100 results found for "cubic-value" in Class 10.
यदि (x-a), (x-b) और (x-c) किसी घन बहुपद के गुणनखंड हैं, तो उसका एक संभावित बहुपद कौन सा है?
If (x-a), (x-b), and (x-c) are factors of a cubic polynomial, which is a possible polynomial?
#polynomials
#cubic
#factors
#hard
A (x-3 -(a+b+c)x-2 +(ab+bc+ca)x-abc)
B (x-3 +(a+b+c)x-2 +(ab+bc+ca)x+abc)
C (x-3 -(ab+bc+ca)x-2 +(a+b+c)x-abc)
D (x-3 +abcx-2 -(a+b+c)x+ab+bc+ca)
Explanation opens after your attempt
Correct Answer
A. (x-3 -(a+b+c)x-2 +(ab+bc+ca)x-abc)
Step 1
Concept
Expanding ((x-a)(x-b)(x-c)) gives the first form. Remember the link between zeroes and factors.
Step 2
Why this answer is correct
The correct answer is A. (x-3 -(a+b+c)x-2 +(ab+bc+ca)x-abc). Expanding ((x-a)(x-b)(x-c)) gives the first form. Remember the link between zeroes and factors.
Step 3
Exam Tip
((x-a)(x-b)(x-c)) फैलाने पर पहला रूप मिलता है। शून्यकों और गुणनखंडों का संबंध याद रखें।
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निम्न में से त्रिघात बहुपद कौन सा है?
Which of the following is a cubic polynomial?
#cubic-polynomial
#degree
A \(x^3-4x+2\)
B \(x^2+9\)
C (6x-1)
D (12)
Explanation opens after your attempt
Correct Answer
A. \(x^3-4x+2\)
Step 1
Concept
A cubic polynomial has degree (3). In \(x^3-4x+2\), the highest power is (3).
Step 2
Why this answer is correct
The correct answer is A. \(x^3-4x+2\). A cubic polynomial has degree (3). In \(x^3-4x+2\), the highest power is (3).
Step 3
Exam Tip
त्रिघात बहुपद की घात (3) होती है। \(x^3-4x+2\) में सबसे बड़ी घात (3) है।
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यदि किसी घन बहुपद का ग्राफ (x)-अक्ष को (-1) पर काटता है और (2) पर छूता है तो अलग-अलग वास्तविक शून्यक कितने हैं?
If the graph of a cubic polynomial crosses the (x)-axis at (-1) and touches it at (2), how many distinct real zeroes are there?
#cubic
#distinct-zeroes
#graph
A दो / Two
B तीन / Three
C एक / One
D शून्य / Zero
Explanation opens after your attempt
Step 1
Concept
The distinct zeroes are only (-1) and (2). A touching zero may be repeated but its distinct value is counted once.
Step 2
Why this answer is correct
The correct answer is A. दो / Two. The distinct zeroes are only (-1) and (2). A touching zero may be repeated but its distinct value is counted once.
Step 3
Exam Tip
अलग-अलग शून्यक केवल (-1) और (2) हैं। छूने वाला शून्यक दोहराया हो सकता है पर अलग मान एक ही गिना जाता है।
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यदि किसी घन बहुपद का ग्राफ (x)-अक्ष को दो अलग बिंदुओं पर छूता और काटता है, तो अलग वास्तविक शून्यक कितने होंगे?
If the graph of a cubic polynomial touches or crosses the (x)-axis at two distinct points, how many distinct real zeroes will it have?
#cubic
#distinct zeroes
#graph reading
A एक / One
B दो / Two
C तीन / Three
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Step 1
Concept
Distinct zeroes are counted from distinct meeting points with the (x)-axis. Tip: degree gives the maximum, but the actual count is read from the graph.
Step 2
Why this answer is correct
The correct answer is B. दो / Two. Distinct zeroes are counted from distinct meeting points with the (x)-axis. Tip: degree gives the maximum, but the actual count is read from the graph.
Step 3
Exam Tip
अलग शून्यक अलग (x)-अक्ष मिलने वाले बिंदुओं की संख्या से मिलते हैं। टिप: घात से अधिकतम संख्या मिलती है, वास्तविक गिनती ग्राफ से पढ़ें।
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यदि किसी घन बहुपद का ग्राफ (x)-अक्ष को केवल एक बार काटता है, तो वास्तविक शून्यकों की संख्या क्या मानी जाएगी?
If the graph of a cubic polynomial cuts the (x)-axis only once, what is the number of real zeroes?
#cubic graph
#real zero
#count
A एक / One
B दो / Two
C तीन / Three
D शून्य / Zero
Explanation opens after your attempt
Step 1
Concept
There is only one intersection, so there is one real zero. Tip: a cubic can have at most three real zeroes, not necessarily three.
Step 2
Why this answer is correct
The correct answer is A. एक / One. There is only one intersection, so there is one real zero. Tip: a cubic can have at most three real zeroes, not necessarily three.
Step 3
Exam Tip
कटान केवल एक है इसलिए एक वास्तविक शून्यक है। टिप: घन बहुपद में अधिकतम तीन वास्तविक शून्यक हो सकते हैं, जरूरी नहीं कि तीन हों।
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किसी घन बहुपद का आलेख (x)-अक्ष को तीन अलग-अलग बिंदुओं पर काटता है। वास्तविक शून्यकों की संख्या क्या है?
The graph of a cubic polynomial cuts the (x)-axis at three distinct points. What is the number of real zeroes?
#cubic graph zeroes
A तीन / Three
B दो / Two
C एक / One
D शून्य / Zero
Explanation opens after your attempt
Correct Answer
A. तीन / Three
Step 1
Concept
Three intersection points show three real zeroes. Tip: count each distinct (x)-axis intersection.
Step 2
Why this answer is correct
The correct answer is A. तीन / Three. Three intersection points show three real zeroes. Tip: count each distinct (x)-axis intersection.
Step 3
Exam Tip
तीन कटान बिंदु तीन वास्तविक शून्यक बताते हैं। टिप: प्रत्येक अलग (x)-अक्ष कटान को गिनें।
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कौन-सा बहुपद घन बहुपद है?
Which polynomial is a cubic polynomial?
#cubic_polynomial
#degree
#classification
A \(x^3-2x+1\)
B \(x^2+4\)
C (7x-9)
D (5)
Explanation opens after your attempt
Correct Answer
A. \(x^3-2x+1\)
Step 1
Concept
A cubic polynomial has degree (3). The highest power in \(x^3-2x+1\) is (3).
Step 2
Why this answer is correct
The correct answer is A. \(x^3-2x+1\). A cubic polynomial has degree (3). The highest power in \(x^3-2x+1\) is (3).
Step 3
Exam Tip
घन बहुपद की घात (3) होती है। \(x^3-2x+1\) की सबसे बड़ी घात (3) है।
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यदि (x=2) पर (p(x)=x-3 +mx-10) का मान (0) है, तो (m) क्या है?
If the value of (p(x)=x-3 +mx-10) at (x=2) is (0), what is (m)?
#evaluation
#parameter
#cubic
A (1)
B -(1)
C (2)
D -(2)
Explanation opens after your attempt
Step 1
Concept
(p(2)=8+2m-10=0). This gives (2m=2) and (m=1).
Step 2
Why this answer is correct
The correct answer is A. (1). (p(2)=8+2m-10=0). This gives (2m=2) and (m=1).
Step 3
Exam Tip
(p(2)=8+2m-10=0) है। इससे (2m=2) और (m=1) मिलता है।
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यदि (p(x)=x-3 +ax-2 +bx+20), (p(1)=0) और (p(-4)=0), तो (a-b) का मान क्या है?
If (p(x)=x-3 +ax-2 +bx+20), (p(1)=0), and (p(-4)=0), what is the value of (a-b)?
#parameter
#zeros
#cubic polynomial
A (13)
B (15)
C (17)
D (19)
Explanation opens after your attempt
Step 1
Concept
The conditions give (a+b=-21) and (4a-b=11), so (a=-2), (b=-19), and (a-b=17). When two zeros are given, form two equations.
Step 2
Why this answer is correct
The correct answer is C. (17). The conditions give (a+b=-21) and (4a-b=11), so (a=-2), (b=-19), and (a-b=17). When two zeros are given, form two equations.
Step 3
Exam Tip
शर्तों से (a+b=-21) और (4a-b=11) मिलते हैं, इसलिए (a=-2), (b=-19) और (a-b=17)। दो शून्य दिए हों तो दो समीकरण बनाएं।
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यदि (p(x)=3x-3 -12x), तो (p(-2)+p(2)) का मान क्या है?
If (p(x)=3x-3 -12x), what is the value of (p(-2)+p(2))?
#evaluation
#opposite inputs
#cubic
A (-24)
B (0)
C (24)
D (48)
Explanation opens after your attempt
Step 1
Concept
(p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.
Step 3
Exam Tip
(p(-2)=0) और (p(2)=0), इसलिए योग (0) है। विपरीत मानों पर संकेतों को सावधानी से रखें।
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यदि (p(x)=x-3 +ax+b), (p(1)=6) और (p(-2)=-9), तो (a) का मान क्या है?
If (p(x)=x-3 +ax+b), (p(1)=6), and (p(-2)=-9), what is the value of (a)?
#parameter
#cubic
#evaluation
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The conditions give (a+b=5) and (-2a+b=-1). Subtracting gives (3a=6), so (a=2).
Step 2
Why this answer is correct
The correct answer is C. (3). The conditions give (a+b=5) and (-2a+b=-1). Subtracting gives (3a=6), so (a=2).
Step 3
Exam Tip
शर्तों से (a+b=5) और (-2a+b=-1) मिलते हैं। घटाने पर (3a=6) नहीं बल्कि (3a=6), इसलिए (a=2)।
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यदि (p(x)=x-3 +ax+b), (p(2)=13) और (p(-1)=-7), तो (a+b) का मान क्या है?
If (p(x)=x-3 +ax+b), (p(2)=13), and (p(-1)=-7), what is the value of (a+b)?
#parameter
#cubic
#evaluation
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The conditions give (2a+b=5) and (-a+b=-6), so \(a=\frac{11}{3}\) and \(b=-\frac{7}{3}\). Hence \(a+b=\frac{4}{3}\), so none of the listed choices is correct.
Step 2
Why this answer is correct
The correct answer is B. (2). The conditions give (2a+b=5) and (-a+b=-6), so \(a=\frac{11}{3}\) and \(b=-\frac{7}{3}\). Hence \(a+b=\frac{4}{3}\), so none of the listed choices is correct.
Step 3
Exam Tip
शर्तों से (2a+b=5) और (-a+b=-6) मिलते हैं, इसलिए \(a=\frac{11}{3}\) और \(b=-\frac{7}{3}\)। अतः \(a+b=\frac{4}{3}\) नहीं बल्कि विकल्पों में कोई सही नहीं होता।
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(p(x)=4x-3 -11x-2 +6x+2) के लिए (p(2)) का मान क्या है?
What is the value of (p(2)) for (p(x)=4x-3 -11x-2 +6x+2)?
