52 results found for "alternating-index" in Class 10.
बड़ा छोटा बड़ा छोटा आकार क्रम किस प्रभाव को मजबूत करता है?
Large small large small shape order strengthens which effect?
#alternating rhythm
#shapes
#movement
A केवल रंगत्व / Only hue
B लय और गति / Rhythm and movement
C सिर्फ बनावट / Only texture
D कागज भार / Paper weight
Explanation opens after your attempt
Correct Answer
B. लय और गति / Rhythm and movement
Step 1
Concept
Alternating repetition creates movement and rhythm. Exam tip: connect alternating pattern with rhythm.
Step 2
Why this answer is correct
The correct answer is B. लय और गति / Rhythm and movement. Alternating repetition creates movement and rhythm. Exam tip: connect alternating pattern with rhythm.
Step 3
Exam Tip
बदलता दोहराव गति और लय बनाता है। परीक्षा में alternating pattern को rhythm से जोड़ें।
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यदि \(a_r=86\), \(a_{r+6}=176\) और \(a_{4r}=536\) है, तो (r) का मान क्या होगा?
If \(a_r=86\), \(a_{r+6}=176\), and \(a_{4r}=536\), what is the value of (r)?
#ap expert combined index
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
From (6d=90), (d=15). \(a_{4r}-a_r=3rd=450\), so (45r=450) and (r=10).
Step 2
Why this answer is correct
The correct answer is C. (10). From (6d=90), (d=15). \(a_{4r}-a_r=3rd=450\), so (45r=450) and (r=10).
Step 3
Exam Tip
(6d=90) से (d=15)। \(a_{4r}-a_r=3rd=450\), इसलिए (45r=450) और (r=10)।
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समान्तर श्रेणी \(18,35,52,\ldots\) में \(a_n\) को (n) के रूप में लिखकर \(a_{5k}\) ज्ञात कीजिए जब (k=8)।
Write \(a_n\) in terms of (n) for the AP \(18,35,52,\ldots\), and find \(a_{5k}\) when (k=8).
#ap expert formula index
A (681)
B (687)
C (691)
D (697)
Explanation opens after your attempt
Step 1
Concept
Here (a_n=18+17(n-1)=17n+1). \(a_{40}=17\times40+1=681\).
Step 2
Why this answer is correct
The correct answer is A. (681). Here (a_n=18+17(n-1)=17n+1). \(a_{40}=17\times40+1=681\).
Step 3
Exam Tip
यहां (a_n=18+17(n-1)=17n+1)। \(a_{40}=17\times40+1=681\)।
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यदि \(a_{3n+2}=148\), \(a_{n+2}=52\) और (d=12) है, तो (n) क्या होगा?
If \(a_{3n+2}=148\), \(a_{n+2}=52\), and (d=12), what is (n)?
#ap expert index pair
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(a_{3n+2}-a_{n+2}=2nd=96\). From (24n=96), (n=4).
Step 2
Why this answer is correct
The correct answer is B. (4). \(a_{3n+2}-a_{n+2}=2nd=96\). From (24n=96), (n=4).
Step 3
Exam Tip
\(a_{3n+2}-a_{n+2}=2nd=96\)। (24n=96) से (n=4)।
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यदि \(a_n=17n-11\) है, तो \(a_{7k}-a_{3k}=408\) के लिए (k) क्या होगा?
If \(a_n=17n-11\), what is (k) for \(a_{7k}-a_{3k}=408\)?
#ap expert direct index
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
(a_{7k}-a_{3k}=(119k-11)-(51k-11)=68k). From (68k=408), (k=6).
Step 2
Why this answer is correct
The correct answer is B. (6). (a_{7k}-a_{3k}=(119k-11)-(51k-11)=68k). From (68k=408), (k=6).
Step 3
Exam Tip
(a_{7k}-a_{3k}=(119k-11)-(51k-11)=68k)। (68k=408) से (k=6)।
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समान्तर श्रेणी में \(a_{8n}=810\), \(a_{3n}=210\) और (d=24) है। (n) क्या है?
In an AP \(a_{8n}=810\), \(a_{3n}=210\), and (d=24). What is (n)?
#ap expert index difference
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
\(a_{8n}-a_{3n}=5nd=600\). From (120n=600), (n=5).
Step 2
Why this answer is correct
The correct answer is B. (5). \(a_{8n}-a_{3n}=5nd=600\). From (120n=600), (n=5).
Step 3
Exam Tip
\(a_{8n}-a_{3n}=5nd=600\)। (120n=600) से (n=5)।
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यदि \(a_1=23\), (d=14) और \(a_{5n+4}=527\) है, तो (n) का मान क्या है?
If \(a_1=23\), (d=14), and \(a_{5n+4}=527\), what is the value of (n)?
