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यदि किरण धनात्मक (x)-अक्ष से \(\frac{7}{3}\) पूर्ण चक्कर दक्षिणावर्त घूमे तो मुख्य धनात्मक कोण क्या होगा?

If a ray turns \(\frac{7}{3}\) complete revolutions clockwise from the positive (x)-axis then what is the principal positive angle?

Explanation opens after your attempt
Correct Answer

D. \(\frac{4\pi}{3}\)

Step 1

Concept

The clockwise angle is \(-\frac{14\pi}{3}\). Adding \(6\pi\) gives the principal angle \(\frac{4\pi}{3}\).

Step 2

Why this answer is correct

The correct answer is D. \(\frac{4\pi}{3}\). The clockwise angle is \(-\frac{14\pi}{3}\). Adding \(6\pi\) gives the principal angle \(\frac{4\pi}{3}\).

Step 3

Exam Tip

दक्षिणावर्त कोण \(-\frac{14\pi}{3}\) है। इसमें \(6\pi\) जोड़ने पर \(\frac{4\pi}{3}\) मुख्य कोण मिलता है।

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