#evaluation
#cubic
#substitution
A (0)
B (2)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
(p(2)=32-44+12+2=2). Evaluate each term separately and then add.
Step 2
Why this answer is correct
The correct answer is B. (2). (p(2)=32-44+12+2=2). Evaluate each term separately and then add.
Step 3
Exam Tip
(p(2)=32-44+12+2=2)। हर पद का मान अलग निकालकर जोड़ें।
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यदि (p(x)=kx-3 +2x-2 -7x+5) और (p(-1)=16), तो (k) का मान क्या है?
If (p(x)=kx-3 +2x-2 -7x+5) and (p(-1)=16), what is the value of (k)?
#evaluation
#parameter
#cubic polynomial
A (-2)
B (-1)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(-1)=-k+2+7+5=14-k), so (14-k=16) and (k=-2). Watch signs carefully when substituting a negative value.
Step 2
Why this answer is correct
The correct answer is A. (-2). (p(-1)=-k+2+7+5=14-k), so (14-k=16) and (k=-2). Watch signs carefully when substituting a negative value.
Step 3
Exam Tip
(p(-1)=-k+2+7+5=14-k), इसलिए (14-k=16) और (k=-2)। ऋणात्मक मान रखने पर संकेतों को ध्यान से देखें।
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यदि (p(x)=x-3 +ax-2 +bx-12), (p(2)=0) और (p(3)=0), तो (a+b) का मान क्या है?
If (p(x)=x-3 +ax-2 +bx-12), (p(2)=0), and (p(3)=0), what is the value of (a+b)?
#parameter
#zeros
#cubic polynomial
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
The conditions give (2a+b=2) and (3a+b=-5), so (a=-7), (b=16), and (a+b=9). When two values are given, form two equations.
Step 2
Why this answer is correct
The correct answer is C. (9). The conditions give (2a+b=2) and (3a+b=-5), so (a=-7), (b=16), and (a+b=9). When two values are given, form two equations.
Step 3
Exam Tip
शर्तों से (2a+b=2) और (3a+b=-5) मिलते हैं, इसलिए (a=-7), (b=16) और (a+b=9)। दो मान दिए हों तो दो समीकरण बनाएं।
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यदि (p(x)=2x-3 -8x), तो (p(-2)+p(2)) का मान क्या है?
If (p(x)=2x-3 -8x), what is the value of (p(-2)+p(2))?
#evaluation
#opposite inputs
#cubic
A (-16)
B (0)
C (16)
D (32)
Explanation opens after your attempt
Step 1
Concept
(p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(-2)=0) and (p(2)=0), so the sum is (0). Handle signs carefully for opposite inputs.
Step 3
Exam Tip
(p(-2)=0) और (p(2)=0), इसलिए योग (0) है। विपरीत मानों पर संकेतों को सावधानी से रखें।
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यदि (p(x)=x-3 +ax+b), (p(1)=6) और (p(-1)=-4), तो (a) का मान क्या है?
If (p(x)=x-3 +ax+b), (p(1)=6), and (p(-1)=-4), what is the value of (a)?
#parameter
#cubic
#evaluation
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
The conditions give (1+a+b=6) and (-1-a+b=-4). Solving them gives (a=4).
Step 2
Why this answer is correct
The correct answer is C. (4). The conditions give (1+a+b=6) and (-1-a+b=-4). Solving them gives (a=4).
Step 3
Exam Tip
शर्तों से (1+a+b=6) और (-1-a+b=-4) मिलते हैं। इन्हें हल करने पर (a=4) मिलता है।
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किस मान के लिए (p(x)=x-3 -5x-2 +mx+8) में (p(1)=0) होगा?
For what value of (m) will (p(1)=0) in (p(x)=x-3 -5x-2 +mx+8)?
#parameter
#evaluation
#cubic
A (-4)
B (-3)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-5+m+8=m+4), so (m=-4). Substitute the given value and solve the equation.
Step 2
Why this answer is correct
The correct answer is A. (-4). (p(1)=1-5+m+8=m+4), so (m=-4). Substitute the given value and solve the equation.
Step 3
Exam Tip
(p(1)=1-5+m+8=m+4), इसलिए (m=-4)। दिए गए मान को रखकर समीकरण हल करें।
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(p(x)=3x-3 -8x-2 +7x-2) के लिए (p(2)) का मान क्या है?
What is the value of (p(2)) for (p(x)=3x-3 -8x-2 +7x-2)?
#evaluation
#cubic
#substitution
A (2)
B (4)
C (6)
D (8)
Explanation opens after your attempt
Step 1
Concept
(p(2)=24-32+14-2=4). Evaluate each term separately and then add.
Step 2
Why this answer is correct
The correct answer is B. (4). (p(2)=24-32+14-2=4). Evaluate each term separately and then add.
Step 3
Exam Tip
(p(2)=24-32+14-2=4)। हर पद का मान अलग निकालकर जोड़ें।
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यदि (p(x)=kx-3 -2x-2 +5x-4) और (p(1)=7), तो (k) का मान क्या है?
If (p(x)=kx-3 -2x-2 +5x-4) and (p(1)=7), what is the value of (k)?
#evaluation
#parameter
#cubic polynomial
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
(p(1)=k-2+5-4=k-1), so (k-1=7) and (k=8). Substitute first and then form a simple equation.
Step 2
Why this answer is correct
The correct answer is C. (8). (p(1)=k-2+5-4=k-1), so (k-1=7) and (k=8). Substitute first and then form a simple equation.
Step 3
Exam Tip
(p(1)=k-2+5-4=k-1), इसलिए (k-1=7) और (k=8)। मान रखने के बाद सरल समीकरण बनाएं।
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यदि (p(x)=x-3 +px-2 +qx-6) के शून्यक (1), (2) और (3) हैं, तो (p+q) का सही मान क्या है?
If the zeroes of (p(x)=x-3 +px-2 +qx-6) are (1), (2), and (3), what is the correct value of (p+q)?
#polynomials
#cubic
#coefficient_matching
#hard
A (5)
B (-5)
C (17)
D (-17)
Explanation opens after your attempt
Step 1
Concept
From ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6), (p=-6) and (q=11). Hence (p+q=5).
Step 2
Why this answer is correct
The correct answer is A. (5). From ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6), (p=-6) and (q=11). Hence (p+q=5).
Step 3
Exam Tip
((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6) से (p=-6) और (q=11)। अतः (p+q=5) है।
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यदि (p(x)=x-3 -4x), तो (p(-2)+p(2)) का मान क्या है?
If (p(x)=x-3 -4x), what is the value of (p(-2)+p(2))?
#evaluation
#opposite inputs
#cubic
A (-8)
B (0)
C (8)
D (16)
Explanation opens after your attempt
Step 1
Concept
(p(-2)=0) and (p(2)=0), so the sum is (0). It behaves like an odd polynomial.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(-2)=0) and (p(2)=0), so the sum is (0). It behaves like an odd polynomial.
Step 3
Exam Tip
(p(-2)=0) और (p(2)=0), इसलिए योग (0) है। यह विषम बहुपद जैसा व्यवहार करता है।
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यदि (p(x)=x-3 +px+q), (p(1)=4) और (p(-1)=-2), तो (p) का मान क्या है?
If (p(x)=x-3 +px+q), (p(1)=4), and (p(-1)=-2), what is the value of (p)?
#parameter
#cubic
#evaluation
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The conditions give (1+p+q=4) and (-1-p+q=-2), so (p=2). Subtracting the two equations is quick.
Step 2
Why this answer is correct
The correct answer is B. (2). The conditions give (1+p+q=4) and (-1-p+q=-2), so (p=2). Subtracting the two equations is quick.
Step 3
Exam Tip
शर्तों से (1+p+q=4) और (-1-p+q=-2), इसलिए (p=2)। दो समीकरणों को घटाना तेज तरीका है।
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किस मान के लिए (p(x)=x-3 -4x-2 +mx+6) में (p(1)=0) होगा?
For what value of (m) will (p(1)=0) in (p(x)=x-3 -4x-2 +mx+6)?
#parameter
#evaluation
#cubic
A (-3)
B (-2)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-4+m+6=m+3), so (m=-3). Substitute the given value and form a simple equation.
Step 2
Why this answer is correct
The correct answer is A. (-3). (p(1)=1-4+m+6=m+3), so (m=-3). Substitute the given value and form a simple equation.
Step 3
Exam Tip
(p(1)=1-4+m+6=m+3), इसलिए (m=-3)। दिए गए मान को रखकर सरल समीकरण बनाएं।
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(p(x)=2x-3 -9x-2 +12x-5) के लिए (p(2)) का मान क्या है?
What is the value of (p(2)) for (p(x)=2x-3 -9x-2 +12x-5)?
#evaluation
#cubic
#substitution
A (-1)
B (0)
C (1)
D (3)
Explanation opens after your attempt
Step 1
Concept
(p(2)=16-36+24-5=-1). Evaluate each term separately and then add.
Step 2
Why this answer is correct
The correct answer is A. (-1). (p(2)=16-36+24-5=-1). Evaluate each term separately and then add.
Step 3
Exam Tip
(p(2)=16-36+24-5=-1)। प्रत्येक पद का मान अलग निकालकर जोड़ें।
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(p(x)=x-3 -2x-2 -5x+6) के लिए कौन सा मान (p(x)=0) बनाता है?
For (p(x)=x-3 -2x-2 -5x+6), which value makes (p(x)=0)?
#zero
#cubic polynomial
#evaluation
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-2-5+6=0), so (1) is a zero of this polynomial. Substituting options is a quick method.
Step 2
Why this answer is correct
The correct answer is A. (1). (p(1)=1-2-5+6=0), so (1) is a zero of this polynomial. Substituting options is a quick method.
Step 3
Exam Tip
(p(1)=1-2-5+6=0), इसलिए (1) इस बहुपद का शून्य है। विकल्पों को रखकर जांचना तेज तरीका है।
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(p(x)=x-3 -4x-2 +x+6) में (p(-1)) का मान क्या है?
What is the value of (p(-1)) in (p(x)=x-3 -4x-2 +x+6)?
#cubic polynomial
#evaluation
#zero
A (0)
B (2)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
(p(-1)=-1-4-1+6=0). Therefore (-1) is a zero of this polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). (p(-1)=-1-4-1+6=0). Therefore (-1) is a zero of this polynomial.
Step 3
Exam Tip
(p(-1)=-1-4-1+6=0)। इसलिए (-1) इस बहुपद का शून्य है।
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यदि (p(x)=x-3 -2x-2 +x), तो (p(1)) का मान क्या है?
If (p(x)=x-3 -2x-2 +x), what is the value of (p(1))?
#cubic-polynomial
#zero
#substitution
A (0)
B (1)
C (2)
D (-1)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-2+1=0). Therefore (1) is a zero of this polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). (p(1)=1-2+1=0). Therefore (1) is a zero of this polynomial.
Step 3
Exam Tip
(p(1)=1-2+1=0) है। इसलिए (1) इस बहुपद का शून्य है।
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यदि (r(x)=x-3 -4x), तो (r(-2)) का मान क्या है?
If (r(x)=x-3 -4x), what is the value of (r(-2))?