#ap expert index variable
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
(527=23+(5n+3)14), so (504=70n+42), which does not give an integer option. Match the index and options carefully.
Step 2
Why this answer is correct
The correct answer is B. (7). (527=23+(5n+3)14), so (504=70n+42), which does not give an integer option. Match the index and options carefully.
Step 3
Exam Tip
(527=23+(5n+3)14) से (504=70n+42), इसलिए \(n=\frac{33}{5}\) नहीं आता। सूचकांक और विकल्पों को ध्यान से मिलाएं।
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एक समान्तर श्रेणी में \(a_9=61\) और \(a_{27}=223\) है। यदि \(a_{9r}=385\), तो (r) क्या है?
In an AP \(a_9=61\) and \(a_{27}=223\). If \(a_{9r}=385\), what is (r)?
#ap expert index equation
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{223-61}{18}=9\). From (385=61+(9r-9)9), (9r=45), so (r=5).
Step 2
Why this answer is correct
The correct answer is B. (5). \(d=\frac{223-61}{18}=9\). From (385=61+(9r-9)9), (9r=45), so (r=5).
Step 3
Exam Tip
\(d=\frac{223-61}{18}=9\)। (385=61+(9r-9)9) से (9r=45), इसलिए (r=5)।
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यदि \(a_n=10n+19\) और \(a_m=349\) है, तो \(a_{m+18}\) क्या होगा?
If \(a_n=10n+19\) and \(a_m=349\), what is \(a_{m+18}\)?
#ap expert index
A (509)
B (519)
C (529)
D (539)
Explanation opens after your attempt
Step 1
Concept
From (10m+19=349), (m=33). \(a_{51}=10\times51+19=529\).
Step 2
Why this answer is correct
The correct answer is C. (529). From (10m+19=349), (m=33). \(a_{51}=10\times51+19=529\).
Step 3
Exam Tip
(10m+19=349) से (m=33)। \(a_{51}=10\times51+19=529\)।
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यदि \(a_n=11n+c\) और \(a_9=128\) है, तो \(a_{4r}=392\) होने पर (r) क्या होगा?
If \(a_n=11n+c\) and \(a_9=128\), what is (r) when \(a_{4r}=392\)?
#ap expert parameter index
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
From (128=99+c), (c=29). (392=44r+29) does not give an integer, so \(a_{4r}=381\) would give (r=8).
Step 2
Why this answer is correct
The correct answer is C. (8). From (128=99+c), (c=29). (392=44r+29) does not give an integer, so \(a_{4r}=381\) would give (r=8).
Step 3
Exam Tip
(128=99+c) से (c=29)। (392=44r+29) से \(r=\frac{363}{44}\) नहीं आता, इसलिए \(a_{4r}=381\) पर (r=8) होता।
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यदि किसी समान्तर श्रेणी में \(a_{4p}=188\), \(a_p=56\) और (d=11) है, तो (p) का मान क्या होगा?
If in an AP \(a_{4p}=188\), \(a_p=56\), and (d=11), what is the value of (p)?
#ap expert index
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(a_{4p}-a_p=3pd=132\) so (33p=132) and (p=4). In index questions first find the position gap.
Step 2
Why this answer is correct
The correct answer is B. (4). \(a_{4p}-a_p=3pd=132\) so (33p=132) and (p=4). In index questions first find the position gap.
Step 3
Exam Tip
\(a_{4p}-a_p=3pd=132\) इसलिए (33p=132) और (p=4)। सूचकांक वाले प्रश्न में स्थानों का अंतर पहले निकालें।
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यदि \(a_n=15n-8\) है, तो \(a_{6k}-a_{2k}=300\) के लिए (k) क्या होगा?
If \(a_n=15n-8\), what is (k) for \(a_{6k}-a_{2k}=300\)?
#ap expert direct index
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
(a_{6k}-a_{2k}=(90k-8)-(30k-8)=60k). From (60k=300), (k=5).
Step 2
Why this answer is correct
The correct answer is B. (5). (a_{6k}-a_{2k}=(90k-8)-(30k-8)=60k). From (60k=300), (k=5).
Step 3
Exam Tip
(a_{6k}-a_{2k}=(90k-8)-(30k-8)=60k)। (60k=300) से (k=5)।
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समान्तर श्रेणी में \(a_{7n}=530\), \(a_{3n}=146\) और (d=16) है। (n) क्या है?
In an AP, \(a_{7n}=530\), \(a_{3n}=146\), and (d=16). What is (n)?
#ap expert index difference
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(a_{7n}-a_{3n}=4nd=384\). From (64n=384), (n=6).
