pair?

Explanation opens after your attempt
Correct Answer

C. कोई हल नहींNo solution

Step 1

Concept

(D=0) with a non-zero auxiliary determinant indicates distinct parallel lines. Hence there is no solution.

Step 2

Why this answer is correct

The correct answer is C. कोई हल नहीं / No solution. (D=0) with a non-zero auxiliary determinant indicates distinct parallel lines. Hence there is no solution.

Step 3

Exam Tip

(D=0) और असंगत सहायक सारणिक समांतर अलग रेखाओं का संकेत देते हैं। इसलिए कोई हल नहीं होता।

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संपाती रेखाओं के लिए सही बीजीय शर्त कौन-सी है?

Which algebraic condition is correct for coincident lines?

Explanation opens after your attempt
Correct Answer

C. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\)

Step 1

Concept

Coincident lines represent the same line. Hence all three ratios are equal and infinitely many solutions occur.

Step 2

Why this answer is correct

The correct answer is C. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\). Coincident lines represent the same line. Hence all three ratios are equal and infinitely many solutions occur.

Step 3

Exam Tip

संपाती रेखाएँ एक ही रेखा को दर्शाती हैं। इसलिए तीनों अनुपात समान होते हैं और अनंत हल मिलते हैं।

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यदि \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\) है, तो दो रैखिक समीकरणों के युग्म के लिए क्या निष्कर्ष होगा?

If \(\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\), what is the conclusion for a pair of two linear equations?

Explanation opens after your attempt
Correct Answer

C. अद्वितीय हलUnique solution

Step 1

Concept

When coefficient ratios are different, the lines intersect at one point. Therefore, a unique solution is obtained.

Step 2

Why this answer is correct

The correct answer is C. अद्वितीय हल / Unique solution. When coefficient ratios are different, the lines intersect at one point. Therefore, a unique solution is obtained.

Step 3

Exam Tip

गुणांक अनुपात अलग होने पर रेखाएँ एक बिंदु पर कटती हैं। इसलिए अद्वितीय हल मिलता है।

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