#substitution
#cubic-polynomial
#zero
A (0)
B (2)
C (4)
D (-4)
Explanation opens after your attempt
Step 1
Concept
(r(-2)=(-2)3 -4(-2)=-8+8=0). Brackets are important for negative values.
Step 2
Why this answer is correct
The correct answer is A. (0). (r(-2)=(-2)3 -4(-2)=-8+8=0). Brackets are important for negative values.
Step 3
Exam Tip
(r(-2)=(-2)3 -4(-2)=-8+8=0) है। ऋणात्मक मानों में कोष्ठक लगाना जरूरी है।
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बहुपद (p(x)=x-3 -3x-2 +3x-1) का कौन सा मान (0) देता है?
Which value gives (0) for the polynomial (p(x)=x-3 -3x-2 +3x-1)?
#zero
#cubic polynomial
#evaluation
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-3+3-1=0), so (1) is a zero of this polynomial. Substituting options can quickly identify the zero.
Step 2
Why this answer is correct
The correct answer is B. (1). (p(1)=1-3+3-1=0), so (1) is a zero of this polynomial. Substituting options can quickly identify the zero.
Step 3
Exam Tip
(p(1)=1-3+3-1=0), इसलिए (1) इस बहुपद का शून्य है। विकल्पों को रखने से शून्य जल्दी मिल सकता है।
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(p(x)=x-3 -6x-2 +11x-6) में (p(1)) का मान क्या है?
What is the value of (p(1)) in (p(x)=x-3 -6x-2 +11x-6)?
#evaluation
#cubic polynomial
#zero
A (0)
B (1)
C (6)
D (11)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-6+11-6=0). Therefore (1) is a zero of this polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). (p(1)=1-6+11-6=0). Therefore (1) is a zero of this polynomial.
Step 3
Exam Tip
(p(1)=1-6+11-6=0)। इसलिए (1) इस बहुपद का शून्य है।
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यदि \(x=\sqrt{6}+\sqrt{5}\), तो \(x^3+\frac{1}{x^3}\) का मान और प्रकृति क्या है?
If \(x=\sqrt{6}+\sqrt{5}\), what is the value and nature of \(x^3+\frac{1}{x^3}\)?
#reciprocal surds
#cubic identity
#irrational numbers
#class 10
A \(42\sqrt{6}\), अपरिमेय / \(42\sqrt{6}\), irrational
B (42), परिमेय / (42), rational
C \(36\sqrt{5}\), अपरिमेय / \(36\sqrt{5}\), irrational
D \(11\sqrt{6}\), अपरिमेय / \(11\sqrt{6}\), irrational
Explanation opens after your attempt
Correct Answer
A. \(42\sqrt{6}\), अपरिमेय / \(42\sqrt{6}\), irrational
Step 1
Concept
(\(\sqrt{6}+\sqrt{5}\)\(\sqrt{6}-\sqrt{5}\)=1), so \(\frac{1}{x}=\sqrt{6}-\sqrt{5}\).
Step 2
Why this answer is correct
\(x+\frac{1}{x}=2\sqrt{6}\), hence (x-3 +\frac{1}{x-3 }=\(2\sqrt{6}\)3 -3\(2\sqrt{6}\)=42\sqrt{6}).
Step 3
Exam Tip
In cube-type questions, finding \(x+\frac{1}{x}\) first is the easier method. चरण 1: (\(\sqrt{6}+\sqrt{5}\)\(\sqrt{6}-\sqrt{5}\)=1), इसलिए \(\frac{1}{x}=\sqrt{6}-\sqrt{5}\)। चरण 2: \(x+\frac{1}{x}=2\sqrt{6}\), अतः (x-3 +\frac{1}{x-3 }=\(2\sqrt{6}\)3 -3\(2\sqrt{6}\)=42\sqrt{6})। चरण 3: घन वाले प्रश्नों में पहले \(x+\frac{1}{x}\) निकालना आसान तरीका है।
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यदि (p(x)=x-3 -2x), तो (p\(\sqrt{2}\)) क्या है?
If (p(x)=x-3 -2x), what is (p\(\sqrt{2}\))?
#cubic polynomial
#irrational value
#zero
A (0)
B \(\sqrt{2}\)
C \(2\sqrt{2}\)
D (4)
Explanation opens after your attempt
Step 1
Concept
(\(\sqrt{2}\)3 =2\sqrt{2}), so \(2\sqrt{2}-2\sqrt{2}=0\). Remember (\(\sqrt{a}\)3 =a\sqrt{a}).
Step 2
Why this answer is correct
The correct answer is A. (0). (\(\sqrt{2}\)3 =2\sqrt{2}), so \(2\sqrt{2}-2\sqrt{2}=0\). Remember (\(\sqrt{a}\)3 =a\sqrt{a}).
Step 3
Exam Tip
(\(\sqrt{2}\)3 =2\sqrt{2}), इसलिए \(2\sqrt{2}-2\sqrt{2}=0\) है। परीक्षा में (\(\sqrt{a}\)3 =a\sqrt{a}) याद रखें।
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मान के अध्ययन में मध्यम मान की भूमिका क्या है?
What is the role of middle value in value study?
#middle value
#transition
#shading
A प्रकाश और छाया के बीच संक्रमण बनाना / Creating transition between light and shadow
B रंग का नाम बदलना / Changing colour name
C आकार मिटाना / Erasing shape
D कागज काटना / Cutting paper
Explanation opens after your attempt
Correct Answer
A. प्रकाश और छाया के बीच संक्रमण बनाना / Creating transition between light and shadow
Step 1
Concept
Middle value connects light and dark parts. Exam tip: connect mid value with transition.
Step 2
Why this answer is correct
The correct answer is A. प्रकाश और छाया के बीच संक्रमण बनाना / Creating transition between light and shadow. Middle value connects light and dark parts. Exam tip: connect mid value with transition.
Step 3
Exam Tip
मध्यम मान उजले और गहरे भागों को जोड़ता है। परीक्षा में mid value को transition से जोड़ें।
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यदि (p(x)=x-3 -1), तो निम्न में से कौन-सा रैखिक गुणनखंड है?
If (p(x)=x-3 -1), which of the following is a linear factor?
#identity
#cubic
#factorisation
A (x-1)
B (x+1)
C (x-3)
D (x+3)
Explanation opens after your attempt
Step 1
Concept
(x-3 -1=(x-1)\(x^2+x+1\)). Therefore (x-1) is a linear factor.
Step 2
Why this answer is correct
The correct answer is A. (x-1). (x-3 -1=(x-1)\(x^2+x+1\)). Therefore (x-1) is a linear factor.
Step 3
Exam Tip
(x-3 -1=(x-1)\(x^2+x+1\)) है। इसलिए (x-1) रैखिक गुणनखंड है।
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यदि (p(x)=x-3 -3x-2 -4x+12), तो पूर्ण गुणनखंड रूप क्या है?
If (p(x)=x-3 -3x-2 -4x+12), what is the complete factor form?
#factorisation
#grouping
#cubic
A ((x-3)(x-2)(x+2))
B ((x+3)(x-2)(x+2))
C ((x-3)(x+2)2 )
D ((x+3)(x-2)2 )
Explanation opens after your attempt
Correct Answer
A. ((x-3)(x-2)(x+2))
Step 1
Concept
By grouping, (x-2 (x-3)-4(x-3)=(x-3)\(x^2-4\)). Thus the factors are ((x-3)(x-2)(x+2)).
Step 2
Why this answer is correct
The correct answer is A. ((x-3)(x-2)(x+2)). By grouping, (x-2 (x-3)-4(x-3)=(x-3)\(x^2-4\)). Thus the factors are ((x-3)(x-2)(x+2)).
Step 3
Exam Tip
समूहीकरण से (x-2 (x-3)-4(x-3)=(x-3)\(x^2-4\)) मिलता है। इसलिए गुणनखंड ((x-3)(x-2)(x+2)) हैं।
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यदि (p(x)=x-3 +px-2 +qx+15) के शून्यक (-1,3,-5) हैं, तो (p+q) क्या है?
If the zeroes of (p(x)=x-3 +px-2 +qx+15) are (-1,3,-5), what is (p+q)?
#cubic-zeroes
#coefficients
#trap
A (0)
B (2)
C -(2)
D (4)
Explanation opens after your attempt
Step 1
Concept
The sum of zeroes is (-3), so (p=3). The pairwise product sum is (-3+5-15=-13), so (q=-13) and (p+q=-10).
Step 2
Why this answer is correct
The correct answer is B. (2). The sum of zeroes is (-3), so (p=3). The pairwise product sum is (-3+5-15=-13), so (q=-13) and (p+q=-10).
Step 3
Exam Tip
शून्यकों का योग (-3) है, इसलिए (p=3)। युग्म गुणनफलों का योग (-3+5-15=-13), इसलिए (q=-13) और (p+q=-10)।
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यदि (p(x)=x-3 -9x), तो इसके कितने भिन्न वास्तविक शून्यक हैं?
If (p(x)=x-3 -9x), how many distinct real zeroes does it have?
#distinct-zeroes
#cubic
#factorisation
A (3)
B (2)
C (1)
D (0)
Explanation opens after your attempt
Step 1
Concept
(x-3 -9x=x(x-3)(x+3)), so the zeroes are (-3,0,3). Hence there are (3) distinct real zeroes.
Step 2
Why this answer is correct
The correct answer is A. (3). (x-3 -9x=x(x-3)(x+3)), so the zeroes are (-3,0,3). Hence there are (3) distinct real zeroes.
Step 3
Exam Tip
(x-3 -9x=x(x-3)(x+3)), इसलिए शून्यक (-3,0,3) हैं। अतः भिन्न वास्तविक शून्यक (3) हैं।
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यदि (p(x)=x-3 +ax-2 +bx-12) के शून्यक (1,3,-4) हैं, तो (a+b) क्या है?
If the zeroes of (p(x)=x-3 +ax-2 +bx-12) are (1,3,-4), what is (a+b)?
#cubic-zeroes
#coefficients
#expert
A -(9)
B (9)
C -(7)
D (7)
Explanation opens after your attempt
Step 1
Concept
The sum (1+3-4=0), so (a=0). The sum of pairwise products is (3-4-12=-13), so (b=-13) and (a+b=-13).
Step 2
Why this answer is correct
The correct answer is A. -(9). The sum (1+3-4=0), so (a=0). The sum of pairwise products is (3-4-12=-13), so (b=-13) and (a+b=-13).
Step 3
Exam Tip
योग (1+3-4=0) है, इसलिए (a=0)। युग्म गुणनफलों का योग (3-4-12=-13), इसलिए (b=-13) और (a+b=-13)।
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यदि (p(x)=x-3 -6x-2 +12x-8), तो (p(x)) का शून्यक किस गुणनता के साथ है?
If (p(x)=x-3 -6x-2 +12x-8), what is the zero of (p(x)) with its multiplicity?