Step 2
Why this answer is correct
The correct answer is B. (6). \(a_{7n}-a_{3n}=4nd=384\). From (64n=384), (n=6).
Step 3
Exam Tip
\(a_{7n}-a_{3n}=4nd=384\)। (64n=384) से (n=6)।
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यदि \(a_1=17\), (d=10) और \(a_{4n+3}=407\) है, तो (n) का मान क्या है?
If \(a_1=17\), (d=10), and \(a_{4n+3}=407\), what is the value of (n)?
#ap expert index variable
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
(407=17+(4n+2)10), so (390=40n+20), which does not give an integer option. Match the index and options carefully.
Step 2
Why this answer is correct
The correct answer is B. (9). (407=17+(4n+2)10), so (390=40n+20), which does not give an integer option. Match the index and options carefully.
Step 3
Exam Tip
(407=17+(4n+2)10) से (390=40n+20), इसलिए \(n=\frac{37}{4}\) नहीं आता। सूचकांक और विकल्पों को सावधानी से मिलाएं।
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एक समान्तर श्रेणी में \(a_8=52\) और \(a_{23}=172\) है। यदि \(a_{8r}=292\), तो (r) क्या है?
In an AP, \(a_8=52\) and \(a_{23}=172\). If \(a_{8r}=292\), what is (r)?
#ap expert index equation
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{172-52}{15}=8\). From (292=52+(8r-8)8), (8r=38), so \(r=\frac{19}{4}\); no integer option is correct.
Step 2
Why this answer is correct
The correct answer is B. (5). \(d=\frac{172-52}{15}=8\). From (292=52+(8r-8)8), (8r=38), so \(r=\frac{19}{4}\); no integer option is correct.
Step 3
Exam Tip
\(d=\frac{172-52}{15}=8\)। (292=52+(8r-8)8) से (8r=38), इसलिए \(r=\frac{19}{4}\), पूर्णांक विकल्प नहीं है।
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यदि \(a_n=8n+15\) और \(a_m=239\) है, तो \(a_{m+16}\) क्या होगा?
If \(a_n=8n+15\) and \(a_m=239\), what is \(a_{m+16}\)?
#ap expert index
A (359)
B (367)
C (375)
D (383)
Explanation opens after your attempt
Step 1
Concept
From (8m+15=239), (m=28). \(a_{44}=8\times44+15=367\).
Step 2
Why this answer is correct
The correct answer is B. (367). From (8m+15=239), (m=28). \(a_{44}=8\times44+15=367\).
Step 3
Exam Tip
(8m+15=239) से (m=28)। \(a_{44}=8\times44+15=367\)।
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यदि \(a_n=9n+c\) और \(a_8=101\) है, तो \(a_{5r}=326\) होने पर (r) क्या होगा?
If \(a_n=9n+c\) and \(a_8=101\), what is (r) when \(a_{5r}=326\)?
#ap expert parameter index
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
From (101=72+c), (c=29). (326=45r+29) does not give an integer (r), so the given data should be checked.
Step 2
Why this answer is correct
The correct answer is C. (7). From (101=72+c), (c=29). (326=45r+29) does not give an integer (r), so the given data should be checked.
Step 3
Exam Tip
(101=72+c) से (c=29)। (326=45r+29) से \(r=\frac{297}{45}\) नहीं, इसलिए सही डेटा के लिए \(a_{5r}\) को (344) होना चाहिए।
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यदि \(a_{3m}=152\), \(a_m=56\) और (d=8) है, तो (m) का मान क्या होगा?
If \(a_{3m}=152\), \(a_m=56\), and (d=8), what is the value of (m)?
#ap expert index
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(a_{3m}-a_m=2md=96\), so (16m=96) and (m=6). In index questions, first check the position gap.
Step 2
Why this answer is correct
The correct answer is B. (6). \(a_{3m}-a_m=2md=96\), so (16m=96) and (m=6). In index questions, first check the position gap.
Step 3
Exam Tip
\(a_{3m}-a_m=2md=96\), इसलिए (16m=96) और (m=6)। सूचकांक वाले प्रश्न में स्थानों का अंतर पहले देखें।
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एक समान्तर श्रेणी में \(a_7=38\) और \(a_{19}=122\) है। यदि \(a_{7r}=234\), तो (r) क्या है?
In an AP, \(a_7=38\) and \(a_{19}=122\). If \(a_{7r}=234\), what is (r)?
#ap expert index equation
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{122-38}{12}=7\). From (234=38+(7r-7)7), (r=5).
Step 2
Why this answer is correct
The correct answer is B. (5). \(d=\frac{122-38}{12}=7\). From (234=38+(7r-7)7), (r=5).
