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Question Easy Biotechnology Processes of Recombinant DNA Technology Cutting of DNA Class 11 Level 55

Restriction enzyme aliquot बनाने का practical लाभ क्या है?

What is the practical benefit of making restriction enzyme aliquots?

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Correct Answer

B. repeated freeze-thaw और contamination risk घटानाTo reduce repeated freeze-thaw and contamination risk

Step 1

Concept

Aliquots avoid repeated thawing of main stock. This preserves enzyme stability and cleanliness.

Step 2

Why this answer is correct

The correct answer is B. repeated freeze-thaw और contamination risk घटाना / To reduce repeated freeze-thaw and contamination risk. Aliquots avoid repeated thawing of main stock. This preserves enzyme stability and cleanliness.

Step 3

Exam Tip

Aliquots main stock को बार-बार thaw करने से बचाते हैं। इससे enzyme stability और cleanliness बनी रहती है।

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Question Easy Biotechnology Processes of Recombinant DNA Technology Isolation of DNA Class 11 Level 43

Long-term storage के लिए DNA को aliquot करने का एक लाभ क्या है?

What is one benefit of aliquoting DNA for long-term storage?

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Correct Answer

A. repeated freeze-thaw damage कम करनाReducing repeated freeze-thaw damage

Step 1

Concept

Aliquots avoid repeated thawing of the same tube. This protects DNA quality.

Step 2

Why this answer is correct

The correct answer is A. repeated freeze-thaw damage कम करना / Reducing repeated freeze-thaw damage. Aliquots avoid repeated thawing of the same tube. This protects DNA quality.

Step 3

Exam Tip

Aliquots same tube को बार-बार thaw करने से बचाते हैं। इससे DNA quality सुरक्षित रहती है।

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Question Expert Chemistry Chapter 01: Solutions 2: Concentration Metrics Class 12 Level 6

100 मिलीलीटर 0.5 मोल प्रति लीटर विलयन में से 20 मिलीलीटर निकालकर जल से फिर 100 मिलीलीटर कर दिया गया। नई मोलरता कितनी होगी?

20 mL is taken out from 100 mL of 0.5 mol L-1 solution and diluted again to 100 mL with water. What is the new molarity?

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Correct Answer

B. 0.10 मोल प्रति लीटर0.10 mol L-1

Step 1

Concept

Moles in the withdrawn 20 mL portion = 0.5 × 0.020 = 0.010 mol.

Step 2

Why this answer is correct

This portion is diluted to 100 mL = 0.100 L. New molarity = 0.010 ÷ 0.100 = 0.10.

Step 3

Exam Tip

Count moles in the taken portion, not in the whole original solution. चरण 1: निकाले गए 20 मिलीलीटर भाग में मोल = 0.5 × 0.020 = 0.010 मोल हैं। चरण 2: इसी भाग को 100 मिलीलीटर यानी 0.100 लीटर तक पतला किया गया। नई मोलरता = 0.010 ÷ 0.100 = 0.10। चरण 3: ऐसे प्रश्नों में पूरे पुराने विलयन के बजाय निकाले गए भाग के मोल गिनें।

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