#multiplicity
#cubic
#identity
A (2) गुणनता (3) / (2) with multiplicity (3)
B (3) गुणनता (2) / (3) with multiplicity (2)
C -(2) गुणनता (3) / (-2) with multiplicity (3)
D (1) गुणनता (3) / (1) with multiplicity (3)
Explanation opens after your attempt
Correct Answer
A. (2) गुणनता (3) / (2) with multiplicity (3)
Step 1
Concept
This is (p(x)=(x-2)3 ), so (2) is a zero three times. Recognizing cube identities is useful.
Step 2
Why this answer is correct
The correct answer is A. (2) गुणनता (3) / (2) with multiplicity (3). This is (p(x)=(x-2)3 ), so (2) is a zero three times. Recognizing cube identities is useful.
Step 3
Exam Tip
यह (p(x)=(x-2)3 ) है, इसलिए (2) तीन बार शून्यक है। घन पूर्ण पहचान को पहचानना उपयोगी है।
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यदि (p(x)=x-3 -4x-2 -7x+10) और (x-1) इसका गुणनखंड है, तो शेष द्विघात गुणनखंड क्या है?
If (p(x)=x-3 -4x-2 -7x+10) and (x-1) is a factor, what is the remaining quadratic factor?
#division
#factorisation
#cubic
A \(x^2-3x-10\)
B \(x^2+3x-10\)
C \(x^2-5x+10\)
D \(x^2-4x-7\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-3x-10\)
Step 1
Concept
Dividing (p(x)) by (x-1) gives \(x^2-3x-10\). Verify by multiplying ((x-1)\(x^2-3x-10\)=p(x)).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-3x-10\). Dividing (p(x)) by (x-1) gives \(x^2-3x-10\). Verify by multiplying ((x-1)\(x^2-3x-10\)=p(x)).
Step 3
Exam Tip
(p(x)) को (x-1) से भाग देने पर \(x^2-3x-10\) मिलता है। गुणा करके जाँचें कि ((x-1)\(x^2-3x-10\)=p(x))।
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यदि (p(x)=x-3 -2x-2 -13x-10) है, तो इनमें से कौन (p(x)) का शून्यक है?
If (p(x)=x-3 -2x-2 -13x-10), which of the following is a zero of (p(x))?
#zero-test
#cubic
#polynomial
A (5)
B (2)
C -(1)
D -(2)
Explanation opens after your attempt
Step 1
Concept
(p(-2)=-8-8+26-10=0), so (-2) is a zero. Test small option values by direct substitution.
Step 2
Why this answer is correct
The correct answer is D. -(2). (p(-2)=-8-8+26-10=0), so (-2) is a zero. Test small option values by direct substitution.
Step 3
Exam Tip
(p(-2)=-8-8+26-10=0), इसलिए (-2) शून्यक है। विकल्पों में दिए छोटे मानों को सीधे रखकर जाँचें।
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(p(x)=x-3 -x-2 -4x+4) में (p(2)-p(-2)) क्या है?
For (p(x)=x-3 -x-2 -4x+4), what is (p(2)-p(-2))?
#evaluation
#difference
#cubic
A (0)
B (8)
C (16)
D (24)
Explanation opens after your attempt
Step 1
Concept
(p(2)=0) and (p(-2)=-16), so (p(2)-p(-2)=16). While subtracting, the sign of the second value changes.
Step 2
Why this answer is correct
The correct answer is C. (16). (p(2)=0) and (p(-2)=-16), so (p(2)-p(-2)=16). While subtracting, the sign of the second value changes.
Step 3
Exam Tip
(p(2)=0) और (p(-2)=-16), इसलिए (p(2)-p(-2)=16)। घटाते समय दूसरे मान का संकेत बदलता है।
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(p(x)=x-3 -3x-2 -4x+12) में (p(2)) और (p(-2)) का गुणनफल क्या है?
What is the product of (p(2)) and (p(-2)) for (p(x)=x-3 -3x-2 -4x+12)?
#evaluation
#product
#cubic
A (-32)
B (0)
C (32)
D (64)
Explanation opens after your attempt
Step 1
Concept
(p(2)=8-12-8+12=0), so the product is (0). If one value is (0), the whole product is (0).
Step 2
Why this answer is correct
The correct answer is B. (0). (p(2)=8-12-8+12=0), so the product is (0). If one value is (0), the whole product is (0).
Step 3
Exam Tip
(p(2)=8-12-8+12=0), इसलिए गुणनफल (0) होगा। एक मान (0) हो तो पूरा गुणनफल (0) होता है।
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यदि (p(x)=x-3 -6x-2 +12x-8), तो (p(5)) क्या है?
If (p(x)=x-3 -6x-2 +12x-8), what is (p(5))?
#identity
#cubic
#evaluation
A (8)
B (18)
C (27)
D (32)
Explanation opens after your attempt
Step 1
Concept
It is ((x-2)3 ), so (p(5)=(5-2)3 =27). Recognizing identities reduces calculation.
Step 2
Why this answer is correct
The correct answer is C. (27). It is ((x-2)3 ), so (p(5)=(5-2)3 =27). Recognizing identities reduces calculation.
Step 3
Exam Tip
यह ((x-2)3 ) है, इसलिए (p(5)=(5-2)3 =27)। पहचान पहचानने से गणना कम होती है।
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यदि (p(x)=x-3 +ax-2 +bx-10) में (x=1) और (x=5) दोनों शून्य हैं, तो (a) क्या है?
If (x=1) and (x=5) are both zeros of (p(x)=x-3 +ax-2 +bx-10), what is (a)?
#zeros
#cubic
#parameter
A (-7)
B (-6)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
(p(1)=0) gives (a+b=9) and (p(5)=0) gives (5a+b=-23), so (a=-8). None of the listed choices is correct.
Step 2
Why this answer is correct
The correct answer is B. (-6). (p(1)=0) gives (a+b=9) and (p(5)=0) gives (5a+b=-23), so (a=-8). None of the listed choices is correct.
Step 3
Exam Tip
(p(1)=0) से (a+b=9) और (p(5)=0) से (5a+b=-23), इसलिए (a=-8) नहीं बल्कि (a=-8) आता है। विकल्पों में कोई सही नहीं है।
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यदि (p(x)=x-3 +ax-2 +bx+18) में (x=1) और (x=-2) दोनों शून्य हैं, तो (a+b) क्या है?
If (x=1) and (x=-2) are both zeros of (p(x)=x-3 +ax-2 +bx+18), what is (a+b)?
#zeros
#cubic
#parameter
A (-19)
B (-18)
C (-17)
D (-16)
Explanation opens after your attempt
Step 1
Concept
From (p(1)=0), (1+a+b+18=0), so (a+b=-19). This condition is directly enough for the asked sum.
Step 2
Why this answer is correct
The correct answer is A. (-19). From (p(1)=0), (1+a+b+18=0), so (a+b=-19). This condition is directly enough for the asked sum.
Step 3
Exam Tip
(p(1)=0) से (1+a+b+18=0), इसलिए (a+b=-19)। पूछे गए योग के लिए यह शर्त सीधे पर्याप्त है।
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यदि (p(x)=x-3 -7x+6), तो इनमें से कौन-सा (p(x)) का गुणनखंड नहीं है?
If (p(x)=x-3 -7x+6), which of the following is not a factor of (p(x))?
#factor-check
#cubic
#trap
A (x+3)
B (x-1)
C (x-2)
D (x+3)
Explanation opens after your attempt
Step 1
Concept
(p(-3)=-27+21+6=0), so (x+3) is actually a factor. This reveals an option error, so check each option using (p(a)).
Step 2
Why this answer is correct
The correct answer is A. (x+3). (p(-3)=-27+21+6=0), so (x+3) is actually a factor. This reveals an option error, so check each option using (p(a)).
Step 3
Exam Tip
(p(-3)=-27+21+6=0), इसलिए (x+3) वास्तव में गुणनखंड है। सही जाँच में यह प्रश्न विकल्प-त्रुटि दिखाता है, इसलिए हर विकल्प को (p(a)) से जाँचें।
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यदि (p(x)=\sqrt{5}x-3 -\frac{2}{3}x+1), तो यह किस प्रकार का बहुपद है?
If (p(x)=\sqrt{5}x-3 -\frac{2}{3}x+1), what type of polynomial is it?
#classification
#cubic
#real-coefficients
A घन बहुपद / Cubic polynomial
B द्विघात बहुपद / Quadratic polynomial
C रेखीय बहुपद / Linear polynomial
D बहुपद नहीं / Not a polynomial
Explanation opens after your attempt
Correct Answer
A. घन बहुपद / Cubic polynomial
Step 1
Concept
The coefficients \(\sqrt{5}\) and \(-\frac{2}{3}\) are real numbers and the highest power is (3). Hence it is a cubic polynomial.
Step 2
Why this answer is correct
The correct answer is A. घन बहुपद / Cubic polynomial. The coefficients \(\sqrt{5}\) and \(-\frac{2}{3}\) are real numbers and the highest power is (3). Hence it is a cubic polynomial.
Step 3
Exam Tip
गुणांक \(\sqrt{5}\) और \(-\frac{2}{3}\) वास्तविक संख्याएँ हैं और सबसे बड़ी घात (3) है। इसलिए यह घन बहुपद है।
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यदि (p(x)=x-3 +x-2 -10x+8) और (x=1) शून्यक है, तो शेष द्विघात गुणनखंड क्या है?
If (p(x)=x-3 +x-2 -10x+8) and (x=1) is a zero, what is the remaining quadratic factor?
#division
#factorisation
#cubic
A \(x^2+2x-8\)
B \(x^2-x+8\)
C \(x^2+8x-2\)
D \(x^2-2x-8\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+2x-8\)
Step 1
Concept
Since (x=1) is a zero, (x-1) is a factor. Division gives \(x^2+2x-8\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+2x-8\). Since (x=1) is a zero, (x-1) is a factor. Division gives \(x^2+2x-8\).
Step 3
Exam Tip
(x=1) शून्यक होने से (x-1) गुणनखंड है। भाग देने पर \(x^2+2x-8\) मिलता है।
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यदि (p(x)=x-3 +3x-2 -4x-12), तो निम्न में से कौन-सा गुणनखंड है?
If (p(x)=x-3 +3x-2 -4x-12), which of the following is a factor?
#factor-theorem
#cubic
#polynomial
A (x+3)
B (x-3)
C (x+2)
D (x-4)
Explanation opens after your attempt
Step 1
Concept
(p(-3)=-27+27+12-12=0), so (x+3) is a factor. For (x+a), test (x=-a).
Step 2
Why this answer is correct
The correct answer is A. (x+3). (p(-3)=-27+27+12-12=0), so (x+3) is a factor. For (x+a), test (x=-a).
Step 3
Exam Tip
(p(-3)=-27+27+12-12=0), इसलिए (x+3) गुणनखंड है। (x+a) के लिए (x=-a) रखकर जाँचें।
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यदि (p(x)=x-3 -6x-2 +11x-6), तो (p(x)) के शून्यक कौन-से हैं?
If (p(x)=x-3 -6x-2 +11x-6), what are the zeroes of (p(x))?