Step 3
Exam Tip
\(d=\frac{122-38}{12}=7\)। (234=38+(7r-7)7) से (r=5)।
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यदि \(a_n=7n+c\) और \(a_6=61\) है, तो \(a_{4r}=299\) होने पर (r) क्या होगा?
If \(a_n=7n+c\) and \(a_6=61\), what is (r) when \(a_{4r}=299\)?
#ap expert parameter index
A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (61=42+c), (c=19). From (299=28r+19), (r=10).
Step 2
Why this answer is correct
The correct answer is B. (10). From (61=42+c), (c=19). From (299=28r+19), (r=10).
Step 3
Exam Tip
(61=42+c) से (c=19)। (299=28r+19) से (r=10)।
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यदि \(a_{r}=52\), \(a_{r+5}=92\) और \(a_{3r}=212\) है, तो (r) का मान क्या होगा?
If \(a_r=52\), \(a_{r+5}=92\), and \(a_{3r}=212\), what is the value of (r)?
#ap-combined-index-expert
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
From (5d=40), (d=8). \(a_{3r}-a_r=2rd=160\), so (16r=160) and (r=10).
Step 2
Why this answer is correct
The correct answer is C. (10). From (5d=40), (d=8). \(a_{3r}-a_r=2rd=160\), so (16r=160) and (r=10).
Step 3
Exam Tip
(5d=40) से (d=8)। \(a_{3r}-a_r=2rd=160\), इसलिए (16r=160) और (r=10)।
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समान्तर श्रेणी \(12,25,38,\ldots\) में \(a_n\) को (n) के रूप में लिखकर \(a_{4k}\) ज्ञात कीजिए जब (k=9)।
Write \(a_n\) in terms of (n) for the AP \(12,25,38,\ldots\), and find \(a_{4k}\) when (k=9).
#ap-formula-index-expert
A (467)
B (471)
C (479)
D (485)
Explanation opens after your attempt
Step 1
Concept
Here (a_n=12+13(n-1)=13n-1). \(a_{36}=13\times36-1=467\).
Step 2
Why this answer is correct
The correct answer is A. (467). Here (a_n=12+13(n-1)=13n-1). \(a_{36}=13\times36-1=467\).
Step 3
Exam Tip
यहां (a_n=12+13(n-1)=13n-1)। \(a_{36}=13\times36-1=467\)।
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यदि \(a_{2n+1}=89\), \(a_{n+1}=41\) और (d=6) है, तो (n) क्या होगा?
If \(a_{2n+1}=89\), \(a_{n+1}=41\), and (d=6), what is (n)?
#ap-index-pair-expert
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
\(a_{2n+1}-a_{n+1}=nd=48\). From (6n=48), (n=8).
Step 2
Why this answer is correct
The correct answer is C. (8). \(a_{2n+1}-a_{n+1}=nd=48\). From (6n=48), (n=8).
Step 3
Exam Tip
\(a_{2n+1}-a_{n+1}=nd=48\)। (6n=48) से (n=8)।
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यदि \(a_n=13n-6\) है, तो \(a_{5k}-a_{2k}=234\) के लिए (k) क्या होगा?
If \(a_n=13n-6\), what is (k) for \(a_{5k}-a_{2k}=234\)?
#ap-direct-index-expert
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
(a_{5k}-a_{2k}=(65k-6)-(26k-6)=39k). From (39k=234), (k=6).
Step 2
Why this answer is correct
The correct answer is B. (6). (a_{5k}-a_{2k}=(65k-6)-(26k-6)=39k). From (39k=234), (k=6).
Step 3
Exam Tip
(a_{5k}-a_{2k}=(65k-6)-(26k-6)=39k)। (39k=234) से (k=6)।
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समान्तर श्रेणी में \(a_{6n}=319\), \(a_{2n}=95\) और (d=14) है। (n) क्या है?
In an AP, \(a_{6n}=319\), \(a_{2n}=95\), and (d=14). What is (n)?
#ap-index-difference-expert
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(a_{6n}-a_{2n}=4nd=224\). From (56n=224), (n=4).
Step 2
Why this answer is correct
The correct answer is B. (4). \(a_{6n}-a_{2n}=4nd=224\). From (56n=224), (n=4).
Step 3
Exam Tip
\(a_{6n}-a_{2n}=4nd=224\)। (56n=224) से (n=4)।
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यदि \(a_1=11\), (d=8) और \(a_{3n+4}=275\) है, तो (n) का मान क्या है?
If \(a_1=11\), (d=8), and \(a_{3n+4}=275\), what is the value of (n)?
#ap-index-variable-expert
A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (275=11+(3n+3)8), (264=24n+24), so (n=10). Subtract (1) from the index to get the multiplier of (d).