#cubic
#zeroes
#factorisation
A (1,2,3)
B (-1,-2,-3)
C (1,-2,3)
D (2,3,6)
Explanation opens after your attempt
Correct Answer
A. (1,2,3)
Step 1
Concept
(x-3 -6x-2 +11x-6=(x-1)(x-2)(x-3)). Zeroes are read directly from the factors.
Step 2
Why this answer is correct
The correct answer is A. (1,2,3). (x-3 -6x-2 +11x-6=(x-1)(x-2)(x-3)). Zeroes are read directly from the factors.
Step 3
Exam Tip
(x-3 -6x-2 +11x-6=(x-1)(x-2)(x-3)) है। गुणनखंडों से शून्यक सीधे मिलते हैं।
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यदि (p(x)=x-3 -4x-2 +x+6), तो इनमें से कौन (p(x)) का शून्यक है?
If (p(x)=x-3 -4x-2 +x+6), which of these is a zero of (p(x))?
#zero-test
#cubic
#polynomial
A (2)
B (1)
C (-1)
D (3)
Explanation opens after your attempt
Step 1
Concept
(p(2)=8-16+2+6=0), so (2) is a zero. Test small integer options first.
Step 2
Why this answer is correct
The correct answer is A. (2). (p(2)=8-16+2+6=0), so (2) is a zero. Test small integer options first.
Step 3
Exam Tip
(p(2)=8-16+2+6=0), इसलिए (2) शून्यक है। विकल्पों में छोटे पूर्णांकों को पहले जाँचें।
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(p(x)=x-3 +2x-2 -4x-8) में (p(2)-p(-2)) क्या है?
For (p(x)=x-3 +2x-2 -4x-8), what is (p(2)-p(-2))?
#evaluation
#difference
#cubic
A (0)
B (8)
C (16)
D (24)
Explanation opens after your attempt
Step 1
Concept
(p(2)=0) and (p(-2)=-16), so (p(2)-p(-2)=16). While subtracting, the sign of the second value changes.
Step 2
Why this answer is correct
The correct answer is C. (16). (p(2)=0) and (p(-2)=-16), so (p(2)-p(-2)=16). While subtracting, the sign of the second value changes.
Step 3
Exam Tip
(p(2)=0) और (p(-2)=-16), इसलिए (p(2)-p(-2)=16)। घटाते समय दूसरे मान का संकेत बदलता है।
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(p(x)=x-3 -2x-2 -3x+4) में (p(1)) और (p(-1)) का गुणनफल क्या है?
What is the product of (p(1)) and (p(-1)) for (p(x)=x-3 -2x-2 -3x+4)?
#evaluation
#product
#cubic
A (-4)
B (0)
C (4)
D (8)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-2-3+4=0) and (p(-1)=-1-2+3+4=4), so the product is (0). Find both values first.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(1)=1-2-3+4=0) and (p(-1)=-1-2+3+4=4), so the product is (0). Find both values first.
Step 3
Exam Tip
(p(1)=1-2-3+4=0) और (p(-1)=-1-2+3+4=4), इसलिए गुणनफल (0) है। पहले दोनों मान निकालें।
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यदि (p(x)=x-3 +3x-2 +3x+1), तो (p(-2)) क्या है?
If (p(x)=x-3 +3x-2 +3x+1), what is (p(-2))?
#identity
#cubic
#evaluation
A (-1)
B (0)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
It is ((x+1)3 ), so (p(-2)=(-1)3 =-1). Recognizing identities reduces calculation.
Step 2
Why this answer is correct
The correct answer is A. (-1). It is ((x+1)3 ), so (p(-2)=(-1)3 =-1). Recognizing identities reduces calculation.
Step 3
Exam Tip
यह ((x+1)3 ) है, इसलिए (p(-2)=(-1)3 =-1)। पहचान पहचानने से गणना कम होती है।
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यदि (p(x)=x-3 +ax-2 +bx-6) में (x=1) और (x=2) दोनों शून्य हैं, तो (a) क्या है?
If (x=1) and (x=2) are both zeros of (p(x)=x-3 +ax-2 +bx-6), what is (a)?
#zeros
#cubic
#parameter
A (-4)
B (-3)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
(p(1)=0) gives (a+b=5) and (p(2)=0) gives (2a+b=-1), so (a=-6). None of the listed choices is correct.
Step 2
Why this answer is correct
The correct answer is A. (-4). (p(1)=0) gives (a+b=5) and (p(2)=0) gives (2a+b=-1), so (a=-6). None of the listed choices is correct.
Step 3
Exam Tip
(p(1)=0) से (a+b=5) और (p(2)=0) से (2a+b=-1), इसलिए (a=-6) नहीं बल्कि (a=-6) आता है। विकल्पों में कोई सही नहीं है।
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यदि (p(x)=x-3 +ax-2 +bx+12) में (x=1) और (x=-3) दोनों शून्य हैं, तो (a+b) क्या है?
If (x=1) and (x=-3) are both zeros of (p(x)=x-3 +ax-2 +bx+12), what is (a+b)?
#zeros
#cubic
#parameter
A (-13)
B (-12)
C (-11)
D (-10)
Explanation opens after your attempt
Step 1
Concept
From (p(1)=0), we directly get (a+b=-13). The second condition checks consistency, but the first is enough for the asked sum.
Step 2
Why this answer is correct
The correct answer is A. (-13). From (p(1)=0), we directly get (a+b=-13). The second condition checks consistency, but the first is enough for the asked sum.
Step 3
Exam Tip
(p(1)=0) से (a+b=-13) सीधे मिलता है। दूसरी शर्त संगति जांचती है लेकिन पूछे गए योग के लिए पहली शर्त पर्याप्त है।
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(p(x)=x-3 -x-2 +x-1) के लिए (p(1)) क्या है?
What is (p(1)) for (p(x)=x-3 -x-2 +x-1)?
#evaluation
#cubic
#zero
A (-1)
B (0)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-1+1-1=0). Add alternating signs in order.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(1)=1-1+1-1=0). Add alternating signs in order.
Step 3
Exam Tip
(p(1)=1-1+1-1=0)। वैकल्पिक संकेतों को क्रम से जोड़ें।
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यदि (p(x)=2x-3 +rx-2 +s), (p(0)=-3) और (p(1)=4), तो (r) क्या है?
If (p(x)=2x-3 +rx-2 +s), (p(0)=-3), and (p(1)=4), what is (r)?
#parameter
#evaluation
#cubic
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
(p(0)=s=-3) and (p(1)=2+r-3=4), so (r=5). First use (x=0) to find the constant term.
Step 2
Why this answer is correct
The correct answer is C. (5). (p(0)=s=-3) and (p(1)=2+r-3=4), so (r=5). First use (x=0) to find the constant term.
Step 3
Exam Tip
(p(0)=s=-3) और (p(1)=2+r-3=4), इसलिए (r=5)। पहले (x=0) से अचर पद निकालें।
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किस बहुपद के शून्यक (0), (2) और (-3) हैं?
Which polynomial has zeroes (0), (2), and (-3)?
#polynomials
#formation
#cubic
#hard
A \(x^3+x^2-6x\)
B \(x^3-x^2-6x\)
C \(x^3+x^2+6x\)
D \(x^3-5x^2+6x\)
Explanation opens after your attempt
Correct Answer
A. \(x^3+x^2-6x\)
Step 1
Concept
From the zeroes, the polynomial is (x(x-2)(x+3)). Expanding gives \(x^3+x^2-6x\).
Step 2
Why this answer is correct
The correct answer is A. \(x^3+x^2-6x\). From the zeroes, the polynomial is (x(x-2)(x+3)). Expanding gives \(x^3+x^2-6x\).
Step 3
Exam Tip
शून्यकों से बहुपद (x(x-2)(x+3)) बनेगा। इसे फैलाने पर \(x^3+x^2-6x\) मिलता है।
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बहुपद \(2x^3-9x^2+13x-6\) का एक गुणनखंड कौन सा है?
Which is a factor of \(2x^3-9x^2+13x-6\)?
#polynomials
#factor_check
#cubic
#hard
A (x-1)
B (x+1)
C (x-4)
D (x+3)
Explanation opens after your attempt
Step 1
Concept
(p(1)=2-9+13-6=0), so (x-1) is a factor. In option checking, try small values first.
Step 2
Why this answer is correct
The correct answer is A. (x-1). (p(1)=2-9+13-6=0), so (x-1) is a factor. In option checking, try small values first.
Step 3
Exam Tip
(p(1)=2-9+13-6=0) है इसलिए (x-1) गुणनखंड है। विकल्प जांच में छोटे मान पहले लगाएं।
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यदि (p(x)=x-3 +px-2 +qx-6) के शून्यक (1), (2) और (3) हैं, तो (p+q) का मान क्या है?
If the zeroes of (p(x)=x-3 +px-2 +qx-6) are (1), (2), and (3), what is (p+q)?
#polynomials
#cubic
#coefficients
#hard
A (-5)
B (5)
C (11)
D (0)
Explanation opens after your attempt
Step 1
Concept
The polynomial is ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6). Hence (p=-6), (q=11), so (p+q=5).
Step 2
Why this answer is correct
The correct answer is A. (-5). The polynomial is ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6). Hence (p=-6), (q=11), so (p+q=5).
Step 3
Exam Tip
बहुपद ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6) है। इसलिए (p=-6), (q=11) और (p+q=5) नहीं बल्कि (5) है।
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बहुपद (p(x)=ax-3 +bx-2 +cx+d) में \(a\ne0\) है। यदि (p(x)) को रैखिक बहुपद कहा जाए, तो यह कथन क्यों गलत है?
In the polynomial (p(x)=ax-3 +bx-2 +cx+d), \(a\ne0\). Why is it wrong to call (p(x)) a linear polynomial?
#polynomials
#degree
#cubic
#hard
A क्योंकि घात (1) है / Because degree is (1)
B क्योंकि घात (2) है / Because degree is (2)
C क्योंकि घात (3) है / Because degree is (3)
D क्योंकि स्थिर पद (d) है / Because constant term is (d)
Explanation opens after your attempt
Correct Answer
C. क्योंकि घात (3) है / Because degree is (3)
Step 1
Concept
The highest power is (3), so the polynomial is cubic. In exams, always check the highest non-zero exponent.
Step 2
Why this answer is correct
The correct answer is C. क्योंकि घात (3) है / Because degree is (3). The highest power is (3), so the polynomial is cubic. In exams, always check the highest non-zero exponent.
Step 3
Exam Tip
सबसे बड़ी घात (3) है इसलिए बहुपद घन है। परीक्षा में हमेशा सबसे बड़े शून्येतर घातांक को देखें।
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(p(x)=2x-3 +x-2 -5x+2) में (p(2)) और (p(-1)) का अंतर (p(2)-p(-1)) क्या है?
For (p(x)=2x-3 +x-2 -5x+2), what is the difference (p(2)-p(-1))?
#evaluation
#difference
#cubic
A (0)
B (2)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
(p(2)=16+4-10+2=12) and (p(-1)=-2+1+5+2=6), so the difference is (6). Find both values separately.
Step 2
Why this answer is correct
The correct answer is D. (6). (p(2)=16+4-10+2=12) and (p(-1)=-2+1+5+2=6), so the difference is (6). Find both values separately.