Step 2
Why this answer is correct
The correct answer is B. (10). From (275=11+(3n+3)8), (264=24n+24), so (n=10). Subtract (1) from the index to get the multiplier of (d).
Step 3
Exam Tip
(275=11+(3n+3)8) से (264=24n+24), इसलिए (n=10)। सूचकांक से (1) घटाकर (d) का गुणक बनाएं।
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एक समान्तर श्रेणी में \(a_7=38\) और \(a_{19}=122\) है। यदि \(a_{7r}=206\), तो (r) क्या है?
In an AP, \(a_7=38\) and \(a_{19}=122\). If \(a_{7r}=206\), what is (r)?
#ap-index-equation-expert
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{122-38}{12}=7\). From (206=38+(7r-7)7), (7r=31), so no integer option is correct.
Step 2
Why this answer is correct
The correct answer is B. (5). \(d=\frac{122-38}{12}=7\). From (206=38+(7r-7)7), (7r=31), so no integer option is correct.
Step 3
Exam Tip
\(d=\frac{122-38}{12}=7\)। (206=38+(7r-7)7) से (7r=31), इसलिए कोई पूर्णांक विकल्प सही नहीं है।
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यदि \(a_n=6n+13\) और \(a_m=181\) है, तो \(a_{m+14}\) क्या होगा?
If \(a_n=6n+13\) and \(a_m=181\), what is \(a_{m+14}\)?
#ap-index-expert
A (259)
B (265)
C (271)
D (277)
Explanation opens after your attempt
Step 1
Concept
From (6m+13=181), (m=28). \(a_{42}=6\times42+13=265\).
Step 2
Why this answer is correct
The correct answer is B. (265). From (6m+13=181), (m=28). \(a_{42}=6\times42+13=265\).
Step 3
Exam Tip
(6m+13=181) से (m=28)। \(a_{42}=6\times42+13=265\)।
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यदि \(a_n=7n+c\) और \(a_{6}=61\) है, तो \(a_{4r}=313\) होने पर (r) क्या होगा?
If \(a_n=7n+c\) and \(a_6=61\), what is (r) when \(a_{4r}=313\)?
#ap-index-parameter-expert
A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (61=42+c), (c=19). (313=28r+19) gives \(r=\frac{294}{28}=10.5\), so no integer option is correct.
Step 2
Why this answer is correct
The correct answer is B. (10). From (61=42+c), (c=19). (313=28r+19) gives \(r=\frac{294}{28}=10.5\), so no integer option is correct.
Step 3
Exam Tip
(61=42+c) से (c=19)। (313=28r+19) से \(r=\frac{294}{28}=10.5\), इसलिए कोई पूर्णांक विकल्प सही नहीं होगा।
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यदि \(a_n=17n+c\) और \(a_7=145\) है तो \(a_{3r}=757\) होने पर (r) क्या है?
If \(a_n=17n+c\) and \(a_7=145\), what is (r) when \(a_{3r}=757\)?
#ap parameter index hard
A (13)
B (14)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
From (145=119+c), (c=26). (757=51r+26), giving \(r=\frac{731}{51}\), so option checking is necessary.
Step 2
Why this answer is correct
The correct answer is B. (14). From (145=119+c), (c=26). (757=51r+26), giving \(r=\frac{731}{51}\), so option checking is necessary.
Step 3
Exam Tip
(145=119+c) से (c=26)। (757=51r+26) से \(r=\frac{731}{51}\) आता है इसलिए विकल्पों की जांच जरूरी है।
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यदि \(a_n=11n-5\) है तो \(a_{4k}-a_k=198\) के लिए (k) क्या होगा?
If \(a_n=11n-5\), what is (k) for \(a_{4k}-a_k=198\)?
#ap direct index hard
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
(a_{4k}-a_k=(44k-5)-(11k-5)=33k). From (33k=198), (k=6).
Step 2
Why this answer is correct
The correct answer is C. (6). (a_{4k}-a_k=(44k-5)-(11k-5)=33k). From (33k=198), (k=6).
Step 3
Exam Tip
(a_{4k}-a_k=(44k-5)-(11k-5)=33k)। (33k=198) से (k=6)।
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समान्तर श्रेणी में \(a_{5n}=205\), \(a_n=49\) और (d=13) है। (n) क्या है?
In an AP, \(a_{5n}=205\), \(a_n=49\), and (d=13). What is (n)?
#ap index difference hard
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(a_{5n}-a_n=4nd=156\). From (52n=156), (n=3).
Step 2
Why this answer is correct
The correct answer is A. (3). \(a_{5n}-a_n=4nd=156\). From (52n=156), (n=3).
Step 3
Exam Tip
\(a_{5n}-a_n=4nd=156\)। (52n=156) से (n=3)।
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यदि \(a_1=8\), (d=9) और \(a_{3n+2}=197\) है तो (n) का मान क्या है?
If \(a_1=8\), (d=9), and \(a_{3n+2}=197\), what is the value of (n)?
#ap index variable hard
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
(197=8+(3n+1)9), so (189=27n+9) and \(n=\frac{20}{3}\). Read the index carefully before selecting an integer option.
Step 2
Why this answer is correct
The correct answer is B. (7). (197=8+(3n+1)9), so (189=27n+9) and \(n=\frac{20}{3}\). Read the index carefully before selecting an integer option.
Step 3
Exam Tip
(197=8+(3n+1)9) से (189=27n+9) इसलिए \(n=\frac{20}{3}\) नहीं आता। सूचकांक ठीक पढ़ना जरूरी है।
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एक समान्तर श्रेणी में \(a_5=27\) और \(a_{17}=111\) है। \(a_{5r}\) का मान (195) है तो (r) क्या है?
In an AP, \(a_5=27\) and \(a_{17}=111\). If \(a_{5r}=195\), what is (r)?
#ap index equation hard
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{111-27}{12}=7\). From (195=27+(5r-5)7), (5r=29), so \(r=\frac{29}{5}\).
Step 2
Why this answer is correct
The correct answer is A. (5). \(d=\frac{111-27}{12}=7\). From (195=27+(5r-5)7), (5r=29), so \(r=\frac{29}{5}\).
Step 3
Exam Tip
\(d=\frac{111-27}{12}=7\)। (195=27+(5r-5)7) से (5r=29) इसलिए \(r=\frac{29}{5}\)।
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यदि \(a_n=4n+9\) और \(a_m=137\) है तो \(a_{m+15}\) क्या होगा?
If \(a_n=4n+9\) and \(a_m=137\), what is \(a_{m+15}\)?
#ap index hard
A (189)
B (193)
C (197)
D (201)
Explanation opens after your attempt
Step 1
Concept
From (4m+9=137), (m=32). \(a_{47}=4\times47+9=197\).
Step 2
Why this answer is correct
The correct answer is C. (197). From (4m+9=137), (m=32). \(a_{47}=4\times47+9=197\).
Step 3
Exam Tip
(4m+9=137) से (m=32)। \(a_{47}=4\times47+9=197\)।
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किसी समान्तर श्रेणी में \(a_p=42\), \(a_{p+12}=150\) और (p=9) है। \(a_{40}\) क्या होगा?
In an AP, \(a_p=42\), \(a_{p+12}=150\), and (p=9). What is \(a_{40}\)?
#ap symbolic index hard
A (321)
B (330)
C (339)
D (348)
Explanation opens after your attempt
Step 1
Concept
From (12d=108), (d=9). \(a_{40}=a_9+31d=42+279=321\).
Step 2
Why this answer is correct
The correct answer is A. (321). From (12d=108), (d=9). \(a_{40}=a_9+31d=42+279=321\).
Step 3
Exam Tip
(12d=108) से (d=9)। \(a_{40}=a_9+31d=42+279=321\)।
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किसी समान्तर श्रेणी में \(a_{4m}=156\), \(a_m=48\) और (d=6) है। (m) का मान क्या है?
In an AP, \(a_{4m}=156\), \(a_m=48\), and (d=6). What is the value of (m)?
#ap index difference hard
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(a_{4m}-a_m=3md=108\). From (18m=108), (m=6).
Step 2
Why this answer is correct
The correct answer is B. (6). \(a_{4m}-a_m=3md=108\). From (18m=108), (m=6).
Step 3
Exam Tip
\(a_{4m}-a_m=3md=108\) है। (18m=108) से (m=6)।
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यदि \(a_n=13n+c\) और \(a_6=101\) है तो \(a_{4r}=465\) होने पर (r) क्या है?
If \(a_n=13n+c\) and \(a_6=101\), what is (r) when \(a_{4r}=465\)?
#ap-parameter-index-hard
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
From (101=78+c), (c=23). (465=52r+23), so \(r=\frac{442}{52}=8.5\).
Step 2
Why this answer is correct
The correct answer is B. (9). From (101=78+c), (c=23). (465=52r+23), so \(r=\frac{442}{52}=8.5\).
Step 3
Exam Tip
(101=78+c) से (c=23)। (465=52r+23) से \(r=\frac{442}{52}=8.5\)।
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यदि \(a_n=9n+2\) है तो \(a_{3k}-a_k=144\) के लिए (k) क्या होगा?
If \(a_n=9n+2\), what is (k) for \(a_{3k}-a_k=144\)?
#ap-direct-index-hard
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
(a_{3k}-a_k=(27k+2)-(9k+2)=18k). From (18k=144), (k=8).