Step 3
Exam Tip
(p(2)=16+4-10+2=12) और (p(-1)=-2+1+5+2=6), इसलिए अंतर (6) है। दोनों मान अलग निकालें।
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(p(x)=2x-3 +x-2 -5x+2) में (p(1)) और (p(-1)) का गुणनफल क्या है?
What is the product of (p(1)) and (p(-1)) for (p(x)=2x-3 +x-2 -5x+2)?
#evaluation
#product
#cubic
A (-12)
B (-8)
C (0)
D (12)
Explanation opens after your attempt
Step 1
Concept
(p(1)=2+1-5+2=0), and (p(-1)=-2+1+5+2=6), so the product is (0). The correct option is (0).
Step 2
Why this answer is correct
The correct answer is A. (-12). (p(1)=2+1-5+2=0), and (p(-1)=-2+1+5+2=6), so the product is (0). The correct option is (0).
Step 3
Exam Tip
(p(1)=0) नहीं बल्कि (2+1-5+2=0), और (p(-1)=-2+1+5+2=6), इसलिए गुणनफल (0) है। सही विकल्प (0) है।
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यदि (p(x)=x-3 -3x-2 +3x-1), तो (p(2)) क्या है?
If (p(x)=x-3 -3x-2 +3x-1), what is (p(2))?
#identity
#cubic
#evaluation
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
It is ((x-1)3 ), so (p(2)=(2-1)3 =1). Recognizing identities reduces calculation.
Step 2
Why this answer is correct
The correct answer is B. (1). It is ((x-1)3 ), so (p(2)=(2-1)3 =1). Recognizing identities reduces calculation.
Step 3
Exam Tip
यह ((x-1)3 ) है, इसलिए (p(2)=(2-1)3 =1)। पहचान पहचानने से गणना कम होती है।
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यदि (p(x)=x-3 +ax-2 +bx+4) में (x=1) और (x=-1) दोनों शून्य हैं, तो (a) क्या है?
If (x=1) and (x=-1) are both zeros of (p(x)=x-3 +ax-2 +bx+4), what is (a)?
#zeros
#cubic
#parameter
A (-4)
B (-2)
C (2)
D (4)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1+a+b+4=0) and (p(-1)=-1+a-b+4=0); adding gives (2a+8=0), so (a=-4). Add signs carefully.
Step 2
Why this answer is correct
The correct answer is A. (-4). (p(1)=1+a+b+4=0) and (p(-1)=-1+a-b+4=0); adding gives (2a+8=0), so (a=-4). Add signs carefully.
Step 3
Exam Tip
(p(1)=1+a+b+4=0) और (p(-1)=-1+a-b+4=0), इसलिए (2a+4=0) नहीं बल्कि जोड़ने पर (2a+8=0), अतः (a=-4)। संकेतों को सावधानी से जोड़ें।
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यदि (p(x)=x-3 +ax-2 +bx+6) में (x=1) और (x=-2) दोनों शून्य हैं, तो (a-b) क्या है?
If (x=1) and (x=-2) are both zeros of (p(x)=x-3 +ax-2 +bx+6), what is (a-b)?
#zeros
#cubic
#simultaneous equations
A (-2)
B (2)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
The conditions give (a+b=-7) and (4a-2b=2), so (a=-2), (b=-5), and (a-b=3). The correct value is (3).
Step 2
Why this answer is correct
The correct answer is C. (4). The conditions give (a+b=-7) and (4a-2b=2), so (a=-2), (b=-5), and (a-b=3). The correct value is (3).
Step 3
Exam Tip
शर्तों से (a+b=-7) और (4a-2b=2), इसलिए (a=-2), (b=-5) और (a-b=3)। सही गणना से (a-b=3) मिलता है।
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(p(x)=x-3 +x-2 +x+1) के लिए (p(-1)) क्या है?
What is (p(-1)) for (p(x)=x-3 +x-2 +x+1)?
#evaluation
#cubic
#zero
A (-2)
B (0)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(-1)=-1+1-1+1=0). Add alternating signs in order.
Step 2
Why this answer is correct
The correct answer is B. (0). (p(-1)=-1+1-1+1=0). Add alternating signs in order.
Step 3
Exam Tip
(p(-1)=-1+1-1+1=0)। वैकल्पिक संकेतों को क्रम से जोड़ें।
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यदि (p(x)=x-3 +rx-2 +s), (p(0)=5) और (p(1)=9), तो (r) क्या है?
If (p(x)=x-3 +rx-2 +s), (p(0)=5), and (p(1)=9), what is (r)?
#parameter
#evaluation
#cubic
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
(p(0)=s=5) and (p(1)=1+r+5=9), so (r=3). First use (x=0) to find the constant term.
Step 2
Why this answer is correct
The correct answer is C. (3). (p(0)=s=5) and (p(1)=1+r+5=9), so (r=3). First use (x=0) to find the constant term.
Step 3
Exam Tip
(p(0)=s=5) और (p(1)=1+r+5=9), इसलिए (r=3)। पहले (x=0) से अचर पद निकालें।
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कौन सा व्यंजक (x) में बहुपद है लेकिन (x) में द्विघात नहीं है?
Which expression is a polynomial in (x) but not quadratic in (x)?
#classification
#cubic
#not quadratic
A \(4x^2-3x+1\)
B \(6x^3-2x+9\)
C \(x^2+\frac{5}{x}\)
D \(7\sqrt{x}+2\)
Explanation opens after your attempt
Correct Answer
B. \(6x^3-2x+9\)
Step 1
Concept
\(6x^3-2x+9\) is a polynomial and its degree is (3), so it is not quadratic. Classify by degree.
Step 2
Why this answer is correct
The correct answer is B. \(6x^3-2x+9\). \(6x^3-2x+9\) is a polynomial and its degree is (3), so it is not quadratic. Classify by degree.
Step 3
Exam Tip
\(6x^3-2x+9\) बहुपद है और इसकी घात (3) है, इसलिए यह द्विघात नहीं है। घात से वर्गीकरण करें।
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कौन सा कथन (p(x)=x-3 +1) के बारे में सही है?
Which statement about (p(x)=x-3 +1) is correct?
#cubic
#degree
#classification
A यह रैखिक बहुपद है / It is a linear polynomial
B यह द्विघात बहुपद है / It is a quadratic polynomial
C यह घन बहुपद है / It is a cubic polynomial
D यह बहुपद नहीं है / It is not a polynomial
Explanation opens after your attempt
Correct Answer
C. यह घन बहुपद है / It is a cubic polynomial
Step 1
Concept
In (p(x)=x-3 +1), the highest power is (3), so it is a cubic polynomial. Decide the type of a polynomial by its degree.
Step 2
Why this answer is correct
The correct answer is C. यह घन बहुपद है / It is a cubic polynomial. In (p(x)=x-3 +1), the highest power is (3), so it is a cubic polynomial. Decide the type of a polynomial by its degree.
Step 3
Exam Tip
(p(x)=x-3 +1) में सबसे बड़ी घात (3) है इसलिए यह घन बहुपद है। बहुपद का प्रकार उसकी घात से तय करें।
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(q(x)=x-3 +2x-2 -5x-6) के लिए (q(-2)) क्या होगा?
For (q(x)=x-3 +2x-2 -5x-6), what is (q(-2))?
#evaluation
#negative input
#cubic
A (0)
B (2)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
(q(-2)=-8+8+10-6=4). Check the sign of every term separately when substituting a negative value.
Step 2
Why this answer is correct
The correct answer is C. (4). (q(-2)=-8+8+10-6=4). Check the sign of every term separately when substituting a negative value.
Step 3
Exam Tip
(q(-2)=-8+8+10-6=4)। ऋणात्मक मान रखते समय प्रत्येक पद का संकेत अलग जांचें।
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कौन सा विकल्प \(2x^3-5x^2+x-4\) की घात और नियत पद को सही बताता है?
Which option correctly gives the degree and constant term of \(2x^3-5x^2+x-4\)?
#degree
#constant-term
#cubic-polynomial
A घात (3), नियत पद (-4) / Degree (3), constant term (-4)
B घात (2), नियत पद (1) / Degree (2), constant term (1)
C घात (1), नियत पद (-5) / Degree (1), constant term (-5)
D घात (4), नियत पद (2) / Degree (4), constant term (2)
Explanation opens after your attempt
Correct Answer
A. घात (3), नियत पद (-4) / Degree (3), constant term (-4)
Step 1
Concept
The highest power is (3) and the term without (x) is (-4). So the correct pair is degree (3), constant term (-4).
Step 2
Why this answer is correct
The correct answer is A. घात (3), नियत पद (-4) / Degree (3), constant term (-4). The highest power is (3) and the term without (x) is (-4). So the correct pair is degree (3), constant term (-4).
Step 3
Exam Tip
सबसे बड़ी घात (3) है और बिना (x) वाला पद (-4) है। इसलिए सही जोड़ी घात (3), नियत पद (-4) है।
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कौन सा विकल्प \(x^3-1\) के प्रकार को सही बताता है?
Which option correctly describes the type of \(x^3-1\)?
#cubic-binomial
#classification
#terms
A रैखिक द्विपदी / Linear binomial
B द्विघात त्रिपदी / Quadratic trinomial
C त्रिघात द्विपदी / Cubic binomial
D नियत एकपदी / Constant monomial
Explanation opens after your attempt
Correct Answer
C. त्रिघात द्विपदी / Cubic binomial
Step 1
Concept
\(x^3-1\) has degree (3) and (2) terms. So it is a cubic binomial.
Step 2
Why this answer is correct
The correct answer is C. त्रिघात द्विपदी / Cubic binomial. \(x^3-1\) has degree (3) and (2) terms. So it is a cubic binomial.
Step 3
Exam Tip
\(x^3-1\) की घात (3) है और इसमें (2) पद हैं। इसलिए यह त्रिघात द्विपदी है।
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निम्न में से किस बहुपद का प्रमुख गुणांक (-2) है?
Which polynomial has leading coefficient (-2)?
#leading-coefficient
#cubic-polynomial
#easy
A \(5x^2-2x+1\)
B \(-2x^3+4x+7\)
C \(x^2-2\)
D (3x-2)
Explanation opens after your attempt
Correct Answer
B. \(-2x^3+4x+7\)
Step 1
Concept
The leading term of \(-2x^3+4x+7\) is \(-2x^3\). So the leading coefficient is (-2).
Step 2
Why this answer is correct
The correct answer is B. \(-2x^3+4x+7\). The leading term of \(-2x^3+4x+7\) is \(-2x^3\). So the leading coefficient is (-2).
Step 3
Exam Tip
\(-2x^3+4x+7\) का प्रमुख पद \(-2x^3\) है। इसलिए प्रमुख गुणांक (-2) है।
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\(5x^3+2x^2-x+8\) में \(x^3\) का गुणांक क्या है?
What is the coefficient of \(x^3\) in \(5x^3+2x^2-x+8\)?
#coefficient
#cubic-term
#polynomial
A (5)
B (2)
C (-1)
D (8)
Explanation opens after your attempt
Step 1
Concept
The multiplier of \(x^3\) is (5). A coefficient is identified from its related term.
Step 2
Why this answer is correct
The correct answer is A. (5). The multiplier of \(x^3\) is (5). A coefficient is identified from its related term.
Step 3
Exam Tip
\(x^3\) के साथ लगा गुणक (5) है। गुणांक हमेशा संबंधित पद से पहचाना जाता है।
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(p(x)=2x-3 +3x-2 -5) में (x) का गुणांक क्या है?
What is the coefficient of (x) in (p(x)=2x-3 +3x-2 -5)?
#coefficient
#missing term
#cubic
A (2)
B (3)
C (0)
D (-5)
Explanation opens after your attempt
Step 1
Concept
There is no (x)-term, so its coefficient is (0). Treat the missing term as (0x).
Step 2
Why this answer is correct
The correct answer is C. (0). There is no (x)-term, so its coefficient is (0). Treat the missing term as (0x).
Step 3
Exam Tip
इसमें (x) का पद उपस्थित नहीं है इसलिए उसका गुणांक (0) है। अनुपस्थित पद को (0x) समझें।
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कौन सा विकल्प एक चर में बहुपद है लेकिन द्विघात नहीं है?
Which option is a polynomial in one variable but not quadratic?
#classification
#cubic
#not quadratic
A \(x^2+2x+1\)
B \(4x^3+x-9\)
C \(\frac{1}{x}+2\)
D \(\sqrt{x}+3\)
Explanation opens after your attempt
Correct Answer
B. \(4x^3+x-9\)
Step 1
Concept
\(4x^3+x-9\) is a polynomial and its degree is (3). Therefore it is not quadratic.
Step 2
Why this answer is correct
The correct answer is B. \(4x^3+x-9\). \(4x^3+x-9\) is a polynomial and its degree is (3). Therefore it is not quadratic.
Step 3
Exam Tip
\(4x^3+x-9\) बहुपद है और इसकी घात (3) है। इसलिए यह द्विघात नहीं है।
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(p(x)=4x-3 -2x-2 +7x-1) में \(x^3\) के पद का गुणांक क्या है?
What is the coefficient of the \(x^3\) term in (p(x)=4x-3 -2x-2 +7x-1)?
#coefficient
#cubic term
#polynomial
A (4)
B (-2)
C (7)
D (-1)
Explanation opens after your attempt
Step 1
Concept
The coefficient attached to \(x^3\) is (4). Identify the exponent and coefficient separately.
Step 2
Why this answer is correct
The correct answer is A. (4). The coefficient attached to \(x^3\) is (4). Identify the exponent and coefficient separately.
Step 3
Exam Tip
\(x^3\) के साथ गुणांक (4) जुड़ा है। घात और गुणांक को अलग अलग पहचानें।
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यदि किसी बहुपद की घात (3) है, तो उसे क्या कहते हैं?
If a polynomial has degree (3), what is it called?
#polynomials
#cubic
#easy
#degree
A घन बहुपद / Cubic polynomial
B द्विघात बहुपद / Quadratic polynomial
C रैखिक बहुपद / Linear polynomial
D नियत बहुपद / Constant polynomial
Explanation opens after your attempt
Correct Answer
A. घन बहुपद / Cubic polynomial
Step 1
Concept
A degree (3) polynomial is called a cubic polynomial. The highest power decides the name.
Step 2
Why this answer is correct
The correct answer is A. घन बहुपद / Cubic polynomial. A degree (3) polynomial is called a cubic polynomial. The highest power decides the name.
Step 3
Exam Tip
घात (3) वाला बहुपद घन बहुपद कहलाता है। सबसे बड़ी घात ही नाम तय करती है।
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\(2x^3+x^2+x+8\) किस प्रकार का बहुपद है?
What type of polynomial is \(2x^3+x^2+x+8\)?
#polynomials
#cubic
#easy
#type
A रैखिक / Linear
B द्विघात / Quadratic
C घन / Cubic
D नियत / Constant
Explanation opens after your attempt
Correct Answer
C. घन / Cubic
Step 1
Concept
The highest power is (3), so it is a cubic polynomial. Classify a polynomial by its degree.
Step 2
Why this answer is correct
The correct answer is C. घन / Cubic. The highest power is (3), so it is a cubic polynomial. Classify a polynomial by its degree.
Step 3
Exam Tip
सबसे बड़ी घात (3) है इसलिए यह घन बहुपद है। बहुपद का प्रकार उसकी घात से तय करें।
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यदि (p(x)=x-3 -3x), तो (p\(\sqrt{3}\)) का मान क्या है?
If (p(x)=x-3 -3x), what is (p\(\sqrt{3}\))?
#cubic
#polynomial zero
#irrational
A (0)
B (3)
C \(3\sqrt{3}\)
D \(-3\sqrt{3}\)
Explanation opens after your attempt
Step 1
Concept
(\(\sqrt{3}\)3 =3\sqrt{3}), so \(3\sqrt{3}-3\sqrt{3}=0\). Simplifying powers is the key step in such questions.
Step 2
Why this answer is correct
The correct answer is A. (0). (\(\sqrt{3}\)3 =3\sqrt{3}), so \(3\sqrt{3}-3\sqrt{3}=0\). Simplifying powers is the key step in such questions.
Step 3
Exam Tip
(\(\sqrt{3}\)3 =3\sqrt{3}), इसलिए \(3\sqrt{3}-3\sqrt{3}=0\) है। परीक्षा में ऐसे प्रश्नों में घात को सरल करना मुख्य कदम है।
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यदि \(\alpha=1+\sqrt{2}\) और \(\beta=1-\sqrt{2}\), तो \(\alpha^3+\beta^3\) क्या है?
If \(\alpha=1+\sqrt{2}\) and \(\beta=1-\sqrt{2}\), what is \(\alpha^3+\beta^3\)?
#cubic-expression
#conjugates
#irrational
A (14)
B (-4)
C (2)
D (10)
Explanation opens after your attempt
Step 1
Concept
\(\alpha+\beta=2\) and \(\alpha\beta=-1\), so (\alpha-3 +\beta-3 =23 -3(-1)(2)=14). Use (\alpha-3 +\beta-3 =\(\alpha+\beta\)3 -3\alpha\beta\(\alpha+\beta\)).
Step 2
Why this answer is correct
The correct answer is A. (14). \(\alpha+\beta=2\) and \(\alpha\beta=-1\), so (\alpha-3 +\beta-3 =23 -3(-1)(2)=14). Use (\alpha-3 +\beta-3 =\(\alpha+\beta\)3 -3\alpha\beta\(\alpha+\beta\)).
Step 3
Exam Tip
\(\alpha+\beta=2\) और \(\alpha\beta=-1\), इसलिए (\alpha-3 +\beta-3 =23 -3(-1)(2)=14)। घन योग में (\alpha-3 +\beta-3 =\(\alpha+\beta\)3 -3\alpha\beta\(\alpha+\beta\)) लगाएँ।
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यदि बहुपद (p(x)=5(x+1)(x-2)(x-4)) है तो ग्राफ (x)-अक्ष को कितने अलग बिंदुओं पर काटेगा?
If (p(x)=5(x+1)(x-2)(x-4)), at how many distinct points will the graph cut the (x)-axis?
#cubic
#factor-form
#distinct-intercepts
A तीन / Three
B दो / Two
C एक / One
D पाँच / Five
Explanation opens after your attempt
Correct Answer
A. तीन / Three
Step 1
Concept
The factors give zeroes (-1), (2), and (4). Three distinct zeroes give three distinct (x)-intercepts.
Step 2
Why this answer is correct
The correct answer is A. तीन / Three. The factors give zeroes (-1), (2), and (4). Three distinct zeroes give three distinct (x)-intercepts.
Step 3
Exam Tip
गुणनखंडों से शून्यक (-1), (2), और (4) हैं। तीन अलग शून्यक तीन अलग (x)-प्रतिच्छेद देते हैं।
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ग्राफ (x)-अक्ष को ((-2,0)), ((0,0)), और ((5,0)) पर काटता है। कौन सा कथन सही है?
The graph cuts the (x)-axis at ((-2,0)), ((0,0)), and ((5,0)). Which statement is correct?
#multiple-zeroes
#origin
#cubic
A शून्यक (-2,0,5) हैं / The zeroes are (-2,0,5)
B शून्यक केवल (-2) और (5) हैं / The zeroes are only (-2) and (5)
C शून्यक ((0,0)) नहीं हो सकता / ((0,0)) cannot give a zero
D शून्यकों की संख्या दो है / The number of zeroes is two
Explanation opens after your attempt
Correct Answer
A. शून्यक (-2,0,5) हैं / The zeroes are (-2,0,5)
Step 1
Concept
The origin also lies on the (x)-axis so (0) is also a zero. Write the (x)-values of all intercepts.
Step 2
Why this answer is correct
The correct answer is A. शून्यक (-2,0,5) हैं / The zeroes are (-2,0,5). The origin also lies on the (x)-axis so (0) is also a zero. Write the (x)-values of all intercepts.
Step 3
Exam Tip
मूल बिंदु भी (x)-अक्ष पर है इसलिए (0) भी शून्यक है। सभी (x)-प्रतिच्छेदों के (x)-मान लिखें।
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यदि (p(x)=(x-4)(x-9)(x-15)) है, तो (4<x<9) में ग्राफ कहाँ होगा?
If (p(x)=(x-4)(x-9)(x-15)), where will the graph be for (4<x<9)?
#sign analysis
#cubic graph
#zeroes
A (x)-अक्ष के ऊपर / Above the (x)-axis
B (x)-अक्ष के नीचे / Below the (x)-axis
C ठीक (x)-अक्ष पर / On the (x)-axis
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Correct Answer
A. (x)-अक्ष के ऊपर / Above the (x)-axis
Step 1
Concept
In this interval the signs are (+), (-), (-), so the product is positive. Tip: the product of two negative factors is positive.
Step 2
Why this answer is correct
The correct answer is A. (x)-अक्ष के ऊपर / Above the (x)-axis. In this interval the signs are (+), (-), (-), so the product is positive. Tip: the product of two negative factors is positive.
Step 3
Exam Tip
इस अंतराल में चिह्न (+), (-), (-) हैं, इसलिए गुणनफल धनात्मक है। टिप: दो ऋणात्मक कारकों का गुणन धनात्मक होता है।
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यदि (p(x)=x-3 -12x-2 +35x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?
If (p(x)=x-3 -12x-2 +35x), what is the set of zeroes of the graph?
#cubic factorization
#zeroes
#graph
A (0,5,7)
B (0,-5,-7)
C (5,7,12)
D केवल (0) / Only (0)
Explanation opens after your attempt
Correct Answer
A. (0,5,7)
Step 1
Concept
(x-3 -12x-2 +35x=x(x-5)(x-7)), so the zeroes are (0), (5), (7). Tip: first take (x) as the common factor.
Step 2
Why this answer is correct
The correct answer is A. (0,5,7). (x-3 -12x-2 +35x=x(x-5)(x-7)), so the zeroes are (0), (5), (7). Tip: first take (x) as the common factor.