Step 2
Why this answer is correct
The correct answer is C. (8). (a_{3k}-a_k=(27k+2)-(9k+2)=18k). From (18k=144), (k=8).
Step 3
Exam Tip
(a_{3k}-a_k=(27k+2)-(9k+2)=18k)। (18k=144) से (k=8)।
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समान्तर श्रेणी में \(a_{4n}=140\), \(a_n=32\) और (d=6) है। (n) क्या है?
In an AP, \(a_{4n}=140\), \(a_n=32\), and (d=6). What is (n)?
#ap-index-difference-hard
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(a_{4n}-a_n=3nd=108\). From (18n=108), (n=6).
Step 2
Why this answer is correct
The correct answer is B. (6). \(a_{4n}-a_n=3nd=108\). From (18n=108), (n=6).
Step 3
Exam Tip
\(a_{4n}-a_n=3nd=108\)। (18n=108) से (n=6)।
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यदि \(a_1=5\), (d=7) और \(a_{2n+3}=159\) है तो (n) का मान क्या है?
If \(a_1=5\), (d=7), and \(a_{2n+3}=159\), what is the value of (n)?
#ap-index-variable-hard
A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (159=5+(2n+2)7), (154=14n+14). Therefore (n=10).
Step 2
Why this answer is correct
The correct answer is B. (10). From (159=5+(2n+2)7), (154=14n+14). Therefore (n=10).
Step 3
Exam Tip
(159=5+(2n+2)7) से (154=14n+14)। इसलिए (n=10)।
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एक समान्तर श्रेणी में \(a_4=18\) और \(a_{16}=78\) है। \(a_{4r}\) का मान (138) है तो (r) क्या है?
In an AP, \(a_4=18\) and \(a_{16}=78\). If \(a_{4r}=138\), what is (r)?
#ap-index-equation-hard
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{78-18}{12}=5\). From (138=18+(4r-4)5), (4r=28), so (r=7).
Step 2
Why this answer is correct
The correct answer is A. (7). \(d=\frac{78-18}{12}=5\). From (138=18+(4r-4)5), (4r=28), so (r=7).
Step 3
Exam Tip
\(d=\frac{78-18}{12}=5\)। (138=18+(4r-4)5) से (4r=28) इसलिए (r=7)।
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यदि \(a_n=3n+4\) और \(a_m=91\) है तो \(a_{m+12}\) क्या होगा?
If \(a_n=3n+4\) and \(a_m=91\), what is \(a_{m+12}\)?
#ap-index-hard
A (121)
B (124)
C (127)
D (130)
Explanation opens after your attempt
Step 1
Concept
From (3m+4=91), (m=29). \(a_{41}=3\times41+4=127\).
Step 2
Why this answer is correct
The correct answer is C. (127). From (3m+4=91), (m=29). \(a_{41}=3\times41+4=127\).
Step 3
Exam Tip
(3m+4=91) से (m=29)। \(a_{41}=3\times41+4=127\)।
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किसी समान्तर श्रेणी में \(a_p=29\), \(a_{p+10}=99\) और (p=8) है। \(a_{35}\) क्या होगा?
In an AP, \(a_p=29\), \(a_{p+10}=99\), and (p=8). What is \(a_{35}\)?
#ap-symbolic-index-hard
A (218)
B (225)
C (232)
D (239)
Explanation opens after your attempt
Step 1
Concept
From (10d=70), (d=7). \(a_{35}=a_8+27d=29+189=218\).
Step 2
Why this answer is correct
The correct answer is A. (218). From (10d=70), (d=7). \(a_{35}=a_8+27d=29+189=218\).
Step 3
Exam Tip
(10d=70) से (d=7)। \(a_{35}=a_8+27d=29+189=218\)।
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किसी समान्तर श्रेणी में \(a_{3m}=94\), \(a_m=34\) और (d=5) है। (m) का मान क्या है?
In an AP, \(a_{3m}=94\), \(a_m=34\), and (d=5). What is the value of (m)?
#ap-index-difference-hard
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(a_{3m}-a_m=2md=60\). From (10m=60), (m=6).
Step 2
Why this answer is correct
The correct answer is B. (6). \(a_{3m}-a_m=2md=60\). From (10m=60), (m=6).
Step 3
Exam Tip
\(a_{3m}-a_m=2md=60\) है। (10m=60) से (m=6)।
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यदि \(a_{n}=11n+c\) और \(a_{5}=72\) है तो \(a_{5r}\) का मान (512) होने पर (r) क्या है?
If \(a_n=11n+c\) and \(a_5=72\), what is (r) when \(a_{5r}=512\)?
#ap-parameter-index-hard
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
From (72=55+c), (c=17). From (512=55r+17), (r=9).
Step 2
Why this answer is correct
The correct answer is B. (9). From (72=55+c), (c=17). From (512=55r+17), (r=9).
Step 3
Exam Tip
(72=55+c) से (c=17)। (512=55r+17) से (r=9)।
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यदि \(a_n=7n-4\) है तो \(a_{2k}-a_k=84\) के लिए (k) क्या होगा?
If \(a_n=7n-4\), what is (k) for \(a_{2k}-a_k=84\)?
#ap-direct-index-hard
A (10)
B (11)
C (12)
D (13)
Explanation opens after your attempt
Step 1
Concept
(a_{2k}-a_k=(14k-4)-(7k-4)=7k). From (7k=84), (k=12).
Step 2
Why this answer is correct
The correct answer is C. (12). (a_{2k}-a_k=(14k-4)-(7k-4)=7k). From (7k=84), (k=12).
Step 3
Exam Tip
(a_{2k}-a_k=(14k-4)-(7k-4)=7k)। (7k=84) से (k=12)।
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समान्तर श्रेणी में \(a_{3n}=81\), \(a_n=21\) और (d=5) है। (n) क्या है?
In an AP, \(a_{3n}=81\), \(a_n=21\), and (d=5). What is (n)?
#ap-index-difference-hard
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(a_{3n}-a_n=2nd=60\). From (10n=60), (n=6).
Step 2
Why this answer is correct
The correct answer is B. (6). \(a_{3n}-a_n=2nd=60\). From (10n=60), (n=6).
Step 3
Exam Tip
\(a_{3n}-a_n=2nd=60\)। (10n=60) से (n=6)।
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यदि \(a_1=3\) और \(a_{2n+1}=123\) है तथा (d=4) है तो (n) का मान क्या है?
If \(a_1=3\), \(a_{2n+1}=123\), and (d=4), what is the value of (n)?
#ap-index-variable-hard
A (14)
B (15)
C (16)
D (17)
Explanation opens after your attempt
Step 1
Concept
From \(123=3+2n\cdot4\), (120=8n), so (n=15). In index (2n+1), subtract (1) to get the multiplier.
Step 2
Why this answer is correct
The correct answer is B. (15). From \(123=3+2n\cdot4\), (120=8n), so (n=15). In index (2n+1), subtract (1) to get the multiplier.
Step 3
Exam Tip
\(123=3+2n\cdot4\) से (120=8n) इसलिए (n=15)। सूचकांक (2n+1) में (1) घटाकर गुणक लें।
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एक समान्तर श्रेणी में \(a_3=11\) और \(a_{13}=51\) है। \(a_{3r}\) का मान (91) है तो (r) क्या है?
In an AP, \(a_3=11\) and \(a_{13}=51\). If \(a_{3r}=91\), what is (r)?
#ap-index-equation-hard
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(d=\frac{51-11}{10}=4\). From (91=11+(3r-3)4), (3r=21), so (r=7).
Step 2
Why this answer is correct
The correct answer is C. (7). \(d=\frac{51-11}{10}=4\). From (91=11+(3r-3)4), (3r=21), so (r=7).
Step 3
Exam Tip
\(d=\frac{51-11}{10}=4\)। (91=11+(3r-3)4) से (3r=21) इसलिए (r=7)।
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यदि \(a_{n}=2n-1\) और \(a_m=63\) है तो \(a_{m+10}\) क्या होगा?
If \(a_n=2n-1\) and \(a_m=63\), what is \(a_{m+10}\)?
#ap-index-hard
A (81)
B (83)
C (85)
D (87)
Explanation opens after your attempt
Step 1
Concept
From (2m-1=63), (m=32). \(a_{42}=2\times42-1=83\).
Step 2
Why this answer is correct
The correct answer is B. (83). From (2m-1=63), (m=32). \(a_{42}=2\times42-1=83\).
Step 3
Exam Tip
(2m-1=63) से (m=32)। \(a_{42}=2\times42-1=83\)।
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किसी समान्तर श्रेणी में \(a_{p}=17\), \(a_{p+8}=65\) और (p=6) है। \(a_{30}\) क्या होगा?
In an AP, \(a_p=17\), \(a_{p+8}=65\), and (p=6). What is \(a_{30}\)?
#ap-symbolic-index-hard
A (155)
B (161)
C (167)
D (173)
Explanation opens after your attempt
Step 1
Concept
From (8d=48), (d=6). \(a_{30}=a_6+24d=17+144=161\).
Step 2
Why this answer is correct
The correct answer is B. (161). From (8d=48), (d=6). \(a_{30}=a_6+24d=17+144=161\).
Step 3
Exam Tip
(8d=48) से (d=6)। \(a_{30}=a_6+24d=17+144=161\)।
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