Step 3
Exam Tip
(x-3 -12x-2 +35x=x(x-5)(x-7)) है, इसलिए शून्यक (0), (5), (7) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।
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यदि (p(x)=x-3 -9x-2 +18x) है, तो ग्राफ के शून्यकों का माध्य क्या है?
If (p(x)=x-3 -9x-2 +18x), what is the mean of the zeroes of the graph?
#cubic factorization
#mean
#zeroes
A (3)
B (6)
C (9)
D \(\frac{18}{3}\)
Explanation opens after your attempt
Step 1
Concept
(p(x)=x(x-3)(x-6)), so the zeroes are (0), (3), (6), and the mean is (3). Tip: factor first.
Step 2
Why this answer is correct
The correct answer is A. (3). (p(x)=x(x-3)(x-6)), so the zeroes are (0), (3), (6), and the mean is (3). Tip: factor first.
Step 3
Exam Tip
(p(x)=x(x-3)(x-6)) है इसलिए शून्यक (0), (3), (6) और माध्य (3) है। टिप: पहले गुणनखंड करें।
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यदि (p(x)=(x-3)(x-6)(x-11)) है, तो (3<x<6) में ग्राफ कहाँ होगा?
If (p(x)=(x-3)(x-6)(x-11)), where will the graph be for (3<x<6)?
#sign analysis
#cubic graph
#zeroes
A (x)-अक्ष के ऊपर / Above the (x)-axis
B (x)-अक्ष के नीचे / Below the (x)-axis
C ठीक (x)-अक्ष पर / On the (x)-axis
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Correct Answer
A. (x)-अक्ष के ऊपर / Above the (x)-axis
Step 1
Concept
In this interval the signs are (+), (-), (-), so the product is positive. Tip: the product of two negative factors is positive.
Step 2
Why this answer is correct
The correct answer is A. (x)-अक्ष के ऊपर / Above the (x)-axis. In this interval the signs are (+), (-), (-), so the product is positive. Tip: the product of two negative factors is positive.
Step 3
Exam Tip
इस अंतराल में चिह्न (+), (-), (-) हैं, इसलिए गुणनफल धनात्मक है। टिप: दो ऋणात्मक कारकों का गुणन धनात्मक होता है।
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यदि (p(x)=x-3 -10x-2 +24x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?
If (p(x)=x-3 -10x-2 +24x), what is the set of zeroes of the graph?
#cubic factorization
#zeroes
#graph
A (0,4,6)
B (0,-4,-6)
C (4,6,10)
D केवल (0) / Only (0)
Explanation opens after your attempt
Correct Answer
A. (0,4,6)
Step 1
Concept
(x-3 -10x-2 +24x=x(x-4)(x-6)), so the zeroes are (0), (4), (6). Tip: first take (x) as the common factor.
Step 2
Why this answer is correct
The correct answer is A. (0,4,6). (x-3 -10x-2 +24x=x(x-4)(x-6)), so the zeroes are (0), (4), (6). Tip: first take (x) as the common factor.
Step 3
Exam Tip
(x-3 -10x-2 +24x=x(x-4)(x-6)) है, इसलिए शून्यक (0), (4), (6) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।
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यदि (p(x)=x-3 -7x-2 +10x) है, तो ग्राफ के शून्यकों का माध्य क्या है?
If (p(x)=x-3 -7x-2 +10x), what is the mean of the zeroes of the graph?
#cubic factorization
#mean
#zeroes
A \(\frac{7}{3}\)
B (7)
C (10)
D \(\frac{10}{3}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{7}{3}\)
Step 1
Concept
(p(x)=x(x-5)(x-2)), so the zeroes are (0), (2), (5), and the mean is \(\frac{7}{3}\). Tip: factor first.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{7}{3}\). (p(x)=x(x-5)(x-2)), so the zeroes are (0), (2), (5), and the mean is \(\frac{7}{3}\). Tip: factor first.
Step 3
Exam Tip
(p(x)=x(x-5)(x-2)) है, इसलिए शून्यक (0), (2), (5) और माध्य \(\frac{7}{3}\) है। टिप: पहले गुणनखंड करें।
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यदि (p(x)=(x-2)(x-5)(x-9)) है तो (2<x<5) में ग्राफ कहाँ होगा?
If (p(x)=(x-2)(x-5)(x-9)), where will the graph be for (2<x<5)?
#sign analysis
#cubic graph
#zeroes
A (x)-अक्ष के ऊपर / Above the (x)-axis
B (x)-अक्ष के नीचे / Below the (x)-axis
C ठीक (x)-अक्ष पर / On the (x)-axis
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Correct Answer
A. (x)-अक्ष के ऊपर / Above the (x)-axis
Step 1
Concept
In this interval the signs are (+), (-), (-), so the product is positive. Tip: the product of two negative factors is positive.
Step 2
Why this answer is correct
The correct answer is A. (x)-अक्ष के ऊपर / Above the (x)-axis. In this interval the signs are (+), (-), (-), so the product is positive. Tip: the product of two negative factors is positive.
Step 3
Exam Tip
इस अंतराल में चिह्न (+), (-), (-) हैं इसलिए गुणनफल धनात्मक है। टिप: दो ऋणात्मक कारकों का गुणन धनात्मक होता है।
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यदि (p(x)=x-3 -8x-2 +15x) है तो ग्राफ के शून्यकों का समूह कौन सा है?
If (p(x)=x-3 -8x-2 +15x), what is the set of zeroes of the graph?
#cubic factorization
#zeroes
#graph
A (0,3,5)
B (0,-3,-5)
C (3,5,8)
D केवल (0) / Only (0)
Explanation opens after your attempt
Correct Answer
A. (0,3,5)
Step 1
Concept
(x-3 -8x-2 +15x=x(x-3)(x-5)), so the zeroes are (0,3,5). Tip: first take (x) as the common factor.
Step 2
Why this answer is correct
The correct answer is A. (0,3,5). (x-3 -8x-2 +15x=x(x-3)(x-5)), so the zeroes are (0,3,5). Tip: first take (x) as the common factor.
Step 3
Exam Tip
(x-3 -8x-2 +15x=x(x-3)(x-5)) है इसलिए शून्यक (0,3,5) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।
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यदि (p(x)=x-3 -25x) है तो ग्राफ (x)-अक्ष को कितने अलग बिंदुओं पर काटेगा?
If (p(x)=x-3 -25x), at how many distinct points will the graph cut the (x)-axis?
#cubic
#distinct zeroes
#graph
A एक / One
B दो / Two
C तीन / Three
D चार / Four
Explanation opens after your attempt
Correct Answer
C. तीन / Three
Step 1
Concept
(x-3 -25x=x(x-5)(x+5)), so there are three distinct zeroes. Tip: first take out the common factor.
Step 2
Why this answer is correct
The correct answer is C. तीन / Three. (x-3 -25x=x(x-5)(x+5)), so there are three distinct zeroes. Tip: first take out the common factor.
Step 3
Exam Tip
(x-3 -25x=x(x-5)(x+5)) है इसलिए तीन अलग शून्यक हैं। टिप: पहले सामान्य गुणनखंड निकालें।
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यदि (p(x)=(x-1)(x-3)(x-5)) है, तो (1<x<3) में ग्राफ कहाँ होगा?
If (p(x)=(x-1)(x-3)(x-5)), where will the graph be for (1<x<3)?
#sign analysis
#cubic graph
#zeroes
A (x)-अक्ष के ऊपर / Above the (x)-axis
B (x)-अक्ष के नीचे / Below the (x)-axis
C ठीक (x)-अक्ष पर / On the (x)-axis
D निर्धारित नहीं / Cannot be determined
Explanation opens after your attempt
Correct Answer
A. (x)-अक्ष के ऊपर / Above the (x)-axis
Step 1
Concept
In this interval the signs are (+), (-), (-), so the product is positive. Tip: an odd number of negative factors gives a negative value.
Step 2
Why this answer is correct
The correct answer is A. (x)-अक्ष के ऊपर / Above the (x)-axis. In this interval the signs are (+), (-), (-), so the product is positive. Tip: an odd number of negative factors gives a negative value.
Step 3
Exam Tip
इस अंतराल में चिह्न (+), (-), (-) हैं, इसलिए गुणनफल धनात्मक है। टिप: विषम संख्या ऋणात्मक कारकों से मान ऋणात्मक होता है।
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यदि (p(x)=x-3 -6x-2 +5x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?
If (p(x)=x-3 -6x-2 +5x), what is the set of zeroes of the graph?
#cubic factorization
#zeroes
#graph
A (0,1,5)
B (0,-1,-5)
C (1,5,6)
D केवल (0) / Only (0)
Explanation opens after your attempt
Correct Answer
A. (0,1,5)
Step 1
Concept
(x-3 -6x-2 +5x=x(x-1)(x-5)), so the zeroes are (0,1,5). Tip: first take (x) as the common factor.
Step 2
Why this answer is correct
The correct answer is A. (0,1,5). (x-3 -6x-2 +5x=x(x-1)(x-5)), so the zeroes are (0,1,5). Tip: first take (x) as the common factor.
Step 3
Exam Tip
(x-3 -6x-2 +5x=x(x-1)(x-5)) है, इसलिए शून्यक (0,1,5) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।
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यदि (p(x)=x-3 -16x) है, तो ग्राफ (x)-अक्ष को कितने अलग बिंदुओं पर काटेगा?
If (p(x)=x-3 -16x), at how many distinct points will the graph cut the (x)-axis?
#cubic
#distinct zeroes
#graph
A एक / One
B दो / Two
C तीन / Three
D चार / Four
Explanation opens after your attempt
Correct Answer
C. तीन / Three
Step 1
Concept
(x-3 -16x=x(x-4)(x+4)), so there are three distinct zeroes. Tip: first take out the common factor.
Step 2
Why this answer is correct
The correct answer is C. तीन / Three. (x-3 -16x=x(x-4)(x+4)), so there are three distinct zeroes. Tip: first take out the common factor.
Step 3
Exam Tip
(x-3 -16x=x(x-4)(x+4)) है, इसलिए तीन अलग शून्यक हैं। टिप: पहले सामान्य गुणनखंड निकालें।
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यदि (p(x)=x-3 -4x-2 -5x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?
If (p(x)=x-3 -4x-2 -5x), what is the set of zeroes of the graph?
#cubic factorization
#zeroes
#graph
A (0, -1, 5)
B (0, 1, -5)
C (4, -5, 0)
D केवल (0) / Only (0)
Explanation opens after your attempt
Correct Answer
A. (0, -1, 5)
Step 1
Concept
(x-3 -4x-2 -5x=x(x-5)(x+1)), so the zeroes are (0), (5), (-1). Tip: first take (x) as the common factor.
Step 2
Why this answer is correct
The correct answer is A. (0, -1, 5). (x-3 -4x-2 -5x=x(x-5)(x+1)), so the zeroes are (0), (5), (-1). Tip: first take (x) as the common factor.
Step 3
Exam Tip
(x-3 -4x-2 -5x=x(x-5)(x+1)), इसलिए शून्यक (0), (5), (-1) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।
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